I asked my teacher for help and she didn’t. Please help. All info is on the pic.
Answers
Total arc lenght of a circle = 360°
mAD + m AB + m BC + m DC = 360
100 + 110 + 90 + mDC = 360
mDC = 360 - 100 - 110 - 90
mDC = 60
Related Questions
Can you help me please
Answers
Solution
1) Which of the following graphs best represent a quadratic function whose discriminant is ZERO
The red and the blue one
2) Which of the following graphs best represent a quadratic function whose discriminant is GREATER THAN 0
The blue and red one
3) Which of the following graphs best represent a quadratic function whose discriminant is LESS THAN 0
The green one
solve for a ab+c=da= b/(c-d)a=(d-c)/ba=b+c/d
Answers
Gemma had $2, 054 in her checking account. She wrote a check for $584 to pay the rent on her apartment. After the landlordcashed the check, how much money did Gemma have left in her checking account?
Answers
SOLUTION:
Case: Checking account (Subtraction application)
Given: Opening account = $2054 and rent paid = $584
Required: To find how much money did Gemma have left in her checking account
Method:
Step 1: First write the opening cost account
$2054
Step 2: Then the cost of rent checked on the account
$584
Step 3: Subtract to see what is left
$2054 - $584 = $ 1470
Final answer:
Gemma has $1470 left in her checking account. Option (C)
Factor completely, or state that the polynomial is prime.y^6 - 256y^2
Answers
We can see that our polynomial is equal to
[tex]y^6-256y^2=y^2(y^4-256)[/tex]Now, we can factorize the term in parenthesis as
[tex]y^4-256=(y^2+16)(y^2-16)[/tex]Similarly,
[tex]y^2-16=(y+4)(y-4)[/tex]finally, we obtain
[tex]y^6-256y^2=y^2(y^2+16)(y+4)(y-4)[/tex]is the SIMPLIFIED form of [tex]2 \sqrt{3} + 3 \sqrt{3} [/tex]rational?
Answers
The given expression is:
[tex]2\sqrt[]{3}+\text{ 3}\sqrt[]{3}[/tex]Note that:
[tex]a\sqrt[]{c}+\text{ b}\sqrt[]{c}=\text{ (a+b)}\sqrt[]{c}[/tex]Therefore, the given expression can be written as:
[tex]undefined[/tex]the national health examination survey reported that in a sample of 13,267 adults, 6634 had high cholesterol (total cholesterol above 200 mg/dl), 8093 were overweight (body mass index above 25), and 4113 were both overweight and had high cholesterol. a person is chosen at random from this study. round all answers to four decimal places. (C) find the probability that the person does not have high cholesterol. The probability that the person does not have high cholesterol is?(D) Find the probability that the person is overweight or has high cholesterol. The probability that the person is overweight or has high cholesterol is?
Answers
The results of the National Health Examination Survey are:
High Cholesterol: 6634
Overweight: 8093
Both overweight and had high cholesterol: 4113
Sample size: 13 267
(C)
We need to calculate the probability that the person does not have high cholesterol. To do that, we need to find the probability that the person does have cholesterol, and then subtract this result from 1. Then:
P[not high cholesterol] = 1 - P[high cholesterol]
P[high cholesterol] = (# people that have high cholesterol) / (Total # of people)
P[not high cholesterol] = 1 - (6634) / (13 267) = 0.499962...
Rounding to four decimal places:
P[not high cholesterol] = 0.5000
(D)
Now, we need to calculate the probability that the person is overweight or has high cholesterol. We define the events:
A: The person has high cholesterol
B: The person is overweight
Then:
P[A ∪ B] = P[A] + P[B] - P[A ∩ B]
Where:
P[A] = 6634/13267
P[B] = 8093/13267
P[A ∩ B] = 4113/13267
Where we defined the probability as:
P[C] = (# of events C) / (# of total events)
Then:
P[A ∪ B] = 6634/13267 + 8093/13267 - 4113/13267 = (6634+8093-4113)/13267
P[A ∪ B] = 10614/13267
Rounding to four decimal places:
P[A ∪ B] = 0.8000
Kendra is filling cone shaped baskets each with a height of 20 inches and radius of 6 inches to use as table decorations.Part Ain terms of pie, what is the exact volume of each cone shaped basket?
Answers
height = 20 inches
radius of the cone = 6 inches
Therefore,
[tex]\begin{gathered} \text{volume}=\frac{1}{3}\pi r^2h \\ \text{volume}=\frac{1}{3}\times\pi\times6^2\times20 \\ \text{volume}=\frac{1}{3}\times\pi\times36\times20 \\ \text{volume}=\frac{720\pi}{3} \\ \text{volume}=240\pi^{}inches^3 \end{gathered}[/tex]KiteKite StringAltitude : 120 ftGroundA kite is flown at a 55° angle of elevation. That is, the kite stringmakes a 55° angle with the ground.If the altitude of the kite is 120 feet, what is the length of the kitestring used? Round your answer to the nearest foot.
Answers
Given:
The altitude of the kite, h=120 ft.
The angle made by the kite string with the ground, θ=55° .
Let x be the length of the string.
Now, using trigonometric property in the above triangle,
[tex]\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{hypotenuse} \\ \sin \theta=\frac{h}{x} \end{gathered}[/tex]Now, substitute the values and solve the equation for x.
[tex]\begin{gathered} \sin 55^{\circ}=\frac{120\text{ ft}}{x} \\ x=\frac{120\text{ ft}}{\sin55^{\circ}} \\ =146.49\text{ ft} \\ \approx146\text{ ft} \end{gathered}[/tex]Therefore, length of the kite string is 146 ft.
Find the 52nd term.-3, -12, -48, -92,…
Answers
The given sequence is
[tex]-3,-12,-48,-92,\ldots[/tex]We will find the common ratio by dividing the 2nd term by the 1st term
[tex]\begin{gathered} r=\frac{-12}{-3} \\ r=4 \end{gathered}[/tex]The rule of the nth term of the geometric sequence is
[tex]a_n=ar^{n-1}[/tex]a is the 1st term
r is the common ratio
n is the position of the term
Since the 1st term is -3, then
a = -3
Since the common ratio is 4, then
r = 4
Since we need to find the 52nd term, then
n = 52
Substitute them in the rule above
[tex]\begin{gathered} a_{52}=-3(4)^{52-1} \\ a_{52}=-3(4)^{51} \end{gathered}[/tex]The answer is
[tex]a_{52}=-3(4)^{51}[/tex]2 This triangle has an area of 16cm2 and a base length of 8cm.
Calculate its vertical height.
Answers
Answer:
h = 4 cm
Step-by-step explanation:
the area (A) of a triangle is calculated as
A = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the vertical height )
here b = 8 and A = 16 , then
[tex]\frac{1}{2}[/tex] × 8 × h = 16
4h = 16 ( divide both sides by 4 )
h = 4 cm
What is the leading coefficient of the polynomial?15x4 - 26x3 - 18x6 – 19x7
Answers
Solution.
In mathematics, the leading coefficient of a polynomial is the coefficient of the term with the highest degree of the polynomial, that is, the leading coefficient of a polynomial is the number that is in front of the x with the highest exponent.
find the lowest common multiple of 32 and 58
Answers
Prime factors of 32: 2
Prime factors of 58: 2, 29
The combined prime factors of 32 and 58 are 2 and 29
Therefore:
[tex]\begin{gathered} 32=2^5 \\ 58=2^1\times29^1 \\ so\colon \\ \operatorname{lcm}(32,58)=2^5\times29^1=928 \end{gathered}[/tex]Answer:
928
Find the domain of f(x) = -√x² – 16.-all real numbersx ≥4 or x ≤ 4x24Ox≥4 or x ≤ - 4
Answers
Given: A function-
[tex]f(x)=-\sqrt{x^2-16}[/tex]Required: To determine the domain of the function.
Explanation: The domain of a function is the set of all the input values or x-values at which the function f(x) exists.
The square root of a negative number does not give any real value. Hence, the function will exist for-
[tex]\begin{gathered} x^2-16\ge0 \\ x^2\ge16 \\ \Rightarrow x\ge4\text{ or }x\leq-4 \end{gathered}[/tex]Hence, the domain is-
[tex]Domain:\text{ \lparen-}\infty,-4]\cup[4,\infty)[/tex]Final Answer: Option D is correct.
A math lab of 12 students has 9 girls. If next semester’s math lab enrolls 36 students, how many students are expected to be girls?
Answers
A math lab of 12 students has 9 girls . Next semester math lab enrolls 36 students, the expected numbers of girls can be calculated as follows
[tex]\begin{gathered} 12\text{ student = 9 girls} \\ 36\text{ students = ?} \\ \text{cross multiply} \\ \text{expected number of girls = }\frac{36\times9}{12} \\ \text{expected number of girls = }\frac{324}{12} \\ \text{expected number of girls = }27 \end{gathered}[/tex]A pool was being emptied at a rate of 5 gallons per hour. The equationy - 60 = -5(x - 5) models the amount of water remaining, where x is time (inhours) and y is the amount of water left (in gallons). Write the correspondingequation in slope-intercept form
Answers
We're given the equation:
[tex]y-60=-5(x-5)[/tex]In order to get to the slope-intercept form we have to clear y :
[tex]\begin{gathered} y-60=-5(x-5) \\ \rightarrow y-60=-5x+25 \\ \rightarrow y=-5x+85 \end{gathered}[/tex]Therefore, the equation in the slope-intercept form is:
[tex]y=-5x+85[/tex]If 12 slices comprise a whole pizza, what is the cost per slice?
Answers
Let x be the cost of the pizza, then the cost per slice is:
[tex]\frac{x}{12}[/tex]Assuming X is the cost of the pizza then the cost of each slice is [tex]\frac{x}{12}[/tex]
State the domain and range for each graph and then tell if the graph is a function
Answers
The domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis.
[tex]\lbrace x|x=2,3\rbrace[/tex]
The range is the set of possible output values, which are shown on the y-axis.
[tex](-\infty,\infty)[/tex]sample oft 22 teen were surveyed and asked about how many hours per day they spend grooming themselves assume that self grooming times for teens is normally distributed if the grooming time for these 22 teens was 1.3 hours a day with s= .35are you going to use student t or standard z to help you calculate this confidence interval calculate a 99% confidence interval to estimate the grooming time for all teens
Answers
Step 1
State the given data
n= 22 teens
mean = 1.3 hours
standard deviation = 0.35
Step 2
A) State with reason if we are to use t or standard z to calculate the confidence level
Conditions for using t standard include
1) n<30
2) The standard deviation is not given
Since the standard deviation is given we will use the z standard to calculate the confidence level
Step 3
Calculate a 99% confidence interval to estimate the grooming time for all teens
To do this we use the expression
[tex]\bar{x}\pm z_{\propto\text{ }}\times\text{ }\frac{s}{\sqrt[]{n}}[/tex]Where
[tex]\begin{gathered} \bar{x}=1.3hours \\ z_{\propto\text{ }}at99percent=2.576 \\ s\text{ = 0.35} \\ n\text{ =22} \end{gathered}[/tex]Substituting these value into the equation gives
[tex]\begin{gathered} =1.3\pm2.576_{}\times\frac{0.35}{\sqrt[]{22}} \\ =\text{ }1.3\pm2.576(0.07462025) \\ =\text{ 1.3 }\pm0.192221765 \\ So\text{ the interval is 1.3 }\pm0.192221765 \end{gathered}[/tex]So the intervals will be
1.107778235 to 1.492221766
find the slope of the line passing through the points (3,4) and (8 -3)
Answers
Answer
Slope = -(7/5)
Explanation
For a straight line, the slope of the line can be obtained when the coordinates of two points on the line are known. If the coordinates are (x₁, y₁) and (x₂, y₂), the slope is given as
[tex]Slope=m=\frac{Change\text{ in y}}{Change\text{ in x}}=\frac{y_2-y_1}{x_2-x_1}[/tex]For this question,
(x₁, y₁) and (x₂, y₂) are (3, 4) and (8, -3)
x₁ = 3
y₁ = 4
x₂ = 8
y₂ = -3
[tex]\text{Slope = }\frac{-3-4}{8-3}=\frac{-7}{5}[/tex]Hope this Helps!!!
the first five boxes are examples but the one at the bottom its a question.
Answers
Percent Decimal
1/ 5 20 % 0.2
1/ 2 50 % 0.5
1/ 2 to percent = 1 / 2 x 100/1 = 50 %
1/ 2 to decimal = 0.5
hello hope all is well with you. Can you help me with this please. The question is find the MEAN age of people who become Zombie?
Answers
Ok, to find the Mean age we are going to add all the ages and next we are going to dividing the total by the number of ages, so let's do it:
20+20+24+29+32+33+35+41+41+42=317/10=31.7
Finally we get that the mean age of people who become Zombie is 31.7, rounded to the nearest integer it's 32.
The expected value of the geometric distribution is given by the formula ____.
Answers
The expected value of the geometric distribution is given by:
[tex]\frac{1}{p}[/tex]Hence the answer is option A. 1/p.
determine the common ratio of a geometric sequence if the second term is -4 and fifth term is -27/2
Answers
ANSWER
The common ratio is 3/2.
EXPLANATION
Given:
[tex]\begin{gathered} \text{ 2nd term of GP: ar = -4} \\ \text{ 5th term of GP: ar}^4\text{ = -}\frac{27}{2} \end{gathered}[/tex]Desired Outcome:
Common ratio
Determine the common ratio
ar = -4
a = -4/r
[tex]\begin{gathered} substitute\text{ a} \\ ar^4\text{ = -}\frac{27}{2} \\ (-\frac{4}{r})r^4\text{ = -}\frac{27}{2} \\ -4r^3\text{ = -}\frac{27}{2} \\ divide\text{ bothe sides by -4} \\ r^3\text{ = }\frac{27}{8} \\ take\text{ cube root of both sides} \\ r^3\text{ = }\frac{3^3}{2^3} \\ r\text{ = }\frac{3}{2} \end{gathered}[/tex]Hence, the common ratio of the geometric sequence is 3/2.
need help finding the anti derivative of each of these
Answers
As given by the question
There are given that the integration:
[tex]\frac{\int5}{x}dx=\frac{s\int1}{x}dx.[/tex]Now,
From the formula of integration:
[tex]\frac{\int1}{x}dx=\ln \lvert x+c\rvert[/tex]T
Y=10/x+7-5 graph the function. State the domain and range
Answers
What is the ratio of 2weeks : 14days : 8weeks
Answers
ANSWER
[tex]1\colon1\colon4[/tex]EXPLANATION
We want to find the ratio of 2 weeks to 14 days to 8 weeks.
To do this, we first have to put all three terms in the same unit. Let us put all the terms in days.
To convert from weeks to days, multiply the weeks by 7:
[tex]\begin{gathered} 2w=2\cdot7=14d \\ 8w=8\cdot7=56d \end{gathered}[/tex]Therefore, the ratio becomes:
[tex]14days\colon14days\colon56\text{days}[/tex]Now, put it in the lowest terms by dividing through by 14. That is:
[tex]1\colon1\colon4[/tex]That is the answer.
2/18 = x/36 solve each proportion
Answers
2 / 8 = x / 36
we multiply both sides of the equation with 36 in order to solve for x.
36 × (2 / 8) = 36 ( x / 36)
9 = x
the proportion is
2 / 8 = 9 / 36
Find the population in 2017 round to the nearest tenth
Answers
Given:
In 2000, the population was 6.08 billion
rate of increase = 1.5% per year
Required: The population in 2017
The formula for calculating population growth is:
[tex]y(t)\text{ = a\lparen1 + r\rparen}^t[/tex]Where y(t) is the population at a later time t
a is the initial population
r is the annual rate of increase
and t is the number of years
For the given problem,
a = 6.08 billion
r = 1.5%
t = 17 years (2017-2000)
Substituting the given values into the formula:
[tex]\begin{gathered} y(t=17)\text{ =6,080,000,000\lparen1 + }\frac{1.5}{100})^{17} \\ =\text{ 7,831,163,611.683507} \\ \approx\text{ 7,831, 163, 611.7} \end{gathered}[/tex]Hence, the population in 2017 should be 7831163611.7
Find mikes average monthly income based on these weekly incomes $284,$292,$$418,$350 and $470
Answers
AVerage Monthly= (284+292+418+350+470)/5
= 1814/5
= $362.80
Answer:
362.8
Step-by-step explanation:
I just want to make sure I solved it correctly this is how the formula looks and 39200[(1+0.082/1)^1(5) / 0.082/1
Answers
Hello! Let's rewrite the formula below:
[tex]A\text{ = }\frac{39200\lbrack(1+\frac{0.082}{1})^{1(5)}-1\text{\rbrack}}{\frac{0.082}{1}}[/tex]First, we can simplify the fractions with 1 in the denominator:
[tex]\begin{gathered} A\text{ = }\frac{39200\lbrack(1+0.082)^{1.(5)}-1\text{\rbrack}}{0.082} \\ \\ A\text{ = }\frac{39200[(1.082)^5-1\text{\rbrack}}{0.082} \\ \\ A\text{ = }\frac{39200\lbrack(\frac{541}{500})^5-1\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{39200\lbrack\frac{541^5}{500^5}^{}-1\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{39200.\frac{541^5}{500^5}^{}-39200\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{39200.\frac{541^5}{500^4.500}^{}-39200\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{392.\frac{541^5}{500^3.500.5}^{}-39200\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = (}98.\frac{541^5}{500^3.125.5}^{}-39200)divided\frac{41}{500} \\ \\ A\text{ = }\frac{98.\frac{541^5}{500^2.500.125.5}^{}-39200}{\frac{41}{500}} \\ \\ A\text{ = }\frac{49\frac{541^5}{500^2.(250.125.5)}^{}-39200}{\frac{41}{500}} \\ \\ A\text{ = }\frac{49\frac{541^5}{500.500.(156250)}^{}-39200}{\frac{41}{500}} \\ \\ A\text{ = }\frac{\frac{49.541^5}{250000.156250}^{}-39200}{\frac{41}{500}} \\ \\ A\cong230889.65 \\ \end{gathered}[/tex]