How many moles of nitrogen gas would be produced if 3.27 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction? 2 NH3(g) + 3 CuO (s) 3 Cu(s) + N2(g) + 3 H2O(g)

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qmitchell · Accepted Answer

Moles of Nitrogen(N) gas would be produced : 1.09Further explanationThe reaction coefficient in a chemical equation shows the mole ratio of the components of the reactants and productsIf one mole of the reactant or product is known, then we can determine the moles of the other compounds involved in the reactionReaction2NH(g) + 3CuO (s) 3Cu(s) + N(g) + 3 HO(g)Copper(II) oxide was reacted with excess Ammonia, so CuO as a limiting reactant and moles of the product is based on moles of CuOmoles of CuO = 3.27From the equation, the mol ratio of CuO : mol N = 3 : 1, so mol N :[tex]	t \dfrac{1}{3}	imes 3.27=1.09[/tex]

How many moles of nitrogen gas would be produced if 3.27 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction? 2 NH3(g) + 3 CuO (s) – 3 Cu(s) + N2(g) + 3 H2O(g)

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How many moles of nitrogen gas would be produced if 3.27 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction? 2 NH3(g) + 3 CuO (s) – 3 Cu(s) + N2(g) + 3 H2O(g)​

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How many moles of nitrogen gas would be produced if 3.27 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction? 2 NH3(g) + 3 CuO (s) – 3 Cu(s) + N2(g) + 3 H2O(g)