A particle is launched at an angle of 37° from horizontal. If the horizontal velocity component is 7.65 meters/second, what is the resultant velocity of the particle?
Answer:
R = 9.58 m/s
Explanation:
cos(37) = (7.65 m/s)/R
R = (7.65 m/s)/cos(37)
R = 9.58 m/s