How many times greater is 1.88 times 10^2 than then mass of 2.35 times 10^-1

Proportionately, it would take the restaurant 22.75 avocadoes to make 14 orders of guacamole since it takes 6.5 avocados to make 4 orders.

Proportion refers to the quantity of a value or variable contained in another value.

Proportion is a fractional value like a ratio that shows the numerical relationship between two or more values.

Proportions are depicted using fractions, decimals, or percentages.

The number of avocados required for 4 orders of guacamole = 6.5

The total number of orders of guacamole required = 14

The number of avocados to make 1 order = 6.5/4

The number of avocadoes required to fill 14 orders = 22.75 (6.5/4 x 14)

Thus, in proportion, it would take 22.75 avocados to make 14 orders of guacamole.

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Answer:

y=5x+1

Step-by-step explanation:

we already know the slope so we can put it in the slope intercept form

y=5x

And now we can put the coordinate points in there to find the y intercept

-4=5(-1)

-4=-5

We need to add 1 to make this equation true so the y intercept is 1

The equation will be

y=5x+1

Hopes this helps please mark brainliest

Answer:

y=5x+1

Steps are in the picture

Answer:

it's 50 g

Step-by-step explanation:

it's like a multiplying assberry kehe

The amount that Charlotte earn per hour on the weekends than she earns during the week is: C. $2.30.

Number of dollars earn per hour during the week = x

Number of dollars earn per hour on the weekend =y

Formulate an equation

13x + 14y = 250.90  Equation 1

15x + 8y = 204.70 Equation 2

Solving  for x and y by multiply equation 1  by -8 and equation 2 by 14 -104x - 112y = -2007.20

210x +112y = 2865.80

106x             = 858.60

Divide both sides by 106x

x = 858.60/106

x =  $8.10

Substitute x into eq 1 so as to solve for y

13(8.10) + 14y = 250.90

105.30 + 14y = 250.90

Subtract 105.30 from both sides

14y = 145.60

Divide both side by 14y

y = 145.60 /14

y  = 10.40

Hence,

Additional earning per hour = y-x

Additional earning per hour = $10.40 - $8.10

Additional earning per hour=$2.30 per hours

Therefore the correct option is C.

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The perimeter of rectangle ABDC is 61.24 units.

The perimeter of a rectangle is defined as the addition of the lengths of the rectangle's four sides.

The rectangle ABDC is given in the question which has:

AB = 8 and AC = 24

Here AC is the diagonal of the rectangle which is the hypotenuse in a right triangle.

As per Pythagoras's theorem,

AC² = AB² + BC²

24² = 8² + BC²

576 = 64 + BC²

BC² = 512

BC = 22.62

The perimeter of rectangle ABDC = 2(AB + BC)

The perimeter of rectangle ABDC = 2(8 + 22.62)

The perimeter of rectangle ABDC = 2(30.62)

The perimeter of rectangle ABDC = 61.24 units

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The area of the  triangle to the nearest hundredth of a square meter is 0.217m²

A right triangle has a hypotenuse of 1 meter and a leg of 1/2 meter

Hypotenuse = 1

base = 0.5

We need to calculate the perpendicular

h² = b² + p²

1² = 0.5² + p²

p² = 1 - 0.25

p = √0.75

p = 0.866

area of the triangle = 1/2 base x height

area = 1/2 (0.5 x 0.866)

area = 0.2165m²

Therefore the area of the  triangle to the nearest hundredth of a square meter is 0.217m²

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Answer:

 3x + y - 4z = -222x + 3y + 4z = 32x - y + 2z = 16 Write and number each equation. Eq 1 3x+y-4z = 16. Eq 2 -222x+3y+4z = 16. Eq 3 32x-y+2z = 16 

Step-by-step explanation:

Hope it helps you buddy(:

Answer: 16

You already got the answer- But whatever.

The values of [x], [y] and [z] are 2, 0 and 7.

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.

The equation of a straight line can be also written to express proportional relationship as -

y = kx  {k is constant}

We have the following system of equation -

3x+y-4z=-22

2x+3y+4z=32

x-y+2z=16

We can write -

x - y + 2z = 16

x = 16 + y - 2z

So, we can write 3x + y - 4z = -22 as -

3(16 + y - 2z) + y - 4z = -22      ...eq[1]

and we can write 2x + 3y + 4z = 32 as -

2(16 + y - 2z) + 3y + 4z = 32      ...eq[2]

Plot eq[1] and eq[2], and find [y] and [z]. Refer to graph.

We get y = 0 and z = 7

So -

x = 16 + 0 - 14

x = 2

Therefore, the values of [x], [y] and [z] are 2, 0 and 7.

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Amount of water after x minutes is more in pool B.

Two or more expressions with an Equal sign is called as Equation.

Given,

Pool A started with 5000 liters of water, and 50 liters per minute are being.

Pool B started with 4800 liters of water, and 30 liters per minute are being.

5000-50x=4800-30x

Add 30x on both sides

5000-50x+30x=4800-30x+30x

5000-20x=4800

5000-4800=20x

200=20x

Divide both sides by 20

20=x

Now substitute x in pool A equation

5000-50x

5000-50(20)=5000-1000

Pool A =4000

Now substitute x in pool B equation

4800-30x

4800-30(20)

4800-600

Pool B =4200

4200>4000

Pool B> Pool A

Hence amount of water after x minutes is more in pool B.

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Answer: -5,5 = B

Step-by-step explanation:

Answer:

b & d

Step-by-step explanation:

Answer:

its "a" your welocome

Step-by-step explanation:

i did the test

1. The linear function .f(2) = 79.4, therefore, test average for maths class after 2 test is: 79.4

2. Using the function table, the test average for science class is after the second test is: 84.

3. f(4) = 79.8

4. g(4) = 80

5. Science class was higher.

The equation of a linear function is given as .f(x) = mx + b, given that m represents the slope/unit rate, and b is the y-intercept or starting value.

The linear function for average test score in maths class is given as, .f(x) = 0.2x + 79

Write the linear function for science class;

Slope (m) = change in y/change in x = (84 - 82)/(2 - 3) = 2/-1

Slope (m) = -2

Substitute m = -2 and (x, y) = (3, 82) into y = mx + b:

82 = -2(3) + b

82 = -6 + b

82 + 6 = b

88 = b

b = 88

Substitute m = -2 and b = 88 into g(x) = mx + b:

g(x) = -2x + 88

Part 1:

Substitute x = 2 into .f(x) = 0.2x + 79

.f(2) = 0.2(2) + 79

.f(2) = 79.4

Test average for maths class after 2 test is: 79.4

Part 2:

Using the function table, when x = 2, the test average for science class is: 84.

Part 3:

Substitute x = 4 into  .f(x) = 0.2x + 79

.f(4) = 0.2(4)+ 79

.f(4) = 79.8

Part 4:

Substitute x = 4 into g(x) = -2x + 88

g(4) = -2(4) + 88

g(x) = 80

Part 5:

Science class had a higher test 4 average of 80.

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The runners whose speeds are in a proportional relationship with each other:

the running speed of Liam, Taylor, Ashley, Nathan, Juan are equal (0.0016) whereas the running speed  of Sarah and Katie are equal.

In this question, we have been given the data for the distance and amount of time each person ran one Saturday morning.

We need to select all the runners whose speeds are in a proportional relationship with each other.

We find the speed using formula, speed = distance / time

Name         Time (seconds)           Distance (miles)              Speed(mps)

Liam                   306.6                           0.5                      0.5/306.6 = 0.0016    

Taylor                756.36                          1.2                      1.2/756.36 = 0.0016

Sarah                 504.35                         0.7                     0.7/504.35 = 0.0014

Ashley               459.9                          0.75                    0.75/459.9 = 0.0016

Connor              600.5                              1                          1/600.5 = 0.0017

Nathan               942.75                         1.5                     1.5/942.75 = 0.0016

Juan                   827.82                         1.35                  1.35/827.82 = 0.0016

Katie                   429.48                          0.6                   0.6/429.48 = 0.0014

Therefore, the runners whose speeds are in a proportional relationship with each other:

the running speed of Liam, Taylor, Ashley, Nathan, Juan are equal (0.0016) whereas the running speed  of Sarah and Katie are equal.

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Answer:

1) 71.83

2) 43

3) 41

4) 755.66

5) 458

6) 1757.12

7) 123 meters

The test statistic is -2.60 as a sample of 380 patients found that 95 were uninsured.

A statistic used in statistical hypothesis testing is known as a test statistic. A test statistic, which can be thought of as a numerical summary of a data set that condenses the data into a single value that can be used to conduct the hypothesis test, is how a hypothesis test is typically expressed. For instance, the Z-statistic, which has the typical normal distribution under the null hypothesis, is the test statistic for a Z-test. Here,

n=380

x=95

p=95/380

p=0.25

test=(0.25-0.31)/√(0.28(1-0.28)/380)

test=-2.60

The test statistic is -2.60 because 95 out of 380 patients in the sample did not have insurance.

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The solution for the expression is X =87/ 48 or 1.812

To solve  for x in the equation we follow the step below:

Step 1: Open the bracket by multiply 4

= 4x +4x/3 = 9 2/3

= 4x +  4x /3 = 29/3

Step 2: Evaluate for X

= [tex]\frac{12x + 4x}{3}[/tex] = [tex]\frac{29}{3}[/tex]

= [tex]\frac{16x}{3}[/tex] =[tex]\frac{29}{3}[/tex]

Step 3: Cross multiply

: 3 (16x) = 3(29)

48x = 87

Step 3: Divide both sides by 48

=[tex]\frac{48x}{48}[/tex] =[tex]\frac{87}{48}[/tex]

x = [tex]\frac{87}{48}[/tex] = 1.812

Therefore, the solution for the expression is X =87/ 48 or 1.812

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number 9 is 36  12x3 is 36

3x²-2x+5 is the other factor of the above polynomial (6x³-x²+8x+5) other than (2x+1).

In mathematics, a polynomial is an equation made up of coefficients and indeterminates, also referred to as variables. Only addition, subtraction, multiplication, and powers of positive-integer variables may be utilized to solve it. An example of a polynomial with one uncertain x is x² + 4x + 7.

Polynomials are commonly used in calculations in both mathematics and science. For instance, in the fundamental sciences of chemistry, physics, economics, and social science, they are used to define polynomial functions. They are also used in numerical analysis and calculus to approximate other functions. Simple word problems to complex scientific conundrums are all represented by polynomial equations. Polynomials are used in advanced mathematics.

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Answer:

y+1=-4(x+5)

Step-by-step explanation:

it changed to point slope form so now it’s different

the equation is y-y1=m(X-x1)

y-(-1)=m(x-(-5)

y+1=m(x+5)

Now to find slope y2-y1/x2-x1

-5+1/-4+5

-4/1

-4 is the slope so we just fill it in

y+1=-4(x+5)

Hopes this helps please mark brainliest

Coppinger Corp is using Scenario Analysis.

Given, that Coppinger Corp is considering the use of a computer to assign probability distributions to the input variables used in the analysis.

The computer would then randomly select input variables from their distributions and calculate npvs based on those selections

Now, A scenario analysis consists of multiple inputs. For eg. a Company may consider how an increase in available fuel can impact their number of goods sold etc.

Here, also Coppinger Corp is assigning multiple values to the computer and getting outputs.

So, this can be the Scenario Analysis.

Hence, Coppinger Corp is using Scenario Analysis.

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The radius of each of the smaller balls is R = 2r.

You can use a tape measure, for instance, to directly measure the distance around the sphere's widest point. The radius of this circle, which serves as the sphere's circumference, is one. A circle's circumference is computed as 2 x x radius. Since the cross-section of the sphere is a circle, the volume in this case is dependent on the diameter of the sphere's radius. The area or region of a sphere's outer surface is known as its surface area. We can use the following formula to get the volume of a sphere whose radius is "r": A sphere's volume is equal to 4/3r³.

Given,

A steel ball is melted down to make eight smaller identical balls. If the radius of the original steel ball was 20 cm:

Let the spherical ball's radius be R.

And with r being the radius of 8 similar balls,

According to the inquiry,

Volume of 8 similar balls = the volume of a larger sphere

3/4πR³ = 8 × 3/4πr³

R³ = 8r³

R = 2r

The radius of each of the smaller balls is R = 2r.

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The required positive number whose product is 25 and whose sum is minimum is 5, 5

Sum of two numbers means adding two same or different number together

Let two positive numbers xy = 25

Divide both side by x

y  = [tex]\frac{25}{x}[/tex]  ----------Equation (1)

Sum of two positive numbers s = x + y  -------Equation (2)

Substitute equation (1) into equation (2)

S = x + [tex]\frac{25}{x}[/tex]

differentiate with respect to x

[tex]\frac{ds}{dx} = \frac{d}{dx} (x + \frac{25}{x} ) = 1 - \frac{25}{x^{2} }[/tex]

[tex]\frac{ds}{dx} = 1-\frac{25}{x^{2} }[/tex]  ---------- Equation (3)

[tex]\frac{ds}{dx} = 0[/tex]

[tex]1[/tex][tex]- \frac{25}{x^{2} }[/tex] = 0  ⇒ [tex]x^{2}[/tex] = 25

x = 5

Differentiate equation (3) again

[tex]\frac{d^{2}s }{dx^{2} } = 0 + \frac{50}{x^{2} }[/tex]

hence, at point x = 5,   [tex]\frac{d^{2} s}{dx^{2} } = \frac{50}{5^{2} }[/tex]  [tex]= \frac{50}{25} = 2[/tex]

Value of s minimum at point x = 5.

substitute the value of x into equation (1)

[tex]y = \frac{25}{x} = \frac{25}{5} = 5[/tex]

Therefore the required positive numbers are 5, 5.

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Answer:

to find horizontal asymptotes, we simply evaluate the limit of the function as it approaches infinity, and again as it approaches negative infinity.

Step-by-step explanation:

Answer:

x = 14

Step-by-step explanation:

the inscribed angle JKL is half the measure of its intercepted arc, that is

83 = [tex]\frac{1}{2}[/tex] arc JL = [tex]\frac{1}{2}[/tex](9x + 40) ← multiply both sides by 2 to clear the fraction

166 = 9x + 40 ( subtract 40 from both sides )

126 = 9x ( divide both sides by 9 )

14 = x

Answer:

-8

Step-by-step explanation:

Graph each side of the equation. The solution is the x-value of the point of intersection.

Answer:

[tex]g(x) + h(x) = x^3 + 6x + 5[/tex]

Step-by-step explanation:

We are told that:

[tex]g(x) = x^3 + 5x[/tex]

[tex]h(x) = x + 5[/tex],

and we are asked to find an expression for [tex]g(x) + h(x)[/tex].

In order to find the expression for  [tex]g(x) + h(x)[/tex], we have to simply add the expressions of [tex]g(x)[/tex] and [tex]h(x)[/tex] together:

[tex]g(x) + h(x)[/tex]

= [tex]x^3 + 5x + x + 5[/tex]

= [tex]x^3 + 6x + 5[/tex]

a) The margin of error for an 80% confidence interval in Arkansas is 0.1041

b) if we want to get an 80% confidence interval with a small margin of error, say only 7%. then the sample size must be 53,599,359

The margin of error is a statistic that describes how much random sampling error there is in survey results. One should have less faith that a poll's findings would accurately reflect those of a population census the higher the margin of error.

n = 3600

standard deviation = 399.876

Confidence Interval = 80%

a) α = 0.20

The margin of error = Zα/2 (σ / √n)

Zα/2 = 1.4395 --- (From the tabular value)

The margin of Error = 1.4395 + 399.876 / √3600

Therefore, the Margin of Error = 8.1041

b) Margin of Error = 0.07 = 7%

α = 0.20

Critical Value = 1.2816

Sample Size = (Zc²σ² / ME²) = (Zcσ / ME)²

n = [(1.2816 * 399.876) / 0.07]²

n = 53599358.98

Therefore, Sample size, n = 53599359

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The given function is strictly decreasing in interval (−∞, 4) & trictly increasing in interval  (4, −∞).

What is an increasing and decreasing functions?

For a given function, y = F(x), the function is known as an increasing function if the value of y increases as the value of x increases, and the function is known as a decreasing function if the value of y decreases as the value of x increases.

We have,

[tex]\frac{5}{512}\left(x-4\right)^2\left(x-8\right)\left(x-10\right)\left(x^2+16\right)[/tex]

[tex]\frac{d}{dx}\left(\frac{5}{512}\left(x-4\right)^2\left(x-8\right)\left(x-10\right)\left(x^2+16\right)\right)[/tex]

[tex]=\frac{5}{512}\frac{d}{dx}\left(\left(x-4\right)^2\left(x-8\right)\left(x-10\right)\left(x^2+16\right)\right)[/tex]

[tex]f'(x)=\left(x-4\right)^2,\:g=\left(x-8\right)\left(x-10\right)\left(x^2+16\right)[/tex]

[tex]=\frac{5}{512}\left(\frac{d}{dx}\left(\left(x-4\right)^2\right)\left(x-8\right)\left(x-10\right)\left(x^2+16\right)+\frac{d}{dx}\left(\left(x-8\right)\left(x-10\right)\left(x^2+16\right)\right)\left(x-4\right)^2\right)[/tex][tex]=\frac{5}{512}\left(2\left(x-4\right)\left(x-8\right)\left(x-10\right)\left(x^2+16\right)+\left(4x^3-54x^2+192x-288\right)\left(x-4\right)^2\right)[/tex]

[tex]f'(x)=\frac{5\left(x-4\right)\left(3x^4-53x^3+300x^2-816x+1856\right)}{256}[/tex]

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.

x = 4, 4i, −4i, 10, 8

∴ f′(x) = 0  

   x = 4,

Now, the point 4 divides the real line into two disjoint intervals i.e., (−∞, 4) and (4, −∞)

In interval (−∞, 4),  f′(x) < 0

Hence, the given function (f) is strictly decreasing in interval (−∞, 4)

​

In interval (4, −∞),  f′(x) > 0

Hence, the given function (f) is strictly increasing in interval  (4, −∞)

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