I got this problem on my homework wrong so I would like some help, I also added some of the formulas we use so hopefully that helps!

I Got This Problem On My Homework Wrong So I Would Like Some Help, I Also Added Some Of The Formulas
I Got This Problem On My Homework Wrong So I Would Like Some Help, I Also Added Some Of The Formulas

Answers

Answer 1
[tex]\begin{gathered} v=10i-3j \\ w=-5i-j \end{gathered}[/tex]

First we need to find the dot product and the magnitude of each vector, so:

[tex]\begin{gathered} \mleft\Vert v\mright||=\sqrt[]{10^2+(-3)^2}=\sqrt[]{109} \\ \mleft\Vert w\mright||=\sqrt[]{(-5)^2+(-1)^2}=\sqrt[]{26} \end{gathered}[/tex][tex]v\cdot w=10\cdot(-5)+(-3)\cdot(-1)=-50+3=-47[/tex]

Therefore:

[tex]\begin{gathered} \theta=\cos ^{-1}(\frac{-47}{\sqrt[]{109}\cdot\sqrt[]{26}}) \\ \theta\approx152.0^{\circ} \end{gathered}[/tex]


Related Questions

Simplifying a ratio of whole numbers: Problem type 2Write this ratio as a fraction in simplest form without any units.40 days to 5 weeksYou can use the table below to help convert the units.1 minute = 60 seconds1 hour = 60 minutes1 day = 24 hours1 week = 7 days

Answers

We want to write the ratio of 40 days to 5 weeks as a fraction. Both values must have the same unit. Let us convert 5 weeks to days. Recall,

1 week = 7 days

5 weeks = 5 x 7 = 35 days

Thus, the ratio as a fraction would be

40/35

Dividing the numerator and denominator by 5, the fraction in the simplest form would be 8/7

The monthly cost (in dollars) of water use is a linear function of the amount of water used (in hundreds of cubic feet,HCF).The cost for using 20 HCF of water is $35.13 and the cost for using 33 HCF is $57.88.what is the cost for using 27 HCF of water?

Answers

Since the relationship is linear, we will solve it as follows:

*We are given two points, we will find the slope:

[tex]m=\frac{57.88-35.13}{33-20}\Rightarrow m=\frac{7}{4}[/tex]

*Now, we replace this slope and one of the points in the following expression:

[tex]y-y_1=m(x-x_1)[/tex]

Now, we replace:

[tex]y-35.13=\frac{7}{4}(x-20)\Rightarrow y-35.13=\frac{7}{4}x-35[/tex][tex]\Rightarrow y=\frac{7}{4}x+0.13[/tex]

Now, we replace the 27 HCF in the expression and solve for the cost:

[tex]y=\frac{7}{4}(27)+0.13\Rightarrow y=47.38[/tex]

So, the cost for 27 HCF is $47.38.

What is the answer to this Dilations of Segments and Angles problem?

Answers

Solution:

Remember that the dilation does not change the measure of angles. According to this, the correct answer is:

[tex]46^{\degree}[/tex]

Mr. K's math class is 14 hours long. After workingproblems on the board for 55 minutes (hour), he gavethe students the rest of the class period to work onhomework. How long did students have to work onhomework? Write your answer in simplest form.A. hourB. hourc. hourD.hourSUBMIT

Answers

Given:

Mr. K's math class is

[tex]1\frac{1}{4}[/tex]

hours long.

Mr. K worked on problems on the board for 55 minutes

[tex]\frac{11}{12}[/tex]

hour.

Required:

Time required by the students to work on homework.

Explanation:

Mr. K's math class is

[tex]1\frac{1}{4}[/tex]

hours long.

Mr. K worked on problems on the board for 55 minutes.

Let x be the time in hours worked on homework by the students.

Thus, the rest of the class period given to students to work on homework is given by,

[tex]\begin{gathered} 1\frac{1}{4}=\frac{11}{12}+x \\ \Rightarrow x=1\frac{1}{4}-\frac{11}{12} \\ \Rightarrow x=\frac{5}{4}-\frac{11}{12} \\ \Rightarrow x=\frac{15-11}{12} \\ \Rightarrow x=\frac{4}{12} \\ \Rightarrow x=\frac{1}{3} \end{gathered}[/tex]

Final Answer:

The time required by the students to work on homework is,

[tex]\frac{1}{3}[/tex]

hour.

Option B is correct.

Use the point onnthe terminal side of Angle to find each of the six trigonometric functions of Angle

Answers

Theres a line with origin at (0,0) and ends in (3,-2)

because its known y and x apply

tan ∆= y/x

tan∆ = -2/3 = -0.6666

then ∆ = -33.68 degrees

Angle = 360° - 33.68 = 326.32 degrees

then tan 326.32= -.6666

cotan x = 1/ tanx= -1.5

sin 326.32 = -.554

Cosecx 1/sinx = -1.8050

cos 326.32= 0.8321

secx = 1/cosx= 1.2017

n the triangle below, if < C = 2x - 5 degrees, and < A = x + 10 degrees, find the measure of < A.

Answers

Given:

[tex]AB=BC[/tex]

[tex]\begin{gathered} \angle C=2x-5 \\ \angle A=x+10 \end{gathered}[/tex]

Required:

To find the angle A.

Explanation:

We know tha "If two sides of a triangle are equal , then it has equal angles".

Therefore

[tex]\angle C=\angle A[/tex][tex]\begin{gathered} 2x-5=x+10 \\ 2x-x=10+5 \\ x=15 \end{gathered}[/tex]

Now angle A ia,

[tex]\begin{gathered} \angle A=x+10 \\ =15+10 \\ =25\degree \end{gathered}[/tex]

Final Answer:

The option D is correct.

[tex]\angle A=25\degree[/tex]

It is estimated that there are 7,500,000,000,000,000,000 grains of sand on all the beaches of the world. How is this number written in scientific notation? А 7.5 x 1015 B 7.5 x 1019 с 7.5 x 1017 D 7.5 x 1018

Answers

[tex]=\text{ 7.5 }\times10^{18}\text{ (option D)}[/tex]

Explanation:

To write in scirentific notation, we start counting from the right towards the left. We start from the last number to the first number

Scientific notation:

[tex]\begin{gathered} 7.5\text{ }\times10^{number\text{ of movement to the first number }} \\ number\text{ of movement to the first number = 18} \\ =\text{ 7.5 }\times10^{18} \end{gathered}[/tex]

how to find the denominator, the associates of x & y

Answers

Given the following System of equations:

[tex]\begin{cases}-3x+2y=18 \\ -2x-y=5\end{cases}[/tex]

You can identify that it has this form:

[tex]\begin{cases}a_1x+b_1y=c_1_{} \\ a_2x+b_2y=c_2\end{cases}[/tex]

Where:

[tex]\begin{gathered} a_1=-3 \\ a_2=-2 \\ b_1=2 \\ b_2=-1 \\ c_1=18_{} \\ c_2=5 \end{gathered}[/tex]

The determinant D is, by definition:

[tex]D=\begin{bmatrix}{a_1} & {b_1} & {} \\ {a_2} & {b_2} & {} \\ {} & {} & \end{bmatrix}=a_1b_2-a_2b_1[/tex]

Then, in this case this is:

[tex]D=\begin{bmatrix}{-3} & {2_{}} & {} \\ {-2_{}} & {-1_{}} & {} \\ {} & {} & \end{bmatrix}=(-3)(-1)-(-2)(2)=7[/tex]

By definition, the determinant associated with "x" is given by:

[tex]D_x=\begin{bmatrix}{c_1} & {b_1} & {} \\ {c_2} & {b_2} & {} \\ {} & {} & \end{bmatrix}=c_1b_2-c_2b_1[/tex]

Then, in this case:

[tex]D_x=\begin{bmatrix}{18_{}} & {2_{}} & {} \\ {5_{}} & {-1_{}} & {} \\ {} & {} & \end{bmatrix}=(18)(-1)-(5)(2)=-28[/tex]

The determinant associated with "y" is given by:

[tex]D_y=\begin{bmatrix}{a_1} & {c_1} & {} \\ {a_2} & {c_2} & {} \\ {} & {} & \end{bmatrix}=a_1c_2-a_2c_1[/tex]

Then, this is:

[tex]D_y=\begin{bmatrix}{-3_{}} & {18_{}} & {} \\ {-2_{}} & {5_{}} & {} \\ {} & {} & \end{bmatrix}=(-3)(5)-(-2)(18)=21[/tex]

The solution of the System of equations can be found as following:

1. For the x-coordinate:

[tex]x_{}=\frac{D_x}{D}=\frac{-28}{7}=-4[/tex]

2. For the y-coordinate:

[tex]y=\frac{D_y}{D}=\frac{21}{7}=3[/tex]

The answers are:

[tex]\begin{gathered} D=7 \\ D_x=-28 \\ D_y=21 \\ \text{Solution}=(-4,3) \end{gathered}[/tex]

. Consider the data from the Anthropology 105 class. The mean height for women in theclass is 64.33 in and the standard deviation is 2.64 in.1. The average height of men in the US is approximately 5ft 10in. What proportion of womenrepresented here are shorter than the average man? (enter the answer as a percent rounded to thenearest hundredth as needed)2. Assume professional volleyball players who are women are at least 6 foot tall. What proportion ofthe population could even hope to be a professional volleyball player by using these standards? Hint:Find the proportion of women who are at least 6 foot tall. (enter the answer as a percent rounded tothe nearest hundredth as needed)

Answers

Given:

The mean height for women in the class = μ = 64.33

The standard deviation = σ = 2.64 in

We will use the formula of the z-score

[tex]z=\frac{x-\mu}{\sigma}[/tex]

We will find the following:

1. The average height of men in the US is approximately 5ft 10in. What proportion of women represented here are shorter than the average man?

1 foot = 12 inches

So, x = 5ft 10in = 5*12 + 10 = 70 in

[tex]z=\frac{70-64.33}{2.64}=2.1477[/tex]

From the normal distribution curve we will find P(z < 2.1477)

So, the percentage will be = 0.9841

rounding to the nearest hundredth,

So, the answer will be 98.41%

=============================================================

2. Assume professional volleyball players who are women are at least 6 feet tall. What proportion of the population could even hope to be a professional volleyball players by using these standards?

So, x = 6 foot = 72 in

[tex]z=\frac{72-64.33}{2.64}=2.9053[/tex]

From the normal distribution curve, we will find P( z > 2.9053)

So, the answer will be 0.0018 = 0.18%

So, the answer will be 0.18%

What is the domain of the mapping diagram shown below?−3≤g(x)≤8{−3,8}1≤x≤3{1,2,3}

Answers

Answer:

(D){1,2,3}

Explanation:

The domain of the mapping is the set of all the values of x.

In the mapping, the values of x are: 1, 2 and 3

Therefore, the domain of the mapping is: {1,2,3}

I need help with this question, I will post it as a photo, please help.

Answers

We need to simplify the next given expression:

[tex]7m+\frac{5}{12}+8z+\frac{4}{12}+8m-3z[/tex]

We need to solve the like terms, "like terms" are terms whose variables and exponents are the same

Therefore, the like terms are:

7m and 8m

8z and -3z

5/12 and 4/12

Organize the expression:

[tex]7m+8m+\frac{5}{12}+\frac{4}{12}+8x-3z[/tex]

Solving the like terms:

[tex]15m+\frac{9}{12}+5z[/tex]

Finally, we can simplify the fraction 9/12 by 3/4 because 3*3 = 9 and

3*4 = 12

Then:

[tex]15m+\frac{3}{4}+5z[/tex]

A toy maker produces wooden trains and wooden airplanes. Each train requires 3 ounces of paint and each airplane requires 5 ounces of paint. The toy maker has a gallon can of paint (64 ounces). If he wants to use it to paint 14 toys, how many of each can he paint?

Answers

Let be "t" the number of wooden trains that he can paint and "a" the number of wooden airplanes he can paint.

Based on the information given in the exercise, you can set up the following System of equations:

[tex]\begin{cases}t+a=14 \\ 3t+5a=64\end{cases}[/tex]

You can solve it using the Substitution method:

1. You can solve for "a" from the first equation:

[tex]a=14-t[/tex]

2. Substitute the new equation into the second equation.

3. Solve for "t".

Then:

[tex]\begin{gathered} 3t+5a=64 \\ 3t+5(14-t)=64 \\ 3t+70-5t=64 \\ -2t=64-70 \\ \\ t=\frac{-6}{-2} \\ \\ t=3 \end{gathered}[/tex]

4. Substitute the value of "t" into any original equation.

5. Solve for the variable "a".

Then:

[tex]\begin{gathered} t+a=14 \\ 3+a=14 \\ a=14-3 \\ a=11 \end{gathered}[/tex]

The answer is: He can paint 3 trains and 11 airplanes.

Wich equastion can be used to describe the realashionship bewtween x and y

Answers

y= 3x -6

1) Examining the graph, we can pick two points from that line to find out the steepness of that (slope):

2) Since the line intercepts the y-axis at the point (0,-6) we can state that the linear coefficient is b= -6 so we can write out the rule of the function or (relationship) between x and y as:

y= 3x -6

Calculate the radius of a circle of its area is 4cm2

Answers

To find the radius of a circle given the area, use the next formulas:

Ac= 4π cm²

Ac = π*r²

Circumference = π * diameter

Solve the equation for x:

4π cm² = π*r²

4 = π*r² / π

4 = r²

√4 = r

2 = r

Determine the constant of proportionality of the graph Commission per Sales 1.250 1.000 Commission Earned Sales tin Thousands)

Answers

Solution

For this case we need to remember that for a line the proportionality constant is given by:

k= y/x

We can select the last point in the graph where x= 5 and y= 1000 and solving for k we got:

k= 1000/5= 200

And our answer would be k=200

find the surface area of a square pyramid with side length 2 m and slant height 2 m

Answers

The surface of a square pyramid is the sum of the area of its four triangular faces and its base.

Since the side length of its base is 2 m, its base area is 2² = 4 m²

Since each of its triangular face has a base 2 m and a height 2 m, its area is (2*2)/2 = 2 m²

Therefore, the surface area of the pyramid is 4 + 4*2 = 12 m²

A school club purchased a total of 50 cheese pizzas and supreme pizzas. Cheese pizzas cost$10 each, and supreme pizzas cost $12 each.Which system of equations can be used to find the number of cheese pizzas, x, and thenumber of supreme pizzas, y, if the total cost of the pizza was $536?A X= 50-y12x + 10y = 536WillBX = 536 - y12x + 10y = SOсx = 50-10x + 12y = 536Dx 536 - y10x + 12y = 50

Answers

Concept

Write two equations, one for the total number of Pizzas and the other for the total cost.

Next,

Let a number of cheese pizzas x, and the number of supreme pizzas y.

Total Pizzas = 50

x + y = 50 .................................. (1)

Cheese pizzas cost $10 each, and supreme pizzas cost $12 each.

10x + 12y = 536 ......................................... (2)

Next, from equation 1, make x subject of the formula.

Therefore, y = 50 - x

Hence,

y = 50 - x

10x + 12y = 536

Final answer

Option C

y = 50 - x

10x + 12y = 536

Hello need a hand on this Best Solve for x.Question 3 options:1) 52) 63) 34) 4

Answers

Solution

The intersecting chords theorem or just the chord theorem is a statement in elementary geometry that describes a relation of the four- line segments created by two intersecting chords within a circle. It states that the products of the lengths of the line segments on each chord are equal.

[tex]a\times b=c\times d[/tex][tex]\begin{gathered} (4x+2)8=9(4x) \\ \end{gathered}[/tex]

Open the bracket

[tex]\begin{gathered} (4x+2)8=9(4x) \\ 32x+16=36x \\ \text{collect the like terms} \\ 16=36x-32x \\ 16=4x \\ \text{Divide both sides by 4} \\ \frac{16}{4}=\frac{4x}{4} \\ \\ x=4 \end{gathered}[/tex]

2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA = 45e^-0.0045ta. What is initial amount of this substance?b. What is half-life of this substance?c. How much will be around in 2500 years?

Answers

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

[tex]A=45e^{-0.0045(t)}[/tex]

a) To find the initial amount of this substance

At t=0, we get

[tex]A=45e^{-0.0045(0)}[/tex][tex]A=45e^0[/tex]

We know that e^0=1 ( anything to the power zero is 1)

we get,

[tex]A=45[/tex]

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

[tex]\frac{45}{2}=45e^{-0.0045(t)}[/tex]

[tex]\frac{1}{2}=e^{-0.0045(t)}[/tex]

Taking natural logarithm on both sides we get,

[tex]\ln (\frac{1}{2})=-0.0045(t)^{}[/tex][tex](-1)\ln (\frac{1}{2})=0.0045(t)[/tex][tex]\ln (\frac{1}{2})^{-1}=0.0045(t)[/tex][tex]\ln (2)=0.0045(t)[/tex][tex]0.6931=0.0045(t)[/tex][tex]t=\frac{0.6931}{0.0045}[/tex][tex]t=154.02[/tex]

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

[tex]A=45e^{-0.0045(2500)}[/tex][tex]A=45e^{-11.25}[/tex][tex]A=45\times0.000013=0.000585[/tex][tex]A=0.000585[/tex]

The amount of substance will be present around in 2500 years is 0.000585 grams

5. Given perimeter of 100 mm, determine each side of aregular decagon, find apothem, then find area.(round your answer to the nearest hundredth)E

Answers

Remember that

A regular decagon has 10 equal sides

so

perimeter P is equal to

P=10s

where

s is the length side

so

P=100 mm

100=10s

s=10 mm

answer Part 1)

each side is 10 mm

Part 2

Find apothem

the regular decagon can be divided into 10 isosceles triangle

see the attached image to better understand tje problem

applying trigonometric identity find the height of triangle (apothem)

we have that

tan(72)=h/5

h=5*tan(72)

h=76.94 mm

answer part 2

apothem is 76.94 mm

Part 3

Find the area

the area is equal to

A=(1/2)*(apothem)*s

A=(1/2)*76.94*10

A=384.71 mm2

The Wildcats and the Leopards are evenly matched football teams. Whenthey play, there is a 0.5 probability that the Wildcats will win. If they play 9times, what is the probability that the Wildcats will win 6 of the games?Round your answer to the nearest tenth of a percent.A 24.6%B. 0.2%O C. 7.0%D. 16.4%

Answers

To answer this question, we need to use the probability using the Binomial Distribution. Because we are finding an exact probability, we can use the next formula:

[tex]C(9,6)\cdot(\frac{1}{2})^6\cdot(\frac{1}{2})^{(6-3)}=0.1640[/tex]

Or the probability is about 16.40%.

C(9, 6) is the combination of 9 out of 6. They are going to play 9 games, but we are finding the probability that the Wildcats win 6. Then:

[tex]C(n,k)=\frac{n!}{(n-k)!\cdot k!}\Rightarrow C(9,6)=\frac{9!}{(9-6)!\cdot6!}=\frac{9\cdot8\cdot7\cdot6!}{3!\cdot6!}=\frac{9\cdot8\cdot7}{3\cdot2\cdot1}=84[/tex]

Then, the general formula for the Binomial Distribution is:

[tex]C(n,k)\cdot(p)^k\cdot(q)^{n-k}[/tex]

In this case, the probability of p = q = 1/2, k = 6, n = 9. Then, applying the formula, we obtain a probability of 0.1640 or about 16.40%. The correct option is D.

What is the slope of the line that contains these points? х 5 6 7 8 у -3 -1 1 3 slope:

Answers

p1( 5, -3) and p2(8,3)

the slope is:

[tex]\text{slope}=\frac{y2-y1}{x2-x1}=\frac{3-(-3)}{8-5}=\frac{3+3}{3}=\frac{6}{3}=2[/tex]

slope = 2

1. Draw a scaled copy of either Figure A or B using a scale factor of 3.2. Draw a scaled copy of either Figure C or D using a scale factor of 1/2

Answers

For a Scaled copy multiply each side length by the scale factor

1.

A

Multiply each side by 3 , and then connect the missing side:

C. figure C

Multiply each side length by 1/2

Manuel's coffee shop makes a blend that is a mixture of two types of coffee. type A coffee costs Manuel $4.35 per pound, and type B coffee cost $5.45 per pound. this month, Manuel made 175 pounds of the blend, for a total cost of $866.85 how many pounds of type A coffee did he use

Answers

Step 1

Type A coffee costs $4.35 per pound

Type B coffee cost $5.45 per pound.

Manuel made 175 pounds of the blend at a total cost of $866.85

Required; To find how many pounds of type A coffee used.

Step 2

Write a system of equation

[tex]\begin{gathered} 4.35A+5.45B=866.85--(1) \\ A+B=175---(2) \end{gathered}[/tex]

Step 3

Find the value of A

[tex]\begin{gathered} \text{From 2} \\ B=175-A \\ \text{Substituting this in 1 gives} \\ 4.35A+5.45(175-A)=866.85 \\ 4.35A+953.75-5.45A=866.85 \\ 953.75-866.85=5.45A-4.35A \\ 86.9=1.1A \\ \frac{1.1A}{1.1}=\frac{86.9}{1.1} \\ A=79\text{ pounds} \end{gathered}[/tex]

Hence, Manuel used 79 pounds of type A coffee

How many terms are in the polynomial abcd + e-h²?O sixO fiveO threeO two

Answers

There are three terms in the given polynomial.

EXPLANATION

Given:

abcd + e - h²

We are to find the number of terms.

Monomial or the sum or difference of two or more polynomials is Known as a polynomial.

Whatever comes (be it a variable or constant) before an addition or subtraction is consideres to be a term.

From the polynomial given;

abcd = first term

e = second term

- h² = third term.

Therefore, there are 3 terms in the given polynomial.

Debby filled 10 times as many buckets of water as Marty, and Melissa filled 6 times as many buckets as Marty. All
3 together filled 136 buckets of water to fill a pool. How many buckets did Marty fill?

Answers

ANSWER

Marty filled 8 buckets of water

EXPLANATION

Let

• x: number of buckets Marty filled

,

• y: number of buckets Debby filled

,

• z: number of buckets Melissa filled

We know that Debby filled 10 times as many buckets as Marty:

[tex]y=10x[/tex]

And that Melissa filled 6 times as many buckets as Marty:

[tex]z=6x[/tex]

All three of them together fulled 136 buckets:

[tex]x+y+z=136[/tex]

Replace y and z as functions of x:

[tex]x+10x+6x=136[/tex]

And solve for x. First add like terms:

[tex]\begin{gathered} (1+10+6)x=136 \\ 17x=136 \end{gathered}[/tex]

And divide both sides by 17:

[tex]\begin{gathered} \frac{17x}{17}=\frac{136}{17} \\ x=8 \end{gathered}[/tex]

We found that Marty filled 8 buckets of water.

Multiply the following by applying the distributive property.- 3a(4a² – 4a+2)=

Answers

Answer:

[tex]-12a^3_{}+12a^2-6a[/tex]

Given:

[tex]-3a(4a^2-4a+2)[/tex]

The distributive property is defined as:

[tex]a(b+c)=ab+ac[/tex]

Applying this to our given expression and we will have:

[tex]\begin{gathered} -3a(4a^2-4a+2) \\ (-3a)4a^2-(-3a)4a+(-3a)2 \\ -12a^3_{}+12a^2-6a \end{gathered}[/tex]

Therefore, the answer is:

[tex]-12a^3_{}+12a^2-6a[/tex]

I need help with this question please. Ignore the words below it, they’re just part of option A. I also have options to choose from.

Answers

We have a guide graph:

[tex]f(x)=x^2[/tex]

but this function undergoes a series of transformations after altering the function to be expressed as follows

[tex]g(x)=3(x-1)^2+2[/tex]

For this, we must remember the function transformation rules.

1.

[tex]y=g(x-c)[/tex]

Where "c" units are moved horizontally to the right.

That is to say that in our function g(x) the function describes a translation of one unit to the right.

2.

[tex]y=g(x)+c[/tex]

Where "c" units are moved vertically upwards.

That is to say that in our function g(x) the function describes a translation of two units to upwards

3.

[tex]y=c\cdot g(x)[/tex]

Where if c>1 it vertically stretches the graph of y=g(x) by a factor of "c".

That is to say that our function has a vertical stretch by a factor of 3.

In conclusion, the option that meets a vertical stretch with a factor of 3 and a translation of 1 unit to the right and 2 units upward is option C.

I need help and the problems are not making sense to me

Answers

Take into account that the range of a function is given by all values of the dependent variable. In this case, the dependent variable is the distance represented by the y-axis.

You can notice that the values of the distance (the range in this case) is in between the following interval:

100 ≤ y ≤ 350

The population of algae in an experiment has been increasing by 30% each day. If there were 100 algae at the beginning of the experiment, predict the number of algae in 5 days.Pls help

Answers

The algae has an increase rate of 30% per day, this is an exponential increase, to calculate ot you have to use the following formula:

[tex]y=a(1-r)^x[/tex]

Where

a is the initial value

r is the growth rate

x is the time passed

y is the total growth after x time has passed

For this exercise, the initial number is 100 algae, the rate of growth is 0.3 and the time is 5 days, replace it in the formula:

[tex]\begin{gathered} y=100(1+0.3)^5 \\ y=371.293 \end{gathered}[/tex]

After 5 days you'll expect that the number of algae will gro by 371.293

Other Questions
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