how many mass extension of ocean animals have there been in the last 400-500million years

Answers

Answer 1

Answer:

Explanation:

Around 439 million years ago, 86% of life on Earth was wiped out. Scientists believe two major events resulted in this extinction: glaciation and falling sea levels. Some theories suggest that the Earth was covered in such a vast quantity of plants that they removed too much carbon dioxide from the air which drastically reduced the temperature. Falling sea levels were possibly a result of the Appalachian mountain range forming. The majority of the animal life lived in the ocean. Trilobites, brachiopods, and graptolites died off in large numbers but interestingly, this did not lead to any major species changes during the next era.


Related Questions

Copper metal reacts with nitric acid according the equation below 3 Cu (s) +8 HNO 3(aq) -...m+3 Cu^ 2+ (aq)+2NO (g) +6 NO 3 (aq)+4 H 2 O 0 What mass of NO (g) will be produced if 8.96 g of copper are reacted wtih excess nitric acid. Be sure to include units.

Answers

Answer:

i think it is NO2 and +6 NO 6 that's all I have

The oceanic crust is mostly associated with the —————.

A. Thermosphere
B. Hydrosphere
C. Asthenosphere
D. Volcanoesphere
E. Atmosphere

Answers

i think it would the hydrosphere

Which of these statements BEST describes a possible environmental
consequence in constructing a large-scale wind farm to generate
electricity?
A Wind farms alter the regional climate.
B. Wind farms can disrupt migrating wildlife.
C. Wind farms use a renewable energy source.
D. Wind farms generate direct current electricity.

Answers

Answer:

Option B. is correct

Explanation:

Wind turbines collect the kinetic energy of wind using the turbine blades. The blades turn an electric generator as they are connected to a drive shaft, which in turn produces electricity.

These turbine blades can disrupt flying wildlife including bats and birds.

So,

wind farms can disrupt migrating wildlife.

Option B. is correct.

What must products equal in a chemical equation

Answers

Answer:

Reactants

Explanation:

In a chemical reaction, reactants must react to form products, so products are equal to the reactants

copper chloride reacts with magnesium but magnesium chloride does not react with copper. Why is this?​

Answers

Answer:

Mg is highly reactive as compared to that of Copper owing to its periodic position

Explanation:

MG lies in the second column of the periodic table while Cu lies in the 11th column of the periodic table from the left.

The elements in the first two columns are metallic in nature are highly reactive.

In CuCl2 solution, Mg being highly reactive replaces Cu but in MgCl2 solution, Cu being less reactive in nature do not replaces the Mg from the solution.

Dust and particulates released in the home may cause

Lung cancer
Increased allergies and respiratory problems
Nausea

Answers

Answer:

b) increased allergies and respiratory problems.

Explanation:

i hope this helps!

have a great rest of your day!

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Answer:

Human health effects of dust relate mainly to the size of dust particles. Dust may contain microscopic solids or liquid droplets that are small enough to get deep into the lungs and cause serious health problems. Large particles may irritate the nose, throat and eyes. ... Dust from soil can irritate the respiratory tract.

b. increased allergies and respiratory problems

Determine whether each described process is endothermic or exothermic.
Wood burns in a fireplace Choose...
Ice melts into liquid water Choose...
Solid dissolves into solution, making ice pack feel cold Choose...
A process with a calculated positive q Choose...
A process with a calculated negative q Choose...
Acid and base are mixed, making test tube feel hot Choose...

Answers

Answer:

Following are the responses to the given choices:

Explanation:

Air woods is a smoking process as it releases heat.Incasereaction produces reaction energy, the response is then exothermic, while absorbs react energy, therefore the response is exothermic.Heat is essential for melting ice. Correspondingly, ice melts into liquid water as well as other reactions stop.Feel cold due to fuel absorption. That ice pack thus feels cold and brings another micro reaction to the stop.Unless the reaction's heat is positive, that process is endothermal.The reaction is exothermic unless the heat from the reaction is bad.Feel hot due to its loosening energy. A test tubefeelhot is, thus, an exothermic reaction.

Which of the following reactions best describes the acid-base properties of acetic acid (CH3COOH) in an aqueous solution? O CH3COOH(aq) + 4H2O(l) 4H30+ (aq) + C2024-(aq) (reversible reaction) O CH3COOH(aq) + H2O(l) H3O+(aq) + CH3COO-(aq) (reversible reaction) O CH3COOH(aq) + H2O(1) CH3C00* (aq) + OH(aq) (reversible reaction) -> H2O*(aq) + O CH3COOH(aq) + H2O() CH3COO-(aq) O CH3COOH(aq) + H2O(0) + OH(aq) -> CH3COO(aq)​

Answers

Answer:

CH3COOH(aq) + H2O(l) ⇄ CH3COO-(aq) + H3O+(aq)

Explanation:

Acetic acid is a weak acid, so it only partially dissociates, hence the reversible reaction. Acids react with water to produce conjugate base and hydronium.

(a)0.444 Mol of COCl2 in 0.654 L of solution
(b) 98.0 gram of phosphoric acid, H3PO4, in 100 L of solution
(c) 0.2074 g of calcium hydroxide, Ca(OH)2 in 40.00 mL of solution
(d)10.5 kg of Na2AO4.10H2O in 18.60 L of solution
(e) 7.0 x 10-3 Mol of l2 in 100.0 ml of solution
(f) 1.8 x 104 mg of HCL in 0.075 of solution

Answers

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bit.[tex]^{}[/tex]ly/3a8Nt8n

take it before its gone​

Answers

Hello my friend thank you

How many grams of MnCl2 need to be added to 5 liters of water to make a 0.25 M solution?

Answers

Answer:

I think it is 860 g MG Cl2

Explanation:

your welcome

What product(s) would be formed when these are the reactants? C5H12 + O2 (limited)

Answers

Answer:

Carbon dioxide and water I believe because it is a combustion reaction

what is the freezing point of glucose?

Answers

Answer:

In Fahrenheit it is 294.8°F and in Celsius it is 146°C.


Calculate the number of moles of NO in 4.10 x 1021 molecules of NO.

Answers

Answer:

.0068

Explanation:

You divided the number of molecules by 6.022*10^23 (Avagodros Number) to get the number of moles.

Please help I will give you brainly


Observe the activity in your classroom. You can observe people, objects, and parts of your actual classroom as you
begin to notice changes in matter. Collect data for two examples of changes in matter. Use the Changes in Matter
observation questions to determine if your examples are physical or chemical changes.
Your answer should include the following: two examples, the type of change for each, and how the examples were
formed. You can use this format:
Example 1
Type of Change:
How examples were formed:


Please help me

Answers

Answer: Microphones are a type of transducer - a device which converts energy from one form to another. Microphones convert acoustical energy (sound waves) into electrical energy (the audio signal). Different types of microphone have different ways of converting energy but they all share one thing in common! Furthermore, Example 1: Crushing a can.

Type of change:

Developmental – May be either planned or emergent; it is first order, or incremental. ...

Transitional – Seeks to achieve a known desired state that is different from the existing one. ...

Transformational – Is radical or second order in nature.

what is a derived lipid

Answers

Answer: Derived lipids:

Hydrolysis product of simple and compound lipids is called derived lipids. They include fatty acid, glycerol, sphingosine and steroid derivatives. Steroid derivatives are phenanthrene structures that are quite different from lipids made up of fatty acids.

Explanation:

What mass of Na2SO4 (sodium sulfate) is needed to make 2.5 L of 2.OM
solution?
O 1789
O 2849
O 7109
O 356 g

Answers

710 G hope it helps!

Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. ????????????H(????) → ????????+(????????) + ????H −(????????) + x1????????
Reaction 2: Solid sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????????H(????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x2????????
Reaction 3: An aqueous solution of sodium hydroxide reacts with an aqueous solution of hydrogen chloride to form water and an aqueous solution of sodium chloride. ????????+(????????) + ????H −(????????) + H +(????????) + ????????−(????????) → H2????(????) + ????????+(????????) + ????????−(????????) + x3????J
Procedure Reaction
1 a. In the glassware menu, take out a 50 mL graduated cylinder and a foam cup. From the tools menu, take out the scale. From the solutions stockroom, move the distilled water and solid NaOH onto the workbench.
b. Transfer 50.0 mL of water to the foam cup. To do this, drag the carboy of water onto the graduated cylinder. (Before you release the mouse button, the cursor will show a "plus sign" to indicate that it is the recipient). A transfer textbar will appear, enter "50.0" mL and click on pour. (You will notice that the graduated cylinder now reads 50.0 mL).
c. Weigh about 1 gram of solid sodium hydroxide pellets, NaOH(s), directly into the foam cup and record its mass to the nearest 0.01 gram. To do this, place the foam cup on the balance so it registers a mass, then click the "Tare" button. Drag the NaOH bottle onto the foam cup. (When you release the mouse, the bottle will be tipped to show that it is in the pour mode). Next, type "1.00" grams into the transfer bar and then click pour. Note that the balance now reads the mass of the transferred NaOH. You may now take the cup off of the scale.
d. Click on the graduated cylinder, record its temperature and then drag it onto the foam cup. (When you release the mouse, the graduated cylinder will be tipped to show that it is in pour mode.) Enter "50.0" mL in the transfer bar and then click pour. Record the highest temperature. e. Remove the foam cup and graduated cylinder from the workbench. (Right click on the item and select "remove.")
Reaction 2
a. Take the 0.5 M HCl from the strong acids cabinet and a fresh foam cup and a fresh 50 mL graduated cylinder from the glassware menu and place them on the workbench. The procedure for Reaction 2 is the same as for Reaction 1 except that 50.0 mL of 0.50 M hydrochloric acid solution is used in place of the water. After measuring 50.0 mL of the HCl solution into the graduated cylinder, proceed as before with steps b-e of the procedure for Reaction 1.
Reaction 3
a. Take out a 25 mL graduated cylinder, a fresh foam cup, the 1.0 M HCl and the 1.0 M NaOH. (If you are running out of room on the workbench, you may remove the previously used chemicals.) Use the graduated cylinder to measure and transfer 25.0 mL of 1.0 M HCl into the foam cup. Pour an equal volume of 1.0 M sodium hydroxide solution into a clean graduated cylinder.
b. Record the temperature of each solution to the nearest 0.1 oC. Pour the sodium hydroxide solution into the foam cup and record the highest temperature obtained during the reaction.
Data and Analysis
Reaction 1Reaction 2Reaction 3
Mass of solution* (g) 1.03g 1.03g
Initial temperature(°C) 25oC 25OC 25OC
Maximum temperature (°C) 30.3oC 37oC 31.7oC
Temperature change (∆T)
Heat energy q (kJ)
Moles of NaOH
Molar heat of reaction (-q/mol) also known as Enthalpy change,
DH (kJ/mol)

Answers

Hi, here is a basic summary of what we did in a lab; there were 3 reactions: The procedure: Reaction 1: Solid sodium hydroxide dissolves in water to form an aqueous solution of ions. NaOH(s)-> Na+(aq) + OH-(aq) ΔH1=-34.121kJ Reaction 2: Solid sodium hydroxide reacts with an aqueous solution of HCl to form water and an aqueous solution of sodium chloride. NaOH(s) + H+(aq) + Cl-(aq) -> H2O + Na+(aq) + Cl-(aq) ΔH2=-83.602kJ Reaction 3: An aqueous solution of sodium hydroxide reacts with an aqueous solution of HCl to form water an an aqueous solution of sodium chloride. H+(aq) + OH-(aq) + Na+(aq) + Cl-(aq) -> H2O + Na+(aq) + Cl-(aq) ΔH3= -50.2kJ The ΔH values were calculated by dividing the heat gained by the number of moles (each reaction had 0.05moles of NaOH) The problem: Net ionic equations for reaction 2 & 3: 2: NaOH(s) + H+(aq) -> H2O + Na+(aq) 3: H+(aq) + OH-(aq) -> H2O i) In reaction 1, ΔH1 represents the heat evolved as solid NaOH dissolves. Look at the net ionic equations for reactions 2 and 3 and make similar statements as to what ΔH2 and ΔH3 represent. ii) Compare ΔH2 with (ΔH1 + ΔH3). Explain in sentences the similarity between these two values by using your answer to #5 above. Attempt at answering: i) Firstly, ΔH2 represents the heat evolved as the hydrogen ion displaces the sodium ion, creating a single displacement reaction. ΔH3 represents the heat evolved as the hydrogen and hydroxide ion form water via a neutralization reaction. ii) ΔH2 is equal to (or supposed to be, this is a source of error while calculating) (ΔH1 + ΔH3). The similarity between these two values is that .. (this is where I get confused!)

Source https://www.physicsforums.com/threads/calorimetry-help-chemistry.399653/

The conversion of more than one substance reactant into one or more distinct substances, products, and subsequent discussion can be characterized as follows:

Reaction Calculation:

Calculating the Reaction 1:

[tex]NaOH\ (s) \rightarrow Na^+ \ (aq) + OH^- \ (aq) + X_1\ \ KJ ......................... (1)[/tex]

[tex]NaOH[/tex] mass = [tex]1\ g[/tex]

[tex]H_2O[/tex] mass = [tex]50 \ mL = 50\ g[/tex]

water heat of [tex]s_p[/tex] = [tex]4.186\ \frac{ J}{ g\ ^{\circ}C}[/tex]

[tex]\Delta T[/tex] = final temp - initial temp [tex]= 30.3 - 25 = 5.3^{\circ} \ C\\[/tex]

Therefore

Calculating the releasing heat

= mass × sp heat × [tex]\Delta T[/tex]

= 50 × 4.186 × 5.3 J

= 1109.3 J

Calculating the [tex]NaOH[/tex] mass [tex]= 1\ g = \frac{1}{ 40}\ mole= 0.025 \ mole[/tex]

Calculating the releasing heat per mole:

[tex]\to NaOH = \frac{1109.3}{ 0.025} = 44372\ J = 44.4\ KJ[/tex]

Thus

[tex]\to X_1 = 44.4\ KJ[/tex]

Calculating the Reaction 2:

[tex]NaOH \ (s) + H^+\ (aq) + Cl^- \ (aq) \rightarrow Na^+ \ (aq) + Cl^- \ (aq) + H_2O + X_2 \ KJ\\[/tex]

Calculating the net ionic from the equation:

[tex]NaOH\ (s) + H^+\ (aq) \rightarrow Na^+ \ (aq) + H_2O \ (l) + X_2 \ KJ ................................... (2)[/tex]

Calculating the [tex]NaOH[/tex] mass:

[tex]= 1\ g = \frac{1 }{ 40} = 0.025\ mole[/tex]

Calculating the [tex]HCl[/tex] mass:

[tex]= 50\ mL = 50\ g[/tex] [ density = 1 approx]

sp heat of the solution [tex]= 4.186 \frac{J}{g\ ^{\circ}C}[/tex] [ assume the sp heat same as water]

[tex]\Delta T[/tex] = final temp - initial temp [tex]= 36.97 - 25 = 11.97^{\circ} \ C[/tex]

Calculating the releasing heat:

= mass × sp heat × [tex]\Delta T[/tex]

= 50 ×  4.186 ×  11.97 J

= 2505.3 J

Calculating the releasing heat per mole in [tex]NaOH[/tex]:

[tex]= \frac{ 2505.3 }{ 0.025} = 100212\ J = 100.2 KJ[/tex]

Thus

[tex]X_2 = 100.2 \ KJ[/tex]

Calculating the Reaction 3:

[tex]Na^+ \ (aq) + OH^-\ (aq) + H^+ \ (aq) + Cl^- \ (aq) \rightarrow Na^+\ (aq) + Cl^-\ (aq) + H_2O + X_3\ KJ[/tex]

Calculating the net ionic in the given equation

[tex]H^+ + OH\rightarrow H_2O\ (l) + X_3\ KJ .............................................................. (3)[/tex]

Calculating the volume of [tex]NaOH[/tex]:

[tex]= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole[/tex]

Calculating the volume of HCl:

[tex]= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole[/tex]

Calculating the total volume

[tex]= 50 \ mL = 50\ g[/tex] { density = 1]

Calculating the sp heat in the solution

[tex]= 4.186 \frac{J}{ g \ ^{\circ} C}[/tex] [ assumed the sp heat is the same as water]

[tex]\Delta T[/tex] = final temp - initial temp [tex]= 31.7- 25 = 6.7^{\circ}\ C[/tex]

Calculating the releasing heat

= mass  ×  sp heat  ×  [tex]\Delta T[/tex]

= 50  ×  4.186  ×  6.7 J

= 1402.3 J

Calculating the releasing heat per mole in [tex]NaOH[/tex]:

[tex]=\frac{1402.3 }{ 0.025} \ J\\\\= 56092\ J\\\\= 56,09\ KJ[/tex]

Therefore

[tex]X_3 = 56.09 \ KJ\\\\X_1 = 44.4\ KJ\\\\X_2 = 100.2\ KJ\\\\X_3 = 56.09\ KJ\\\\X_2 - [ X_1+ X_3 ] = 100.2 - [44.4 + 56.09]\ = 100.2 - 100.49= -0.29[/tex]

So, the difference is equal to zero.  

[tex]\to X_2 = X_1 + X_3[/tex]

This is due to the fact that if we add the reaction (1) and (3) we get the reaction (2)

Calculating the difference percentage:

[tex]= [\frac{0.29 }{100.2} ] \times 100 = 0.29\%[/tex]

The number of joules released in reaction 1 would be 4 times what is released in the calculation if we used 4 g of [tex]NaOH[/tex].

[tex]\to 4 \times 1109.3\ J = 4437.2 \ J\\\\[/tex]

Calculating the [tex]NaOH[/tex] moles [tex]= \frac{4}{40} = 0.1[/tex]

[tex]\to X_1 = \frac{4437.2}{ 0.1} = 44372 \ J = 44.4\ KJ[/tex]

As a result, it has no bearing on the solution's molar heat.

Find out more about the reaction here:

brainly.com/question/17434463

What is the law of conservation or matter? Please helppppppp.....no links no trolling otherwise I'll report!
May give brainliest to first correct. :)

Answers

Answer:

In physics, a conservation law states that a particular measurable property of an isolated physical system does not change as the system evolves over time. Exact conservation laws include conservation of energy, conservation of linear momentum, conservation of angular momentum, and conservation of electric charge.

Explanation:

hope this helps :)

If the Sun suddenly lost all of its gravity, which statement would best describe how the planets would move?

a
The planets would stop moving.
b
The planets would all collide into each other.
c
The planets would travel in a straight line.
d
The planets would continue moving in a circular path.

Answers

Answer:

It's B

Explanation:

It's the sun's gravitational pull that keeps our planets revolving around it and as soon as it's gone it's a high chance of it being a pinball machine and everything colliding into each other.

Most acids are strong acids.

A. True
B. False

Answers

Answer:

False, There are only a few strong acids, so many people choose to memorize them. All the other acids are weak

Explanation:

False because most acid is not actually an strong acid for example grapes

A buffer solution contains 0.20 mol of propionic acid (CH3CH2COOH) and 0.25 mol of sodium propionate (CH3CH2COONa) in 1.50 dm3.

What is the pH of this buffer?
Enter your answer using two decimal places.

Answers

Answer:

I don't know how to do it the subject

True or False:

The geocentric model of the solar system is correct.

Answers

Answer:

True

Explanation:

You have a solution of NaOH that is 3.0 M. If you need 250 mL of a 1.5 M solution, what volume of the stock solution should you use?

Answers

Answer:

answer is 30 g!!!!!!!!!

A gas sample has a volume of 185 mL at 45°C. What is its volume at 109°C?

Answers

Answer:

342 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 185 mL

Initial temperature (T₁) = 45 °C

Final temperature (T₂) = 109 °C

Final volume (V₂) =?

Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 45 °C

Initial temperature (T₁) = 45 °C + 273

Initial temperature (T₁) = 318 K

Final temperature (T₂) = 109 °C

Final temperature (T₂) = 109 °C + 273

Final temperature (T₂) = 382 K

Finally, we shall determine the final volume of the gas as follow:

Initial volume (V₁) = 185 mL

Initial temperature (T₁) = 318 K

Final temperature (T₂) = 382 K

Final volume (V₂) =?

V₁/T₁ = V₂/T₂

285 / 318 = V₂ / 382

Cross multiply

318 × V₂ = 285 × 382

318 × V₂ = 108870

Divide both side by 318

V₂ = 108870 / 318

V₂ ≈ 342 mL

Therefore, the new volume of the gas is 342 mL

Answer:

342 mL

Explanation:

Hope this helps

how many liters are present in 31.998 g of O2?

Answers

Answer:

Explanation:

First calculate how many moles of O2 you have. O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters.

1.5625 × 22.4 = 35 liters.

Its been 15 years since I graduated HS, and I still remember how to do this. Do your own homework next time and in 15 years you may be able to do the same.

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Below is a diagram of a man pushing a furniture to the left with 100N of force. Which of the following statements is incorrect?

A.) The furniture does not move if the force of friction is 100N to the right.

B.) The force exerted by the man on the furniture is equal to the force exerted by the furniture on the man.

C.) The force of friction must be lower than 100N for the cabinet to move.

D.) The force exerted by the man and the force of friction must be balanced in order to accelerate it to the left.​

Answers

Answer:

If I'm not mistake it should be D

Explanation:

Please inform me if im right or wrong.

Which of the following are in our solar system? Select all answers that apply.
A the star Canis Majoris
B Jupiter's Moons
C Andromeda Galaxy
D Earth
E Asteroid Belt

Answers

Answer:

hola como esats UwU

Explanation:

yo bien y tu? UwU

Vines most successfully compete for sunlight in tropical rainforests by _______.
a.
climbing up into the canopy
b.
strangling the trees they grow on
c.
having broader leaves that absorb more light
d.
having thick, woody stems

Answers

Answer:

climbing up into the canopy

Explanation:

Define What is boiling

Answers

Answer:

Boiling is the rapid vaporization of a liquid, which occurs when a liquid is heated to its boiling point, the temperature at which the vapour pressure of the liquid is equal to the pressure exerted on the liquid by the surrounding atmosphere.

Explanation:

Hi

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