How many volts would it take to push 1 amp through a resistance of 1 ohm?

The given vectors quantities can be described by their properties of both

magnitude and direction.

Reasons:

a. The magnitude of the vector = 190 N

The direction in which the vector acts = East

Therefore, in vector form, we have;

[tex]\vec{F}[/tex] = 190 × cos(0)·i + 190 × sin(0)·j = 190·i

The vector can be represented by an horizontal line, 190 units long

Coordinate points on the vector = (0, 0) and (190, 0)

The drawing of the vector with the above points using MS Excel is attached.

b. Magnitude of the velocity vector = 120 km/hr. 25° North of east

Solution;

The vector form of the velocity is; [tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j, which gives;

[tex]\vec{v}[/tex] = 120 × cos(25)·i + 120×sin(25)·j ≈ 108.76·i + 50.714·j

[tex]\vec{v}[/tex] ≈ 108.76·i + 50.714·j

Therefore, points that define the vector are; (0, 0) and (108.76, 50.714)

The drawing of the vector is attached

c. The magnitude of the vector = 60 m

The direction of the vector is southwest = West 45° south

The vector form of the displacement is [tex]\vec{d}[/tex] = 60 × cos(45°)·i + 60 × sin(45°)·j

Which gives;

[tex]\vec{d}[/tex] = 30·√2·i + 30·√2·j

Points on the vector are therefore; (0, 0), and (30·√2, 30·√2)

The drawing of the vector is attached

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Answer:

V=1.5V

Explanation:

p=I×V

4.5=3×V

[tex]v = \frac{4.5}{3} [/tex]

[tex]v = \frac{3}{2} [/tex]

v=1.5

Happy Holidays!

Recall that:

Impulse = Change in Momentum = mass × change in velocity

Since both cars are identical and have the same initial velocity of 60 mph, them breaking to a stop means that they both experience the same change in velocity.

Thus, both of the cars' impulses are equal.

Answer:

C is the right answer for the question

Answer:

applications of density measurements. The densities of brass and aluminum will be calculated from mass and volume measurements.

Explanation:

Answer:

W = 34.775J

Explanation:

W = F × d

W = 53.5N × 0.65m

W = 34.775J

W = work = unknown

f = force = 53.5N

d = distance = 0.65m

Answer:

translucent

Explanation:

Hope this helps! Pls give brainliest! Also, please sub to Kgirl633 on yt.

(a) The angle the planks make with the ground in order for the lathe to slide down at constant velocity is 90⁰.

(b) Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

The given parameters:

The net force on the wooden skids is calculated as follows;

[tex]\Sigma F = 0\\\\F - \mu mg cos\theta = 0\\\\ma - \mu mg cos\theta = 0\\\\ma = \mu mg cos \theta \\\\a = \mu g cos\theta\\\\at \ constant \ velocity , \ a = 0\\\\0 = \mu g cos \theta\\\\cos \theta = 0\\\\\theta = 90 ^0[/tex]

Yes, at this angle the lathe will start sliding at constant velocity because of the sharp steepness.

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The initial velocity of the ball when it was projected is 15.64 m/s.

The given parameters:

The initial velocity of the ball is calculated by applying formula for range of projectile as follows;

[tex]R = \frac{u^2 sin(2\theta)}{g} \\\\u^2 = \frac{Rg}{sin(2\theta)} \\\\u = \sqrt{\frac{Rg}{sin(2\theta)} } \\\\u =\sqrt{\frac{24 \times 9.8}{sin(2\times 37)} } \\\\u = 15.64 \ m/s[/tex]

Thus, the initial velocity of the ball when it was projected is 15.64 m/s.

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Answer: 6 OR 7

Explanation:

The order of the location of each process in the carbon cycle are as follows;

Reasons:

Ingestion; During the ingestion process, the products of the direct Sunlight and photosynthesis, which

are energy rich chemical substances are ingested by herbivores.

Decomposition; The plants and animals die and undergo decomposition.

Fossilization; A long period the decomposed plants and animals manifest

into hard petrified materials, with their parts transformed to fossils.

Combustion; The remains of plants and animals, subjected to heat and

pressure due to compression, as when as bacteria decomposition that

removes several other elements, leaving a carbon and hydrogen rich

sludge that can be processed into fuel used for combustion. The

combustion process produces carbon dioxide which restarts the cycle.

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Answer:

S = V t     where S is the horizontal distance traveled

1/2 g t^2 = H       where H is the vertical distance traveled

t^2 = 2 H / g

V^2 = S^2 / t^2 = S^2 g / (2 H) combining equations

tan theta = H / S

V^2 = S g / (2 tan theta)

Using S = L cos theta

V^2 = L g cos theta / (2 tan theta)

Giving V in terms of L and theta

Answer:

Tom

Explanation:

if for example both their work is 40 and Tom stops working after 2 hours but Claudia continues and stops after 3 hours when you divide their work by their time Claudia will get a lower number of power.

(in your explanation maybe use different numbers based on you book or notes)

Answer:

Claudia had more power. She did more work than Tom, and she did it in less time.

Explanation:

sample answer on edmentum. maybe change it up. hope this helps:)

[tex]\text{Given that,}\\\\\text{Force, F =200 N}\\\\\text{Mass, m = 20 kg}\\\\\text{Using Newton's second law,}\\\\F = ma \\\\\implies a = \dfrac{F}{m} = \dfrac{200}{20}= 10 ~ \text{ m s}^{-2}\\\\\text{The acceleration is 10 m s}^{-2}.[/tex]

The magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

Given that a racquetball with a mass of 42 g is moving with a horizontal speed of 7 m/s to the right (+x direction).

mass m  = 42g = 42/1000 = 0.042kg

initial velocity before collision u = 7 m/s

It hits the wall of the court and rebounds to the hitter with a horizontal speed of 7m/s to the left (-x direction). That is,

velocity after collision v = 7 m/s

To calculate the magnitude of the racquetball's change in momentum, we will use the formula below

Change in momentum = Mv - Mu

Since momentum is a vector quantity, we will consider the direction.

Change in momentum = 0.042 x 7 - ( 0.042 x - 7)

Change in momentum = 0.294 + 0.294

Change in momentum = 0.588 kgm/s

Therefore, the magnitude of the racquetball's change in momentum is 0.59 kgm/s approximately.

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Answer:

I think it is   To make a higher pitch, stretch the rubber band more

Explanation:

I'm not too sure. Sry if u got it wrong

Answer:

To make a higher pitch ,pluck the rubber band more

Answer:

The magnitude of a gravity is always 9.8 which is later approximated to 10m/s.

Answer:

a. 9.8

Explanation:

The magnitude of acceleration due to gravity is 9.8

Explanation:

the sum of its potential (position) energy and kinetic (motion) energy.

v = d/t

= 400/25

= 16 m/s

I'm not sure though

Answer:

Magnets have two poles, called north and south. The like poles are attracted to unlike poles, but like poles repel each other. For example, the north pole of one magnet is attracted to the south pole of another. ... To make objects move with a magnet attach a piece of metal, or another magnet, to it.

7777Answer:

Explanation:

Answer: 5.7

Explanation: 38% of 15.

The weight we experience ourselves and the ability to stand in the ground is due to the gravitational pull of earth. If this pull is lower we feel weight loss. So the cat will have a weight of 5.7 pounds or 2.58 kg in mars where the gravitation is about 38% of earth.

Gravitational force is a kind force by which a body attracts other objects into its centre of mass. Earth have strong gravitational effect on objects and thus we are all standing on the surface and everything falling from a height hits the ground.

As the mass of the object increases, gravitational effect also increases. The weight experienced by a body is the product of its mass and gravity. Thus massive body have greater weight.

Our mass is constant everywhere but weight will change according a change in gravity. Mars  have only 38% of gravity of earth. Thus the cat weighing 15 pounds on earth will loss its weight in mars by 38%.

Thus, 15 × 38/100= 5.7 pounds will be the weight of the cat in mars.

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Answer:

B

Explanation:

If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is

F' = G (5m₁) (2m₂) / d²

F' = 10  Gm₁m₂ / d²

but this is really just F' = 10F. So J is the correct choice.

Hi there!

Using Newton's Law of Universal Gravitation:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]

Fg = Force of gravity (N)

G = Gravitational Constant

m₁ = mass of object 1 (kg)

m₂ = mass of object 2 (kg)

d = distance between the objects (m)

There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:

[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]

Thus, the correct answer is J. 10Fg.

Using the gravitational force of F= G(m1*m2/r^2)

m1= 5.97 x 10^24 kg (Earth)

m2= 1.99 x 10^30 kg (Sun)

r= 1.48 x 10^11 m

G is a known value, it is 6.672 x 10^-11

All units are proper. Therefore plug in the values and you get 3.16 x 10^22 N.

Let me know if I calculated this wrong and it is something else so I can delete this. Thank you. I don't want to make other students put down the wrong answer.

Answer:

[tex]\boxed {\boxed {\sf F_g \approx 3.62 *10^{22} \ N}}[/tex]

Explanation:

We are asked to find the gravitational force between Earth and the Sun. Use the following formula:

[tex]F_g= \frac{Gm_1m_2}{r^2}[/tex]

G is the universal gravitational constant. One mass (m₁) is the Earth and the other (m₂) is the Sun. r is the distance between the planets.

Substitute the values into the formula.

[tex]F_g = \frac{ (6.67*10^{-11} N*m^2/kg^2)(5.97*10^{24} \ kg)(1.99*10^{30} \ kg) }{ (1.48 *10^{11} \ m)^2}}[/tex]

Multiply the numerator. The units of kilograms cancel.

[tex]F_g = \frac {7.9241601 *10^{44} \ N*m^2}{ (1.48 *10^{11} \ m)^2 }[/tex]

Solve the exponent in the denominator.

[tex]F_g= \frac {7.9241601 *10^{44} \ N*m^2}{ 2.1904*10^{22} \ m^2}[/tex]

Divide. The units of meters squared cancel.

[tex]F_g=3.61767718 *10^{22} \ N[/tex]

The original values all have 3 significant figures, so our answer must have the same. For the number we found, that is the hundredth place. The 7 in the thousandth place tells us to round the 1 up to a 2.

[tex]F_g \approx 3.62 *10^{22} \ N[/tex]

The gravitational force between Earth and the Sun is approximately 3.62 *10²² Newtons.

Answer:

answer to this question is c

Answer:

3

Explanation:

because the battery's power is not functioning well

Answer:

where m < M is delivered to the space station. Soon after, the space station's orbit is adjusted so that it is 50 km ...

A payload of mass m, where m<M, is delivered to the space station.

The maximum mass that the vehicle is capable of moving is referred to as the mass's payload. The carrying capacity of a packet or other transmission data unit is referred to as a payload.

The phrase, which has military roots, is frequently used in relation to malicious code that can be executed and cause harm. A payload is a section of code that runs when hackers take advantage of a weakness. In other words, it's a module for an exploit.

It typically consists of a few commands that will execute on the targeted operating system in order to steal data and carry out other malicious deeds (such as keyloggers).

Therefore, A payload of mass m is sent to the space station, where m<M.

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Answer:

“The only true wisdom is in knowing you know nothing.” ― Socrates. Socrates had it right. Remain humble and appreciate the fact that you don't know everything. ... Thankfully, one's search for knowledge has no end as there is always something new to learn, giving one's life meaning and purpose.

Explanation:

Answer:

knowing wisdom cool

Explanation:

lol

Answer:

A chemical reaction is a process that occurs when two or more molecules interact to form a new product(s).

Endothermic reactions are chemical reactions in which the reactants absorb heat energy from the surroundings to form products.

Example:

A popular example of an endothermic chemical reaction is photosynthesis. During this process, plants absorb energy from the Sun and convert it into carbon dioxide and water into glucose and oxygen.

An exothermic reaction releases energy into the surrounding of the system.

Example:

the chemical reaction between sodium and chlorine results in the formation of sodium chloride (also known as common salt).