We have that for the Question "How much force is required to raise a 0.2 kg mass?" it can be said that
The Force required to raise W=1.962N will be F=1.962N since F=W
F=1.962N
From the question we are told
How much force is required to raise a 0.2 kg mass?
Generally the equation for the Weight is mathematically given as
[tex]W=M*g\\\\W=0.2*9.81\\\\W=1.962N\\\\[/tex]
Therefore
The Force required to raise W=1.962N will be F=1.962N since F=W
F=1.962N
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what is meant by si unit?
Answer:
The SI base units are the standard units of measurement defined by the International System of Units (SI) for the seven base quantities of what is now known as the International System of Quantities: they are notably a basic set from which all other SI units can be derived.
Explanation:
A car moves with a velocity of 54km/h to a velocity of 72lm/h for 5 minutes. determine the distance covered
Answer:
The distance covered is 5250 meters
Explanation:
Motion With Constant Acceleration
It's a type of motion in which the velocity of an object changes uniformly in time.
The change of velocities is given by the following equation :
[tex]v_f=v_o+at\qquad\qquad [1][/tex]
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is given by:
[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2][/tex]
Solving [1] for a:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The car changes its speed from vo=54 Km/h to vf=72 Km/h in t=5 minutes. Let's convert all to meters and seconds.
vo=54 Km/h * 1000/3600 = 15 m/s
vf=72 Km/h * 1000/3600 = 20 m/s
t = 5 min * 60 = 300 s
Now we calculate the acceleration:
[tex]\displaystyle a=\frac{20-15}{300}[/tex]
[tex]\displaystyle a=\frac{5}{300}[/tex]
[tex]a=0.0167\ m/s^2[/tex]
Now for the distance:
[tex]\displaystyle x=15*300+\frac{0.0167*300^2}{2}[/tex]
[tex]\displaystyle x=4500+750=5250[/tex]
x = 5250 m
Note: We have shown only some of the decimals for the acceleration, but we have used all the decimals stored in the calculator to present accurate results.
The distance covered is 5250 meters
HELP PLEASE!!!
An 85-kg clown is fired from rest out of a 480-kg cannon. If the clown’s speed is 18 meters per second after the firing, then what is the recoil speed of the cannon?
Answer:
101.65 m/s
Explanation:
Step one:
Given data
m1= mass of gun.= 480kg
m2= mass of bullet. = 85kg
v1=
v2= final velocities of bullet. = 18 meters per second
m1u1+m2u2=m1v1+m2v2
u1=0; u2=0
0=m1v1+m2v2
Step two:
Recoil velocity v1= -(m1/m2)v2
v1= -(480/85)18
v1= 5.64*18
v1=101.65 m/s
John sees Linda Running towards him at 11 m/s. while running, Linda throws a ball at 5m/s. what is the speed of the ball as observed by John?
Friction converts Kinetic energy to what type of energy?
Answer: Friction between the two surfaces converts kinetic energy into thermal energy.
Explanation: Friction occurs because no surface is perfectly smooth. Rougher surfaces have more friction between them. Friction produces heat because it causes the molecules on rubbing surfaces to move faster and have more energy.