i need help asap pls!!

Answer:

7 pepperoni pizzas

Step-by-step explanation:

First, you take the biggest number and subtract it by 9.5 until you get a number that can be divided into 11 which is 77.

Answer:

7 pepperoni pizzas

Step-by-step explanation:

Where p = # of pepperoni pizzas and m = # of mushroom pizzas

124.50 = 11p + 9.5m

Now you need to guess and check:

Use this equation: (124.5 - 11 * p) / 9.5 and replace p with whole numbers until you get a whole number as the output

I got p=7 and m=5

So she bought 7 pepperoni pizzas

Answer:

La²+8La+16 = La²+70

Step-by-step explanation:

8La+16 = 70

8La=70-16

La=54/8

La= 6.75

Area b = (6.75+4)*(6.75+4)

Area b = 10.75*10.75

Area b =115.563

The area of a square is the square of its side lengths

The area of square B is 116 centimeter square

Let the side length of square A be (a), and the side length of square B be (b)

So, we have:

[tex]\mathbf{A_a = a^2}[/tex]

[tex]\mathbf{A_b = b^2}[/tex]

From the question, we have:

[tex]\mathbf{A_b = 70 + a^2}[/tex]

[tex]\mathbf{b = 4 + a}[/tex]

Take square of both sides

[tex]\mathbf{b^2 = (4 + a)^2}[/tex]

[tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex]

Substitute [tex]\mathbf{b^2 = 16 + 8a+ a^2}[/tex] in [tex]\mathbf{A_b = b^2}[/tex]

[tex]\mathbf{A_b = 16 + 8a+ a^2}[/tex]

So, we have:

[tex]\mathbf{16 + 8a+ a^2 = 70 + a^2}[/tex]

Subtract a^2 from both sides

[tex]\mathbf{16 + 8a = 70}\\[/tex]

Subtract 16 from both sides

[tex]\mathbf{8a = 54}[/tex]

Divide both sides by 8

[tex]\mathbf{a = 6.75}[/tex]

Recall that:

[tex]\mathbf{A_b = 70 + a^2}[/tex]

So, we have:

[tex]\mathbf{A_b = 70 + 6.75^2}[/tex]

[tex]\mathbf{A_b = 115.5625}[/tex]

Approximate

[tex]\mathbf{A_b = 116}[/tex]

Hence, the area of square B is 116 centimeter square

Read more about areas at:

https://brainly.com/question/1658516

Answer:

The correct option is B

Step-by-step explanation:

just did the test on Ed.

Answer:

no se yo hablo español si me entiendes sigueme y te sigo

Answer:

c = 48m

Step-by-step explanation:

For every box, she can make 240/5 = 48 cupcakes. So, the equation is

c = 48m

Answer:

Step-by-step explanation:

c

Answer:

Step-by-step explanation:

5x⁴ - 2x³ + 12x² + 24x - 26

Degree = 4

Leading term = 5x⁴

Leading coefficient = 5

Answer:

31.4

Step-by-step explanation:

Answer:

Step-by-step explanation:

Option c

Answer:

I don't know that but the W is x+1/2

Step-by-step explanation:

hope this helps

Answer:

A

Step-by-step explanation:

The chance the coin will show 'tails' is 1/2, since there are only 2 sides to a coin. The chance that the die will show an even number is also 1/2, since half of the numbers on a die are even, and half are odd. But, since both of these events depend on each other, or in other words, are dependent, we have to multiply both numbers. 1/2 x 1/2 = 1/4, therefore your answer is A.

Answer:

fafafasda

Step-by-step explanation:

wdwasdsa wr 1+11123121

Answer:

Graph #2

Step-by-step explanation:

I would use Desmos for this, makes it easier to find out which graph is for the equation.

9514 1404 393

Answer:

  an = 13 -5(n -1)

Step-by-step explanation:

The "take away 5" rule means the common difference between terms is d=-5. For first term a1=13, the n-th term is ...

  an = a1 +d(n -1)

  an = 13 -5(n -1)

Answer:

10 feet

Step-by-step explanation:

2.5/5=5/Summer's shadow

Summer's shadow=25/2.5

Summer's shadow=10 feet

Answer:

28.5

Step-by-step explanation:

Plzz mark brainlies thanks!!

Answer:

82 is 42 degrees warmer than 40

Step-by-step explanation:

if you subtract 40 from 82, you get 42 meaning that the answer will be 42 degrees more than 40

Answer:

hows your day going? :)

Answer:

y=2/7x

Step-by-step explanation:

y=mx+b where m=slope and b=y-intercept

y=2/7x+0

y=2/7x

Answer:

Calculate the volume of a cylinder using the formula V = r2 × π × h. Begin by first finding the area of the circle at one end. Square the radius of the circle and multiply the result by "pi" (the symbol π), or approximately 3.14. Multiply this result by the cylinder's height to get its volume.

Step-by-step explanation:

the height is 4 and the radius is 2

Answer: 6

Step-by-step explanation:  [tex]log_{2} 64 = 6[/tex]

Answer:

9/8 of a bag

she doesn't have enough beads.

Step-by-step explanation:

Bag of bead poppy has = 1

Bag of bead needed for necklace 1 = 3/8 of a bag

Bag of bead needed for necklace 2 = 1/8 of a bag

Bag of bead needed for necklace 3 = 5/8 of a bag

Total bag of beads needed = 3/8 + 1/8 + 5/8

= (3+1+5)/8

= 9/8

She needs 9/8 of a bag of bead

9/8 = 1 1/8

Therefore, she doesn't have enough beads.

Answer:

19.47

Step-by-step explanation:

I plugged it into a right triangle trig calculator

Answer:

HERE ARE SOME NOTES ON HOW TO DO these types of geo- problems and some more ! SORRY .

See attachment below!

Step-by-step explanation:

If your in High school Geometry, I could help with that and more!

If your someone who likes to have Notes.. I could send you some PDF's and more for Geometry!!  I took Geometry and have good notes!

Step-by-step explanation:

y = 6x-11

substitute y into 2x+3y=7

2x+3(6x-11)=7

2x + 18x-33 = 7

20 x = 7+33

x = 2

y?

y= 6(2)-11

y = 12-11 = 1

so, x = 2 and y = 1

Answer:

Hence, the total amount of money that the investor would have after 6 years will be $ 536.04 .

Step-by-step explanation

Answer:

Interest = $3573.048

Step-by-step explanation:

Given: $3000 is invested for a period of 3 years at a rate of 6% compound monthly. What will the balance in the account be at the end of 3 years?

The formula to compound interest is:

I = P(1 + R)^T

First, put in the terms:

I = $3000(1 + 6%)^3

Then calculate:

I = $3000(1 + [tex]\frac{6}{100}[/tex])^3

I = $3000(1 + 0.06)^3

I = $3000(1.06)^3, 1.06^3 = 1.191016

I = $3000 x 1.191016

I = $3573.048

Answer:

x=[tex]-3+\frac{1}{2}\sqrt{2}[/tex]  

x=[tex]-3+\frac{-1}{2} \sqrt{2}[/tex]

Step-by-step explanation:

Answer: the answer is 2 teaspoons of vanilla extract.

hope this helped

Answer:

[tex]\displaystyle 5[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{32}{39}} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

OR

[tex]\displaystyle \boxed{y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-1\frac{25}{39}} \hookrightarrow \frac{-\pi}{\frac{39}{64}\pi} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{3\frac{11}{39}} \hookrightarrow \frac{2}{\frac{39}{64}\pi}\pi \\ Amplitude \hookrightarrow 5[/tex]

As you can see, the right-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5cos\:\frac{39}{64}\pi{x} + 1,[/tex]in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph farthest to the left], accourding to the horisontal shift formula above. Also keep in mind that −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so be very careful with your calculations. So, between both photographs, we can tell that the cosine graph [centre right photograph] is shifted [tex]\displaystyle \frac{32}{39}\:unit[/tex]to the right, which means that in order to match the sine graph [photograph farthest to the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{32}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you get [tex]\displaystyle \boxed{-\frac{32}{39}} = \frac{-\frac{\pi}{2}}{\frac{39}{64}\pi}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = -5cos\:(\frac{39}{64}\pi{x} + \frac{\pi}{2}) + 1.[/tex]Intermediate, we have two sine graphs [centre left photograph and the photograph farthest to the left]. The left-centred photograph displays the trigonometric graph of [tex]\displaystyle y = -5sin\:\frac{39}{64}\pi{x} + 1.[/tex]So, just like before, we need to figure out the appropriate C-term that will horisontally shift the graph back into position ["position", meaning shifting this sine graph back in plase (matching the sine graph in the photograph on the left)]. So, between the two photographs, we can tell that the left-centred sine graph is shifted [tex]\displaystyle 1\frac{25}{39}\:unit[/tex]to the right, which means that in order to match the leftward sine graph, we need to shift the graph BACKWARD [tex]\displaystyle 1\frac{25}{39}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-1\frac{25}{39}} = \frac{-\pi}{\frac{39}{64}\pi}.[/tex]So, when shifted back into original position, the sine graph is [tex]\displaystyle y = -5sin\:(\frac{39}{64}\pi{x} + \pi) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-6\frac{22}{39}, 1],[/tex]from there to [tex]\displaystyle [-3\frac{11}{39}, 1],[/tex]they are obviously [tex]\displaystyle 3\frac{11}{39}\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 3\frac{11}{39}.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, and in case you want to be certain, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended five units beyond the midline, hence, your amplitude. Now... the sine graph in the photograph farthest to the right is the OPPOCITE of the sine graph in the photograph farthest to the left, and the reason for this is because of the negative inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of any trigonometric equation, the whole graph reflects over the midline. Keep this in mind moving forward. So, overall, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

the answer is c hope it help

Answer: D

Step-by-step explanation:

1. movethe constanat to the right

2. Calculate

3.The statement is false