Answer:
to see how much you are getting of something
Explanation:
Answer:
I would use it to track everything nutrition wise.
Explanation:
I would use it to track everything nutrition wise. Meaning that if I do anything that is in the process of eating or consuming food, I would log it down. A good example of what goes in a dietary log would be how much you ate, the amount of calories you ate, and occasionally the amount of serving you ate based off the recommended serving size. It should be important to keep a fitness log if you are interested in keeping a diet diary; to further track calories!
Hope this helps <3
A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
GIVING THE REST OF MY POINTS!
Energy can be:
A. destroyed or converted to another form.
B. destroyed.
C. created, but never destroyed.
D. converted to another form.
emotional symptoms that may occur in those with a schizophrenic Disorder generally include all of the following except ______ emotion.
A. Flat
B. Appropriate
C. No
D. Inappropriate
Answer:
B
Explanation:
edge 2020
The emotional symptoms that may occur in those with a Schizophrenic disorder generally include all of the following except appropriate emotion. Hence, option (B) is correct.
What is schizophrenic disorder?Schizophrenia is a persistent, severe mental illness that has an impact on a person's relationships with others as well as their thinking, acting, and emotional expression. Despite not being as prevalent as other severe mental illnesses, schizophrenia can be the most persistent and incapacitating.
Schizophrenia patients frequently struggle to function well in relationships, the workplace, and academic settings. They can appear to have lost their sense of reality, feel afraid and withdraw. This chronic illness cannot be cured, but it can be managed with the right care.
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Al inicio de un paseo recorrerá una distancia de 200 km/h, los primeros 120 km lo hará a una velocidad constante de 60 km/h y el resto a una velocidad constante de 90 km/h,¿Cuánto tiempo en horas total durará el viaje?
Responder:
1 hora 20 min
Explicación:
Paso uno:
datos dados
Durante los primeros 120 km, se nos dice que la velocidad es de 60 km / h.
sabemos que velocidad = distancia / tiempo
por lo tanto, distancia = velocidad * tiempo
deja que el tiempo sea ty la velocidad sea s
distancia = s * t
distancia = 60t -------------------- 1
Segundo paso:
Durante los segundos 80 km, se nos dice que la velocidad es de 90 km / h.
sabemos que velocidad = distancia / tiempo
por lo tanto, distancia = velocidad * tiempo
deja que el tiempo sea ty la velocidad sea s
distancia = s * t
desatancia = 90t ------------------- 2
La distancia total recorrida es de 200 km.
entonces 200 = 60t + 90t
200 = 150t
t = 200/150
t = 1,3 horas
Por lo tanto, el viaje tendrá una duración de 1 hora y 20 minutos aproximadamente.
EARTH SPACE SCIENCE.
I NEED HELP ASAP DUE TODAY. PLEASE 20 POINTS
Using the topographic map above, match the description to the letter that it represents.
Highest point on the map-
[ Select ]
Stream flowing to the East-
[ Select ]
Letter near the steepest slope-
[ Select ]
Letter near the flattest area-
[ Select ]
Stream flowing to the North- F
Answer:
c,e,f,d
Explanation:
A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
Answer:
Mass, m = 71.42 kg
Explanation:
Given that,
Normal force acting on a box, F = 700 N
We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,
F = mg
Where m is the mass of the box
[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]
So, the mass of the box is 71.42 kg.
W1 has a weight of 220 N acting 0.6m away from the pivot.
How far does W2 whose weight is 180 N need to sit for the see
saw to be in equilibrium.
&
?
W-220 N
W2 - 180N
a) 0.3 m
Ob) 0.73 m
C) 0.5m
O d) 0.83 m
Answer:
0.73m
Explanation:
Given parameters:
W1 = 220N
D1 = 0.6m
W2 = 180N
Unknown
D2 = ?
Solution:
The torque on each side must be balanced;
Torque = force x distance
T₁ = T₂
W1 x D1 = W2 x D2
Insert the parameters and solve for D2;
220 x 0.6 = 180 x D2
132 = 180D2
D2 = [tex]\frac{132}{180}[/tex] = 0.73m
write an essay on the great wall of china
Due to the friction between a tire and the road surface, the temperature of the air inside a tire increases as one drives. If the tire pressure is 37 psi when the car is in the driveway at 25° C, What is the pressure of the tire when the temperature increases to 50° C?
Answer:
40.10 atm .
Explanation:
Here volume of tire is assumed to be nearly constant .
Modified gas law ,
P₁ / T₁ = P₂ / T₂
37 / ( 273 + 25 ) = P₂ / ( 273 + 50)
37 / 298 = P₂ / 323
P₂ = 37 x 323 / 298
= 40.10 atm .
HELP NEEDED ASAP I'M GIVING BRAINLIEST
1) Select the best answer from the choices below. Light has many properties of waves, but sometimes it also behaves like:
a
A photon
b
Polarized light
c
Ultraviolet rays
d
A stream of particles
2) What type of waves transmit signals in satellite communication?
a
Microwaves
b
X-rays
c
Gamma Rays
d
Radio Waves
3) Cell phones use digital signals to send and receive information. These digital signals travel as what kind of wave?
a
Gamma rays
b
X-rays
c
Microwaves
d
Radio waves
Answer:
1.
d . A stream of particles
2. D. Radiowave
3. Microwaves
Answer:
1.
d . A stream of particles
2. D. Radiowave
3. Microwaves
Explanation:
PLEASE HELP ME QUICKLY!!!!!!!!!!!!!!
Answer:
I think thats the correct answer
Explanation:
Please help with this!
On the way down the ball's velocity is Positive 9.8.
Option A) is the correct answer.
What is velocity:?
This refers to the speed at which an object moves in a given direction. It unit is meters per secocond, m/s.
What is acceleration?
This is the rate of change of velocity with respect to time. The speed and direction of the accelerating object are also very important. It unit is meters per second square, m/s².
What is Gravity?
This is the force that pulls a body toward the center of the earth. This force causes objects to fall freely. This free-falling object has an acceleration of 9.8m/s downward the earth. This is called acceleration gravity.
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A 58-kg boy swings a baseball bat, which causes a 0.140-kg baseball to move toward 3rd base with a velocity of 38.0 m/s.
Calculate the kinetic energy of the baseball (rounding your answer to the integer).
Answer:
101 J
Explanation:
Answer:
[tex]\boxed {\boxed {\sf 101 \ Joules}}[/tex]
Explanation:
Kinetic energy can be found using the following formula:
[tex]KE=\frac{1}{2}mv^2[/tex]
The mass of the baseball is 0.140 kilograms and the velocity is 38.0 meters per second.
[tex]m= 0.140 \ kg \\v= 38.0 \ m/s[/tex]
Substitute the values into the formula.
[tex]KE=\frac{1}{2} [0.140 \ kg][(38.0 \ m/s)^2][/tex]
First, evaluate the exponent.
(38.0 m/s)²= 38.0 m/s * 38.0 m/s = 1444 m²/s²[tex]KE=\frac{1}{2}(0.140 \ kg)(1444 \ m^2/s^2)[/tex]
Multiply the two numbers in parentheses together.
[tex]KE=\frac{1}{2}(202.16 \ kg*m^2/s^2)[/tex]
Multiply the fraction by the number, or divide the number by 2.
[tex]KE=101.08 \ kg*m^2/s^2[/tex]
Round to the nearest whole number. The 0 in the tenth place tells us we can leave the number as is.
[tex]KE\approx 101 \ kg*m^2/s^2[/tex]
1 kg*m²/s² is equal to 1 Joule. Therefore, our answer of 101 kg*m²/s² is equal to 101 Joules (J).
[tex]KE\approx 101 \ J[/tex]
The kinetic energy of the baseball is about 101 Joules.
Disponemos de datos de presión y volumen de tres situaciones de un gas ideal que se han medido manteniendo la temperatura del gas constante representa los valores de un gráfico p-v expresa matemáticamente la ley de Boyle-Mariotte y calcula el valor de la constante
Answer:
Explanation:
This is an exercise in thermodynamics, the ideal gas equation is
PV = n R T
In this case the temperature is constant, so
n R T = cte
throughout the experiment
We can write the relationship for the three points 1, 2 and 3
P₁ V₁ = P₂ V₂ = P₃ V₃ = cte
In the attached graph we can see a graph of this relationship
the data for this graph are
V(m³) P ( Pa)
V₀ P₀
V₀/2 2 P₀
V₀/4 4 P₀
for the graph, let it be assumed that V₀ = 1 and P₀ = 1
To calculate the value of the constant s, you must know the moles of gas and the temperature at which the experiment is carried out, for example, if we have a mole of gas and room temperature (T = 300K), the constant is
n R T = 1 8,314 300
n R T = 2492.2 J
An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.
Answer:
Resultant force = [tex]\sqrt{91}[/tex]N
Explanation:
Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]
Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]
Rf = [tex]\sqrt{36+25+30}[/tex]
Rf = [tex]\sqrt{91}[/tex]
doesn't look right though...
The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given parameters:
Two forces are 6 N and 5N.
Angle between them is 60 degree.
So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N = = 9.54 N.
Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°) } = 33⁰.
Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
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A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum height reached by the ball?
Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]
Therefore, the maximum height reached by the ball is 2.84 m
The components of a 15-meters-per-second velocity at an angle of 60.° above the horizontal are (1) 7.5 m/s vertical and 13 m/s horizontal (2) 13 m/s vertical and 7.5 m/s horizontal (3) 6.0 m/s vertical and 9.0 m/s horizontal (4) 9.0 m/s vertical and 6.0 m/s horizontal
Answer:
13 m/s vertical and 7.5 m/s horizontal
Explanation:
❤️
The vertical and horizontal components of a projectile is required.
The correct option is (2) 13 m/s vertical and 7.5 m/s horizontal
u = Initial velocity of projectile = 15 m/s
[tex]\theta[/tex] = Angle of projectile = [tex]60^{\circ}[/tex]
The horizontal component
[tex]u_x=u\cos \theta\\\Rightarrow u_x=15\cos60^{\circ}\\\Rightarrow u_x=7.5\ \text{m/s}[/tex]
The vertical component
[tex]u_y=u\sin \theta\\\Rightarrow u_x=15\sin60^{\circ}\\\Rightarrow u_x=13\ \text{m/s}[/tex]
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A horse gallops for 3.5 minutes around the raceing track. During this time it changes velocity from 543 min to 628 min. Calculate the acceleration of the horse during this 3.5min interval
Answer:
The acceleration of the horse during this time interval is 24.286 m/min²
Explanation:
Given;
initial velocity of the horse during the gallop, u = 543 m /min
final velocity of the horse during the gallop, v = 628 m /min
time of motion, t = 3.5 minutes
The acceleration of the horse is given by the change in velocity per change in time;
[tex]a = \frac{v-u}{t}\\\\a = \frac{628-543}{3.5}\\\\a = 24.286 \ m/min^2[/tex]
Therefore, the acceleration of the horse during this time interval is 24.286 m/min²
do you think it’s likely that there are other earth-like planets in our universe?
Answer:
yes it's a matter of probability
Answer:
Absolutely!
Explanation:
Its almost impossible that we are the only goldilocks planet when there are billions of stars, each of them being suns with planets. Some other planet somewhere must be able to support life, don't you think?
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance travelled by the truck during this?
Answer:
82.7 m
Explanation:
u= 22m/s
a= 2.4 m/s^2.
t= 3.2 secs
Therefore the distance travelled can be calculated as follows
S= ut + 1/2at^2
= 22 × 3.2 + 1/2 × 2.4 × 3.2^2
= 70.4 + 1/2×24.58
= 70.4 + 12.29
= 82.7 m
Hence the distance travelled by the truck is 82.7 m
Which two fundamental forces are only attractive?
O A. Gravitational and strong nuclear
O B. Electromagnetic and weak nuclear
O C. Electromagnetic and strong nuclear
O D. Gravitational and weak nuclear
The two fundamental forces that are only attractive is A. Gravitational and strong nuclear.
What connection exists between the strong nuclear force and gravity?The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.
Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.
Therefore, option A is correct.
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A ball weighing 60 N is swinging like a pendulum at the end of a 6.0 m rope. As the
ball swings through its lowest point, its speed is measured at 5.0 m/s. What is the
tension in the rope at this point?
Answer:
Tension = 60 N
Explanation:
The ball is executing a motion like a pendulum. The lowest point of a pendulum's motion is the mean position, where its potential energy becomes zero and kinetic energy becomes maximum. At this point the rope becomes straight vertical. Hence, the tension in the rope becomes exactly equal to the weight of the object at the lowest point. Also, in this case when the ball swings through the lowest point during its motion like a pendulum, the tension in the rope will become equal to the weight of the ball.
Tension = Weight
Tension = 60 N
A stone is thrown at an angle of 34.0° above the horizontal from the top edge of a cliff with an initial speed of 18.3 m/s. A stopwatch measures the stone's trajectory time from the top of the cliff to the bottom at 2.6 s. What is the height of the cliff?
Answer:
Explanation:
Using the formula for calculating the maximum height in projectile
H = u²sin²theta/2g
u is the initial velocity = 18.3m/s
g is the acceleration due to gravity = 9.8m/s²
theta = 34°
Substitute
H = u²sin²theta/2g
H = 18.3²(sin34)²/2(9.8)
H = 334.89(0.5592)²/19.62
H = 5.337m
Hence the height of the cliff is 5.337m
Please help I will give brainliest
Answer:
ask questions that the findings bring up
Explanation:
hope this helps :)
Answer:
ask questions that the findings bring up
Choose the best real world exzample of convection:
A. clouds forming in the atmosphere
B. touching a warm cooking pot handle
C. sitting in front of a warm fireplace
WHICH ONE IS THE ANSWER HELP PLESEEE
Why does a liquid thermometer work
who songs are better jason derulo or Dababy , roddy ricch
Answer:
roddy i guess?
Explanation:
Answer:
Dababy and Roddy Ricch. Jason's songs use to be fire years back but now....not so much.
Explanation:
Which of the following is a FALSE statement? (A) Heat moves through solids by conduction (B) Molecules move faster in warmer substances (C) Warm water is denser than cold water (D) Heat moves through liquids and gases by convection
Answer:
C.
Explanation:
Un vagón de carga de 5000-kg se mueve a 2m/s e impacta a un vagón de 10000-kg que se encuentra en reposo. Después de la colisión inelástica a que rapidez se mueven.
Answer:
0.67 m/s
Explanation:
Mass of car 1, m₁ = 5000 kg
Mass of car 2, m₂ = 10,000 kg
Initial speed of car 1, u₁ = 2 m/s
Final speed of car 2, u₂ = 0 (at rest)
We need to find the final velocity of both cars when inelastic collision occurs. The momentum will remain conserved in case of inelastic collision. Using the conservation of momentum. Let V is the final speed.
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{m_1u_1}{(m_1+m_2)}\\\\V=\dfrac{5000\times 2}{(5000+10000)}\\\\V=0.67\ m/s[/tex]
So, after the inelastic collision, they will move with a speed of 0.67 m/s.
DO boys cheat more than girls?
Answer:
I'm not sure.
Explanation:
Look up the statistics
Answer: honestly girls cheat more than guys, its statically proven that females cheat more than guys its because they dont believe in value in a relationship
Explanation: