First, find the molar mass of the compound NaCl. The molar mass of Na is 22.99 grams per mole, and the molar mass of Cl is 35.45 grams per mole. Then, add these molar masses 22.99+35.45 = 58.44 grams per mol.
Then, we use the ratio of 58.44 grams / 1 mol to find the number of moles in 25.0 g of NaCl.
[tex]25g\cdot\frac{1\text{mol}}{58.44g}=0.428mol[/tex]Therefore, there are 0.428 moles of NaCl.
Which of the following solutions will have the highest electrical conductivity?O 0.10 M LiBr© 0.045 M (NH4)2C03O 0.10 M NalO 0.045 M Al2(S04)3
Explanation:
We have four ionic compounds and with high dissociation constants, so we can assume that they are soluble and full dissociation.
We can also assume that the electrical conductivity is proportional to the number ions dissolved in the solution.
We have to find the number of ions dissolved for each solution supposing that we have 1 L of solution.
a) 0.10 M of LiBr:
LiBr ---> Li⁺ + Br⁻
1 mol of LiBr will dissolve into 2 mols of ions.
1 mol of LiBr = 2 moles of ions
Volume of solution = 1 L
molarity = 0.10 M
Molarity = moles of LiBr/(Volume of solution in L)
moles of LiBr = molarity * volume of solution in L
moles of LiBr = 0.10 M * 1 L
moles of LiBr = 0.10 moles
Since 1 mol of LiBr will be converted into 2 moles of ions.
moles of ions = 0.10 moles of LiBr * 2 moles of ions/(1 mol of LiBr)
moles of ions = 0.20 moles
b) 0.045 M of (NH₄)₂CO₃:
(NH₄)₂CO₃ ---> 2 NH₄⁺ + CO₃²⁻
1 mol of (NH₄)₂CO₃ = 3 moles of ions
molarity = 0.045 M
moles of (NH₄)₂CO₃ = 0.045 moles/L * 1 L
moles of (NH₄)₂CO₃ = 0.045 moles
moles of ions = 0.045 moles of (NH₄)₂CO₃* 3 moles of ions/(1 mol of (NH₄)₂CO₃)
moles of ions = 0.135 moles
c) 0.10 M of NaI:
NaI ---> Na⁺ + I⁻
1 mol of NaI = 2 moles of ions
molarity = 0.10 M
moles of NaI = molarity * volume of solution in L
moles of NaI = 0.10 M * 1 L
moles of NaI = 0.10 moles
moles of ions = 0.10 moles of NaI * 2 moles of ions/(1 mol of NaI)
moles of ions = 0.20 moles
d) 0.045 M of Al₂(SO₄)₃:
Al₂(SO₄)₃ ----> 2 Al³⁺ + 3 SO₄²⁻
1 mol of Al₂(SO₄)₃ = 5 moles of ions
molarity = 0.045 M
moles of Al₂(SO₄)₃ = 0.045 moles/L * 1 L
moles of Al₂(SO₄)₃ = 0.045 moles
moles of ions = 0.045 moles of Al₂(SO₄)₃* 5 moles of ions/(1 mol of Al₂(SO₄)₃)
moles of ions = 0.225 moles
The solutions with the greatest amount of ions is the Al₂(SO₄)₃ (0.225 moles) so we can assume that it will have the highest conductivity.
Answer: 0.045 M Al₂(SO₄)₃
23.It is possible to dilute a solution by...Select one:a. adding more solute to the solution.b. adding more solvent to the solution.c. lowering the temperature of the solution.d. stirring the solution.
To dilute a solute in a solution, it is necessary to add a proper solvent for the reaction to occur, and adding more solvent will cause the solution to dilute even more, therefore the best answer will be letter B
Ammonium sulfate, an important fertilizer, can be prepared by the reaction of ammonia with sulfuric acid accordingto the following balanced equation: ___ NH3 (g) + ___ H2SO4 → ___ (NH4)2SO4 (aq) a. Calculate the volume of NH3 needed at 24oC and 25 atm to react with 1500 g of H2SO4.
The first step to solve this question is to balance the given equation:
[tex]2NH_3+H_2SO_4\rightarrow(NH_4)_2SO_4[/tex]The next step is to convert the mass of H2SO4 to moles, using the molar mass of H2SO4 (98g/mol).
[tex]1500gH_2SO_4\cdot\frac{molH_2SO_4}{98gH_2SO_4}=15.3molH_2SO_4[/tex]Now, use the stoichiometric ratio given by the reaction to define how many moles of NH3 react with 15.3 moles of H2SO4:
[tex]15.3molH_2SO_4\cdot\frac{2molNH_3}{1molH_2SO_4}=30.6molNH_3[/tex]Finally, use the ideal gas law to determine the volume of the gas at 24°C (297.15K) and 25atm:
[tex]\begin{gathered} PV=nRT \\ V=\frac{nRT}{P} \\ V=\frac{30.6mol\cdot0.082atmL/molK\cdot297.15K}{25atm} \\ V=29.82L \end{gathered}[/tex]The volume of NH3 needed is 29.82L.
Now, provide the following information about your chosen molecule: Describe why the molecule is important and its function within the human body.
The molecule of water is one of the most important molecules on the planet. First of all, several hypotheses concerning the origin of life put water in the central role: since water is present in all living beings (except a virus, which is not held in the scientific community as being for sure a living being), it is supposed that life must have started in water somehow.
Water also has a very important role in regulating the temperature of Earth, both water vapour in the atmosphere and water currents. We could also mention its importance to generate electricity in usines.
But, most important of all, water is an essencial molecule for life. Pratically all the reactions that take place in the human body use water as a solvent. Water is also an important component of our blood, which carries O2 troughout our whole body. Without water, much of some important reactions in our body would just stop, and we wouldn't be able to carry O2 to our tissues.
A very good example of a reaction that is extremely important to life as a whole, and which demands water, is the photosynthesis:
[tex]6CO_{2(g)}+6H_2O_{(l)}\rightarrow C_6H_{12}O_{6(aq)}+6O_{2(g)}[/tex]This reaction is responsible for the production of O2 in the atmosphere, which we, human beings, as well as several other mammals, need in order to properly breath. This reaction also eliminates CO2 of the atmosphere, a gas that can be a problem due to the greenhouse effect. Even though it is not directly happening within the human body, it still as crucial as a reaction that happens in our body: no water, no photosynthesis. No photosynthesis, no oxygen.
A testing chamber holds a 2.00 L sample of neon gas at 300.0 K. If the pressure is measured inside the chamber as 3.25 atm, how many moles of neon are present?____ mol Ne
Answer:
There are 0.26 moles of neon.
Explanation:
From the information in the exercise we know that:
- Volume (V): 2.00L
- Temperature (T): 300.0K
- Pressure (P): 3.25atm
Using the Ideal Gases Law formula, we can calculate the number of moles (n), by replacing the values of V, T and P:
[tex]\begin{gathered} P*V=n*R*T \\ 3.25atm*2.00L=n*0.082\frac{atm*L}{mol*K}*300.0K \\ 6.5atm*L=n*24.6\frac{atm*L}{mol} \\ \frac{6.5atm*L}{24.6\frac{atm*L}{mol}}=n \\ 0.26mol=n \end{gathered}[/tex]So, there are 0.26 moles of neon (0.3 rounded).
How do I find the volume of NaOH in L with given info in trial 1?
NaOH is the titrant, so it's in the burette.
To know the volume of NaOH, we need to subtract the final volume of the buret reading by the initial volume:
30.00 - 0.35 = 29.65 mL
Answer: 29.65 mL of NaOH.
To find the volume in L we just divide 29.65 mL by 1000:
0.02965 L
Because 1000 mL = 1L
Answer: 0.02965 L
I was just wondering if this is right or I made a mistake
We have two redox reactions, one spontaneous and one non-spontaneous. Redox reactions are those in which the oxidation states of the reactants change and we can identify two types of compounds, the oxidizing agent and the reducing agent.
The oxidizing agent is one that oxidizes other substances, lowers their oxidation state and is reduced.
In the case of reactions, the oxidizing agent will be A for the first reaction and second reaction. Since A reduces its oxidation state, it goes from a 0 state to a -1 state.
But we must keep in mind that the second reaction is not spontaneous. In other words, in this case, the opposite reaction will be more important, and product C will be a stronger oxidizing agent than A.
So, the answer will be: C
Which of the following is a constraint of a chlorine bleach shock to remove contaminants from drinking water?
Answer:
[tex]D[/tex]Explanation:
Here, we want to select the setback of using chlorine bleach
Chlorine is a choice material in water purification because of its track record in the removal of pathogens from water.
However, while it is effective in battling microscopic organisms such as bacteria and viruses, it is otherwise useless in removing other contaminants such as heavy metal residue from industrial effluent. Thus, it is only useful in the aspect of removing microscopic organisms from water
Answer: Answer B: just took the test
Explanation:
Choose the option that best completes the sentence.__ is the process of matter changing from a solid to a liquid, while__ is the process of matter changing from gas to liquid
Explanation:
Melting is the process of matter changing from a solid to a liquid.
Condensation is the process of matter changing from gas to liquid.
Answer: Melting, condensation.
Do question "a" of the calculations part. Question "a" is in the image. The topic is about Titration.
Trial 1; 0.102M
Trial 2: 0.094M
Trial 3: 10M
Explanations:According to the dilution formula;
[tex]C_1V_1=C_2V_2[/tex]where:
• C1 and C2 are the initial and final concentration
,• V1 and V2 are the initial and final volume
For the Trial 1:
• Concentration of HCl C1 = 0.1M
,• Volume of HCl V1 = 10mL
,• Volume of NaOH V2 = Vf - Vi = 10.3 - 0.5
,• Volume of NaOH V2 = 9.8mL
Using the formula to determine molarity of base C2
[tex]\begin{gathered} C_2=\frac{C_1V_1}{V_2} \\ C_2=\frac{0.1\times10}{9.8} \\ C_2=0.102M \end{gathered}[/tex]For the Trial 2:
• Concentration of HCl C1 = 0.1M
,• Volume of HCl V1 = 10mL
,• Volume of NaOH V2 = Vf - Vi = 20.9 - 10.3
,• Volume of NaOH V2 = 10.6mL
[tex]\begin{gathered} C_2=\frac{0.1\times10}{10.6} \\ C_2=0.094M \end{gathered}[/tex]For the Trial 3:
• Concentration of HCl C1 = 0.1M
,• Volume of HCl V1 = 10mL
,• Volume of NaOH V2 = Vf - Vi = 30.0 - 20.9
,• Volume of NaOH V2 = 0.1mL
[tex]\begin{gathered} C_2=\frac{0.1\times10}{0.1} \\ C_2=10M \end{gathered}[/tex]If you had excess chlorine, how many moles of of aluminum chloride could be produced from 25.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. Express your answer to three significant figures and include the appropriate units.
So,
According to the reaction:
[tex]2Al_{(s)}+3Cl_{2(g)}\to2AlCl_{3(s)}[/tex]We have an initial amount of 25.0g of Al and excess chlorine.
What we're going to do to find the number of moles of aluminum chloride that could be produced, is to follow the steps:
1. Pass the grams to moles dividing the mass given by the molar mass of Al:
[tex]\frac{25.0gAl}{\frac{26.98g}{mol}}=0.92661molesAl[/tex]2. State the relation between the coefficients of the reaction. They tell us that each 2 moles of Al produce 2 moles of AlCl3. So,
[tex]0.92661molesAl_{}\cdot\frac{2molesAlCl_3}{2molesAl}=0.927molesAlCl_3[/tex]Therefore, 0.927 moles of aluminum chloride could be produced.
Which of the following terms describes alkanes but not alkenes and alkynes?O A. AromaticOB. HydrocarbonC. UnsaturatedOD. Saturated
Answer:
D. Saturated.
Explanation:
Let's remember the concept of alkanes: An alkane is a hydrocarbon in which there are only single covalent bonds.
Remember that a hydrocarbon is an organic compound that is made up of only carbon and hydrogen, and aromatic hydrocarbons are molecules that contain benzene rings.
Now, an unsaturated molecule has double or triple bonds, whereas a saturated molecule has just simple bonds (this means more hydrogen atoms, that's why it's called saturated).
Alkenes are hydrocarbons that have double bonds, and alkynes are hydrocarbons that have triple bonds.
As we already know, based on the logic of the given definitions, alkanes, alkenes, and alkynes are hydrocarbons, but alkenes and alkynes are unsaturated molecules, but alkanes are saturated molecules.
The answer would be D. Saturated.
A 435 mL solution was made by mixing 201 mL of cyclohexane, Which has a density of 0.78 g/mL, and 257 mL of toluene, Which has a density of 0.87 g/mL. Calculate the volume percentage of the cyclohexane in the solution. Be sure and answer has right number of significant digits.
Answer:
[tex]46.2\text{ \%}[/tex]Explanation:
Here, we want to calculate the volume percentage of cyclohexane in the solution
Mathematically, we have this as:
[tex]\frac{volume\text{ of cyclohexane}}{\text{volume of solution}}\times\text{ 100\%}[/tex]Thus, we have the volume percentage as follows:
[tex]\frac{201}{435}\times\text{ 100 \% = 46.2 \% }[/tex]If 11.3 grams of sodium chloride are formed in the reaction, what is the percent yield of this reaction?1CuCl2 + 2NaNO3 → 1Cu(NO3)2 + 2NaCl15 grams of copper (II) chloride react with 20 grams of sodium nitrate
Step 1
The reaction:
1CuCl2 + 2NaNO3 → 1Cu(NO3)2 + 2NaCl (balanced)
---------------
Step 2
Information provided: the actual yield = 11.3 g NaCl (sodium chloride)
Mass of CuCl2 = 15 g and mass of NaNO3 = 20 g
Information needed: the limiting reactant, and the molar masses of:
CuCl2) 134.4 g/mol
NaNO3) 85.0 g/mol
NaCl) 58.4 g/mol
--------------
Step 3
The limiting reactant and the excess: Procedure
134.4 g CuCl2 -------------- 2 x 85.0 g NaNO3
15 g CuCl2 ------------- X = 18.9 g NaNO3
For 15 g CuCl2, 18.9 g NaNO3 is needed, therefore the excess is NaNO3, and the limiting reactant is the CuCl2.
------------
Step 4
The theoretical yield: mass of NaCl formed from the stoichiometry
134.4 g CuCl2 ------------ 2 x 58.4 g NaCl
15 g CuCl2 ------------ X = 13.0 g = theoretical yield
-----------
Step 5
The % yield = actual yield/theoretical yield x 100 = 11.3 g/13.0 g x 100 = 86.9 %
Answer: % yield = 86.9 %
Which of the following compounds will be the least soluble in water?CH4NH3CH3OHCH3CH2OH
Explanation:
NH3 is very soluble in water
CH4
CH3OH is soluble in water because of the hydrogen bonds it has.
CH3CH2OH is also soluble in water.
-----
CH4 is the least soluble in water in comparison with the others.
CH4 is soluble in ethanol, d
Answer: CH4
How do I write these chemical formulas? I’m having a hard time understanding
To match the axes correctly, we have to combine both symbols and use the criss cross method.
For the second row:
[tex]\begin{gathered} Na^++OH^-\rightarrow NaOH \\ Na^++NO_3^-\rightarrow NaNO_3 \\ Na^++CO_3^{-2}\rightarrow Na_2CO_3 \\ Na^++SO_4^{-2}\rightarrow Na_2SO_4 \\ Na^++PO_4^{-3}\rightarrow Na_3PO_4 \end{gathered}[/tex]For the third row:
[tex]\begin{gathered} Mg^{+2}+OH^-\operatorname{\rightarrow}Mg(OH)_2 \\ Mg^{+2}+NO_3^-\operatorname{\rightarrow}Mg(NO_3)_2 \\ Mg^{+2}+CO_3^{-2}\rightarrow MgCO_3 \\ Mg^{+2}+SO_4^{-2}\rightarrow MgSO_4 \\ Mg^{+2}+PO_4^{-3}\rightarrow Mg_3(PO_4)_2 \end{gathered}[/tex]For the last row:
[tex]\begin{gathered} NH_4^++OH^-\operatorname{\rightarrow}NH_4OH \\ NH_4^++NO_3^-\rightarrow NH_4NO_3 \\ NH_4^++CO_3^{-2}\rightarrow(NH_4)_2CO_3 \\ NH_4^++SO_4^{-2}\rightarrow(NH_4)_2SO_4 \\ NH_4^++PO_4^{-3}\rightarrow(NH_4)_3PO_4 \end{gathered}[/tex]Just give full answer with equation that go with it
In this question, we need to find how many moles of Carbon are needed to react with the given moles of SO2, first thing we need to do is set up the properly balanced equation:
5C + 2 SO2 -> CS2 + 4 CO
We have:
7.24 moles of SO2
According to the concepts of molar ratio, between C and SO2 we have a molar ratio of 5:2, which means 5 moles of C are needed to react with 2 moles of SO2, but what if we have 7.24 moles of SO2:
5C = 2 SO2
x C = 7.24 SO2
x = 18.1 moles of C are needed to react with 7.24 moles SO2
4000 grams of heptane (C7H16) is combusted with 7000 grams of oxygen.C7H16 + 11 O2 —> 7 CO2 + 8 H2OWhat is the limiting reactant?How many grams of carbon dioxide is produced?
To find the limiting reactant, we have to convert the given masses to moles of each substance, using their molecular masses:
[tex]4000g\cdot\frac{mol}{100g}=40mol[/tex][tex]7000g\cdot\frac{mol}{31g}=225.8mol[/tex]Use the mole ratio to determine the amount of one of the reactants to the other one:
[tex]40\text{molC}7H16\cdot\frac{11\text{ molO2}}{1\text{molC7H16}}=440molO2[/tex]There is not enough oxygen to react with the given amount of heptane. It means that the limiting reactant is oxygen.
Use the mole ratio to find the amount of carbon dioxide produced:
[tex]225.8molO_2\cdot\frac{7molCO_2}{11molO_2}=143.7molCO_2[/tex]Convert the answer to grams using the molecular mass of carbon dioxide:
[tex]143.7molCO_2\cdot\frac{44g}{mol}=6322.8g[/tex]The answer is 6322.8 grams.
Balance this chemical equation using algebraic method ( A value is 2 ) ( please include procedure) Cr(NO2)2 + (NH4)2SO4 = CrSO4 + NH4NO2
In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients
Cr(NO2)2 + (NH4)2SO4 -> CrSO4 + 2 NH4NO2
Using the algebraic method we have:
Cr: 1a = 1c
N: 2a + 2b = 2d
O: 4a + 4b = 4c + 2d
H: 8a = 4d
S: 1b = 1c
If a = 1
Cr 1*1 = 1c, therefore c also = 1
H: 8*1 = 4d
8 = 4d
d = 2
N: 2*1 + 2b = 2*2
2 + 2b = 4
2b = 2
b = 1
Therefore
a = 1
b = 1
c = 1
d = 2
Exactly what we found
A sample of oxygen at 29°C occupies 478 mL.If this sample later occupies 1132 mL at 62°Cand 1.7 atm, what was its original pressure?Answer in units ofatm.
To solve this problem we can use the Ideal gas law:
[tex]\frac{P_1\cdot V_1}{T_1}=\frac{P_2\cdot V_2}{T_2}[/tex]We deduce from the text:
V1=478mL
T1=29°C=302.15K
V2=1132mL
T2=62°C=335.15K
P2=1.7atm
Then we just have to solve for P1 and use the provided data:
[tex]P_1=\frac{P_2\cdot V_2}{T_2\cdot V_1}\cdot T_1=\frac{1.7atm\cdot1132mL}{335.15K\cdot478mL}\cdot302.15k=3.63atm[/tex]The initial pressure was P1= 3.63atm
2C8H18(I) + 25 O2 (g) = 16 CO2(g) + 18 H2O (g)If you burned one gallon of gas (C8H18) (approximately 4000 grams) how many liters of carbon dioxide would be produced at a temp of 21.0 C and a pressure of 1.00 atm? (Answer to 3 SFs)
The reaction is balanced, so we can proceed with the calculations. To solve the question we will follow the following steps:
1. We calculate the moles of C8H18, dividing the mass of the fuel by its molar mass. The molar mass of C8H18 is: 114.23g/mol.
2. By stoichiometry we find the moles of CO2 that are produced from the moles of C8H18 found.
3. We find the volume of CO2 formed using the ideal gas law which tells us:
[tex]PV=nRT[/tex][tex]V=\frac{nRT}{P}[/tex]Where,
P is the pressure of the gas in atm, 1.00 atm
T is the temperature of the gas in Kelvin, 21.0°C=294.15K
R is a constant, 0.08206atm.L/mol.K
n is the number of moles of the gas
V is the volume of the gas in liters
Let's continue with the calculations.
1. Moles of C8H18
[tex]molC_8H_{18}=givengC_8H_{18}\times\frac{1molC_8H_{18}}{MolarMass,gC_8H_{18}}[/tex][tex]molC_8H_{18}=4000gC_8H_{18}\times\frac{1molC_8H_{18}}{114.23gC_8H_{18}}=35.0molC_8H_{18}[/tex]2. Moles of CO2
The ratio CO2 to C8H18 is 16/2, so the moles of CO2 formed will be:
[tex]molCO_2=givenmolC_8H_{18}\times\frac{16molCO_2}{2molC_8H_{18}}[/tex][tex]molCO_2=35.0molC_8H_{18}\times\frac{16molCO_2}{2molC_8H_{18}}=280molCO_2[/tex]3. Volume of CO2
We replace the known data in the gas ideal law:
[tex]V=\frac{nRT}{P}[/tex][tex]V=\frac{280mol\times0.08206\frac{atm.L}{mol.K}\times294.15K}{1.00atm}=6761.9L=6.76\times10^3L[/tex]Answer: Would be produced 6.76x10^3 liters
Identify the quantitive observation below:O The bus is 12 feet long.O The apple is red.O The aloe plant’s leaves are pointy.O The wings on the glider are floppy.
Answer
The bus is 12 feet long
Explanation
Quantitative observation implies an objective collection of data for analysis based on their numerical and statistical attributes. This observation involves the depiction of obtained variables in terms of their quantity. The primary focus is on numbers and values.
Examples of quantitative observation include age, weight, height, length, population, size and other numerical values while examples of qualitative observation are color, smell, taste, touch or feeling, typology, and shapes.
Therefore, the correct option is:
The bus is 12 feet long
Which of the following could be an empirical formula?Select a Choice BelowABN₂O4N₂ H6N₂OsMore than one could be an empirical formula
Answer:
C. N2O5.
Explanation:
Let's remember the concept of the empirical formula: empirical formulas show the simplest ratio of whole numbers of atoms in a substance.
Let's analyze each option:
A. N2O4 doesn't have the simplest ratio in the number of atoms because we can 'simplify it' if we divide each number by 2, so we would have NO2. It's not an empirical formula.
B. N2H6 can be 'simplify it' too if we divide each number of atoms by 2, so we will obtain NH3. It's not an empirical formula.
C. N2O5 cannot be 'simplify it' because there are no numbers divisible by 2 and 5; in fact, they are prime numbers, so based on the logic of the given definition of empirical formula, this could be an empirical formula.
The answer would be C. N2O5.
I'm stuck with this question,can you help me solve this please.
Electronic structure refers to the way atoms are organized according to electron shell theory. It tells us what energy level the electrons are in and the number of electrons per energy level.
The groups of the periodic table are classified according to the valence electrons, that is, the electrons that they have in their last energy level. These electrons can make an atom more or less reactive. For example, an element in the last period, period 8. It has 8 valence electrons, that is, it complies with the octet rule and these atoms are very stable. Therefore, its reactivity is very low compared to other groups.
Groups 1 and 7 are quite reactive since group 1 has an electron in the last energy level. So it only has to lose one electron to form a bond and react. Group 7 has 7 electrons in its last energy level, that is, it needs 1 electron to form a bond. In general, group 7 elements are very reactive with group 1 elements.
So the main difference in group reactivity will be the valence electrons.
HAc (aq) + H20 (l) <-- --> Ac- (aq) + H30+ (aq)a. Write the equilibrium expression. Are we using Ka or Kb?b. Label the acid, base, conjugates, and/or salt.c. Which bases are competing for a proton?d. If the K value is 0.06 which base is stronger?
Answer:
[tex]\begin{gathered} a)\text{ }\frac{[H_3O^+][Ac^-]}{[HA_c]} \\ b)\text{ HAc - acid} \\ H_2O-base \\ Ac^--conjugate\text{ base} \\ H_3O^+-conjugate\text{ acid} \\ c)\text{ H}_2O \\ d)\text{ Ac}^{-\text{ }}is\text{ stronger since k > 0} \end{gathered}[/tex]Explanations:
Given the equilibrium expression shown below;
[tex]HAc(aq)+H_2O(l)\rightleftarrows Ac^-(aq)+H_3O^+(aq)[/tex]a) The equilibrium expression for the reaction is given as:
[tex]\begin{gathered} k_a=\frac{[H_3O^{^+}][Ac^-]}{[H_2O][HAc]} \\ Since\text{ }[H_2O]-1,\text{ hence;} \\ k_a=\frac{[H_3O^+][Ac^-]}{[HA_c]} \end{gathered}[/tex]The equilibrium constant we are using will be Ka.
b) The compound that is given off a proton is an acid while the compound accepting a proton is a base. From the given equation HAc acts as an acid while H2O acts as a base. Ac- is the conjugate base while H3O+ is the conjugate acid.
c) The base that is competing for a proton is H2O (water)
d) Since a lower value of k shows a stronger base, hence the conjugate base hence H2O will be a stronger base than that of Ac. Recall that if k < 1, the reverse reaction is favoured and the forward reaction does not proceed to a great extent showing that H2O will be the stronger base.
what is the mass of blue nose pitbull that has a density of 468 kg/cm^3 and the volume is 900 ml
It is known that 1ml=1cm^3. We can use this information to convert the volume to cm^3 and then use the density to find the mass:
[tex]900ml\cdot\frac{1cm^3}{1ml}=900cm^3[/tex][tex]900cm^3\cdot\frac{468kg}{cm^3}=421,200kg[/tex]The mass of blue nose pitbull is 421,200kg.
When the following chemical equation is correctly balanced, what will be the coefficient for N2H4? ___________N2H4 + ___________N2O4 ----------> ________N2 + _______H2OGroup of answer choices12345
ANSWER
[tex]\text{ The number of moles of N}_2H_4\text{ is 2}[/tex]EXPLANATION
Given that:
[tex]\text{ N}_2H_4\text{ }+\text{ N}_2O_4\text{ }\rightarrow\text{ N}_2\text{ }+\text{ H}_2O[/tex]To balance the above equation, apply the law of conservation of mass
The law of conservation of mass states that matter can neither be created nor destroyed but can be tranformed from on point to another.
The above law implies that the total number of atoms on the reactant side must be equal to the total number of atoms on the products side
On the reactant side, we have,
4 atoms of nitrogen
4 atoms of hydrogen
4 atoms of oxygen
On the product sides
2 atoms of hydrogen
2 atoms of nitrogen
1 atom of oxygen
To balance the equation, we have,
2 moles of N2H4
1 mole of N2O4
3 moles of N2
4 moles of water
[tex]\text{ 2N}_2H_4\text{ }+N_2O_4\text{ }\rightarrow\text{ 3N}_2\text{ }+\text{ 4H}_2O[/tex]In the new equation above, we have the following
on the reactants side
6 atoms of nitrogen
8 atoms of hydrogen
4 atoms of oxygen
on the products side
6 atoms of nitrogen
8 atoms of hydrogen
4 atoms of oxygen
Therefore, the number of moles of N2H4 is 2
The American Heart Association recommends that for every 1000 dietary calories consumed, the sodium intake should be 1000 mg orless and should not exceed a daily limit of 3300 mg for an adult. What is the yearly limit on sodium intake in kilograms?1. 2.7kg2. 1.2kg3. 730kg4. 120000kg5. 2.1kg
Answer:
[tex]1.2\text{ kg}[/tex]Explanation:
Here, we want to get the yearly limit on sodium intake
To calculate this, we have to multiply the daily limit by the number of days in a year
The number of days in a year is 365
The daily limit is given as 3300 mg
Thus, we have the yearly limit as:
[tex]365\text{ }\times\text{ 3300 = 1,204,500 mg}[/tex]Now, we have to convert this to kg
To do this, we divide the kg value by 1,000,000
We have this as:
[tex]\frac{1204500}{1000000}\text{ = 1.2045 kg}[/tex]This is approximately 1.2 kg
A solution contains a compound with a molar mass of, 87.82 g/mol. How many gramsof this compound are contained if the solution has a volume of 1,034.9 mL and amolarity of 1.4 M?
The question requires us to calculate the mass of a compound, in grams, contained in 1,034.9 mL of a 1.4 M solution of this compound, given its molar mass corresponds to 87.82 g/mol.
The molarity of a solution can be calculated as (Equation 1):
[tex]C=\frac{n}{V}[/tex]where C corresponds to the molarity (in mol/L), n corresponds to the number of moles (in mol) and V is the volume of the solution (in L).
Also, the number of moles of a compound can be defined as (Equation 2):
[tex]n=\frac{m}{M}[/tex]where n is the number of moles (in mol), m is the mass of the compound (in g) and M corresponds to the molar mass of this compound (in g/mol).
We can combining the equations 1 and 2 above and arrive at the following expression:
[tex]C=\frac{m}{M\times V}[/tex]where we are able to calculate the molarity of a solution from its mass (in grams), molar mass (in grams per mol) and volume (in liters).
We can also rearrange this equation in order to obtain the mass of the compound:
[tex]C=\frac{m}{M\times V}\to m=C\times M\times V[/tex]Note that, in the last equation, we must use the volume of the solution in units of liter (L). Thus, to apply the values given by the question to this equation, we need to convert the volume from mL to L:
1000 mL = 1 L
1,034.9 mL = 1.0349 L
Now, we can use the values of molarity, molar mass and volume from the question to calculate the mass required:
[tex]\begin{gathered} m=C\times M\times V \\ m=(1.4mol/L)\times(87.82g/mol)\times(1.0349L) \\ m=127.2g \end{gathered}[/tex]Therefore, the mass of compound contained in the solution given is 127.2g.
Predict the number of Hydrogens for a hydrocarbon with 28 carbons
Answer
tH
Step-by-step explanation:
[tex]\begin{gathered} \text{The general molecular formula for alkane compound is given as} \\ C_nH_{2n\text{ + 2}} \\ \text{ Since the number of carbon atom is 28} \\ \text{let n = 28} \\ C_{28}H_{2(28)\text{ + 2}} \\ C_{28}H_{56\text{ + 2}} \\ C_{28}H_{58_{}} \\ \text{Hence, the number of hydrogen atoms for a hydrocarbon with 28 carbons is 58 hydrogens} \end{gathered}[/tex]