The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.
Momentum transfered to the more massive cartThe momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the smaller cartu₁ is the initial velocity of the samller cartm₂ is the mass of the bigger cart = 3m₁u₂ is the initial velocity of the bigger cartv₁ is the final velocity of the smaller cartv₂ is the final veocity of the bigger cart⁻ΔP₁ = ΔP₂
ΔP₂ = m₂v₂ - m₂u₂
ΔP₂ = m₂(v₂ - u₂)
ΔP₂ = 3m₁(v₂ - u₂)
ΔP₂ = 3 x 3.8 x (1.7 - 0)
ΔP₂ = 19.38 kgm/s
Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.
The complete question is beblow
A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.
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static frictional Force
Answer:
The static frictional force is the force between the magnetic forces statically and contains only two objects during this physical reaction. It results in electricity and a slight shock.
Which of the following is an example of the characteristic of excretion?
A) We shiver when we get cold.
B) Moss on the side of the tree is active even though it looks still.
C) Human kidneys produce urine.
D) A rabbit gets nutrients from a carrot.
Answer:
C
because urine is waste product
An elastic string of length 20cm stretch by 7mm under a load 50N . The strain in the spring is?
Answer:
0.035
Explanation:
7÷1000
=0.007m
0.007/0.2
=0.035
Mechanical strain of an elastic substance is the ratio of its change in length to the original length. The strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.
What is strain ?Strain is a physical quantity used to express the change in dimension of an elastic material. It is the ratio of change in length to the original length. Stress is the force that causing the deformation.
According to Hook's law of elasticity, the strain is directly proportional to the strain. They show a linear relation. Let L be the original length of a string and its change in length be ΔL.
Thus, strain = ΔL / L
Given that, the change in length = 7 mm = 0.7 cm
original length of the string = 20 cm
strain = 0.7 cm/ 20 cm
= 0.035
Therefore, the strain of the elastic string of length 20 cm when stretched by 7 mm is 0.035.
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The electric potential, which is a scalar field, may be represented graphically by equipotential curves. The lines of electric field may be obtained from those equipotentials.
Four rectangles have been placed on the graph below. Assess the region of the graph where the magnitude of the electric field is greatest. Drag the label Emax to the rectangle in that region. Assess the region of the graph where the magnitude of the electric field is smallest. Drag the label Emin to the rectangle in that region.
The region with high electric potential (80 V and 70 V) will have high electric field while the region with low electric potential (20 V) will have low electric field.
What is Electric field?
Electric field is the field that surrounds electrically charged particles and exerts force on all other charged particles in the field.
Relationship between electric potential and electric fieldE = V/d
where;
V is electric potential (V)E is electric field (V/m)d is the distance (m)Since electric field is directly proportional to electric potential, the region with high electric potential (80 V and 70 V) will have high electric field while the region with low electric potential (20 V) will have low electric field.
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2. Which of the diagrams shows the least gravitational force between the two objects?
a. I
b. II
c. III
d. IV
Which of the diagrams shows the least gravitational force between the two objects?
Options :-a. I
b. II
c. III
d. IV
Answer :- Option D . IV Explanation :- Gravitational force directly proportional to both the masses and in 4th and 3th case we have least mass of 2 on both side which is less than 10 in 2 cases Gravitational force is inversely proportional to square of the distance between the masses and in case 1st and 4th we have more distance than in 2nd and 3th . we know larger the distance lesser will be the forceFrom above observation we can conclude that gravitational force is least in 4th case because we have less mass on both side and we have more distance between the 2 masses that others with same mass .
An unbalanced force acting on an object results in ______.
A. inertia
B. friction
C. acceleration
D. faster
E. slower
Answer:
friction
Explanation:
what property of light is suggested by the formation of shadows
Answer:
The reflection and rectilinear propagation of light helps in the formation of shadows and also tells light doesn't penetrate opaque materials.
Which number represents runoff on the hydrologic cycle diagram?
1
2
3
4
Answer:
number 3
Explanation:
3 represents runoff
Runoff is the water collected after rainfall that drains from the surface area of land. It will be tricky to choose 4 which is likely a smaller waterbody draining to a bigger waterbody
hope it helped
What is the relationship between latent heat and the hydrogen bonds which hold the molecules together?
Answer:
The molecules form strong hydrogen bonds, and water has a correspondingly high latent heat of vaporization. When no strong bonds are present, heating a liquid can easily free the molecules to form a gas, and the latent heat of vaporization is low.
Explanation:
Alex (31kg) and Cassie (19Kg) sit on a 10kg metre-long see-saw at the local park. The pivot of the see-saw is in the middle of its length. If Cassie sits at one end of the see-saw, where relative to the other end must Alex sit so the net torque is balanced? (unit:metres)
Answer:
M1 g L1 = 19 kg * 9.8 m/s^2 * 5 m = counter clockwise torque - Cassie at left end
M1 g L1 = M2 g L2 for torques to balance
L2 = M1 L1 / M2 = 19 * 5 / 31 = 3.06 M
Alex should sit at 3.1 m from the fulcrum (at 5 m from each end)
Three identical 6.67-kg masses hang at rest from three identical springs, numbered as in the figure. Each spring has an unstretched length of 0.23 m and a spring constant of 8.13 kN/m. How long, L , is spring 2?
[Hint: Draw some FBDs and apply Newton's second law. Remember to account for both the spring's stretch and its unstretched length.]
The length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
Extension of the spring 2
The extension of the spring 2 is determined from the net force acting on spring 2.
F(net) = Kx
Net force on spring 2 = sum of forces acting downwards - sum of forces acting upwards.
Net force on spring 2 = (force on 2 + force on 3) - (force on 1)
F(net) = (m₂ + m₃)g - (m₁)g
F(net) = (6.67 + 6.67)9.8 - (6.67)9.8
F(net) = 130.732 - 65.366
F(net) = 65.366 N
x = F/k
x = (65.366)/(8130)
x = 0.00804 m
The length of spring 2 = x + 0.23 m
= 0.00804 m + 0.23 m = 0.238 m
Thus, the length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.
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Which statement correctly describes the relationship between frequency and wavelength?
A :As the frequency of a wave increases, the longer its wavelength is
B: As the frequency of a wave increases, the shorter its wavelength is.
C: As the frequency of a wave increases, its wavelength remains the same.
Answer:
It is B
Explanation:
Option B talks about how the frequency of the wave increases the shorter it's wavelengths
Answer:
It's b
Explanation:
A curve is banked at an angle of 29.1 degrees above the horizontal and the road surface has a coefficient of static friction of 0.4. What must the radius of curvature be for the safe minimum speed of 27.1 m/s?
Hi there!
We can begin by summing the forces acting on the car.
Along the axis of the incline, the forces of friction and gravity are working. The force of friction points towards the top of the ramp, while the force of gravity works towards the bottom.
We can use trigonometry to determine the force due to gravity along the ramp.
[tex]F_g = Mg sin\theta[/tex]
The force due to friction is equal to:
[tex]F_f = \mu N[/tex]
The normal force is the vertical component of the force due to gravity, so:
[tex]F_f = \mu Mgcos\theta[/tex]
Now, the combination of these two forces produces a component of the centripetal force. Drawing a diagram, we see that the true centripetal force is the HYPOTENUSE, while these forces sum up to its horizontal component along the ramp.
Therefore:
[tex]F_c sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]
The centripetal force is equivalent to:
[tex]F_c = \frac{Mv^2}{r}[/tex]
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Rewrite:
[tex]\frac{Mv^2}{r}sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]
Cancel out 'M'.
[tex]\frac{v^2}{r}sin\theta = gsin\theta - \mu gcos\theta[/tex]
Rearrange to solve for 'r'.
[tex]r = \frac{v^2sin\theta}{gsin\theta - \mu gcos\theta}[/tex]
Plug in values and solve.
[tex]r = \frac{(27.1^2)sin(29.1)}{(9.8)sin(29.1) - 0.4(9.8)cos(29.1)} = \boxed{266.365 m}[/tex]
What are the three symbols used in Ohm's law. Explain what each symbol represents and give the units for each of the variables.
Answer:
Step by step explanation:
In question 8 from “Problems 2”, you calculated that an archery arrow shot with an initial velocity of 45 m/s at an angle of 10 degrees would travel 70.67 m (2 d.p.) before hitting a target at the same height from which it was released. If the archery target was moved further away from the archer, discuss some kinematic-based strategies that the archer could adopt to ensure that the arrow reaches the target. Ensure that the variables discussed are relevant to your answer. Assume air resistance is negligible.
The distance traveled by the arrow and horizontal velocity are directly proportional, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.
Time of motion of the projectileIf the horizontal distance the projectile would travel before hitting the target is 70.67 m, the time of motion of the projectile is calculated as;
X = Vx(t)
t = X/Vx
t = X/Vcosθ
t = (70.67) / (45 x cos10)
t = 1.6 s
When the archery target is moved further away from the archer, the archer needs increase the initial velocity of the arrow assuming the angle of projection is constant.
Since the distance and horizontal velocity are directly proportional to each other, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.
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You are standing on roller skates if you try to throw a 20-pound bowling ball while standing on skates,
what happens. How does this show Newton 3rd law
Answer:
I'd probably drop it on my toes. That would happen.
Explanation:
16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current drawn b) The quantity of electricity in Coulombs taken in 5 minutes c) The energy absorbed in 100 hours.
Answer:
If by 1.5 MJ you mean 1.5E6 Joules then
W = P t = power X time
W / t = P power
P = 1.5E6 J / 600 sec = 2500 J / s
P = I V
a) I = 2500 J/s / (240 J/c) = 10.4 C / sec = 10.4 amps
b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs
c) E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules
Who came up with the 3 Laws of Motion?
Answer:
Isaac Newton came up with the 3 Laws of Motion
Answer:
Isaac Newton came up with three laws of motion
Which of the following examples BEST describes the life characteristic of respiration?
A) A cheetah races across the plain.
B) Starfish cells divide and multiply as it gets larger.
C) Humans eliminate some wastes through urine and feces.
D) Humans breathe in oxygen and release carbon dioxide.
Answer:
D if I'm incorrect then sorry.
Explanation:
help me get a answer
Answer:
I think D sorry if I'm wrong
A horizontal push of 197 N is applied to a 49.1 kg crate to slide it along a level floor. The crate is accelerating at 3.337 m/s2 (speeding up). What is the magnitude of the kinetic friction force between the crate and the floor
The magnitude of the kinetic friction force between the crate and the floor is 33.15 N.
Kinetic frictional force
The magnitude of kinetic frictional force is determined by applying Newton's second law of motion as shown below;
F - Ff = ma
where;
Ff is kinetic frictional forcea is acceleration of the crateF is the applied forceSubsitute the given parameters and solve for kinectic frictional force
197 - Ff = 49.1(3.337)
197 - Ff = 163.85
Ff = 33.15 N
Thus, the magnitude of the kinetic friction force between the crate and the floor is 33.15 N.
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Need help with this question. Thirty points.
[tex]1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\[/tex]
[tex]4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J[/tex]
define capacitance of a capacitor and state its SIbunit
Answer: what I know that the unit is farad
Explanation:
The amount of energy released when 45 g of -175° C steam is cooled to 90° C is
A. 101,700 J
B. 317,781 J
C. 419,481 J
D. 417,600 J
Answer:
The answer should be choice B.
You want to improve your dominant trait score, and you decide to take daily walks by yourself. What trait will you strengthen with this activity?
Muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.
Which muscles get stronger due to walking?The quadriceps, hamstrings, the calf muscles and the hip adductors are the muscles which get stronger by doing walking because impact is produced on these muscles while walking. Walking is a good exercise which have many health benefits.
So we can conclude that muscles such as quadriceps, hamstrings, the calf muscles and the hip adductors get stronger by walking.
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Answer:
introversion is the correct answer
Explanation:
God bless! Have a great day!
What must be the charge of a particle having E = 81 N/C at 49 mm from the said particle? Express in Coulombs. Use k = 9.0 x 109 kg⋅m3⋅s−2⋅C−2
[tex]\text{Given that,}\\\\\text{Electric field strength,}~ E = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} = \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle is}~2.1609\times 10^{-11} ~C[/tex]
The resultant of two vectors is of magnitude 3 units and 4 units is 1 units, what is the value of their dot product?
Answer:
A dot B = C is the vector equation for this expression
A · B = A B cos θ
3 * 4 cos θ = 1 the value 1 is their dot product
cos θ = 1 / 12 = .083 θ = 85.2 deg
If something weighs 2891N on earth, what’s it’s mass?
Answer:
289.1kg
Explanation:
because W=M*G, and M=W/G, so 2891N/10m/s²=289.1kg
Which of the following would NOT cause acceleration?
A. an object falling towards the earth
B. the wind catching the sail of a sailboat
C. a car traveling at a constant velocity
D. a pitcher throwing a baseball
.
A
saloon car starting from rest will accelerates
to velocity of 48 km/h in 10 seconds. calculate
the
aceleration-
What’s the answer ?
Answer:
47
Explanation:
48km:1hr (10sec×60min=600hr)
¥ :600hr
1hr÷¥=1. 48×600÷1=2800
2800÷60=47
47 will be the acceleration
[tex]\text{Initial velocity,}~ u = 0 ~ ms^{-1}\\\\\text{Final velocity,}~ v = 48~kmh^{-1} = \dfrac{48\times 1000}{3600} ms^{-1} = 13.33 ms^{-1}\\ \\\text{Time,}~ t = 10~ sec\\\\\text{Acceleration,}~ a = \dfrac{v-u}{t} = \dfrac{13.33-0}{10} = \dfrac{13.33}{10} = 1.33 ~ ms^{-2}\\\\\text{Hence the acceleration of the car is}~ 1.33 ~ms^{-2}.[/tex]