i need help on this math problem

Answer:

1  C

2  A

Step-by-step explanation:

1 C No it cannot be defined because A and B are not congruent

2  A Yes, the lines will remain parallel

PS. It's only 50 points because two answers are allowed. Each answerer gets half.

let's recall that the conjugate of say a + b is simply the same thing with a different sign in between, namely a - b, so let's use the conjugate of the denominator and multiply top and bottom by it.

[tex]\textit{difference of squares} \\\\ (a-b)(a+b) = a^2-b^2 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{4+\sqrt{2}}{2-\sqrt{2}}\cdot \cfrac{2+\sqrt{2}}{2+\sqrt{2}}\implies \cfrac{(4+\sqrt{2})(2+\sqrt{2})}{\underset{\textit{difference of squares}}{(2-\sqrt{2})(2+\sqrt{2})}}\implies \cfrac{(4+\sqrt{2})(2+\sqrt{2})}{2^2-(\sqrt{2})^2}[/tex]

[tex]\cfrac{8+4\sqrt{2}+2\sqrt{2}+(\sqrt{2})^2}{4-2}\implies \cfrac{8+4\sqrt{2}+2\sqrt{2}+2}{2}\implies \cfrac{10+6\sqrt{2}}{2} \\\\\\ \cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(5+3\sqrt{2})}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \boxed{5+3\sqrt{2}}[/tex]

Answer:

3

Step-by-step explanation:

3.45x+2*1.65+5>=20

3.45x+8.3>=20

3.45x>=11.7

after rounding

x>=3

Answer:

i believe the and\swe is g because it is located within the boundaries of plane p but is on a line (not the green segments) that goes outside of plane p

Step-by-step explanation:

Answer: I think the answer is C.. It looks like an 180 angle from my perspective.

I hope that is correct

Answer:

C

Step-by-step explanation:

Well, we know all the angles must sum up to 180º. From this, we can write the equation ' 3xº + 80º + 2xº = 180º ', which is answer choice C

Answer:

19

Step-by-step explanation:

Note that

[tex]\dfrac{10a}{b+c} + \dfrac{10b}{a+c} + \dfrac{10c}{a+b} = 10\left(\dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b} \right)[/tex]

and

[tex]\dfrac{7-b-c}{b+c}+\dfrac{7-a-c}{a+c}+\dfrac{7-a-b}{a+b}=\dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b}[/tex]

from [tex]a+b+c=7 \implies a=7-bc; b = 7-a-c; c = 7-a-b[/tex]

and

[tex]\dfrac{7-b-c}{b+c}+\dfrac{7-a-c}{a+c}+\dfrac{7-a-b}{a+b} = 7\left(\dfrac{1}{a+b}+\dfrac{1}{b+c}+\dfrac{1}{a+c}\right)-3[/tex]

because it is not difficult to note that

[tex]$\sum \dfrac a{b+c}=\dfrac a{b+c}+\dfrac b{c+a}+\dfrac c{a+b}$[/tex]

Therefore,

[tex]7\left(\dfrac{7}{10}\right)-3 = \dfrac{49}{10}-3 =\boxed{ \dfrac{19}{10}} = \dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b}[/tex]

Finally,

[tex]10\left(\dfrac{a}{b+c} + \dfrac{b}{a+c} + \dfrac{c}{a+b} \right) = 10 \cdot \dfrac{19}{10} = 19[/tex]

The numbers are 30, 22, and 66 if the sum of three numbers is 118. The second number is 8 less than the first. The third number is 3 times the second.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

Let's suppose the number are x, y and z

Then,

x + y + z = 118  ...(1)

y = x - 8   ...(2)

z = 3y  ....(3)

After solving the above three equation by plugging the value of z in the equation (1) then solve this equation with (2) we will get:

x = 30

y = 22

Then z from the equation (3):

z = 3(22) = 66

Thus, the numbers are 30, 22, and 66 if the sum of three numbers is 118. The second number is 8 less than the first. The third number is 3 times the second.

Learn more about the linear equation here:

brainly.com/question/11897796

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Answer:

x=16/15

Step-by-step explanation:

Answer:

20

Step-by-step explanation:

9+9+2​=20

Hope this helps :)

Answer: 20

Step-by-step explanation:9x2=18 +2=20 or 9+9=18+2=20

Answer:

1/7

Step-by-step explanation:

4-3/7

1/7

Hope This Helps You.

Answer:

3 4/7

Step-by-step explanation:

Regroup 4 as 3 7/7.

Subtract 3 7/7 - 3/7 = 3 4/7

There's your answer!

please mark brainliest!

The demand is decreasing at the rate of 2units per week.

Given the price p (in dollars) and the demand x (in thousands of units) of a commodity satisfy the demand equation 6p+x+xp=94

Differentiating the function with respect to time will result in;

[tex]6\frac{dp}{dt}+\frac{dx}{dt} + x \frac{dp}{dt} + p\frac{dx}{dt} = 0[/tex]

Given the following paramters

p = $6

dp/dt = $2/wk

Substitute the given parameters into the formula to have:

[tex]6(2)+\frac{dx}{dt} + 2x + 9\frac{dx}{dt} = 0[/tex]

To get the demand x, we will simply substitute  p = 9 into the expression to have:

6(9)+x+9x=94

10x+54 = 94

10x = 94 - 54

10x = 40

x = 4

Substitute x = 4 into the derivative to have:

[tex]6(2)+\frac{dx}{dt} + 2x + 9\frac{dx}{dt} = 0\\6(2)+\frac{dx}{dt} + 2(4) + 9\frac{dx}{dt} = 0\\6(2)+\frac{dx}{dt} + 8 + 9\frac{dx}{dt} = 0\\20 + 10\frac{dx}{dt} =0\\10\frac{dx}{dt} =-20\\\frac{dx}{dt} =\frac{-20}{10}\\\frac{dx}{dt} =-\$2/wk[/tex]

Hence the demand is decreasing at the rate of 2units per week.

Learn more here: https://brainly.com/question/11859175

Answer:

Where is the problem?

Step-by-step explanation:

Answer:

Step-by-step explanation:

As given, the other rectangle has the same area as this one, but its width is 21 cm. Hence, length is 192 cm.

Answer:

Step-by-step explanation: its b

Pascal's triangle up to the 7th row (starting with 0)

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

1 6 15 20 15 6 1

1 7 21 35 35 21 7 1

Then the 6th term in the expansion of (x + 5)⁷ is

7 • x¹ • 5⁶ = 109375x

Answer:

9 months

Step-by-step explanation:

99 + 40 + 40 + 40 + 40 + 40 + 40 + 40 + 40 + 40 = $459

We can see that the number of 40's has been repeated 9 times. So therefore, 9 months is our answer.

Answer:

Infinity probally. But there is a number called the god's number reported by Galileo in which he states a number in which the enitre universe fits.

Step-by-step explanation:

Avg = 20 + 14 + 28 + 18 /4

Avg = 80/4 = 20

Answer:

y = -2x-1

Step-by-step explanation:

The formula for a line is [tex]y-y_{1} = m(x-x_{1})[/tex].

Plug in the information given in the problem: y-(-7) = -2(x-3)

So you get y+7 = -2x+6.

The final form you want needs to be equal to y (that means you want y by itself on the left side of the equals), so subtract 7 from both sides.  

You get y = -2x-1

[tex](\stackrel{x_1}{3}~,~\stackrel{y_1}{-7})~\hspace{10em} m = -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-7)}=\stackrel{m}{-2}(x-\stackrel{x_1}{3}) \\\\\\ y+7=-2x+6\implies \blacktriangleright y=-2x-1 \blacktriangleleft[/tex]

Answer:

70

Step-by-step explanation:

First you want to find the amount of x per 1 y so you divide 21 by 3 to get when x = 7 y = 1. Now you can just multiply 10 by 7 to get 70.

I hope this helps!

Answer:

ninth grade teacher is going   skipping 30  to each class

Step-by-step explanation:

Answer:

5/6+1/8 = 23/24

Step-by-step explanation:

The lowest common denominator here is the smallest denominator that can be divided evenly by both 6 and 8.  It is 24.  Note that 6 = 2·3 and that 8 = 2·2².  We use the factors 2³ and 3 to come up with the LCD 24.

Then 5/6 + 1/8 can be rewritten with this LCD as:

20/24 + 3/24 = 23/24

5/6+1/8 = 23/24

Answer:

x = 0

Step-by-step explanation:

[tex]\frac{3}{2}(\frac{7}{3}x + 1) = \frac{3}{2}[/tex]

To start, let's multiply each side by the reciprocal of [tex]\frac{3}{2}[/tex].  Multiplying a fraction by its reciprocal gives us 1, which will make the left side of our equation simpler.

[tex]\frac{2}3} * \frac{3}{2}(\frac{7}{3}x + 1) = \frac{2}3} * \frac{3}{2}[/tex]

[tex]\frac{2}{3} * \frac{3}{2} = 1[/tex], so we have:

[tex]1(\frac{7}{3}x + 1) = 1[/tex] or [tex]\frac{7}{3}x + 1= 1[/tex]

Next, we can subtract 1 from both sides to further simplify the left side:

[tex]\frac{7}{3}x + 1 - 1= 1 - 1\\\frac{7}{3}x=0[/tex]

Finally, we can multiply by the reciprocal of [tex]\frac{7}{3}[/tex] on both sides in order to isolate x on the left.  Anything multiplied by 0 = 0, so now we have:

x = 0

7/2x + 3/2 = 3/2 <=> 7/2x = 0 <=> x=0

Answer:

True

Explanation:

3 feet is 1 yard so 13/3 is 4.3 yards approximately

True

[tex] \frac{1 \: yard}{3 \: feet} = \frac{x \: yard}{13 \: feet} [/tex]

3x = 13

[tex]x = \frac{13}{3} yards[/tex]