The amount of charge transferred is 4.5C (coulombs). This is calculated by dividing 45 J (joules) of work by 9.0 V (volts) of voltage.
We can use the equation W = qV, where W is the work done, q is the charge transferred, and V is the potential difference (voltage) across the battery.
Rearranging the equation to solve for q, we get q = W/V.
Plugging in the values given, we have:
q = 45 J / 9.0 V
q = 5.0 C
Therefore, the battery transfers 5.0 coulombs of charge from the negative to the positive terminal while doing 45 J of work.
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a van exerts a force on trailers of different masses m. compared with the force exerted on each trailer, rank the magnitude of force each trailer exerts on the van. (or are all pairs of forces equal in magnitude?)
The trailer pulls on the vehicle with an average force of A=B=C.
Newton's second law of acceleration is expressed as follows: F = ma
In this case, the mass is m, and the acceleration is a.
Assume that g=9.8 m/s2 represents the acceleration caused by gravity.
The acceleration of the object will be zero if it is travelling at a constant speed.
Because of the constant velocity, the van's net force on the trailer is therefore zero.
As a result, the van applies the same amount of force to each trailer. Thus, FA FB = FC.
As a result, each trailer pulls on the van with the same amount of force in the opposite direction. FA' = FB' = Fc', therefore.
As a result, A=B=C represents the rank of the force the trailer exerts on the van.
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A dog can hear sounds in the range from 15
to 50,000 Hz.
What wavelength corresponds to the lower
cut-off point of the sounds at 20◦C where the
sound speed is 344 m/s?
Answer in units of m.
Explanation:
Speed of sound is 344
The frequency corresponding to the lower cut-off point is the lowest frequency which his 15Hz
F=15Hz
The relationship between the wavelength, speed and frequency is given as
v=fλ
Then,
λ=v/f
λ=v/f
λ=344/15
λ=22.93m
2. according to our equations, what should be the relationship between the total current and the currents passing through each resistor? does your data show this relationship
According to Ohm's Law, the relationship between the total current and the currents passing through each resistor is that the total current is equal to the sum of the currents passing through each resistor.
What is Ohm's Law?This can be represented mathematically as I total = I₁ + I₂ + I₃ + ... where I total is the total current and I₁, I₂, I₃, etc. are the currents passing through each resistor.
This relationship is consistent with Kirchhoff's Current Law, which states that the sum of the currents entering and leaving a junction in a circuit must be equal to zero. Therefore, the current flowing through each resistor must add up to the total current in the circuit. Yes, this relationship is observed in data obtained from circuits.
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a wire with a current of 4 amps is in a magnetic field of 2 tesla. the magnetic field is oriented perpendicular to the wire. what is the magnitude of the force per unit length on the wire?
The magnitude of the force per unit length on the wire carrying a current of 4 amps in a magnetic field of 2 Tesla, oriented perpendicular to the wire will be 8 N/m.
It can be determined using the formula F = BIL,
where F is the force per unit length,
B is the magnetic field,
I is the current and
L is the length of the wire.
For the given data, B = 2 T, I = 4 A, L = 1 meter.
Therefore, F = BIL= 2 T x 4 A x 1 m= 8 N/m. Thus, the magnitude of the force per unit length on the wire is 8 N/m.
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a car is traveling at 40 m/s as it enters a turn of radius 25 meters. what minimum coefficient of friction must be maintained between the road and tires to make sure the car does not slide out of the turn?
The minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.
This is determined using the equation for the maximum centripetal force that the car can withstand. This equation states that the maximum centripetal force is equal to the mass of the car times its speed squared divided by the radius of the turn multiplied by the coefficient of friction. Using this equation, 0.21 is the coefficient of friction that is required to make sure the car does not slide out of the turn.
The equation for maximum centripetal force can be written as:
F = m*v2/r * μ Where m is the mass of the car, v is the velocity of the car, r is the radius of the turn, and μ is the coefficient of friction.
Since we are solving for the coefficient of friction (μ), we can solve this equation for μ:
μ = m*v2/r * F
Plugging in the given values, we get:
μ = (1000 kg) * (40 m/s)2 / (25 m) * (10000 N) = 0.21
Therefore, the minimum coefficient of friction required for a car travelling at 40 m/s to not slide out of a turn of radius 25 meters is 0.21.
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a spherical capacitor has vacuum between its conducting shells and a capacitance of 125 pf . the outer shell has inner radius 9.00 cm . what is the outer radius of the inner shell? express your answer with the appropriate units.
For a spherical capacitor with a capacitance of 125 and a vacuum between its conducting shells, the outer radius of the inner shell is around 5.60 cm.
The capacitance of a spherical capacitor is given by:
C = 4πε₀[(r₁r₂)/(r₂-r₁)]
where C is the capacitance, ε₀ is the electric constant (8.85 x [tex]10^{-12}[/tex] F/m), r₁ is the radius of the inner shell, and r₂ is the radius of the outer shell.
In this case, we know that the capacitance C = 125 pF (picoFarads), r₂ = 9.00 cm, and we want to find r₁.
We can rearrange the equation to solve for r₁:
r₁ = (C × r₂)/(4πε₀ + C)
Substituting the values:
r₁ = (125 x [tex]10^{-12}[/tex] F × 0.09 m) / (4π × 8.85 x [tex]10^{-12}[/tex] F/m + 125 x [tex]10^{-12}[/tex] F)
r₁ ≈ 5.60 cm
Therefore, the outer radius of the inner shell is approximately 5.60 cm.
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an n-type piece of silicon experiences an electric field equal to 0.1v/m. (a) calculate the velocity of electrons and holes in this material
In an n-type piece of silicon, the electric field causes the electrons to accelerate due to the attractive force between the negatively charged electrons and the positively charged electric field. This acceleration causes the electrons to reach a velocity of V = E/μ, where E is the electric field (0.1V/m) and μ is the mobility of electrons in silicon (1350 cm2/V⋅s). Therefore, the velocity of electrons in this material would be equal to 0.1V/m/1350cm2/V⋅s = 0.0741 cm/s.
The holes, on the other hand, experience a repulsive force due to the positive electric field. This causes the holes to decelerate, with a velocity of V = -E/μ. Therefore, the velocity of holes in this material would be equal to -0.1V/m/1350cm2/V⋅s = -0.0741 cm/s.
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Please help. Due at Midnight!
The magnitude and direction of the net force on the center charge is 3.929 x 10⁻⁴ N.
What is unit of charge?The unit of charge is the Coulomb (C). It is named after French physicist Charles-Augustin de Coulomb and is defined as the amount of electric charge that flows through a circuit when a current of one ampere flows for one second. One Coulomb is also equivalent to the charge on approximately 6.24 x 10¹⁸ electrons. The Coulomb is one of the seven base SI units (International System of Units) and is used to measure electric charge in physics and engineering.
So, the magnitude of the net force on the center charge is 3.929 x 10⁻⁴ N. Since F12 is directed towards the left, and F23 is directed towards the right, the net force is also directed towards the left. Therefore, the direction of the net force on the center charge is to the left.
According to Coulomb's law to calculate the force exerted by each of the other charges on the center charge, and then add them vectorially.
Let's call the left charge Q1, the center charge Q2, and the right charge Q3.
The force exerted on Q2 by Q1 is given by:
F₁₂ = k * |Q1| * |Q2| / r₁₂²
where k is Coulomb's constant, |Q1| and |Q2| are the magnitudes of the charges, and r₁₂ is the distance between them. Since Q1 is positive and Q2 is negative, the force F₁₂ is attractive and directed towards Q1. Because the distance between them is 2m, we can say:
F₁₂ = 9 x 10⁹ Nm²/C² * |52 x 10⁻⁶ C| * |3.10 x 10⁻⁶ C| / (2m)²
= 3.468 x 10⁻⁴ N (attractive)
The force exerted on Q2 by Q3 is given by:
F₂₃ = k * |Q2| * |Q3| / r₂₃²
where |Q3| is positive, and |Q2| is negative, so the force F23 is repulsive and directed away from Q3. The distance between them is also 2m, so:
F₂₃ = 9 x 10⁹ Nm²/C² * |3.10 x 10⁻⁶ C| * |68 x 10⁻⁶ C| / (2m)²
= 5.383 x 10⁻⁵ N (repulsive)
To find the net force on Q2, we need to add these two forces vectorially. Since they act along the same line, we can simply subtract their magnitudes:
Fnet = |F₁₂| - |F₂₃|
= 3.468 x 10⁻⁴ N - 5.383 x 10⁻⁵N
= 3.929 x 10⁻⁴ N.
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A bar magnet is falling through a loop of wire with constant velocity. The north pole enters first. As the south pole
leaves the loop of wire, the induced current (as viewed from above) will be in which direction?
a) is counterclockwise.
b) is along the length of the magnet
c) is zero
d) is clockwise
As the south pole leaves the loop of wire, the induced current (as viewed from above) will be in the clockwise direction.
Whenever a magnet is moved near a closed circuit or wire loop, an emf (electromotive force) is generated in the conductor. When the magnet moves in and out of the coil or loop, the magnitude and direction of this voltage changes, generating an induced current. This is referred to as Faraday's law of electromagnetic induction, which states that an emf is induced in a closed conductor when the magnetic flux through the surface enclosed by the conductor changes over time.
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a 7.6 nc point charge and a - 2.6 nc point charge are 3.1 cm apart. what is the electric field strength at the midpoint between the two charges?
The electric field strength at the midpoint between a 7.6 nc point charge and a -2.6 nc point charge which are 3.1 cm apart is 279.8 N/C.
What is an electric field?An electric field refers to a field surrounding a charged object, through which another charged object would feel a force. A charge placed in an electric field is subjected to a force depending on the charge and distance from the source of the field.
The electric field intensity or strength may be calculated using Coulomb's law by taking the charge 'Q' as a point charge and then determining the value of the electric field at a distance 'r' from the charge.
The magnitude of the electric field due to a point charge Q at a distance r is
E=kQ/r²,
where k is Coulomb's constant,
k=9×10⁹ Nm²/C².
So, the electric field at the midpoint is due to the combined effect of both charges. The charges are located 3.1 cm apart, so the midpoint is 1.55 cm from each of the charges. Therefore, we need to calculate the electric field due to each of the charges separately and add them up. The electric field at the midpoint due to a 7.6 nc point charge E₁=kQ₁/r₁²
=(9×10⁹ Nm²/C²)(7.6×10⁻⁹ C)/(0.0155 m)²
=294.47 N/C.
The electric field at the midpoint due to a -2.6 nc point charge
E₂=kQ₂/r₂²
=(9×10⁹ Nm²/C²)(-2.6×10⁻⁹ C)/(0.0155 m)²
=-14.67 N/C.
The net electric field at the midpoint is given by
E=E₁+E₂=294.47 N/C-14.67 N/C
=279.8 N/C.
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Worked Calculate the number of electrons that a positively charged object gains if its charge decreases by 3,2 x 10-18 C.
The positively charged object gains 20 electrons when its charge decreases by 3.2 x 10^-18 C.
What is Positive Charge?
A positive charge is an electrical property of matter that describes the presence of more positively charged protons than negatively charged electrons in an atom or molecule. In other words, an object with a positive charge has lost one or more electrons, resulting in a net charge that is greater than zero.
We know that the charge on a single electron is 1.602 x 10^-19 C.
To calculate the number of electrons gained by a positively charged object when its charge decreases by 3.2 x 10^-18 C, we can use the formula:
number of electrons = (magnitude of charge lost) / (charge on a single electron)
number of electrons = (3.2 x 10^-18 C) / (1.602 x 10^-19 C)
number of electrons = 20
Therefore, the positively charged object gains 20 electrons when its charge decreases by 3.2 x 10^-18 C.
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which of the following are waves that can travel without a medium? select all that apply. visible light seismic waves x-rays waves on a lake sound waves radio waves
The following waves can travel without a medium: visible light, x-rays, and radio waves. Seismic waves and waves on a lake require a medium, such as air or water, to travel through.
Visible light is a form of electromagnetic radiation that is composed of various colors. It can travel through a vacuum, such as the space between planets, and does not require a medium to travel through. X-rays are also electromagnetic radiation, but with a higher frequency than visible light, allowing them to pass through objects that visible light cannot. Radio waves are also a form of electromagnetic radiation, and can travel through a vacuum. Seismic waves, on the other hand, require a medium, such as air or rock, to travel through. These waves are used to measure earthquakes and are created when energy is released from the ground. Similarly, waves on a lake require a medium, such as water, to travel through.
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if you hold a 1.85 kg k g package by a light vertical string, what will be the tension in this string when the elevator accelerates as in the previous part?
The tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. When the elevator accelerates, the force of acceleration on the package will be equal and opposite to the tension in the string, causing the tension to increase.
The equation for tension in a string is:
Tension = Mass x Acceleration
Therefore, in this case, the tension in the string is equal to 1.85 kg x Acceleration.
If we assume that the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
To sum up, the tension in the string of a 1.85 kg package held by a light vertical string will depend on the acceleration of the elevator. If the acceleration of the elevator is a constant rate, then the tension in the string can be calculated by multiplying the mass of the package by the acceleration of the elevator.
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in u.s. customary units, air pressure is measured in pounds per square inch. in the metric system, it is measured in pascals, and one pascal is equal to
In the metric system, air pressure is measured in pascals. One pascal is equal to a force of one newton per square meter.
Air pressure can be measured using different units. Pascal is a unit of pressure, defined as one newton per square meter. This unit is named after Blaise Pascal, a French mathematician, physicist, and philosopher who made important contributions to the fields of hydrodynamics and hydrostatics.
In the US customary system, air pressure is measured in pounds per square inch (psi), while in the International System of Units (SI), it is measured in pascals (Pa). The unit psi is used to measure pressure in liquids and gases, and it is defined as the amount of pressure exerted by a force of one pound-force per square inch.
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at what angle of deflection makes the magnetic field strngth produced by the coil of the wire equal to the ambient magnetic field
The magnetic field strength created by the wire coil is equivalent to the ambient magnetic field when it is deflected at a right angle.
The magnetic field strength created by the wire coil is equivalent to the ambient magnetic field when it is deflected at a right angle. The Biot-Savart Law, which relates magnetic field strength to the current in a wire and the distance from the wire, applies to a wire coil.
The strength of the magnetic field generated by a current-carrying wire is proportional to the current in the wire and the number of turns per unit length. The magnetic field's intensity is determined by the number of turns in the wire coil, the current in the wire coil, the radius of the coil, and the permeability of free space.
The equation for calculating the magnetic field strength at a point in space around a current-carrying wire is given by the Biot-Savart Law:
B = µ₀I/2πr.
Where µ₀ is the permeability of free space, I is the current, and r is the distance from the wire to the point where the magnetic field strength is to be calculated.
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a 100 ohm resistor is connect in parallel with a 300 ohm resistor. what is the equivalent resistance?
The equivalent resistance of the two resistors in parallel is 75 ohms.
To calculate the equivalent resistance of a 100-ohm resistor and a 300-ohm resistor connected in parallel, the following formula can be used:
Req = 1 / ((1/R1) + (1/R2))
where Req is the equivalent resistance, R1 is the resistance of the first resistor, and R2 is the resistance of the second resistor.
In this situation, the values of R1 and R2 are 100 ohms and 300 ohms, respectively.
Therefore, we can substitute these values into the equation as follows:
Req = 1 / ((1/100) + (1/300))= 1 / (0.01 + 0.00333)= 1 / 0.01333= 75 ohms
Therefore, the equivalent resistance of the two resistors in parallel is 75 ohms.
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A skydiver of mass 95kg ,before opening his parachute, falls at t1 with V1= 11m/s and at t2 with t2 v2=27m/s; supposing friction is zero, find the distance covered between t1 and t2
The skydiver covered a distance of approximately 94.9 meters before opening his parachute between t1 and t2, assuming no air resistance or friction.
v = final velocity = v2 = 27 m/s
u = initial velocity = v1 = 11 m/s
a = acceleration = g = 9.8 m/[tex]s^2[/tex]
s = (v² - u²) / 2a
s = (27² - 11²) / (2 x 9.8) = 94.9 meters
Resistance measures an item's potential to impede the drift of electrical present-day through it. it's far measured in ohms (Ω). Resistance is decided by way of the bodily residences of an item, along with its dimensions, material, and temperature. while electric-powered present-day flows thru a conductor, it encounters resistance that slows down its float. This resistance is as a result of the collisions among electrons and the atoms inside the conductor.
Resistance can be laid low with changes inside the bodily properties of the conductor, such as duration, cross-sectional region, or temperature. an extended or narrower conductor may have higher resistance, even as a much broader conductor could have decreased resistance. understanding resistance is critical for designing and working electrical circuits. with the aid of controlling the resistance of a circuit, engineers can make sure that the appropriate amount of current flows to electricity the devices linked to it.
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A solid cylinder of mass M = 1.25 kg and radius R = 13.5 cm pivots on a thin fixed frictionless bearing a string wrapped around the cylinder pulls downward with a force of F = 7.259 N
What is the magnitude of the angular acceleration of the cylinder?
86.03259 rad/s^2
Consider that instead of force F, a block with mass 0.74 kg with force = 7.259 N is attached to the cylinder with a mass less string.
What is now the magnitude of the angular acceleration of the cylinder
39.3943 rad/s^2
How far does the mass M travel downward before T equals 0.49S and T equals 0.69 S.
0.62755 m
The cylinder is changed to one with the same mass and radius but a different moment of inertia starting from mass starting from rest. The mass is now moved. The distance of 0.448 mass in the time interval of 0.47 seconds.
Find the Inertia of the new cylinder
The inertia of the new cylinder is 0.0566 kgm². Other answers provided are correct.
How to find inertia?The moment of inertia of the new cylinder can be calculated using the formula:
I = (M × d²) / (4 × Δθ)
Where:
M = mass of the cylinder
d = distance moved by the mass
Δθ = change in angular displacement (in radians)
Substituting the given values:
I = (1.25 × 0.448²) / (4 × 0.47)
I = 0.0566 kgm²
Therefore, the moment of inertia of the new cylinder is 0.0566 kgm².
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Lebohang says that when you use a thick syringe to "drive" a thin syringe, you lose strength but gain distance. What do you think
Lebogang says that when you use a thick syringe to "drive" a thin syringe, you lose strength but gain distance. Jaamiah disagrees this means that there is indeed a mechanical advantage, but a distance disadvantage.
A syringe is a medical device that is used for injecting liquids into or extracting liquids from the body. It typically consists of a cylindrical barrel, a plunger, and a needle. The barrel is usually made of plastic or glass and is marked with volume measurements. The plunger fits inside the barrel and can be pushed or pulled to draw or expel liquid. The needle is attached to the end of the barrel and is used to penetrate the skin or other tissue to inject or extract the liquid.
Syringes are commonly used in medical settings for a variety of purposes, such as administering vaccines, medications, or anesthesia. They can also be used to remove fluid from the body, such as in the case of draining abscesses or collecting blood samples for testing.
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Complete Question: -
Lebogang says that when you use a thick syringe to "drive" a thin syringe, you lose strength but gain distance. Jaamiah disagrees. She says that you gain both distance and strength. What do you think, and why do you think so?
the time interval between flashes on a strobe light is 1/70th of a second. what is the frequency of these flashes.
(Use f=time/vibe)
Show work
The strobe light's flashes occur at a 70 Hz frequency.
What frequency does sound have?The frequency of a sound pressure wave, also known as pitch, is the quantity of times every second that it repeats. A bullfrog cry is far downward communication than a whistle, while a cricket is much downward communication than a drum beat.
To calculate the flash frequency, use the formula below.:T is the amount of time between flashes in seconds, and f is the frequency expressed in Hertz (Hz).We obtain the following value by inserting the given value: f = 1 / (1/70) f = 70 Hz.
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old faithful geyser in yellowstone national park shoots water every hour to a height of 40.0 m. with what velocity does the water leave the ground?
The velocity with which the water leaves the ground is 28.0 m/s (downward).
The Old Faithful Geyser in Yellowstone National Park shoots water every hour to a height of 40.0 meters.
To find the velocity with which the water leaves the ground, we can use the following kinematic equation:
v² = u² + 2as
Here,
v = final velocity
u = initial velocity
a = acceleration due to gravity
s = distance traveled by the object
The initial velocity of the water when it leaves the ground is 0 m/s.
Also, we can assume the final velocity of the water when it reaches the maximum height to be 0 m/s.
We know that the acceleration due to gravity is -9.8 m/s² (negative due to the direction).
The distance traveled by the water is the height to which it rises, i.e., 40.0 meters.
Using the above values in the kinematic equation, we get:
v² = 0² + 2*(-9.8)*40.0v² = -784v = √(-784)
Since the answer is coming out to be negative, it indicates that the velocity is in the downward direction.
So, the velocity with which the water leaves the ground is 28.0 m/s (downward).
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7) you drop a stone down a well that is 9.5 m deep. how long is it before you hear the splash? the speed of sound in air is 343 m/s and air resistance is negligible
If you drop a stone down a well that is 9.5 m deep, it will take approximately 0.028 seconds for you to hear the splash. This is because the speed of sound in air is 343 m/s, and air resistance is negligible.
The question is about finding the time it will take for the sound of the splash to reach the surface of the well. Given data:
Depth of the well = 9.5 m
Speed of sound in air = 343 m/s
We have to find the time it will take for the sound of the splash to reach the surface of the well.
Let's assume that "t" is the time that the sound of the splash takes to reach the surface of the well.
Using the formula:
t = Distance/Speed
Using the above formula, let's find the time it will take for the sound of the splash to reach the surface of the well.
Distance = Depth of the well = 9.5 m
Speed = Speed of sound in air = 343 m/s
So, the time is:
t = Distance/Speed
t = 9.5/343
t = 0.0277 s ≈ 0.028 s
Therefore, the time it will take for the sound of the splash to reach the surface of the well is 0.028 s
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is the transfer of information between two or more points that are not connected by an electrical conductor?
Yes, the transfer of information between two or more points that are not connected by an electrical conductor is possible and is referred to as wireless communication.
Wireless communication involves the use of electromagnetic waves such as radio waves, microwaves, and infrared waves, to transmit data between two points without the need for physical contact or connection.
Wireless communication is used in various fields, such as broadcasting, radio communication, mobile communication, satellite communication, and Internet access. Wireless communication technology has revolutionized communication and enabled a wide range of applications, from wireless microphones to Wi-Fi networks, GPS tracking systems, Bluetooth connectivity, and cellular communication.
Wireless communication is an important component of the modern world and will continue to play a major role in the advancement of communication technology.
Therefore, the transfer of information between two or more points that are not connected by an electrical conductor is possible and is done through wireless communication.
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Which type of engine has a wheel with several blades mounted on a shaft that rotate a shaft when hit with heated air at a high velocity?
The type of engine that has a wheel with several blades mounted on a shaft that rotates when hit with heated air at a high velocity is called a gas turbine engine.
What is a gas turbine engine?
The gas turbine engine is also known as a combustion turbine engine. A gas turbine engine is a type of internal combustion engine that converts the chemical energy of fuel into mechanical energy, which can be used to power various machines and equipment. The engine works by compressing air and then mixing it with fuel in a combustion chamber, where it is ignited to produce a high-temperature, high-pressure gas stream. This gas stream then flows through a series of turbine blades, causing them to spin, which drives a shaft that is connected to various machines or equipment. As the shaft rotates, it generates mechanical power that can be used for various applications.
Gas turbine engines are commonly used in aircraft, power plants, and marine propulsion.
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the cantilevered beam is made of a36 steel and is subjected to the loading shown. determine the displacement at b using the method of superposition. for a36 steel beam, the moment of inertia i
Thus using method of superposition, the total displacement is 0.0276.
A36 steel beam is used Cantilever beam is loaded. The moment of inertia is I. For A36 steel beam, I = 6667 in4 (approx.)As per the method of superposition, the total displacement of the beam at point B is given as follows:δtotal = δP + δWWhere,δP is the displacement of point B due to the point loadδW is the displacement of point B due to the uniformly distributed load.
Considering point load,P = 1500 lb. Distance of the point load from point B = 5 ft. Thus, the moment at point B due to point load can be calculated as follows: MBP = PL = 1500 × 5 = 7500 lb-ft. Similarly, considering uniformly distributed load,W = 200 lb/ft. Thus, the moment at point B due to uniformly distributed load can be calculated as follows:Mbw = (wL2)/12Where,L is the length of the beam= 10 ft
Therefore, Mbw = (200 × 102)/12 = 1667 lb-ft (approx.)Thus, total moment at point B,M = MBP + MBW= 7500 + 1667= 9167 lb-ft. Thus, using the formula for deflection of cantilever beam,δP = (PbL2)/(2EI) = (1500 × 52)/(2 × 29 × 106 × 6667) = 0.0026 inδW = (WbL3)/(3EI) = (200 × 5103)/(3 × 29 × 106 × 6667) = 0.024 in
Therefore, the displacement at point B is 0.0276 in.
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two 4.0cm*4.0cm metal plates are separated by a 0.20-mm-thick piece of teflon. a. what is the capacitance? b. what is the maximum potential difference between the plates?
The capacitance of two metal plates separated by a 0.20-mm-thick is approximately 0.25 pF and the maximum potential difference between the plates is 8.4 kV.
a. The capacitance of two metal plates separated by a 0.20-mm-thick piece of Teflon is approximately 0.25 pF (picofarad).
b. The maximum potential difference between the two metal plates is determined by the permittivity of the dielectric material, which in this case is Teflon.
The permittivity of Teflon is about 2.1 and the capacitance of the plates is 0.25 pF, so the maximum potential difference between the plates can be calculated using the equation:
Vmax = (permittivity * Capacitance) / Area.
Therefore, the maximum potential difference between the plates is 8.4 kV.
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a hard billiard ball elastically collides with another hard billiard ball of equal mass. which situation is possible?
In an elastic collision, the total kinetic energy and momentum of the system are conserved. So, in the case of a hard billiard ball elastically colliding with another hard billiard ball of equal mass,
There are two possible situations that can occur. These situations are as follows:
When the two hard billiard balls collide head-on and return with equal speed.When the two hard billiard balls collide at an angle, they deflect at the same angle, and their speed remains the same.
Elasticity refers to the ability of a substance to return to its original shape and size when an external force is applied to it.
Elasticity is an essential concept in the field of physics and is used to describe the behavior of materials under stress.The coefficient of restitution is a measure of the elasticity of an object.
It is defined as the ratio of the relative speed of separation to the relative speed of approach after a collision between two objects.
The coefficient of restitution ranges from 0 to 1, with 0 representing a completely inelastic collision and 1 representing a completely elastic collision.
When two hard billiard balls elastically collide, they can either collide head-on and return with equal speed or collide at an angle and deflect at the same angle while maintaining the same speed.
Elasticity is a fundamental concept that is used to describe the behavior of materials under stress. The coefficient of restitution is a measure of the elasticity of an object.
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a coil is placed in a changing magnetic field and an emf is induced. what happens to the induced emf if the rate of change of magnetic field quadruples?
The induced EMF increases to four times its initial value if the rate of change of the magnetic field quadruples.
Faraday's law of electromagnetic induction specifies that an emf (electromotive force) is induced in a closed conductor or coil whenever there is a change in magnetic flux associated with it.
EMF = − d(ΦB) /dt
ΦB = BAcosθ
This equation suggests that emf is proportional to the rate at which magnetic flux ΦB is changing with respect to time. As a result, if the rate of change of the magnetic field quadruples, the induced EMF increases to four times its initial value.
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magnus has reached the finals of a strength competition. in the first round, he has to pull a city bus as far as he can. one end of a rope is attached to the bus and the other is tied around magnus's waist. if a force gauge placed halfway down the rope reads out a constant 1400 newtons while magnus pulls the bus a distance of 1.55 meters, how much work does the tension force do on magnus? the rope is perfectly horizontal during the pull.
The work done by the tension force on Magnus is 2170 J.
What is work?
Work is the product of the force acting on an object and the distance through which the object moves. In other words, work is accomplished when a force is used to transfer energy to an object, causing the object to move some distance as a result.
The force of 1400 N, Distance of 1.55 meters, and a rope tied around Magnus's waist.
The work done by the tension force on Magnus is the product of the force exerted by the tension force and the distance through which Magnus is moved.
W = Fd
where W = Work done by the tension force on Magnus
F = Force of tension force
= 1400 Nd
= Distance moved by Magnus
= 1.55 m
Substituting these values:
W = 1400 N x 1.55 mW
= 2170 J
Hence, the work done by the tension force on Magnus is 2170 J.
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two students sit on a seesaw in a way that makes it balance and not move. when a third person pushes down on one side, that side moves down. what caused the seesaw to move?
The seesaw moved when a third person pushed down on one side. This is because the seesaw is a simple machine that consists of a long plank balanced in the middle with a pivot point that allows it to move up and down.
When the two students sit on the seesaw in a way that makes it balance and not move, they are evenly distributed on each end. However, when the third person pushes down on one side, this distribution of weight becomes unequal, and the seesaw moves in the direction of the heavier side.
The heavier end of the seesaw moves down while the lighter end moves up. This is because the heavier side creates more force, or torque, on the pivot point, causing the seesaw to tilt towards that side.
As a result, the seesaw moves and is no longer in balance.
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