How much heat is required to boil 500 grams of water at 100 degrees C if the Hy is 813,700 J/g? Be sure to put the correct units at the end of​

Answers

Answer 1

Answer:

406850000 J

Explanation:

From the question

Q = cm...................... Equation 1

Where Q = Amount of heat, c = latent heat of water, m = mass of water

Given: c = 813700 J/g, m = 500 grams

Substitute these values into equation 1

Q = 500×813700

Q = 406850000 J

Hence the amount of heat requires to boil water at 100°C = 406850000 J


Related Questions

a violin is less than 0.5 m long. a bass fiddle is more than 1.5 m long. which instrument do you expect to be able to play notes with a lower pitch and why?

Answers

Explanation:

When there is a high frequency sound the speed of the vibrations is faster and makes a high pitch sound. When there is a low frequency sound the speed of the vibrations is slower and makes a lower pitch sound.

Can someone pls help! I’m stuck on c and d. I’ll rate your answer the brainliest

Answers

Answer:

i think is c

Explanation:

Answer:

C

Explanation:

C makes more sense than D, Because it says the minimum value is when it stays at rest.

Prove the correctness of this equation s=vt + 1/2at ​

Answers

Answer:

The formula is dimensionally correct.

Explanation:

Given

[tex]s = ut + \frac{1}{2}at^2[/tex]

Required

Prove its correctness

Write out the dimension of each:

[tex]s = M^0LT^0[/tex] --- displacement

[tex]ut = M^0LT^{-1} * T[/tex] --- velocity * time

[tex]\frac{1}{2}at^2 = M^0LT^{-2} * T^2[/tex] --- acceleration * square of time

The expression becomes:

[tex]s = ut + \frac{1}{2}at^2[/tex]

[tex]M^0LT^0 = M^0LT^{-1} * T + M^0LT^{-2} * T^2[/tex]

Apply law of indices

[tex]M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}[/tex]

[tex]M^0LT^0 = M^0LT^{0} + M^0LT^{0}[/tex]

[tex]M^0LT^0 = M^0LT^{0}[/tex]

Both sides of the equation are equal

why do you say that they are good conductors of heat and electricity?​

Answers

Answer:

because they conduct heat and electricity and vibrate the neighboring molecules

plz mark me branliest

the
11. A sinusoidal A.C has a maximum value of 15A.
1) What are its r.m.s values?
ii) If the time is recorded from the instant the current is zero and is becoming
positive, what is the instantaneous value of the current after 1/300s, given the
frequency is 50 Hz.​

Answers

Answer:

1.) 10.61 A

2.) 0.27 A

Explanation:

Given that a sinusoidal A.C has a maximum value of 15A.

1) What are its r.m.s values?

ii) If the time is recorded from the instant the current is zero and is becoming

positive, what is the instantaneous value of the current after 1/300s, given the

frequency is 50 Hz.​

Solution.

1.)

The r.m.s current = peak current/root 2

The r.m.s current = 0.7071 × 15

The r.m.s current = 10.61 A

2.)

Given that

Time = 1/300 s

Frequency = 50 Hz

Instantaneous current can be calculated by using the formula

I = I sin wt

Where w = 2πf

Instantaneous current = 15( sin 2πft)

I = 15 × sin ( 2 × 3.143 × 50 × 1/300 )

I = 15 × sin ( 1.047 )

I = 15 × 0.01827

I = 0.27 A

Therefore, the instantaneous current is 0.27A

There is only one temperature where the Celsius and Fahrenheit thermometers will read the same and no conversions need to be made. What is it?

A. -25 degrees
B. -40 degrees
C. 25 degrees
D. 0 degrees

Answers

-40 degrees is the same in both F and C

Answer:

-40 degrees

Explanation:

I just took the Temperature Quiz and got it right. :)

a particle moves along of the x_axis according to the equation X=2t+3t^2, whare x is in m and t is in second. calcualt the instantaneous velocity and the instantaneous acceleration in t=3s​

Answers

Answer:

Instantaneous velocity  [tex]= 20[/tex] meter per second

Instantaneous acceleration  [tex]= 6[/tex] meter per second square

Explanation:

Given equation of distance X = [tex]2t+3t^2[/tex]

Instantaneous velocity [tex]= \frac{dX}{dt}[/tex]  [tex]= 2 + 6 t[/tex]

Substituting the value of t = 3 seconds, we get -

[tex]\frac{dX}{dt} = 2 + 6*3 = 20[/tex] meter per second

Instantaneous acceleration  [tex]= \frac{d^2X}{dt^2}[/tex]  [tex]= 6[/tex] meter per second square

AAAAAAAAA HELP QUICK PLS!!!
How do we measure the average kinetic motion of molecules in a solution?
Thank you <3

Answers

maybe by using formula k.E = 1/2mV^2

I really need the answer

Answers

Answer:

The first answer is correct.  All of the other options include sound, which travels by material force, and can not be transmitted in a vacuum.  Infra-red, radio, and microwaves are all different frequencies of light, and can thus travel through a vacuum.

Dynamic stretching is a series of movements that warm up the body before an intended activity. Which dynamic stretch would warm an individual before a one mile run

Answers

Answer:

They would likely do a whole series of dynamic stretches

Explanation:

It would include warming up the body and then dynamically stretching the lower body, and some upper body as well. This isn't a question with one specific answer

Make a claim about which fossil in the diagram is the oldest. Use evidence and scientific reasoning to support your claim.

Answers

The fish is the oldest because the oldest fossils are found on the bottom and the youngest are found on the top.

From the diagram, the fossil of fish is considered the oldest fossil. Because the oldest fossils are formed at the bottom whereas the others are at the top of the soil.

What are the fossils?

When living organisms like plants, animals, and human beings are died, their  bodies get buried in the form of sediments in the sand, rock water bodies, etc..,

It also includes the preserved remains of life for more than 10,000 years. It is the preserved remains, sediments, and impressions to trace the life of the organisms and their behavior.

When living organisms died and are buried in sand or mud, the tissues of living organisms get decomposed leaving the bones which is harder. After the organisms are buried in the sand or mud, several sediments, and sand was built over the top of the buried organisms.

These sand and sediments over the buried organisms eventually form the layer of rocks. This is how fossils are made and these fossils were identified when the rocks were broken or by cause of soil erosion.

The age of the fossils was identified by the stacks of layered rocks with the help of the superposition principle. The oldest fossils are present at the bottom of the rocks whereas the youngest fossils are present at the top of the rocks. This process is called Relative dating.

Hence, from the given diagram the fossil of fish is present at the bottom of the rock unlike the others fossils like monkeys and lizard. Thus, the oldest fossil is fish and the youngest one is a monkey.

To learn more about the Fossils:

https://brainly.com/question/31419516

#SPJ2

What number belongs where "X" is to properly balance this equation?
2 NaCl →
2 Na + Ecl2
04
o
2.
оо

Answers

Answer:

Option D: 1

Explanation:

The chemical equation given is;

2NaCl = 2Na + XCl2

We want to find the value of X.

On the left hand side, we can see we have 2 moles of both Na and Cl.

On the right hand side, we can see that we have 2 moles of Na and also 2 moles of Cl. Thus, the equation is balanced and as such X = 1

Low air pressure and warm temperatures over land are most likely to result in which of the following weather conditions or events?
A.Clear sunny skies
B. tropical hurricane
C. chance of snow
D.Cloudy skies with rain

Answers

I would say d bc low air pressure results in cloudy and rainy days which also can bring in warm weather

Coherent light from a sodium-vapor lamp is passed through a filter that blocks everything except for light of a single wavelength. It then falls on two slits separated by 0.460 mm. In the resulting interference pattern on a screen 2.20 m away, adjacent bright fringes are separated by 2.82 mm. What is the wavelength of the light that falls on the slits

Answers

Answer:

[tex]5.896\times 10^{-7}\ \text{m}[/tex]

Explanation:

D = Distance of the screen from the light source = 2.2 m

d = Distance between slits = 0.46 mm

m = Order

Distance between adjacent bright fringes is 2.82 m

[tex]y_{m+1}-y_m=2.82\ \text{mm}\\\Rightarrow \dfrac{D(m+1)\lambda}{d}-\dfrac{Dm\lambda}{d}=2.82\times 10^{-3}\\\Rightarrow \dfrac{D\lambda}{d}(m+1-m)=2.82\times 10^{-3}\\\Rightarrow \lambda=\dfrac{d}{D}2.82\times 10^{-3}\\\Rightarrow \lambda=\dfrac{0.46\times 10^{-3}\times 2.82\times 10^{-3}}{2.2}\\\Rightarrow \lambda=5.896\times 10^{-7}\ \text{m}[/tex]

The wavelength of the light that falls on the slits is [tex]5.896\times 10^{-7}\ \text{m}[/tex].


Find the velocity of an object that has a mass of 500x10-6 kg and a charge of 1pc if it starts from
rest and passes through a potential difference of 120kV

Answers

Answer:

 v = 4.8 10⁻⁴ m / s

Explanation:

To solve this exercise we can use the concepts of energy. In this case the potential energy is transformed into kinetic energy

          U = K

          q V = ½ m v²

          v = [tex]\sqrt { \frac{2qV}{m} }[/tex]

in the exercise they indicate the value of the charge q₁ = 1 pC = 1 10⁻¹² C

let's calculate

          v = [tex]\sqrt{ \frac{2 \ 1 \ 10^{-12} 120 \ 10^3}{500 ^{2} }[/tex]

          v = 4.8 10⁻⁴ m / s

advice students on how to manage stress throughout their studies​

Answers

Answer:

Drink water

Make your find fresh by doing the stuff you love too ❤️

1. Get enough sleep
2. Listen to music
3. Calming breathes
4. Practicing Visualization

PLZ WHAT I DOO
I BROKE A WINDOW WHAT I DO

Answers

Hmmmm, you either tell your parent, try to fix it, or blame it on the dog with a baseball bat that always comes on your yard and tries to eat you.

o(* ̄▽ ̄*)ブ

eifhewfiowehfoiwehfoiwe

Answers

Answer:

LEKWKKAKDJFKWNFKWFF

Explanation:

INLOVE THE WORDS U USE THERE


4. Which of the following is the DNA sequence that a restriction enzyme binds to?

Answers

Answer:

DNA ligase

Explanation:

DNA Ligase is the enzyme that binds fragments of DNA together by forming two phosphodiester bonds between the 3' hydroxyl end of one nucleotide with the 5' phosphate end of the other. This reaction requires the hydrolysis of ATP.

Help me pls???!!
In the circuit shown, the
battery voltage, V = 12V and the load resistance, R = 252.

The ammeter reading is____
A.
The Voltmeter reading is_____
V.​

Answers

Answer:

A. I = V / R = 12 / 252 = .048 amps

V = I * R = .048 * 252 = 12 V

V is also the reading the voltage across the battery (12 Volts)

Two polarizing sheets have their transmission axes crossed so that no light is transmitted. A third sheet is inserted so that its transmission axis makes an angle with the transmission axis of the first sheet. (a) Derive an expression for the intensity of the transmitted light as a function of (b) Show that the intensity transmitted through all three sheets is maximum when\

Answers

Answer:

a)    I= I₀ (cos²θ - cos⁴θ)    b) 75.5º

Explanation:

a) For this exercise we must use Malus's law

         I = I₀ cos² θ

where tea is the angle between the two polarizers.

We apply this expression to our case

* Polarizer 1 suppose that it is vertical and polarizer 2 (intermediate) is at an angle θ with respect to the vertical

         I₁ = I₀ cos² θ

* We analyze for the polarity 2 and the last polarizer 3 which indicate that it must be at 90º from the first one, therefore it must be horizontal.

The angle of polarizers 2 and 3 is θ' measured from the horizontal, if we measure with respect to the vertical

              θ₂ = 90- θ’ = θ

fiate that in the exercise we must take a reference system and measure everything with respect to this system.

          I = I₁ cos² θ'

       

we substitute

         I = (I₀ cos² tea) cos² (θ - 90)

        cos (θ -90) = cos θ cos 90 + sin θ sin 90 = sin θ

         I = Io cos² θ sin² θ

        1= cos²θ+ sin²θ

       sin²θ = 1 - cos²θ

        I= I₀ (cos²θ - cos⁴θ)

b) to find when the intensity is maximum,

we can use that we have an extreme point when the drift is zero

          [tex]\frac{dI}{d \theta}[/tex] = 0

          \frac{dI}{d \theta}= Io (2 cos θ - 4 cos³θ) = 0

whereby

            cos θ - 2 cos³ θ = 0

            cos θ ( 1 - 2 cos² θ) = 0  

The zeros of this function are in

           θ = 90º

           1-2cos²θ =0       cos θ = 0.25  θ =  75.5º

Let's analyze this two results for the angle of 90º the intnesidd is zero with respect to the first polarizer, so it is not an acceptable solution.

Consequently, the angle that allows the maximum intensity to pass is 75.5º

what is the minimum effort required to raise the block?​

Answers

Answer:

2000 N.

Explanation:

From the question given above, the following data were obtained:

Load (L) = 8000 N

Mechanical advantage (MA) = 4

Effort (E) =?

The mechanical advantage of a machine is simply defined as:

Mechanical advantage = Load / Effort

MA = L / E

With the above formula, we can obtain the effort used to raise the load of 8000 N as follow:

Load (L) = 8000 N

Mechanical advantage (MA) = 4

Effort (E) =?

MA = L / E

4 = 8000 / E

Cross multiply

4 × E = 8000

Divide both side by 4

E = 8000 / 4

E = 2000 N

Thus, the effort used to raised the load is 2000 N.

Tarzan, whose mass is 103 kg, is hanging at rest from a tree limb. Then he lets go and falls to the ground. Just before he lets go, his center of mass is at a height 2.4 m above the ground and the bottom of his dangling feet are at a height 1.5 above the ground. When he first hits the ground he has dropped a distance 1.5, so his center of mass is (2.4 - 1.5) above the ground. Then his knees bend and he ends up at rest in a crouched position with his center of mass a height 0.3 above the ground.

Required:
Consider the real system. What is the net change in internal energy for Tarzan from just before his feet touch to the ground to when he is in the crouched position?

Answers

Answer:

   v₀ = 60.38 mi / h

With this stopping distance, the starting speed should have been 60.38 mi/h, which is much higher than the maximum speed allowed.

Explanation:

For this exercise let's start by using Newton's second law

Y axis

        N-W = 0

        N = W

X axis

         fr = m a

the expression for the friction force is

         fr = μ N

we substitute

        μ mg = m a

        μ g = a

calculate us

         a = 0.620  9.8

         a = 6.076 m / s²

now we can use the kinematics relations

          v² = v₀² - 2 a x

suppose v = 0

          v₀ = [tex]\sqrt{2ax}[/tex]Ra 2ax

let's calculate

         v₀ = [tex]\sqrt{2 \ 6076 \ 60}[/tex]

         v₀ = 27.00 m / s

let's slow down to the english system

          v₀ = 27.0 m / s (3.28 ft / 1m) (1 mile / 5280 ft) (3600s / 1h)

          v₀ = 60.38 mi / h

With this stopping distance, the starting speed should have been 60.38 mi/h, which is much higher than the maximum speed allowed.

A closed, rigid container holding 0.2 moles of a monatomic ideal gas is placed over a Bunsen burner and heated slowly, starting at a temperature of 300 K. The initial pressure of the ideal gas is atmospheric pressure, and the final pressure is four times the initial pressure.

Determine the following:
a. the change in the internal energy of the gas.
b. the work done by the gas.
c. the heat flow into or out of the gas.

Answers

Answer:

a) 2250 J

b) 0 J

c) 2250 J

Explanation:

a) Since, the process is isochoric

the change in internal energy

[tex]\Delta U = n C_v(T_f-T_i)[/tex]

Here, n = 0.2 moles

Cv = 12.5 J/mole.K

We have to find T_f so we can use gas equation as

[tex]\frac{P_1V_1}{P_2V_2} =\frac{T_i}{T_f}\\Since, V_1=V_2 [isochoric/process]\\\Rightarrow \frac{P_{atm}}{4P_{atm}} = \frac{300}{T_f} \\\Rightarrow T_f = 1200 K[/tex]

So,  [tex]\Delta U= 0.2\times12.5(1200-300)\\=2250 J[/tex]

b) Since, the process is isochoric no work shall be done.

c) By first law of thermodynamics we have

[tex]\Delta U = Q-W\\Since, W = 0\\\Delta U = Q\\Therefore, Q = 2250 J[/tex]

Since, Q is positive 2250 J of heat will flow into the system.

The net force experienced by an object is increased. What affect does this have on the acceleration of the object?

Answers

Answer:

The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

Explanation:

hope it helps pls give me brainless

which instrument fan be used to measure heat​

Answers

for sure thermometers and pryometers as I just learned and did some search ing. so these are. two classes of the heat measure measurement s! your welcomes!!

you can probably find out more of this and other stuff on here for more information scientificamerican

Definition of continental polar

Answers

cold, dry, and stable air masses .

Calculate the volume occupied by a glass cup having a mass of 260 g knowing that the
density of glass is equal to 2.6 g/cm3

Answers

Answer:

100 milliliters

Explanation:

Part C
What happens when you increase the frequency of the water drops? What happens to the wavelength of the waves ont
surface of water?

Answers

Answer:the wave lengths are shorter and faster

Explanation:

Plato

A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The smalldrive-wheel has a radius of 2.20 cm and accelerates at the rate of 8.00 rad/s2, and it is in contact with the pottery wheel (radius 28.0 cm). Both wheels move without slipping.The rubber drive wheel rotates in the clockwise sense.

Required:
a. Find the angular acceleration (both magnitude and direction) of the large pottery wheel.
b. Calculate the tune it takes the pottery wheel to reach its required speed of 60 rpm. if both wheels start from rest.

Answers

Answer:

[tex]0.629\ \text{rad/s}^2[/tex] counterclockwise

[tex]9.98\ \text{s}[/tex]

Explanation:

[tex]r_1[/tex] = Small drive wheel radius = 2.2 cm

[tex]\alpha_1[/tex] = Angular acceleration of the small drive wheel = [tex]8\ \text{rad/s}^2[/tex]

[tex]r_2[/tex] = Radius of pottery wheel = 28 cm

[tex]\alpha_2[/tex] = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

[tex]r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2[/tex]

The angular acceleration of the pottery wheel is [tex]0.629\ \text{rad/s}^2[/tex].

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

[tex]\omega_i[/tex] = Initial angular velocity = 0

[tex]\omega_f[/tex] = Final angular velocity = [tex]60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}[/tex]

t = Time taken

From the kinematic equations of linear motion we have

[tex]\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}[/tex]

The time it takes the pottery wheel to reach the required speed is [tex]9.98\ \text{s}[/tex]

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