How was the position of planet Uranus predicted?

Answer:

40.1 g

Explanation:

The balanced equation is:

First we convert 86.5 g of calcium chlorate into moles, using its molar mass:

Then we convert Ca(ClO₃)₂ moles into O₂ moles, using the stoichiometric coefficients of the balanced reaction:

Finally we convert O₂ moles into grams:

Answer:

Explanation:

your not so smart

Answer:

This question is a bit vague. We're not told if 500ml is the volume of the solution and additional info is not given to calculate the volume of pbNo3 being added.

If you solve with 500ml as the volume of solution ... You'll have the answer below.

Molarity=moles of solutes/Volume of solvent(in litres)

moles of solute given=1.565moles

Volume = 500ml. There's 1000ml to a litre. Dividing by 1000ml to convert to Litres... You have 0.5L

Molarity = 1.565/0.5

=3.13M

Answer:

Approximately [tex]1.95 \times 10^{2}\; \rm J[/tex].

Explanation:

Look up the specific heat of gaseous neon:

[tex]c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}[/tex].

Calculate the required temperature change:

[tex]\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K[/tex].

Let [tex]m[/tex] denote the mass of a sample of specific heat [tex]C[/tex]. Energy required to raise the temperature of this sample by [tex]\Delta T[/tex]:

[tex]Q = c \cdot m \cdot \Delta T[/tex].

For the neon gas in this question:

Calculate the energy associated with this temperature change:

[tex]\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}[/tex].

Answer:

Iron, according to:

[tex]2Al(s)+3Fe(NO_3)_2(aq)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq)[/tex]

Explanation:

Hi there!

In this case, according to the law of conservation of mass, which states that matter cannot be neither created nor destroyed, it is possible for us to figure out the missing element in the reaction by taking into account this is a single displacement reaction in which Al goes with NO3 to produce the Al(NO3)3, and therefore the other element would be iron (Fe) as can be seen on the following chemical reaction:

[tex]2Al(s)+3Fe(NO_3)_2(aq)\rightarrow 3Fe(s)+2Al(NO_3)_3(aq)[/tex]

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Answer:

1.84

Explanation: just input the value into the formula pv=nrt

p*30=2*0.08206*337 then divide both sides by 30 and  get 1.84

Answer:

pH = 2.25

Explanation:

pH is a measurement in chemistry defined as the -log [H₃O⁺]. Molarity [], is defined as the ratio between moles of solute (HCl) and the liters of solution

To solve this question we must find the molarity of the H₃O⁺ knowing: [HCl] = [H₃O⁺]

[HCl]:

0.0084moles / 1.500L

= 0.0056M = [HCl] = [H₃O⁺]

pH = -log [H₃O⁺] = -log [0.0056M]

A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a molar concentration of HCl of 5.6 × 10⁻³ M, a molar concentration of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.

A solution is prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution. The molarity of HCl is:

[tex][HCl] = \frac{0.0084mol}{1.5L} = 5.6 \times 10^{-3} M[/tex]

HCl is a strong acid according to the following equation.

HCl(aq) + H₂O(l) ⇒ Cl⁻(aq) + H₃O⁺(aq)

Thus, the concentration of H₃O⁺ will be equal to the initial concentration of HCl, 5.6 × 10⁻³ M.

Finally, we will calculate the pH of the solution using its definition.

[tex]pH = -log [H_3O^{+} ] = -log (5.6 \times 10^{-3} ) = 2.3[/tex]

A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a molar concentration of HCl of 5.6 × 10⁻³ M, a molar concentration of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.

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Answer:

78.14% Pb²⁺ and 21.86% of Cd²⁺

Explanation:

The first titration involves the reaction of both Pb²⁺ and Cd²⁺

In the second titration, as the buffer is HCN/NaCN, the Cd²⁺ precipitates as Cd(CN)₂ and the only ion that reacts is Pb²⁺

In the first titration:

Moles EDTA = Moles Pb²⁺ and Cd²⁺:

28.89mL = 0.02889L * (0.06950moles / L) = 2.008x10⁻³ moles in the aliquot. In the sample:

2.008x10⁻³ moles * (250.0mL / 50.0mL) =

0.01004 moles = Pb²⁺ + Cd²⁺ (1)

In the second titration:

19.07mL = 0.01907L * (0.06950mol / L) = 1.325x10⁻³ moles Pb²⁺ in the aliquot. In the sample:

1.325x10⁻³ moles Pb²⁺ * (250.0mL / 50.0mL) =

6.626x10⁻³ moles Pb²⁺

That means the moles of Cd²⁺ are:

0.01004 moles = Cd²⁺ + 6.626x10⁻³ moles Cd²⁺

3.413x10⁻³ moles Cd²⁺

The mass of each ion is:

Cd²⁺ -Molar mass: 112.411g/mol-:

3.413x10⁻³ moles Cd²⁺ * (112.411g / mol) =

0.384g of Cd²⁺

Pb²⁺ -Molar mass: 207.2g/mol-:

6.626x10⁻³ moles Pb²⁺ * (207.2g / mol) =

1.373g of Pb²⁺

The percent mass of each ion is:

1.373g Pb²⁺ / 1.757g = 78.14% Pb²⁺

And:

0.384g of Cd²⁺ / 1.757g * 100 = 21.86% of Cd²⁺

Answer:  4 atoms is the answer. I hope it helped you.

Explanation:

Answer:

It's B

Explanation:

It's the sun's gravitational pull that keeps our planets revolving around it and as soon as it's gone it's a high chance of it being a pinball machine and everything colliding into each other.

Answer:

See explanation

Explanation:

Recall that from Boyle's law;

Volume is inversely proportional to pressure at constant temperature

V α 1/P

V = k/P

k = PV

Hence, for Boyle's law, PV = constant

In the first case;

P = 2.0 atm , V= 110 L

PV = 110 * 2.0 = 220

In the second case;

P = 4.0 atm , V= 5.5 L

PV = 4.0 * 5.5 = 22

Since PV is not constant in both cases, the gas does not obey Boyle's law.

Answer:

my guy we need to read lesson cuz int know what any of that mean

Explanation:

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Answer: True

I hope this helped!

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Answer:

true

Explanation:

Explanation:

21.0 g of potassium reacts with 62.5 g of barium nitride, what mass of potassium nitride will be produced

Answer:

a means of work

Explanation:

since its near oceans they are closer to the fish

Explanation:

I think it is the first option

Answer:

1) They expand to completely fill their container.   :)

Explanation:

Answer:

[tex]f=4.47\times 10^{14}\ Hz[/tex]

Explanation:

Given that,

The wavelength of light, [tex]\lambda=670\ nm=670\times 10^{-9}\ m[/tex]

We need to find the frequency of the light. The relation between the frequency and wavelength is given by :

[tex]v=f\lambda[/tex]

The speed of light is equal to c.

So,

[tex]f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{670\times 10^{-9}}\\\\f=4.47\times 10^{14}\ Hz[/tex]

So, the frequency of light is equal to [tex]4.47\times 10^{14}\ Hz[/tex].

Answer: Food chain

Explanation: none

Answer:

c

Explanation:

Answer:

The solution is Basic

Answer:

True

Explanation:

As a result, when a substance absorbs enough energy then its atoms or molecules move around. And, when increase in this energy takes place then atoms tend to collide frequently with each other. Hence, it causes change in state of a substance. Therefore, changes in matter are important for the conservation of energy

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Answer:

b) The total moles of each element present in the reactants and in the products.

Explanation:

Hello there!

In this case, since the law of conservation of mass is used to realize that the mass, atoms and molecules of all the species involved in a chemical reaction must be the same at both reactants and products, we can see that a and c stand for those that must be equal; thus, we infer that the moles can be different as they stand for the amount of substance which is related to the mass via molar masses. Therefore, the answer would be b) The total moles of each element present in the reactants and in the products.

Regards!

Answer:

Density differences

Explanation:

The water transports cool masses of air and hot air, the transports is driven by the amount of changes of Temperature and Salinity (ThermoHaline)

Answer:

The Coriolis effect

Explanation:

The Coriolis effect is the effect that makes tornados, water spouts, and are often seen in storms. They make water curve and rotate as well as the wind And current.

Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature (T₂-T₁). The specific heat of water is 4.184 J/g °C. We are given the mass of water (m = 18.3 g), the final temperature (T₂ = 49.32 °C), and the initial temperature (T₁ = 11.88 °C). The change in temperature, ΔT, equals 49.32 °C - 11.88 °C = 37.44 °C. With all these values at hand, we can solve for the amount of energy needed, Q:

Q = (18.3 g)(4.184 J/g °C)(37.44 °C) = 2866.7 J ≈ 2870 J (three sig figs).