How/what do I answer this?--> "heat of the chemical reactions"
like this is the question :/

Answer:

A) Chocolate Milk

Explanation:

A homogeneous mixture is one that is made of one substance. Technically, none of these are, but chocolate milk would be the closest. Pizza has cheese, pepperoni, and crust. Chocolate chip cookies have chips and the cookie. Peanut butter sandwiches have peanut butter and bread. Therefore, chocolate milk is right, as it has no other parts.

Answer:

25.42 grams

Explanation:

The specific heat of water is 4.18 J/g •°C, so that means that it takes 4.18 joules of energy to raise one gram of water 1 °C.

Change in temp = 55 - 15 = 40°C

So we can calculate how much energy it would take to raise the temp of one gram of water by one degree using the following

(4.18 J/g•°C) * (40°C) * (1 gram) = 167.2 J

So if it takes 167.2 J of energy to raise on gram of water 40°C, we now we can calculate the amount of grams of water that can heated with 4250 J of energy

(4250 J) ÷ (167.2 J) = 25.42 grams of water can be heated from 15°C to 55°C

Answer:

They are considered nonrenewable because they are prehistoric animals that has been extinct therefore can't be renew.

Answer:

d- The resulting pH will be equal to 7 because a strong base will neutralize a strong acid.

Explanation:

The reaction between potassium hydroxide and hydrochloric acid of equal volume and equal concentration yields a solution of pH 7 at equivalence point. We must note that KOH is a strong base while HCl is a strong acid. This fact influences the pH of the system at equivalence point.

Owing to the fact that the acid is exactly neutralized by the base; at the equivalence point of such titration, it is expected that hydrogen ions(H+) and hydroxide ions (OH-) must have reacted to form water, this leads to a final pH of 7.  

Answer: Anode: [tex]Pb+SO_4^{2-}\rightarrow PbSO_4+2e^-[/tex]

Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]

Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]

Explanation:

Lead storage battery is a secondary cell used in automobiles and invertors. The anode is made up of lead and undergoes oxidation during discharging and cathode is made up of lead oxide and acts as cathode during discharging. The electrolyte used is dilute .

Lead storage battery acts as electrochemical cell while discharging.

Discharging reaction for  Anode:

Discharging reaction for  Cathode: [tex]PbO_2+4H^++SO_4^{2-}+2e^-\rightarrow PbSO_4+2H_2O[/tex]

Overall cell reaction : [tex]Pb+2SO_4^{2-}+PbO_2+4H^+\rightarrow 2PbSO_4+2H_2O[/tex]

A lead storage battery is an energy storage device. At the anode lead and sulfate ion reacts to produce Lead(II) sulfate and release two electrons.

In secondary cells or the recharge-discharge cells during recharge, the positive electrode is the anode, while during discharge cathode is the positive electrode.

The anode (lead) of the cell undergoes an oxidation reaction during the discharge, whereas the lead oxide or the cathode undergoes reduction.

The discharging reaction at the anode of the cell is given as,

[tex]\rm Pb + SO_{4}^{2-} \rightarrow PbSO_{4} + 2e^{-}[/tex]

The discharging reaction at the cathode of the cell is given as,

[tex]\rm PbO_{2} + 4H^{+} + SO_{4}^{2-} + 2 e^{-} \rightarrow PbSO_{4} + 2H_{2}O[/tex]

The overall cell reaction is given as,

[tex]\rm Pb + 2SO_{4}^{2-} + PbO_{2} + 4H^{+} \rightarrow 2PbSO_{4} + 2H_{2}O[/tex]

Therefore, the gain and loss of electrons are represented at the cathode and the anode of the cell.

Learn more about discharge battery here:

https://brainly.com/question/8341588

Answer: The standard state refers to 1 atm and [tex]25^{o}C[/tex].

Explanation:

It is known that a chemical/substance can either be present in a solid, liquid or gaseous state.

So, when the phase of a substance like solid, liquid or gas is present at 1 atmosphere pressure and at a temperature of [tex]25^{o}C[/tex] then it known as standard state of substance.

Thus, we can conclude that standard state refers to 1 atm and [tex]25^{o}C[/tex].

Answer:

[tex]m_{NH_3}=0.0213gNH_3[/tex]

Explanation:

Hello there!

In this case, since it is known that the reaction between ammonia and acetic acid is:

[tex]CH_3COOH+NH_3\rightarrow CH_3COONH_4[/tex]

It is possible for us to realize that the mole ratio of acetic acid (vinegar) to ammonia is 1:1, that is why we can relate the concentrations as follows:

[tex]M_{acid}V_{acid}=M_{base}V_{base}\\\\[/tex]

In such a way, by knowing that the volume of these two are the same, we infer that their concentrations is also de same; and therefore, the mass of ammonia is calculated as:

[tex]m_{NH_3}=0.005L*0.25\frac{molNH_3}{L}*\frac{17.04gNH_3}{1molNH_3}\\\\m_{NH_3}=0.0213gNH_3[/tex]

Regards!

Answer:

See Explanation

Explanation:

When a constraint such as a change in temperature, concentration or pressure is imposed on a reaction system in equilibrium, the system will readjust itself in such a way as to annul the constraint. This readjustment occurs when the equilibrium position shifts towards the left or right in order to annul the constraint.

a. increasing the concentration of CO: When the concentration of CO is increased, the equilibrium position shifts to the right in order to annul the constraint. This means that more CO2 is produced in the system while the concentration of CO and O2 are decreased until equilibrium is reestablished.

b. decreasing the amount of O2: When the amount of O2 is decreased, the equilibrium position will shift to the left and more CO and O2 are produced while the concentration of CO2 decreases until equilibrium is reestablished.

c. decreasing the the volume of the system: When the volume of the system is decreased, the equilibrium position shifts towards the right hand side where there is less total volume. Hence the concentration of CO and O2 decreases while the concentration of CO2 increases.

Answer:

A

Explanation:

got from another website

The simulation which is least suitable to scientists for solving a problem is when performing an experiment that would be too costly or dangerous to conduct in the real world.

Scientific approach is an empirical method of acquiring knowledge and result. This method involved the careful observation of the problem, applying skepticism about the problem and giving cognitive assumptions also.

If a scientist wants to investigate several problems, then they will perform a large no. of trials at regular intervals to get the required result. But if performing of any experiment is dangerous to conduct in the real world then scientists will ignore to solve that problem.

Hence, option (C) is correct.

To know more about scientific approach, visit the below ink:

https://brainly.com/question/497944

Answer:

V₂ = 4.00 L

Explanation:

Given that:

Volume (v1) = 6.00 L

Temperature (T1) = 300 K

Pressure (P1) = 1.00 atm

VOlume (V2) = unknown???

Temperature (T2) = 600 K

Pressure (P2) = 3.00 atm

Using combined gas law equation:

[tex]\dfrac{P_1V_1}{T_1}= \dfrac{P_2V_2}{T_2}[/tex]

[tex]\dfrac{1 \times 6}{300} = \dfrac{3 \times V_2}{600}[/tex]

[tex]\dfrac{1}{50} = \dfrac{1 \times V_2}{200}[/tex]

200 = 50V₂

V₂ = 200/50

V₂ = 4.00 L

Explanation:

[tex]H _{2}O _{2(aq)} →H _{2}O _{(l)} + O _{2}(g) \\ solution : 2 \: and\: 2[/tex]

Answer:

A-Sphalerite + Dioxygen+Zinc Oxide+Sulfur Trioxide

B-Sodium+Magnesium+Sodium iodide

Explanation:

Heyyy love good luck i may be wrong on letter B so if it is thats my bad but A should be correct :)

Answer:

P₄ + 6 H₂ ⇒ 4 PH₃

Explanation:

Let's consider the unbalanced reaction that takes place when phosphorus reacts with hydrogen to form phosphine. This is a synthesis reaction.

P₄ + H₂ ⇒ PH₃

We will balance this reaction using the trial and error method. First, we will balance P atoms by multiplying PH₃ by 4.

P₄ + H₂ ⇒ 4 PH₃

Finally, we get the balanced equation by multiplying H₂ by 6.

P₄ + 6 H₂ ⇒ 4 PH₃

Answer:

1. The gas law used: Dalton's law of partial pressure.

2. Pressure of nitrogen = 331 mmHg

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 592 mmHg

Pressure of Oxygen (Pₒ) = 261 mmHg

Pressure of nitrogen (Pₙ) =?

The pressure of nitrogen in the sample can be obtained by using the Dalton's law of partial pressure. This is illustrated below:

Pₜ = Pₒ + Pₙ

592 = 261 + Pₙ

Collect like terms

592 – 261 = Pₙ

331 = Pₙ

Pₙ = 331 mmHg

Therefore, the pressure of nitrogen in the sample is 331 mmHg

Answer: The mass in grams of potassium chloride required to prepare this solution is 1.862 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

moles of [tex]KCl[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{74.5g/mol}[/tex]

Now put all the given values in the formula of molality, we get

[tex]0.100=\frac{x\times 1000}{74.5g/mol\times 250.0ml}[/tex]

[tex]x=1.862g[/tex]

Therefore, the mass in grams of potassium chloride required to prepare this solution is 1.862 grams

Answer:

ako po kailangan ko po nga ayuda

Explanation:

thanks for the points ❤️

Answer:

the frequency of photons [tex]v = 1.509\times10^{39}Hz[/tex]

Explanation:

Given:  first ionization energy of 1000 kJ/mol.

No. of moles of sulfur = 1 mole

[tex]\Delta E_1 = 1000KJ/mol[/tex]

We know that plank's constant

[tex]h = 6.626\times10^{-34} Js[/tex]

Let the frequency of photons be ν

Also we know that ΔE = hν

this implies ν = ΔE/h

[tex]= \frac{10^6J}{6.626\times10^{-34} Js}[/tex]

[tex]v = 1.509\times10^{39}Hz[/tex]

Hence, the frequency of photons [tex]v = 1.509\times10^{39}Hz[/tex]

Answer:

A. Yes

B. The new temperature of the gas is -116 °C

Note: The question is incomplete. The complete question is given below :

For many purposes we can treat butane C H10) as an ideal gas at temperatures above its boiling point of - 1. °C. Suppose the pressure on a 500 mL sample of butane gas at 41.0°C is cut in half. Iyes Is it possible to change the temperature of the butane at the same time such that the volume of the gas doesn't change? yes no If you answered yes, calculate the new temperature of the gas. Round your answer to the nearest °C.

Explanation:

A. According to the pressure law of gases,for a fixed mass of gas the pressure of a gas is directly proportional to its Kelvin temperature once the volume is kept constant. This means that a change in temperature can bring about a change in pressurein a gas at constant volume.

B. From the pressure law of gasese: P1/T1 = P2/T2

Where initial pressure = P1, final pressure = P2

Initial temperature = T1, final temperature = T2

For the butane gas;

P1 = P

P2 = P/2

T1 = 41°C = (273 + 41 ) K = 314 K

T2 = ?

From the equation, T2 = T1 × P2 / P1

T2 = 314 × P/2 /P

T2 = 157 K

T2 = (157 - 273) °C = -116 °C

Therefore, the new temperature of the gas is -116 °C

Answer:

B

Explanation:

Answer:

D Fracture

Explanation:

jus took the test

Answer:

B

Explanation:

The appropriate diagram of the question is shown in the first image attached below.

From the diagram, we see the reaction of Cyclopentanol taking place under Tscl pyridine. We are to show the reaction mechanism and determine from the options, which appropriate product fits in.

So, from the reaction, the hydroxyl substituent reacts with Tscl where cl is being lost. This process is followed by an attack of N substituent on the pyridine with the Hydrogen atom and cleaves off for the structure to form a stable structure. The stereochemistry of the compound remains unchanged and it maintains its stick formula.

Thus, X is the appropriate and the correct product.

Answer:

1. [H⁺] = 2.0×10¯¹¹ M

2. [OH¯] = 4.8×10¯⁴ M

3. pOH = 3.3

4. pH = 10.7

Explanation:

From the question given above, the following data were obtained obtained:

Molarity of Ca(OH)₂ = 0.00024 M

We'll begin by calculating the concentration of the hydroxide ion [OH¯]. This can be obtained as follow:

Ca(OH)₂ (aq) —> Ca²⁺ + 2OH¯

From the balanced equation above,

1 mole of Ca(OH)₂ produced 2 moles of OH¯.

Therefore, 0.00024 M Ca(OH)₂ will produce = 2 × 0.00024 = 4.8×10¯⁴ M OH¯

Thus, the concentration of the hydroxide ion [OH¯] is 4.8×10¯⁴ M

Next, we shall determine the pOH of the solution. This can be obtained as follow:

Concentration of the hydroxide ion [OH¯] = 4.8×10¯⁴ M

pOH =?

pOH = –Log [OH¯]

pOH = –Log 4.8×10¯⁴

pOH = 3.3

Next, we shall determine the pH of the solution. This can be obtained as follow:

pOH = 3.3

pH =?

pH + pOH = 14

pH + 3.3 = 14

Collect like terms

pH = 14 – 3.3

pH = 10.7

Finally, we shall determine the concentration of hydrogen ion [H⁺]. This can be obtained as follow:

pH = 10.7

Concentration of hydrogen ion [H⁺] =?

pH = –Log [H⁺]

10.7 = –Log [H⁺]

Divide both side by –1

–10.7 = Log [H⁺]

Take the antilog of –10.7

[H⁺] = Antilog (–10.7)

[H⁺] = 2.0×10¯¹¹ M

SUMMARY:

1. [H⁺] = 2.0×10¯¹¹ M

2. [OH¯] = 4.8×10¯⁴ M

3. pOH = 3.3

4. pH = 10.7

Explanation:

maybe umm think so pick think so

Answer:

The appropriate solution is:

(a) n ≈ 900

(b) n ≈ 1165

Explanation:

According to the question,

(a)

The final number of molecules throughout water will be:

= [tex](\frac{1000}{1000}\times 4\times 10 )^n[/tex]

where, n = number of extractions

Now,

The initial number of molecules will be:

= [tex]1.06\times 10^{-4}\times 6.023\times 10^{23}[/tex]

= [tex]6.387\times 10^{19}[/tex]

Final number of molecule,

⇒ [tex]1.566\times 10^{-16}=(\frac{1000}{1040} )^n[/tex]

                       [tex]n \approx 900[/tex]

(b)

Final molecules of X = left (0.01%)

hence,

⇒ [tex]initial = 6.384\times 10^{19}[/tex]

   [tex]\frac{1}{6.384\times 10^{19}} =(\frac{1000}{1040} )^2[/tex]

                 [tex]n \approx 1165[/tex]

Answer: There are [tex]145 \times 10^{23}[/tex] atoms in 24 moles of Fe.

Explanation:

According to the mole concept, 1 mole of a substance contains [tex]6.022 \times 10^{23}[/tex] atoms.

Therefore, atoms present in 24 moles of Fe are calculated as follows.

[tex]24 mol \times 6.022 \times 10^{23} atoms/mol\\= 144.52 \times 10^{23} atoms\\or, 145 \times 10^{23} atoms[/tex]

Thus, we can conclude that there are [tex]145 \times 10^{23}[/tex] atoms in 24 moles of Fe.

Answer:

9.18g

Explanation:

Step 1: Write the reduction half-reaction

Au³⁺(aq) + 3 e⁻ ⇒ Au(s)

Step 2: Calculate the mass of gold is produced when 15.0A of current are passed through a gold solution for 15.0min

We will use the following relationships:

The mass of gold produced is:

[tex]15.0 min \times \frac{60s}{1 min} \times \frac{15.0C}{1s} \times \frac{1 mol e^{-} }{96486C} \times \frac{1molAu}{3 mol e^{-} } \times \frac{196.97gAu}{1molAu} = 9.18gAu[/tex]