How much energy is required to raise the temperature of 12.2 grams of gaseous nitrogen from 24.5 °C to 39.3 °C ?

Approximately 2.62% of college students sleep for more than 8.3 hours.

To determine the proportion of college students who sleep for more than 8.3 hours, we need to use the provided information: the average sleep time is 7 hours per night with a standard deviation of 40 minutes (which is equivalent to 2/3 of an hour or 0.67 hours). Since the sleep time is normally distributed, we can use the Z-score formula to find the proportion.

First, calculate the Z-score: Z = (X - μ) / σ, where X is the desired sleep time (8.3 hours), μ is the average sleep time (7 hours), and σ is the standard deviation (0.67 hours).

Z = (8.3 - 7) / 0.67 ≈ 1.94

Now, we can use a Z-table to find the proportion of students who sleep for more than 8.3 hours. The table value for a Z-score of 1.94 is approximately 0.9738. However, this value represents the proportion of students who sleep 8.3 hours or less. To find the proportion of students who sleep more than 8.3 hours, subtract the table value from 1:

Proportion = 1 - 0.9738 ≈ 0.0262

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Answer:

Step-by-step explanation:

1. 2x-4=10

2x=14

x=7

2. 3x+3=2x-1

3x-2x=-1-3

x=-4

3. 7x+x=24

8x=24

x=3(

4. 5+x=-18

x=-18-5

x=-23

5. -14=10-6x

6x=10+14

6x=24

x=4

6. 2x-2=x+12

2x-x=12+2

x=14

7. 3x-31=2

3x=2+31

3x=33

x=11

8. 5x-14=16

5x=16+14

5x=30

x=6

9. 2x+8=4(5-x)

2x+8=20-4x

2x+4x=20-8

6x=12

x=2

10. 2x-3=3(1+x)

2x-3=3+3x

2x-3x=3+3

-x=6

With quarterly compounding and an interest rate of 4%, the account balance after 4 years will be around $587.44.

From the formula for compound interest to find the amount in the account:

[tex]A = P(1 + r/n)^{nt}[/tex]

where A is the amount in the account, P is the principal, r is the annual interest rate (as a decimal), t is the time (in years), and n is the number of compounding periods per year.

In this case, P = $500, r = 0.04 (since 4% = 0.04), t = 4 years, and the interest is compounded quarterly, so n = 4.

Substituting the values, we get:

[tex]A = $500(1 + 0.04/4)^{4*4}\\A = 500(1 + 0.01)^{16}\\A = 500(1.01)^{16}\\A = 500(1.1749)[/tex]

A = 586.29 (rounded to two decimal places)

Therefore, the amount in the account after 4 years with a quarterly compounding period and a 4% interest rate is approximately $587.44.

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Answer:

Step-by-step explanation:

50 possible dimensions

Answer:

Step-by-step explanation:

The domain of the function y = √(5x-10) is: D. x ≥ 2.

In order to find the  the domain of the function  we have to first of all  find or determine the values of x that make the function undefined.

Let  solve the inequality 5x-10 ≥ 0 to find the values of x that make the function defined:

5x-10 ≥ 0

5x ≥ 10

Divide by 5x

x ≥ 10/5

x ≥ 2

Therefore the correct option is D.

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The equation 20(x + 2) + 31 = 4(5x + 10) + 31 is also true for all the values of x by the addition and multiplication property of equality.

Given equation which is true for all the values of x is,

5(x + 2) = 5x + 10

We have to explain the reason behind the equality of the other equation through this equation.

Using multiplication property of equality, multiplying both sides of the equation with the same number will hold the equation true.

Multiplying both sides by 4,

4 [5(x + 2)] = 4 [5x + 10]

20(x + 2) = 4(5x + 10)

By the addition property of equality, adding both sides by 31,

20(x + 2) + 31 = 4(5x + 10) + 31

which gives the required equation.

Hence the equation 20(x + 2) + 31 = 4(5x + 10) + 31 is true for all x.

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For z = 1.22, The area to the left of z = 1.22 under the standard normal curve is approximately 0.8888. For z = 0.43, The area to the left of z = 0.43 under the standard normal curve is approximately 0.6664.

To find the indicated area under the standard normal curve to the left of a given z-value, we can use a standard normal table. For the first question, we need to look up the area to the left of z = 1.22 in the table. From page 1, we find the row for 1.2 and the column for 0.02, which gives us the value 0.88493. Adding the area to the left of z = 1.2 (0.88493) to the area between z = 1.20 and z = 1.22 (0.04846), we get the area to the left of z = 1.22 as 0.9334 (rounded to four decimal places).

For the second question, we need to look up the area to the left of z = 0.43 in the table. From page 1, we find the row for 0.4 and the column for 0.03, which gives us the value 0.66640. Adding the area to the left of z = 0.4 (0.65542) to the area between z = 0.40 and z = 0.43 (0.01392), we get the area to the left of z = 0.43 as 0.6693 (rounded to four decimal places).

To find the indicated area under the standard normal curve, follow these steps:

1. Locate the z-score in the standard normal table.
2. Read the corresponding decimal value for the given z-score.
3. Round the decimal value to four decimal places as needed.

For z = 1.22:
1. Find the intersection of the row labeled 1.2 and the column labeled 0.02 in the standard normal table.
2. The corresponding decimal value for z = 1.22 is 0.8888.
3. The area to the left of z = 1.22 under the standard normal curve is approximately 0.8888.

For z = 0.43:
1. Find the intersection of the row labeled 0.4 and the column labeled 0.03 in the standard normal table.
2. The corresponding decimal value for z = 0.43 is 0.6664.
3. The area to the left of z = 0.43 under the standard normal curve is approximately 0.6664.

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The value of 4 is an input of the function.

Now, we know that;

In a linear equation, the variable x represent the independent variable or input value and the variable y represent the dependent variable or output value

Hence, In this problem we have that the given line passes through the points (1,3), (4,0) and (18,-14)

So, we get;

The input values are (1,4,18)

And, The output values are (3,0,-14)

Therefore, The value of 4 is an input of the function.

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The given nonhomogeneous equation is:

y'' - y = 17t

To find the general solution, we need to find the complementary solution and particular solution separately.

Complementary Solution:

The associated homogeneous equation is:

y'' - y = 0

The characteristic equation for this is:

r^2 - 1 = 0

Solving for the roots, we get:

r = ±1

So the complementary solution is:

y_c(t) = c1e^t + c2e^(-t)

where c1 and c2 are constants.

Particular Solution:

The particular solution is given as:

y_p(t) = -17t

We can substitute this into the nonhomogeneous equation to find the value of the constant:

y'' - y = 17t

(-17)'' - (-17) = 17t

0 + 17 = 17t

t = 1

Therefore, the constant is -17.

So the particular solution is:

y_p(t) = -17t

General Solution:

The general solution is the sum of the complementary solution and the particular solution:

y(t) = y_c(t) + y_p(t) = c1e^t + c2e^(-t) - 17t

where c1 and c2 are constants.

Therefore, the general solution to the given nonhomogeneous equation y'' - y = 17t with particular solution yp(t) = -17t is:

y(t) = c1e^t + c2e^(-t) - 17t

where c1 and c2 are constants.

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The equation of the line in slope intercept form based on the location of two points is (2x + 3).

To find the equation of line in slope intercept form, we need to calculate the slope first. The formula is -

Slope = ([tex] y_{2}[/tex] - [tex] y_{1}[/tex])/([tex] x_{2}[/tex] - [tex] x_{1}[/tex])

Keep the values in formula

Slope = (9-1)/(3-(-1))

Add the values in numerator and denominator

Slope = 8/4

Divide the values

Slope = 2

The equation of line in slope intercept form is -

y - [tex] y_{1}[/tex] = m(x - [tex] x_{1}[/tex)

Again keeping values

y - 1 = 2(x - (-1))

Multiply the values on RHS

y - 1 = 2(x + 1)

y - 1 = 2x + 2

Simplify the equation

y = 2x + 3

Hence, the equation is 2x + 3.

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The equation √(12x - 25) = √(3x -11) + √(3x) has a solution at x = 5.444

From the question, we have the following parameters that can be used in our computation:

√(12x - 25) = √(3x -11) + √(3x)

To do this, we solve graphically

When plotted on a graph, we have the value of x to be

x = 5.444

This means that the equation has a root

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The equation to find dimensions of the actualfield is y= 5/2x.

We have,

2 inch = 5 feet

So, the equation can be

y= 5/2 x

Now, width = 10 inch

So, y= 5/2(10)

y= 25 feet

and, length = 20 inch

So, y= 5/2(20)

y= 50 feet

So, the Area of field is

= 10 x 20

= 20 inch²

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Answer:  if the input value 55 were included in the table, we would expect the rule to assign an output value of 265. However, since this value is not currently included in the table, we cannot verify its accuracy based on the given data.

Step-by-step explanation: a. To complete the table using the equation y = 5x - 10, we can substitute each input value of x into the equation and solve for the corresponding output value of y:

Input, x Output, y

10 40

Copy code

2    |     0

-10 | -60

20 | 90

64 | 310

15 | 65

10 | 40

64 | 310

10 | 40

40 | 190

30 | 140

96 | 470

20 | 90

90 | 440

40 | 190

64 | 310

50 | 240

32 | 150

30 | 140

b. If the table included the input value 55, we can use the same equation to find the corresponding output value:

y = 5x - 10

y = 5(55) - 10

y = 275 - 10

y = 265

Therefore, if the input value 55 were included in the table, we would expect the rule to assign an output value of 265. However, since this value is not currently included in the table, we cannot verify its accuracy based on the given data.

This suggests that the mean age of teachers at Ravenwood High School is less than 47.6. Based on the given information, we have two hypotheses, H.: u = 47.6 and H.: u < 47.6, where u represents the mean age of teachers at Ravenwood High School.

The calculated p-value is 0.023, and we need to make a conclusion at a significance level of 0.10.

If we compare the p-value with the significance level, we see that the p-value is less than the significance level (0.023 < 0.10). This means that we have strong evidence to reject the null hypothesis H.: u = 47.6 in favor of the alternative hypothesis H.: u < 47.6.

Therefore, we can conclude that the mean age of teachers at Ravenwood High School is significantly less than 47.6 years at a significance level of 0.10.

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The probability that the baby was born in February if a baby born in 2011 is randomly selected is  0.0754 or 7.54%.

The probability that the baby was born in February if a baby born in 2011 is randomly selected is calculated from the formula below:

Probability(February) = 299 / 3966

Probability(February) = 0.0754

Hence, the probability that a baby born in 2011 was born in February is equal to 0.0754 or 7.54%.

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we write the iterated integral of a continuous function f over the region using the order dy dx. Since the region is symmetric with respect to the x-axis, we can integrate over the top half of the region and then multiply by 2.
Here, "region" refers to the part of the circle of radius 5 centered at the origin that lies in the first quadrant, "integral" refers to the calculation of the area or volume under a curve or surface, and "quadrant" refers to one of the four regions obtained by dividing a plane into four equal parts by the x- and y-axes.

Step 1: Sketch the region
The region (R) is in the first quadrant, which means x ≥ 0 and y ≥ 0. The region is bounded by a circle with radius of 5 centered at the origin (0,0). This circle can be represented by the equation x^2 + y^2 = 25.

Step 2: Write the iterated integral
To find the iterated integral of a continuous function f over the region R using the order dy dx, we first need to find the bounds for y and x.
The limits of integration for y are from 0 to the y-coordinate of the top half of the circle, which is √(25-x^2). The limits of integration for x are from 0 to 5. Therefore, the iterated integral is:
∫ from 0 to 5 ∫ from 0 to √(25-x^2) f(x,y) dy dx

For y: Since R is in the first quadrant and bounded by the circle, the lower bound for y is y = 0. The upper bound for y, given x, is the equation of the circle's top half, solving for y: y = sqrt(25 - x^2).

For x: Since R is in the first quadrant, the lower bound for x is x = 0, and the upper bound is x = 5 (the radius of the circle).

Now we can write the iterated integral using these bounds:
∫(from x=0 to x=5) ∫(from y=0 to y=sqrt(25-x^2)) f(x,y) dy dx

This iterated integral represents the continuous function f over the specified region R in the first quadrant, using the order dy dx.

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E[X] = 21.

E[f(X = n)] = 1.

a. To find the expected value of the random variable X, we need to use the formula:

E[X] = Σn P(X = n) * n

where Σn denotes the sum over all possible values of X.

Given that the pmf of X is given by:

f(X = n) = 4/(n(n+1)(n+2)),

we have:

P(X = n) = f(X = n) * 21 = 84/(n(n+1)(n+2))

Substituting this into the formula for E[X], we get:

E[X] = Σn P(X = n) * n
    = Σn (84/(n(n+1)(n+2))) * n
    = Σn (84/(n+1)(n+2)))
    = 84 * Σn (1/(n+1)(n+2))

Now, using partial fractions, we can write:

1/(n+1)(n+2) = (1/2) * [1/(n+1) - 1/(n+2)]

Substituting this back into the expression for E[X], we get:

E[X] = 84 * Σn [(1/2) * (1/(n+1) - 1/(n+2))]
    = 42 * Σn [1/(n+1) - 1/(n+2)]
    = 42 * [(1/2) - (1/3) + (1/3) - (1/4) + ...]
    = 42 * (1/2)
    = 21



b. To find the expected value of f(X = n), we simply need to substitute the pmf into the formula for expected value:

E[f(X = n)] = Σn f(X = n) * P(X = n)

Substituting the given pmf, we have:

E[f(X = n)] = Σn (4/(n(n+1)(n+2))) * 21

Using partial fractions as before, we can write:

4/(n(n+1)(n+2)) = (2/n) - (4/(n+1)) + (2/(n+2))

Substituting this into the expression for E[f(X = n)], we get:

E[f(X = n)] = Σn [(2/n) - (4/(n+1)) + (2/(n+2))] * 21
            = 2 * [1 - (4/2) + (2/3) - (4/3) + (2/4) - (4/4) + ...] * 21
            = 2 * [(1/2) + (1/3) + (1/4) + ...] * 21
            = 42 * [(1/2) + (1/3) + (1/4) + ...]

This is the harmonic series, which diverges. However, note that we are interested in the expected value of f(X = n), not the sum of f(X = n) over all possible values of X. Therefore, we can say that E[f(X = n)] = 1, since the pmf is normalized to sum to 1:

Σn f(X = n) = Σn (4/(n(n+1)(n+2))) * 21
            = 21 * Σn (2/n) - Σn (4/(n+1)) + Σn (2/(n+2))
            = 21 * (2 - 1 + 1/2)
            = 21

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Answer:

112

Step-by-step explanation:

use the formula BASE×PERPENDICULAR HEIGHT

14×8= 112

The study involved 18 participants who were asked to read a controversial essay on Social Security and rate their level of agreement with the author's opinion.

In this scenario, a social psychologist conducts research to measure the effectiveness of the author's age on the persuasiveness of an opinion about Social Security.
Measuring the participants' level of agreement on a numerical scale allows the researcher to quantitatively analyze the data and determine if there is a correlation between the age of the author and the persuasiveness of their opinion on Social Security. Overall, this study aims to provide insights into the factors that influence individuals' opinions and beliefs about Social Security.

1. The social psychologist gathers 18 participants to read a controversial essay about Social Security.

2. Each participant reads the essay and is informed of the author's age, which might be manipulated or varied across different groups of participants.

3. After reading the essay, each participant rates the extent to which they agree with the author on a scale. The higher the number, the more they agree with the author's opinion.

4. The researcher then collects these ratings and analyzes the data to determine if there is a significant relationship between the age of the author and the persuasiveness of the essay as measured by the participants' agreement scores.

5. Based on the findings, the social psychologist can draw conclusions about the influence of the author's age on the persuasiveness of opinions about Social Security among the participants.

Complete Question:

A social psychologist is interested measuring the effect of the age of the author on the persuasiveness of an opinion about Social Security. 18 research participants read a controversial essay about Social Security. Each participant rated the extent to which he or she agreed with the author (the higher the number, the more the person agreed with the author).

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The slope of the line, based on the information given in the table is: the cost of purchasing one pencil.

In a given situation, the slope of a line can be defined as the unit rate between two variables. It is calculated as the rate of change of the dependent variable over the rate of change of the independent variable.

In this scenario, to find the slope, use two pairs of values from the table, (3, 1.05) and (7, 2.45):

Slope in this case = cost of purchasing one pencil (unit rate) = 2.45 - 1.05 / 7 - 3

Slope = $0.35 per pencil.

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To find the ucrit (critical value) for a two-sample t-test with the given information, you need to use a t-distribution table.

Since a = 0.052 tail, the significance level (α) is 0.052. You need to find the degrees of freedom (df) first:

Step 1: Calculate the degrees of freedom:
df = n1 + n2 - 2
df = 6 + 8 - 2
df = 12

Step 2: Look up the ucrit value in the t-distribution table using α and df:
For a one-tailed test at α = 0.052 and df = 12, the ucrit value is approximately 1.782.

Your answer: The ucrit value for n1 = 6, n2 = 8, and a = 0.052 tail is approximately 1.782.

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The values of x and y are 67.4 degrees and 18. 78 respectively.

How to determine the value

Using the sine rule, we have;

sin A/a = sin B/b = sin C/c

Given that;

From the diagram shown, we have;

sin 38/12 = sin x/18

Cross multiply the values, we get;

sin x = sin 38(18)/12

Find the value and multiply

sin x = 0. 9234

x = 67. 4 degrees

To determine the side y

sin 38/12 = sin 74. 6/y

Then,

y = 18. 78

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Answer:

Step-by-step explanation:

well, since we know the diameter, half-way of it, is where the center is, and half that distance from endpoint to endpoint is its radius

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 4 -2}{2}~~~ ,~~~ \cfrac{ 1 +5}{2} \right) \implies \left(\cfrac{ 2 }{2}~~~ ,~~~ \cfrac{ 6 }{2} \right)\implies \stackrel{ center }{(1~~,~~3)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(~~4 - (-2)~~)^2 + (~~1 - 5~~)^2} \implies d=\sqrt{(4 +2)^2 + (1 -5)^2} \\\\\\ d=\sqrt{( 6 )^2 + ( -4 )^2} \implies d=\sqrt{ 36 + 16 } \implies d=\sqrt{ 52 } \\\\[-0.35em] ~\dotfill\\[/tex]

[tex]\stackrel{\textit{half of that diameter is its radius}}{r=\cfrac{\sqrt{52}}{2}\implies r^2=\cfrac{52}{4}}\implies r^2=13 \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{1}{h}~~,~~\underset{3}{k})}\qquad \stackrel{radius}{\underset{\frac{\sqrt{52}}{2}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - 1 ~~ )^2 ~~ + ~~ ( ~~ y-3 ~~ )^2~~ = ~~\left( \frac{\sqrt{52}}{2} \right)^2\implies \boxed{(x-1)^2 + (y-3)^2=13} \\\\\\ (x^2-2x+1)+(y^2-6y+9)=13\implies \boxed{x^2+y^2-2x-6y=3}[/tex]

Based on these results, we would conclude that on average, the population of all ferrets tend to decrease in weight when exposed to the virus.

Based on the results of the hypothesis test in part (b) and the confidence interval in part (c), we can conclude that the population mean weight of ferrets tends to decrease when exposed to the virus.

In part (b), we found that the p-value was less than the significance level of 0.05, which means that we reject the null hypothesis that the mean weight of ferrets is not affected by the virus. This indicates that there is strong evidence that the virus has a significant effect on the weight of ferrets.

In part (c), we constructed a 95% confidence interval for the difference between the mean weight of ferrets before and after exposure to the virus. The interval was (−0.643,−0.057), which does not contain 0. This means that we are 95% confident that the true difference between the mean weights is negative, indicating that the weight tends to decrease after exposure to the virus.

Therefore, based on these results, we would conclude that on average, the population of all ferrets tend to decrease in weight when exposed to the virus.

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There is a 20.7% chance that exactly two emails will successfully go through.

a. The probability that all three emails go through is the product of the individual probabilities of each email going through:

P(all three go through) = 0.925^3 = 0.779

Therefore, there is a 77.9% chance that all three emails will successfully go through.

b. The probability that the emails to the bank and magazine go through but not the one to your professor is the product of the probability that the bank and magazine emails go through and the probability that the email to your professor does not go through:

P(bank and magazine go through, professor does not) = 0.925^2 x (1 - 0.925) = 0.069

Therefore, there is a 6.9% chance that the emails to the bank and magazine will go through, but not the one to your professor.

c. The probability that exactly two emails go through can occur in three different ways: the bank and magazine emails go through and the professor's does not, the bank and professor's emails go through and the magazine's does not, or the magazine and professor's emails go through and the bank's does not.

The probability of each of these events happening can be calculated as follows:

P(bank and magazine go through, professor does not) = 0.925^2 x (1 - 0.925) = 0.069

P(bank and professor go through, magazine does not) = 0.925^2 x (1 - 0.925) = 0.069

P(magazine and professor go through, bank does not) = 0.925^2 x (1 - 0.925) = 0.069

Therefore, the total probability that exactly two emails go through is the sum of these probabilities:

P(exactly two go through) = 0.069 + 0.069 + 0.069 = 0.207

Therefore, there is a 20.7% chance that exactly two emails will successfully go through.

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The yield on the corporate bond is 8.65%.

A bond yield is a general term that relates to the return on the capital you invest in a bond.  To calculate the yield of a bond, the forumula to use is "yield = (annual interest payment / purchase price) x 100%".

Data:

Face value of the bond is $1000

Fixed interest rate is 8%.

Annual interest payment = 8% x $1000

Annual interest payment = $80

The purchase price is $925.

we can substitute these values to find the yield:

= ($80 / $925) x 100%

= 0.0864864865 * 100%

= 8.65%

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Answer:

99

Step-by-step explanation:

cuz its correct

It is true to claim that when squaring a complex number using De Moivre's theorem, there is only one answer. Option B is correct.

It is a theorem developed by the mathematician Abrahan Moivre. Its purpose is to establish a formula for calculating powers of complex numbers in trigonometric or polar form. The first de Moivre formula is given by:

Therefore, this theorem is used to find roots of complex numbers, and after application in formulas, we have that when squaring a complex number using De Moivre's theorem, there is only one answer.

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