I hate angles Please help......

Answer:

1.504 x 10^4

Step-by-step explanation:

The probability that a randomly selected can in the box is dented or contains vegetables is 19/20.

To solve the problem, we need to use the formula for the probability of the union of two events:

P(A or B) = P(A) + P(B) - P(A and B)

where A and B are two events.

In this case, we want to find the probability that a randomly selected can is dented or contains vegetables. Let's call these events D and V, respectively.

We are given that there are 20 cans in total, 12 of which contain vegetables, and 5 of which are dented, with 2 of the dented cans containing vegetables. This information allows us to calculate the probabilities of the individual events

P(D) = 5/20 = 1/4

P(V) = 12/20 = 3/5

P(D and V) = 2/20 = 1/10

To find the probability of the union of these events, we plug these values into the formula

P(D or V) = P(D) + P(V) - P(D and V)

= 1/4 + 3/5 - 1/10

= 19/20

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If 54 oranges cost 36 naira, then the cost of 3 oranges​ is 2 naira

Unitary method is a method of solving problems by finding the value of one unit and then using that value to find the value of a given number of units

To find the cost of 3 oranges, we can use unitary method which involves finding the cost of one orange and then multiplying it by 3.

Let's first find the cost of one orange

54 oranges cost 36 naira

So, 1 orange will cost:

1/54 of 36 naira = (36/54) naira = (2/3) naira

Now, we can find the cost of 3 oranges by multiplying the cost of one orange by 3

Cost of 3 oranges = 3 x (2/3) naira = 2 naira

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It is true that common or natural causes of variation determine control limits, as they are used to establish the expected range of variation in a process, helping to identify when the process is in control or experiencing unusual variations due to special causes.

True.

Common or natural causes of variation do determine control limits.

In the context of quality control and process improvement, control limits are boundaries set to help identify when a process is behaving as expected (in control) or when it is experiencing unusual variations (out of control).

These limits are determined using statistical calculations based on data collected from a process over time.
Common causes of variation are the inherent sources of variability within a process, which occur naturally and are considered normal.

Examples of common causes include minor differences in raw materials, fluctuations in temperature, and slight variations in machine settings.

When a process is in control, it is operating with only common causes of variation present.
Control limits are calculated based on the average and standard deviation of a process, which take into account the natural variability caused by common causes.

By setting upper and lower control limits, we can monitor the process and determine if it is staying within the expected range of variation.

If data points fall outside of the control limits, it suggests that special or assignable causes of variation are present, indicating a need for further investigation and potential process improvement.

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Answer:

point in original figure 2,4

point in final figure -4,2

Step-by-step explanation:

Answer:

[tex] \frac{ {g}^{4} {h}^{2} }{ g{h}^{6} } = \frac{ {g}^{3} }{ {h}^{4} } [/tex]

because other values are 1, and this one is less, because g<h

[tex]\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ V=2827.43\\ h=4 \end{cases}\implies 2827.43=\pi r^2(4)\implies \cfrac{2827.43}{4\pi }=r^2 \\\\\\ \sqrt{\cfrac{2827.43}{4\pi }}=r\hspace{5em}\stackrel{\textit{twice that is the \underline{diameter}}}{2\sqrt{\cfrac{2827.43}{4\pi }}} ~~ \approx ~~ \text{\LARGE 30}[/tex]

The solution to the system of equations using the substitution method is option (c) (-5,8)

To solve this system of equations using the substitution method, we need to substitute the second equation into the first equation for y, then solve for x.

The substitution method is a way to solve a system of equations by solving one of the equations for one of the variables, and then substituting that expression into the other equation to get an equation with only one variable.

Substitute y = 8 into the first equation

x + y = 3

x + 8 = 3

x = 3 - 8

Subtract the numbers

x = -5

Therefore, the correct option is (c) (-5,8).

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The answer is A. Evaluation researchers encounter more logistical problems than other researchers because evaluation research occurs in the context of real life.

Evaluation research often takes place in real-world settings, which can present logistical challenges such as accessing participants, coordinating schedules, and dealing with unexpected events. Additionally, evaluation research often involves multiple stakeholders and requires collaboration and communication among various groups, which can further complicate logistical issues. While evaluation research may also involve longer timelines, higher costs, measurement problems, and examination of multiple variables, these factors do not necessarily contribute to greater logistical challenges.

This means that evaluation researchers have to navigate complex, real-world situations, adapt to unforeseen challenges, and work with various stakeholders, making the research process more logistically challenging compared to controlled laboratory settings or theoretical research.

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Evaluation research is a type of research that focuses on assessing the effectiveness, efficiency, and impact of programs, policies, or interventions in real-life settings.

The correct answer is A. occurs in the context of real life.

This often involves evaluating the outcomes and impacts of interventions in complex and dynamic environments, such as organizations, communities, or systems. As a result, evaluation researchers may encounter more logistical problems compared to other types of researchers because they need to navigate real-life contexts, deal with multiple stakeholders, collect data from diverse sources, and address issues such as ethics, confidentiality, and validity in the evaluation process. Logistical problems may include challenges related to data collection, measurement, sample selection, data quality, and managing time and resources.

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Probability that the total weight for the two animals is 225 pounds or more is 0.17.

We need to use the joint probability distribution for X and Y, where X and Y are the weights of the first and second animals, respectively. Let's denote the joint probability distribution as P(X=x, Y=y).

From the table given, we can see that the possible values of X and Y are 100, 120, and 140 pounds. To find the probability that the total weight is 225 pounds or more, we need to sum the joint probabilities for all pairs of (X,Y) that satisfy X+Y≥225.

These pairs are:

So, we have:

P(X+Y≥225) = P(X=120, Y=120) + P(X=100, Y=120) + P(X=120, Y=100) + P(X=100, Y=140) + P(X=140, Y=100) + P(X=120, Y=140) + P(X=140, Y=120) + P(X=140, Y=140)

Substituting the values from the table, we get:

P(X+Y≥225) = 0.04 + 0.03 + 0.03 + 0.01 + 0.01 + 0.02 + 0.02 + 0.01

P(X+Y≥225) = 0.17

Therefore, the probability that the total weight for the two animals is 225 pounds or more is 0.17.

So the response closest to 0.17 is 0.195.

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To perform a bootstrapped likelihood ratio test, you need to fit the two nested models to your data, calculate the likelihood ratio test statistic, generate bootstrap samples, fit the two models to each bootstrap sample, calculate the p-value, and interpret the results.

The bootstrapped likelihood ratio test is a statistical method used to compare the goodness-of-fit of two nested models. Here's how you can perform a bootstrapped likelihood ratio test

Fit the two nested models: Start by fitting the two nested models to your data. One model is a restricted model, and the other is an unrestricted model that contains additional parameters.

Calculate the likelihood ratio test statistic: Calculate the likelihood ratio test statistic by subtracting the log-likelihood of the restricted model from the log-likelihood of the unrestricted model. This gives you the test statistic (often denoted as "LR").

Generate bootstrap samples: Generate a large number of bootstrap samples from the original dataset. Each bootstrap sample should be the same size as the original dataset and drawn with replacement.

Fit the two models to each bootstrap sample: For each bootstrap sample, fit the two nested models and calculate the likelihood ratio test statistic as described in steps 1 and 2.

Calculate the p-value: Calculate the p-value as the proportion of bootstrap samples for which the likelihood ratio test statistic is greater than or equal to the test statistic calculated from the original dataset.

Interpret the results: If the p-value is less than your chosen significance level (e.g., 0.05), you can reject the null hypothesis that the restricted model is better than the unrestricted model in favor of the alternative hypothesis that the unrestricted model is better.

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Estimate the mean number of travel days per year for salespeople employed by three hardware distributors with a 0.90 degree of confidence and an error margin of 2 days, a sample size of at least 179 salespeople should be selected.

The sample size needed to estimate the population mean with a 0.90 degree of confidence:

[tex]n = (Z\times\sigma / E)^2[/tex]

where:

Z = the Z-score for the desired level of confidence (0.90 corresponds to a Z-score of 1.645)

σ = the population standard deviation (unknown)

E = the maximum error of the estimate, which is given as 2 days

We can estimate the population standard deviation using the sample standard deviation from the pilot study, which is given as 16 days.

Therefore, plugging in the values, we get:

[tex]n = (1.645 \times 16 / 2)^2 = 178.26[/tex]

Rounding up to the nearest whole number, we get a minimum sample size of 179 salespeople.

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76.74 milligrams will remain after 32 hours.

N(t) = N₀e^(-kt)

where:

N(t) is the amount of substance remaining after time t

N₀ is the initial amount of substance

k is the decay constant

To solve for the decay constant, use the information given in the problem:

100 = 200e^(-22k)

Dividing both sides by 200, we get:

0.5 = e^(-22k)

Taking the natural logarithm of both sides, we get:

ln(0.5) = -22k

Solving for k, we get:

k = ln(0.5)/(-22) = 0.0316

Use this value of k to find the amount of substance remaining after 32 hours:

N(32) = 200e^(-0.0316*32) = 76.74 mg

Therefore, approximately 76.74 milligrams of the substance will remain after 32 hours.

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76.4 milligrams will remain after 32 hours.

Exponential refers to a mathematical function in which a constant base is raised to a variable exponent. The value of the function increases or decreases rapidly as the exponent increases, depending on whether the base is greater than 1 or between 0 and 1. Exponential functions are commonly used to model situations where a quantity grows or decays at a constant percentage rate over time.

Decay is the natural process of deterioration or rotting of a substance over time. It can occur in both organic and inorganic materials and is often caused by the activity of microorganisms, exposure to oxygen or other environmental factors.

To determine the amount of radioactive substance that remains after 32 hours, we can use the formula A = A₀ ×[tex]e^{-kt}[/tex], where A is the amount remaining, A₀ is the initial amount, k is the decay constant, and t is the time elapsed.

we can use the same formula for exponential decay to find the value of k:

100 = 200 × [tex]e^{(-k*22)}[/tex]

0.5 = [tex]e^{(-k*22)}[/tex]

ln(0.5) = -k×22

k = ln(2)/(22)

Now we can use this value of k to find the amount of substance remaining after 32 hours:

N(32) = 200 [tex]e^{(-k*32)}[/tex]

N(32) = 200 [tex]e^{(-(ln(2)/(22))32)}[/tex]

N(32) ≈ 76.4 mg

Therefore, approximately 76.4 milligrams of the substance will remain after 32 hours.

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f(x) = N * 4^x  is an exponential function that represents the number of new participants of the challenge as a function of the day number, x.

We define our variables:

N: the total number of participants on Day 1 (including Aliyah, Kim, and Reese)

r: the constant ratio by which the number of participants grows each day

x: the number of days since Day 1

r = 4.

There are N participants on Day 1. Each of the N participants contacts 4 new participants on Day 2, resulting in a total of 4N participants.

Each of the 4N participants makes contact with 4 new participants on Day 3, resulting in a total of 4(4N) = 16N people. Since we can see that there are more participants every day, we can write:

f(x) = N * 4^x as an exponential function that represents the number of new participants of the challenge as a function of the day number, x.

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Answer: Let x be the number of race entries. In order to raise at least $55,000, we must have 45x + 17,900 ≥ 55,000 −45x ≥ −37,100 x ≤ -37,100/45 x ≤ 824.44 Therefore, the charity needs 824 or more race entries to raise at least $55,000.

9. The value of the land today, if the land was purchased for $3,500 in 1960, at the value increased at 3% per year is $22,532.7

A percentage increase is the ratio of the difference in the initial and current value of an item to the initial value, expressed as a percentage.

The year the land was purchased = 1960

The amount at which the land was purchased, P = $3,500

The percentage rate by which the value of the land increased, r = 3%

The value of the land today, A, can be found using the compound interest formula as follows;

Value of the land, A = P·(1 + r)ⁿ

Where;

n = The number of years = 2023 - 1960 = 63

Therefore; A = 3500 × (1 + 3/100)⁶³ ≈ 22532.7

The value of the land today is about $22,532.7

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Answer:

0.71 weeks

Step-by-step explanation:

To convert 5 days to weeks, we can use the conversion factor:

1 week = 7 days

Therefore, we have:

5 days = 5/7 weeks

Rounding to the nearest hundredth, we get:

5 days ≈ 0.71 weeks

Therefore, 5 days is approximately equal to 0.71 weeks.

Answer: 4545 yards

Step-by-step explanation:

We can use similar triangles to solve this problem. Let's represent the height of the flagpole with the variable "x".

Using the triangle formed by Carla's line of sight, the height of the apartment building, and the top of the flagpole, we can set up the following proportion:

x / (x + 1515) = 15 / 20

Simplifying this proportion, we get:

4x = 3(x + 1515)

4x = 3x + 4545

x = 4545

Therefore, the height of the flagpole is 4545 yards.

The average speed of the current is 1 mile per hour.

To construct a rational equation that can be solved for the speed of the current, we can use the relationship t = d/r, where t is the time taken, d is the distance traveled, and r is the speed. We can set up two equations using this relationship, one for the upstream journey and one for the downstream journey:

Upstream journey: t = 4/(10-c)

Downstream journey: t = 6/(10+c)

Here, c represents the speed of the current. We use 10-c for the upstream journey because the current is going against the boat's direction, effectively reducing the boat's speed. Conversely, we use 10+c for the downstream journey because the current is aiding the boat's direction, effectively increasing the boat's speed.

Now, we can set these two equations equal to each other and solve for c:

4/(10-c) = 6/(10+c)

Multiplying both sides by (10-c)(10+c), we get:

4(10+c) = 6(10-c)

Simplifying and solving for c, we get:

c = 1

This means that when the boat is traveling with the current, its effective speed is 11 miles per hour, and when it's traveling upstream, its effective speed is 9 miles per hour.

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Answer:

5x

6xy

2x3y

hope it's helpful

Answer:

44.12

Step-by-step explanation:

since area of a circle is (pi)(r^2), a semi circle would be that divided by 2. and so plugging in the radius squared, multiplying by pi, then dividing by 2, boom. A=44.12.

Answer: second one!

Step-by-step explanation:

Answer:√2/2

Step-by-step explanation:

Let's label the sides of the right triangle as follows:

The side adjacent to the angle θ (cosine is adjacent/hypotenuse): 6

The hypotenuse (the longest side): 6√2

The side opposite to the angle θ (sine is opposite/hypotenuse): 6√3

Using the Pythagorean theorem, we can find the length of the missing side:

a² + b² = c²

6² + (6√3)² = (6√2)²

36 + 108 = 72

144 = 72

√144 = √72

12 = 6√2

Now that we know the length of all three sides, we can use the cosine ratio to find the value of cos(θ):

cos(θ) = adjacent/hypotenuse = 6/6√2 = √2/2

Therefore, the value of cos(θ) in the right triangle with sides of 6, 6√2, and 6√3 is √2/2.

Answer: To solve -x²-2x=0 by factoring, we can factor out x from the left-hand side:

x(-x-2) = 0

This equation is true if either x = 0 or -x-2 = 0. Solving for x in the second equation:

-x-2 = 0

-x = 2

x = -2

Therefore, the solutions to the equation -x²-2x=0 are x = 0 and x = -2.

To solve x²-4x-8--6x by factoring, we can simplify it first by combining like terms:

x²-10x-8 = 0

To factor this quadratic, we need to find two numbers that multiply to -8 and add to -10. These numbers are -2 and -8, so we can write:

x²-2x-8x-8 = 0

(x²-2x) - (8x+8) = 0

x(x-2) - 8(x+1) = 0

(x-8)(x-2) = 0

Therefore, the solutions to the equation x²-4x-8--6x are x = 8 and x = 2.

To solve 3x² +12=-21x-24 by completing the square, we first need to move all the terms to one side:

3x² + 21x + 36 = 0

Next, we divide both sides by 3 to simplify the coefficient of x²:

x² + 7x + 12 = 0

To complete the square, we need to add and subtract (7/2)² = 49/4 inside the parentheses:

x² + 7x + 49/4 - 49/4 + 12 = 0

(x + 7/2)² = 1/4

Taking the square root of both sides and solving for x, we get:

x + 7/2 = ±1/2

x = -7/2 ± 1/2

Therefore, the solutions to the equation 3x² +12=-21x-24 by completing the square are x = -4 and x = -3.

To solve -x²-3x-13 = -2x² by using the quadratic formula, we first need to move all the terms to one side:

-x² + x - 13 = 0

Next, we identify the coefficients a, b, and c:

a = -1, b = 1, c = -13

Substituting these values into the quadratic formula:

x = (-b ± sqrt(b² - 4ac)) / 2a

x = (-1 ± sqrt(1² - 4(-1)(-13))) / 2(-1)

x = (-1 ± sqrt(1 + 52)) / (-2)

x = (-1 ± sqrt(53)) / (-2)

Therefore, the solutions to the equation -x²-3x-13 = -2x² by using the quadratic formula are approximately x = -3.25 and x = 4.25.

Step-by-step explanation:

Statement (c) is correct i.e. The data is bimodal, with a maximum range of 24. This means that the tide was frequently between 6 to 10 or 16 and 20 feet.

What is Histogram?

A histogram is a  representation of data that shows the distribution of numerical data. It consists of a series of rectangles, called bins or bars, that represent intervals or ranges of data values, and the height of each rectangle represents the frequency or count of data values that fall within that interval. Histograms are used to visualize the shape of the distribution of data, including measures of central tendency and variability.

number of observations of each interval are :

1 to 5: 2 observations.

6 to 10: 6 observations.

11 to 15: 2 observations.

16 to 20: 5 observations.

21 to 25: 1 observations.

Here are two similarly high bins 1-5 and 11-15,

hence, the distribution can be said to be bimodal.

the max range can be calculated as  25 - 1 = 24.

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The solution to the given system of equations is x = -3 and y = 4 or (-3,4)

Now, for given problem

2x + 5y = 14 ................(1)

4x + 2y = -4 ................(2)

Multiply equation (1) by '2' and equation (2) by '-1' :

4x + 10y = 28 ................(3)

-4x - 2y = 4 ..................(4)

Adding equations (3) and (4) to eliminate 'x':

4x + 10y + (-4x) - 2y = 28 + (4)

8y = 32

y = 32 / 8

y = 4

on substituting the value (y = 4) into equation (1), we get :

2x + 5(4) = 14

2x + 20 = 14

2x = 14 - 20

2x = -6

x = (-3)

Hence, solution for the given system of equations is (-3,4).

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The only ball that weighs 30g is ball A. So the answer is: Ball A weighs 30g.

To determine which ball weighs 30g, we need to compare the weights of each ball.

We know that there are five balls, and that their weights are 30g, 50g, 50g, 50g, and 80g.

Since we are looking for the ball that weighs 30g, we can eliminate the other weights one by one. We know that ball E weighs 80g, so it cannot be the one we're looking for. We can also eliminate balls B, C, and D since they all weigh 50g.

Therefore, the only ball that weighs 30g is ball A. So the answer is: Ball A weighs 30g.

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Point A = (5,4). If you rotated A 90 degrees about the point (2,-1), the coordinates of A' is (-1,2).

Rotation is the process of rotating an object or a point around a fixed point or axis. In mathematics, rotation refers to a transformation that preserves the size and shape of an object while changing its orientation. It is a basic geometric transformation that is used in various fields, including mathematics, physics, engineering, and computer graphics.

In a two-dimensional space, a rotation is typically described by an angle of rotation and a fixed point, which is known as the center of rotation. The angle of rotation represents the amount by which the object is rotated, while the center of rotation is the point around which the object is rotated. In a three-dimensional space, a rotation is described by an axis of rotation and an angle of rotation.

To rotate point A 90 degrees counterclockwise about the point (2,-1), we can use the following formula:

A' = (x', y') = (a + (x - a) cosθ - (y - b) sinθ, b + (x - a) sinθ + (y - b) cosθ)

where (a,b) is the center of rotation and θ is the angle of rotation (90 degrees in this case).

Substituting the given values, we get:

a = 2, b = -1, x = 5, y = 4, θ = 90 degrees

x' = 2 + (5 - 2) cos(90) - (4 + 1) sin(90) = 2 - 3 = -1

y' = -1 + (5 - 2) sin(90) + (4 + 1) cos(90) = -1 + 3 = 2

Therefore, the coordinates of A' are (-1, 2).

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Answer:

$21.28

Step-by-step explanation:

We Know

Dylan bought 3 identical shirts online for a total cost of $71.83

$7.99 for shipping

We have the equation:

71.83 = 3s + 7.99

63.84 = 3s

s = $21.28

So, each shirt cost $21.28