But on an orbital sense, the gravitational force between two objects depends on the mass of both the larger and the smaller object. ... The pull between Earth and Sun grows weaker, and the planets would drift farther from the Sun, spending much more time at much greater distances from the Sun.
2. If you are sitting on the passenger side of a car driving down the
highway, name a frame of reference that indicates you are NOT moving?
Answer:
The building are not getting farther and farther away, road signs, exits, other cars
Explanation:
A satellite orbits earth at constant speed in circular orbit.Which statement is correct? A The resultant force on the satellite is zero. B The resultant force on the satellite is towards the Earth. C The resultant force on the satellite is away from the Earth. D The resultant force on the satellite is in the direction of motion.
Answer:
B The resultant force on the satellite is towards the Earth.
Explanation:
In the case when the satellite orbits earth would be at constant speed in the circular orbit so hee the resultant force that on the satellite would be with regard to the earth
So as per the given situation, the option B is correct
And, the rest of the options would be wrong
And, the same would be relevant
A fruit basket of mass 44.5 kg weighs approximately how much in newton? (Answer should have a number and a proper unit) *
Answer:
445N
Explanation:
F=mg
m=44.5kg
g=10m/s2
F=44.5 * 10
=445N
A dentist uses a small concave mirror to locate a cavity in a patient's tooth. The focal length of the mirror is 2.00 cm. If the mirror is held 1.60 cm from the tooth, how many times bigger will the image be? (In other words, what is the magnification?)
Answer:
m = 4.0
Explanation:
For this exercise in geometric optics we will use the equation of the constructor
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
where f is the focal length, p and q are the distance to the object and image, respectively.
In the exercise indicate the focal length f = 2.00 cm, the distance to the object p = 1.60 cm, let's find the distance to the image
[tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p}[/tex]
let's calculate
[tex]\frac{1}{q} = \frac{1}{2} - \frac{1}{1.6}[/tex]1 / q = ½ - 1 / 1.6
[tex]\frac{1}{q}[/tex] = -0.125
q = -8 cm
the magnification is
m = - q / p
m = 8/2
m = 4.0
Un atleta tiene en un instante dado una velocidad de 4 m/s. Si a partir de ese instante y durante 2 s adquiere un MRUA con una aceleración de 3 m/s2. Calcula la velocidad que alcanza al cabo de esos 2 s.
Answer:
Velocidad final, V = 8 m/s
Explanation:
Dados los siguientes datos;
Velocidad inicial, u = 4 m/s
Aceleración, a = 2 m/s²
Tiempo, t = 2 segundos
Para encontrar la velocidad final (v), usaríamos la primera ecuación de movimiento;
V = u + at
Sustituyendo en la fórmula, tenemos;
V = 4 + 2*2
V = 4 + 4
Velocidad final, V = 8 m/s
A race car has a mass of 710kg. It starts from rest and speeds up to 12m/s in 12.0s. The car is uniformly accelerated during the entire time. What net force is applied to it?
Calculate the pressure exerted on the ground by a boy of a mass 60 kg if he stands on one foot.the area of the sole of his shoe is 150cm²
Answer:
40 Kpa
Explanation:
150 cm2 = 0.015 m2
[tex]p \: = \frac{mg}{ a} = 40000[/tex]
Calculate the first and second velocities of the car with three washers attached to the pulley, using the formulas
v1 = 0.25 m / t1, and
v2 = 0.25 m / (t2 – t1)
where t1 and t2 are the average times the car took to reach the 0.25 and the 0.50 meter marks. Record these velocities, to two decimal places, in Table E.
What is the first velocity of the car with three washers at the 0.25 meter mark?
m/s
What is the second velocity of the car with three washers at the 0.50 meter mark?
m/s
Answer:
0.19 and 0.45
Explanation:
edge
The first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.
What is velocity?The velocity of an object is defined as the product of the distance travelled in a given direction and the time required to travel that distance. The velocity is expressed mathematically as,
v = d/t
Here, d represents the travelled distance.
And t is the typical amount of time needed to go the distance.
Given,
The value of the first distance is, d1 = 0.25 m.
The value of the second distance is, d2 = 0.50 m.
Then the first velocity of the car at 0.25 m is,
[tex]v_1 = d_1/t_1\\v_1 = 0.25 / t_1[/tex]
Thus,[tex]t_1[/tex] denotes the first distance's typical time.
The second velocity of the car with three washers at the 0. 50 m mark is
[tex]v_2 = d_2/t_2\\v_2 = 0.50 /t_2[/tex]
Here, [tex]t_2[/tex] stands for the second distance's typical time.
Thus, the first and second velocities of the car are [tex]0.25/t_1[/tex] and [tex]0.50/t_2[/tex]respectively.
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PLEASEEEE HELP
Blue light of wavelength 435 nm
enters diamond (n = 2.42). What
is the wavelength of the light in
diamond?
(Unit = nm)
Answer:
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Explanation:
Given:
Blue light of wavelength λ1 = 435 nm
n2 in diamond = 2.42
Find:
Wavelength of light in diamond λ2
Computation:
Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.
So,
n1λ1 = n2λ2
(1)(435) = (2.42)λ2
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Answer:
180
Explanation:
got it right on acellus
If you walk for 1.5 hours at an average speed of 4 miles/hr. How far will you have walked?
Can you describe how and why the molecules move from one side to the other?
The molecules move from one side to another across the concentration gradient by breaking weaker bonds among the atom into stronger bonds. This is done to decrease the overall kinetic energy to become a more stable molecule.
The kinetic strength of the molecules consequences in random movement, causing diffusion. In simple diffusion, this method proceeds without the useful resource of a transport protein. it is the random motion of the molecules that reasons them to move from a place of excessive attention to a place with decreased awareness.
The molecules in a gas, a liquid, or a strong are in consistent movement due to their kinetic electricity. Molecules are in steady movement and collide with each different. those collisions cause the molecules to move in random guidelines. over time, however, greater molecules may be propelled into the less concentrated place.
The majority of the molecules flow from better to decrease awareness, although there can be some that circulate from low to excessive. the general (or net) motion is consequently from high to low concentration.
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Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?
A. Elements with intermediate numbers of valence electrons are the last chemically stable.
B. Elements with the highest number of valence electrons are the most chemically stable.
C. Elements with intermediate number of valence electrons are the most chemically stable.
D. Elements wit the lowest number of valence electrons are the most chemically stable.
Answer:
C. Elements with intermediate number of valence electrons are the most chemically stable.
what type of beetle is this?
HOW TO ANSWER THIS QUESTION PLEASE
Answer:
radioactive decay is a random processuse long tongsExplanation:
Quantum theory has taught us that virtually everything to do with the nature of matter in the universe is a random process. The decay of atomic nuclei is something that makes that randomness "visible" with appropriate instrumentation. As such, the rate of decay will vary over the "short" term. Consequently, it is not surprising to see a variation of a few counts in an activity measurement over a period of a few minutes.
__
Safety with respect to radioactive materials involves staying as far away from them as possible. The use of long tongs for handling would be appropriate.
Answer:
Radioactive decay is a long proxyUse long tongs↔ for safety precautions the scientist should used this upon working with radioactive materials in a laboratory.