How many solutions does the following equation have?
9z-6+7z=16z-6

Given:

PQRS is a rectangle.

X is the midpoint of SR.

To find:

The measure of QX.

Solution:

It is given that X is the midpoint of SR. Draw a perpendicular on PQ from point X as shown in the below figure.

Now, the line XY divides the rectangle PQRS into two equal squares of sides 4 units.

The diagonal of a square is:

[tex]d=a\sqrt{2}[/tex]

Where, a is the side length of the square.

QX is the diagonal of the square whose side length is 4 units. So, the length of QX is:

[tex]d=4\sqrt{2}[/tex]

[tex]d=5.656854[/tex]

[tex]d\approx 5.7[/tex]

Therefore, the measure of segment QX is about 5.7 units.

Given:

The table of values of an exponential function.

To find:

The function for the given table of values.

Solution:

The general exponential function is:

[tex]y=ab^x[/tex]        ...(i)

Where, a is the initial value and b is growth factor.

From the given table it is clear that the function passes through the points (1,9) and (2,36). It means the function must be true for these two points.

[tex]9=ab^1[/tex]        ...(ii)

[tex]36=ab^2[/tex]       ...(iii)

On dividing (iii) by (ii), we get

[tex]\dfrac{36}{9}=\dfrac{ab^2}{ab}[/tex]  

[tex]4=b[/tex]  

Putting [tex]b=4[/tex] in (ii), we get

[tex]9=a(4)^1[/tex]

[tex]\dfrac{9}{4}=a[/tex]

Putting [tex]a=\dfrac{9}{4},b=4[/tex] in (i), we get

[tex]y=\dfrac{9}{4}(4)^x[/tex]

[tex]y=9(4)^{x-1}[/tex]

The function notation with variable n is:

[tex]f(n)=9(4)^{n-1}[/tex]

Therefore, the correct option is D.

Answer:

300

Step-by-step explanation:

Answer:

Quadrilateral ABCD is a rhombus, because all four sides are congruent and adjacent sides are not perpendicular .

Step-by-step explanation:

Given :

A quadrilateral with its coordinates as follows:

Where  A (3, 1), B (4,4), C (7,5), D (6,2).

We will measure the length of the congruent sides by applying distance formula.

Distance formula = square root (x^2 - x^1)^2 + (y^2 - y^1)^2

So,  

AB = ( insert the coordinates using the formula )

BC = ( insert the coordinates using the formula )  

CD = ( insert the coordinates using the formula )

DA = ( insert the coordinates using the formula )

It all equals = squareroot 10

From the above measurement and looking into the diagram we can conclude that the Quadrilateral ABCD is a rhombus.  

In rhombus the adjacent sides are not perpendicular and its diagonals are of different length.

Answer:

(2,2)

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

Answer:

[tex]4 \sqrt{15} [/tex]

Answer:

jeez, one lazy person must you be if you dont have time to finish this xD

answer is 181

Step-by-step explanation:

well first divide the two objects, a triangle, and a rectangle. Now we have no idea what the bottom of the triangle is so lets calculate that. 18 - 2 -5 = 11

so the triangles dimesions are a10, b11.  Now we have to implement the pythagorem theroem since it doesnt give us the side "c". its a simple a^2+b^2=c^2. so side "c" is 14.866. now we can calculate and add everything together. so 18*7=126. and the triangles area is 55. so add 126+55 and viola. you get 181. Im a bit skeptical that i got something  wrong but i hope its all correct. hope this helps!

Answer:

A - 1/8

Step-by-step explanation:

just did it 2021

Answer:

1/8

Step-by-step explanation:

Answer:

$107.60

Step-by-step explanation:

100 [1 + (0.076 * 1)] = 107.6

= $107.60

Answer: C. They are similar by the SSS rule

Step-by-step explanation:

There are three ways to prove triangle similar

--------------------------------------------------------------------------------

Here, we see in the figures, the side lengths are given, and there are no angles. So, supposedly, we are going to use SSS similar theorem.

Solve

MN corresponds to UV

ML corresponds to UT

LN corresponds to TV

MN/UV=24/8=3

ML/UT=33/11=3

LN/TV=42/14=3

∴MN/UV=ML/UT=LN/TV

∴They are similar

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Basic physics and common sense would say that of course they'd reach the same height if placed an equal distance away. I don't really know what else to do

Answer:

10.2*6.3=64.26

Step-by-step explanation:

Solve 102*63, then move the decimal point two numbers from the right:

Since 102*63=6426, then moving the decimal point two numbers from the right will mean 10.2*6.3=64.26

Answer:

64.26

Step-by-step explanation:

This is a simple multiplication

When you 'multiply' or 'times' even a product of a number you add it to itself a number of times, for this problem, 10.2 multiplied by 6.3 is the same as saying 10.2 + 10.2 + 10.2 = 64.26. Multiplication is therefore a quicker way of adding the same number many times, for example, 10.2 × 6.3 = 64.26. Therefore, the product of 10.2 and 6.3​ is 64.26.

Answer:

1.5x + 2

Step-by-step explanation:

(3x + 4)/2 = 1.5x + 2

Answer:

C

Step-by-step explanation:

p³ - 216q³ ← is a difference of cubes and factors in general as

a³ - b³ = (a - b)(a² + ab + b²) , then

p³ - 216q³

= p³ - (6q)³

= (p - 6q)(p² + 6pq + 36q²) → C

Answer:

C. (p - 6q)(p² + 6pq + 36q²)

Step-by-step explanation:

Equation at the end of step 1

[tex](p^{3} ) - (2^{3} 3^{3} q^{3} )[/tex]

Trying to factor as a Difference of Cubes:

Factoring:  p^3 - 216q^3

Theory: A difference of two perfect cubes, a^3 - b^3 can be factored into

(a-b) • (a^2 +ab +b^2)

Proof: [tex](a-b)(a^{2} +ab+b^{2} ) =[/tex]

[tex]a^{3} + a^{2} b+ab^{2} -ba^{2} -b^{2} a-b^{3} =[/tex]

[tex]a^{3} +(a^{2} b-ba^{2} )+(ab^{2} -b^{2} a)-b^{3} =[/tex]

[tex]a^{3} +0+0-b^{3} =[/tex]

[tex]a^{3} -b^{3}[/tex]

Check:  216 is the cube of 6

Check:  p^3 is the cube of p^1

Check:  q^3 is the cube of q^1

Factorization is:

[tex](p-6q)(p^{2} + 6pq+36q^{2} )[/tex]

Trying to factor a multi variable polynomial :

Factoring: p^2 + 6pq + 36q^2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final Result:

(p - 6q)(p² + 6pq + 36q²)

Answer:

6563kmph

Step-by-step explanation:

take 21,000 divided by 3.2 hours to get the speed

21,000/3.2 = 6562.5

It says to round 6562.5 to the nearest whole number so its 6563

Answer:

11

Step-by-step explanation:

sqrt(24×5+1)

sqrt(120+1)

sqrt(121)

11

Step-by-step explanation:

b=4, so

7²+4²=c²

49+16=c²

65=c²

Sq root both sides

8.06=c

Answer:

Step-by-step explanation:

A= πr2 = π·72 ≈153.93804

Step-by-step explanation:

The formula for an area of a circle is: π[tex]r^{2}[/tex]

In this instance you are using 3.14 for pi.

3.14 ([tex]7^{2}[/tex])= 153.86

Area= 153.86[tex]ft^{2}[/tex]

to be honest with you, I dont know

The work required to lift the massive car of 2400 kg is more than lifting the car with 120 kg

Work is defined as the energy that is applied to or removed from an object by applying force along a displacement. For a constant force acting in the same direction as the motion, the work is defined as the product of the force's magnitude and the distance traveled. The dimensions of work is

ML²T⁻² and the SI unit of work is Joule

Work = Force x Distance

The SI unit for work is the joule (J), or newton meter ( Nm ). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m

Given data ,

Let the work required to move the 2400kg car be W₁

Let the work required to move the 1200kg car be W₂

Now , the force in moving the 2400 kg car = F₁

The value of F₁ = 2400 ( a )

And , the force in moving the 1200 kg car = F₂

The value of F₂ = 1200 ( a )

where a is the acceleration

Let the distance moved be height H

Now , the work W₁ = Force x Distance

Substituting the values in the equation , we get

W₁ = 2400 ( a ) H

And , W₂ = 1200 ( a ) H

Now , W₁ > W₂

Hence , the work required to move 2400 kg car is greater

To learn more about work click :

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Answer:

Variación de temperatura: 310°C

Step-by-step explanation:

La variación de temperatura entre la temperatura más baja conocida en la tierra (-273°C = 273° bajo cero) y la temperatura promedio de la tierra (37°C) será el valor absoluto de la diferencia de estos dos valores, es decir:

Variación de temperatura: |-273°C - 37°C|

Variación de temperatura: |-310°C|

Como el valor absoluto de un número negativo es su valor positivo (|-x| = x)

Answer:

9. 81.3953% increase

10. 26.6667% decrease

Step-by-step explanation:

Hope this helps.

Answer:

7.415 ≤ x < 7.425

Step-by-step explanation:

The number x was rounded to 2 decimal places to give 7.42.

Since rounded off to 2 decimal places, the error interval for x is half of 0.01 subtracted from and added to 7.42.

Thus;

7.42 ± (0.01/2)

(7.42 - 0.005),(7.42 + 0.005)

7.415, 7.425

Now, 7.425 will not be included in the internal because approximating it doesn't give 7.42.

Thus,the error interval is;

7.415 ≤ x < 7.425

Answer:

2000000Taka.

Step-by-step explanation:

Area of the room= 250x100

=25000m²

Each m²= Tk 80

so, 25000x80

=2000000 Taka.

plz mark me as brainliest !

Answer:

what are the answer choices

Step-by-step explanation:

The linear expression 24y - 12 is not equivalent to the expression 2(12y - 12) option (A) 2(12y - 12) is correct.

It is defined as the combination of constants and variables with mathematical operators.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have a linear expression:

= 24y - 12

From the above linear expression take 2 as a common factor:

= 2(12y - 6)

Take 2 as common factor again:

= 2(2)(6y - 3)

= 4(6y - 3)

Now, take 3 as a common factors:

= 12(2y - 1)

The expression 24y - 12 is equivalent to the expressions 2(12y - 6), 4(6y - 3), and 12(2y - 1).

Thus, the linear expression 24y - 12 is not equivalent to the expression 2(12y - 12) option (A) 2(12y - 12) is correct.

Learn more about the expression here:

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Answer: B is 44 degrees.

Step-by-step explanation:

(6x+22)=(7x+16)=90.

x=4

(7(4)+16)=44

Answer:

Step-by-step explanation:

"The capture-recapture of individually distinctive signature whistles has not been attempted before," says the paper's senior author Dr Tess Gridley, Co-Director of Sea Search and the Namibian Dolphin Project and a postdoctoral fellow in the Department of Botany and Zoology at SU. "The dolphins use these sounds throughout life and each has its own unique whistle. Therefore, by recording signature whistles over time and in different places we can calculate where animals are moving to and how many animals there are in a population."

Working with Dr Simon Elwen of Stellenbosch University, the Namibian Dolphin Project has been researching Namibia's resident bottlenose dolphins for the past 12 years, and built up a catalogue of more than 55 signature whistles dating back to 2009.

This particular study was led by Emma Longden, who began the project during her BSc (Hons) Marine Biology degree at the University of Plymouth. As an undergraduate, Emma completed an internship with the Namibia Dolphin Project for a month in 2016, and returned again in 2018 to complete work on the mark-recapture project.

She analysed more than 4000 hours of acoustic data from four hydrophones positioned along the coast south and north of Walvis Bay, Namibia, during the first six months of 2016.

All in all, they identified 204 acoustic encounters, 50 of which contained signature whistle types. From these encounters, 53 signature whistle types were identified; 40 were in an existing catalogue developed in 2014 for the Walvis Bay bottlenose dolphin population, and 13 were newly identified. Of the 53 signature whistle types identified, 43% were captured only once, whereas the majority (57%) were recaptured twice or more.

"One of the great things about bioacoustics is that you can leave a hydrophone in the water for weeks at a time and collect so much data without interfering with the lives of the animals you are studying," says Emma, whose work on the project was also supervised by Dr Clare Embling, Associate Professor of Marine Ecology at the University of Plymouth.

Dr Embling added: "This work is incredibly important as it allows us to track and count the number of dolphins in small vulnerable populations. It builds on our previous research looking at the impacts of noise on marine organisms and monitoring vulnerable marine mammal populations. It also showcases the fantastic level of research that our marine biology students are able to achieve, and the opportunities available to them through our partnerships with conservation organisations such as the Namibia Dolphin Project and the Ocean Giants Trust."

Future research includes the work undertaken by PhD student Sasha Dines from Stellenbosch University to further refine the technique to better understand the population of endangered humpback dolphins in South Africa. Another PhD student, Jack Fearey from the University of Cape Town, is continuing to conduct research along the Namibian Coast.