How many times will the while loop that follows be executed? var months = 5; var i = 1; while (i < months) { futureValue = futureValue * (1 + monthlyInterestRate); i = i+1; }
a. 5
b. 4
c. 6
d. 0

Question:

1. Open a command prompt window, type ipconfig/ all and press Enter.

2. Write down the information for your system’s active network connection(most likely either Ethernet or Wi-Fi).

* Physical address in paired hexadecimal form.

* Physical address expressed in binary form.

Answer:

00000000 11111111 00000011 10111110 10001100 11011010

Explanation:

(i)First, open a command prompt window by using the shortcut: Windows key + X then select command prompt in the list.

(ii)Now type ipconfig/ all and press Enter. This will return a few information

(a) To get the Physical address in paired hexadecimal form, copy any of the Physical Addresses shown. E.g

00-FF-03-BE-8C-DA

This is the hexadecimal form of the physical address.

(b) Now let's convert the physical address into its binary form as follows;

To convert to binary from hexadecimal, we can use the following table;

Hex                 |         Decimal                |           Binary

0                      |          0                           |           0000

1                       |          1                            |           0001

2                      |          2                           |           0010

3                      |          3                           |           0011

4                      |          4                           |           0100

5                      |          5                           |           0101

6                      |          6                           |           0110

7                      |          7                           |           0111

8                      |          8                           |           1000

9                      |          9                           |           1001

A                     |          10                           |           1010

B                      |          11                           |           1011

C                      |          12                           |           1100

D                      |          13                           |           1101

E                      |          14                           |           1110

F                      |          15                           |           1111

Now, from the table;

0 = 0000

0 = 0000

F = 1111

F = 1111

0 = 0000

3 = 0011

B = 1011

E = 1110

8 = 1000

C = 1100

D = 1101

A = 1010

Put together, 00-FF-03-BE-8C-DA becomes;

00000000 11111111 00000011 10111110 10001100 11011010

PS: Please make sure there is a space between ipconfig/ and all

Answer:

Internet backbone

Explanation:

The internet backbone is made up of multiple networks from multiple users. It is the central data route between interconnected computer networks and core routers of the Internet on the large scale. This backbone does not have a unique central control or policies, and is hosted by big government, research and academic institutes, commercial organisations etc. Although it is governed by the principle of settlement-free peering, in which providers privately negotiate interconnection agreements, moves have been made to ensure that no particular internet backbone provider grows too large as to dominate the backbone market.

Answer:

def random_marks(apostrophe, quotation, apostrophe_quotation):

   return "'"*apostrophe + "\""*quotation + "'\""*apostrophe_quotation

print(random_marks(3, 2, 3))

Explanation:

Create a function called random_marks that takes apostrophe, quotation, and apostrophe_quotation as parameters. Inside the function, return apostrophe sign times apostrophe plus quotation mark times quotation plus apostrophe sign quotation mark times apostrophe_quotation.

Note that plus sign (+) is used to concatenate strings. Also, if you multiply a string with a number, you get that number of strings ("#"*3 gives ###).

Then, call the function with given parameters and print

Answer:

According to the principles of design, Repetition refers to the recurrence of elements of the design

One of the advantages of this is that it affords uniformity. Another is that it keeps the user of such a system familiar or with the interface of the operating system.

One major drawback of this principle especially as used in the question is that it creates a familiar route for hackers.

Another drawback is that creates what is called "repetition blindness". This normally occurs with perceptual identification tasks.

The  phenomenon may be  due to a failure in sensory analysis to process the same shape, figures or objects.

Cheers!

Answer:

packet filtering

Explanation:

We can use a packet filtering firewall, for something like this, reasons because when visiting a site these types of firewalls should block all incoming traffic and analyze each packet, before sending it to the user. So if the packet is coming from a malicious origin, we can then drop that packet and be on our day ;D

Answer:

Security controls are those measures taken to prevent, identify, counteract, and reduce security risks to computer systems, whereas, Security Requirements are guidelines or frameworks that stipulates measures to ensure security control.

Explanation:

Security controls encompass all the proactive measures taken to prevent a breach of the computer system by attackers. Security requirements are those security principles that need to be attained by a system before it can be certified as safe to use.

Security controls are of three types namely, management, operational, and technical controls. Examples of technical controls are firewalls and user authentication systems. A statement like 'The system shall apply load balancing', is a security requirement with an emphasis on availability.

Answer:

Linked lists and arrays are both linear data structures but while an array is a collection of items that can be accessed randomly, a linked list can be accessed sequentially.

A sparse matrix contains very few non-zero elements. For example;

_                        _

|  0   0   3  0  6    |

|   0   5   0  0  4   |

|   2   0   0  0  0   |

|_ 0   0   0  0  0 _|

In the implementation of a sparse matrix, the following are some of the pros and cons of using a linked list over an array;

PROS

i.  Linked lists are dynamic in nature and are readily flexible - they can expand and contract without having to allocate and/or de-allocated memory compared to an array where an initial size might need to be set and controlled almost manually. This makes it easy to store and remove elements from the sparse matrix.

ii. No memory wastage. Since the size of a linked list can grow or shrink at run time, there's no memory wastage as it adjusts depending on the number of items it wants to store. This is in contrast with arrays where you might have unallocated slots. Also, because the zeros of the sparse matrix need not be stored when using linked lists, memory is greatly conserved.

CONS

i. One of the biggest cons of linked lists is the difficulty in traversing items. With arrays, this is just of an order of 0(1) since the only requirement is the index of the item. With linked lists, traversal is sequential which means slow access time.

ii. Storage is another bottle neck when using linked lists in sparse matrix implementation. Each node item in a linked list contains other information that needs to be stored alongside the value such as the pointer to the next or previous item.

Answer:

Here is the C++ program for Employee class with fields id,name and sal.

#include <iostream>  // to use input output functions

#include <string>  //to manipulate and use strings

using namespace std;   // to access objects like cin cout

class Employee {  //class Employee

private:  

/* the following data members are declared as private which means they can only be accessed by the functions within Employee class */

  string name;  //name field

  int id; //id field

  double sal;   //salary field

public:    

  Employee();  // constructor that initializes an object when it is created

/* setName, setID and setSalary are the mutators which are the methods used to change data members. This means they set the values of a private fields i.e. name, id and sal */

  void setName(string n)  //mutator for name field

     { name = n; }        

  void setId(int i)  //mutator for id field

     { id = i; }        

  void setSalary(double d)  //mutator for sal field

     { sal = d; }  

/* getName, getID and getSalary are the accessors which are the methods used to read data members. This means they get or access the values of a private fields i.e. name, id and sal */

  string getName()  //accessor for name field

     { return name; }        

  int getId()  //accessor for id field

     { return id; }        

  double getSalary()  //accessor for sal field

     { return sal; }  };  

Employee::Employee() {  //default constructor where the fields are initialized

  name = "";  // name field initialized

  id = 0;  // id field initialized to 0

  sal = 0;   }   // sal field initialized to 0

void display(Employee);  

// prototype of the method display() to display the data of Employee

int main() {  //start of the main() function body

  Employee emp;  //creates an object emp of Employee class

/*set the name field to Abc Xyz which means set the value of Employee class name field to Abc Xyz  through setName() method and object emp */

  emp.setName("Abc Xyz");  

/*set the id field to 1234 which means set the value of Employee class id field to 1234  through setId() method and object emp */

  emp.setId(1234);

/*set the sal field to 1000 which means set the value of Employee class sal field to 1000  through setSalary() method and object emp */

  emp.setSalary(1000);    

  display(emp);  }   //calls display() method to display the Employee data

void display(Employee e) {  // this method displays the data in the Employee //class object passed as a parameter.

/*displays the name of the Employee . This name is read or accessed through accessor method getName() and object e of Employee class */

  cout << "Name: " << e.getName() << endl;  

/*displays the id of the Employee . This id is read or accessed by accessor method getId() and object e */

  cout << "ID: " << e.getId() << endl;

/*displays the salary of the Employee . This sal field is read or accessed by accessor method getSalary() and object e */

  cout << "Salary: " << e.getSalary() << endl;  }

Explanation:

The program is well explained in the comments mentioned with each statement of the program.

The program has a class Employee which has private data members id, name and sal, a simple default constructor Employee(), mutatator methods setName, setId and setSalary to set the fields, acccessor method getName, getId and getSalary to get the fields values.

A function display( ) is used to display the Employee data i.e. name id and salary of Employee.

main() has an object emp of Employee class in order to use data fields and access functions defined in Employee class.

The output of the program is:

Name: Abc Xyz                                                                                                      

ID: 1234                                                                                                                  

Salary: 1000

The program and its output are attached.

Answer:

A. LCD power inverter

B. AC adapter

C. Battery

Answer:

D.  A maximum RPO of 60 minutes

Explanation:

Note that an option is not included in this list of options.

The complete list of options is:

A. A maximum MTTR of 30 minutes

B. A maximum MTBF of 30 minutes

C. A maximum RTO of 60 minutes

D.  A maximum RPO of 60 minutes

E. An SLA guarantee of 60 minutes

The Recovery Point Objective tells how old a backup file must be before it can be  recovered by a system after failure.

Since the data in the failover systems described in this question must be backup and recovered after the failure, it will be important to include the Recovery Point Objective (RPO) in the Business Continuity Plan.

Since the failover systems must use back up data that is no older than one hour, the backup of the system data must be done at intervals of 60 minutes or less. Meaning that the maximum RPO is 60 minutes.

Note that RPO is more critical than RTO in data backup

Answer:

The program written in Python is as follows

nums = []

for i in range(0,68):

-->nums.append(i)

print(nums)

Explanation:

Please note that --> is used to denote indentation

The first line creates an empty list

nums = []

This line creates an iteration from 0 to 67, using iterating variable i

for i in range(0,68):

This line saves the current value of variable i into the empty list

nums.append(i)

At this point, the list has been completely filled with 0 to 67

This line prints the list

print(nums)