I need help please with the drop down menus

I Need Help Please With The Drop Down Menus

Answers

Answer 1

Answer:

When the archer releases the arrow, the elastic potential energy in the bowstring transforms into kinetic energy for the arrow.

Explanation:

When the string of a bow and arrow is pulled from equilibrium, the elastic potential energy in the bow is converted to kinetic energy of the arrow when the string is released.


Related Questions

What is the mole ratio of nitrogen (N2) to ammonia (NH3)?
N2 + 3 H2 → 2 NH3

a.2:3
b3:1
c.3:2
d.1:3

Answers

B is the correct answer your welcome

whose model was discarded as a result of Rutherford's model?
A Dalton's model
B Thomson's model
C Bohr's model
D Quantum's model​

Answers

Answer:

A. Dalton's model

Explanation:

Dalton's model was discarded as a result of Rutherford's model.

[tex]\small\sf{Whose\: model \:was \:discarded \:as \:a \:result\:of}[/tex][tex]\small\sf{ Rutherford's \:model\:?}[/tex]

[tex]{ }[/tex]

[tex]\small\sf\:\:\:\:\:\:\:\:{:}\:\Longrightarrow{\bold{\pink{\sf{Thomson's \:model}}}}[/tex]

Which part of the kite catches the wind?
a Cover
b Frame
c Tail
d Kite string

Answers

Answer:

cover A

Explanation:

Answer:

cover sorry if im wrong

Explanation:

the cover makes the kiete float using air resisance

What is the final volume?

Answers

Answer:

Option A. 9.4 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 8 L

Initial temperature (T₁) = 293 K

Final temperature (T₂) = 343 K

Final volume (V₂) =?

V₁ / T₁ = V₂ / T₂

8 / 293 = V₂ / 343

Cross multiply

293 × V₂ = 8 × 343

293 × V₂ = 2744

Divide both side by 293

V₂ = 2744 / 293

V₂ = 9.4 L

Therefore, the final volume of the gas is 9.4 L

Carbon dioxide ( a greenhouse gas) is breathed out by billions of people all over the world? Yes or no

Answers

Answer:

yes

Explanation:

Answer:

yes

Explanation:

Humans inhale oxygen and breath out carbon dioxide.

Which of the following is a true statement?

A. Erosion due to wind-blown sand is a process of chemical weathering.
B. due to wind-blown sand is a process of geological weathering.
C. Erosion due to wind-blown sand is a process of biological weathering.
D.Erosion due to wind-blown sand is a process of mechanical weathering.

Answers

Answer:

C

Explanation:

Wind is geological therefore it is geological weathering

To make some oatmeal, Sally combined 40 grams of oatmeal, 10 grams of maple syrup, and some warm water. If the combined mass was 100 grams, how much water did she add?

ANSWER THIS EMEDIATLY PLEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEAAAAAAAAAASE

thank you
















(ps.this is the closest subject to science (that deals with volume, mass, and matter you know that kind of stuff )that I could find

Answers

100-40-10= 50 grams of water

What is the mass of 500 trillion (5.0 x 10'4)
molecules of water?

Answers

15 x 10^-9 grams or 0.000000015 grams

PLEASE ANSWER!! THANK YA!
Using Graham's Law of Effusion, calculate
the approximate time it would take for
1.0 L of argon gas to effuse, if 1.0 L of
oxygen gas took 12.7 minutes to effuse
through the same opening.

Answers

Answer:

I think the answer is X

Explanation:

X is a variable and variables stand for the unknown

Rocks are classified as sedimentary, metamorphic, or igneous on the basis of
the
a. age of the rocks.
b. way the rocks were formed.
c. types of fossils the rocks contain.
d. number of minerals found in the rocks.

Answers

The answer is b. way the rocks were formed.
The answer is B hope it correct cause I need more information

After you set up your apparatus for the second part of the experiment, your group begins to add the textbooks on top of the plunger. It appears that the plunger continues to drop with every added book and does not return to its original place after the books are removed. What possible sources of error could be given for this experimental outcome? Be specific and give at least two reasons.

Answers

The possible sources of error that could be given for this experimental outcome is the change in the density of the air.

What is an experiment?

An experiment simply means the procedure that is carried out in order to refute a particular hypothesis. It should be noted that experiments are important to provide insights into the cause and effect of a particular situation.

In this situation, with every added book, the volume of that air column will reduce. It is just important that the temperature should remain constant when the gas compression is taking place.

Another source of error is the assumption of moles that was assumed was constant during the experiment. In this scenario, it's possible that some gas could have escaped while the compression was taking place.

Learn more about experiments on:

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The volume of a gas is 18.6 L at 0.10 atm and 273 K. Calculate the pressure in
atms of the gas if its volume is changed to 1000 ml while the temperature remains
constant?

Answers

Answer:

1.86 atm

Explanation:

The following data were obtained from the question:

Initial volume (V₁) = 18.6 L

Initial pressure (P₁) = 0.10 atm

Final volume (V₂) = 1000 mL

Final pressure (P₂) =?

NOTE: The temperature is constant.

Next, we shall convert 1000 mL to L.

1000 mL = 1 L

Finally, we shall determine the final pressure of the gas as follow:

Initial volume (V₁) = 18.6 L

Initial pressure (P₁) = 0.10 atm

Final volume (V₂) = 1 L

Final pressure (P₂) =?

P₁V₁ = P₂V₂

18.6 × 0.10 = P₂ × 1

1.86 = P₂

P₂ = 1.86 atm

Thus, the final pressure of the gas is 1.86 atm

hi, if your looking for extra points (50+) and brainiest here is ur chance, answer this question correctly plz

Answers

Answer:

again, I'm going to say D lol.

(b) The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully
equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is
measured to be 45.6 mL. The atmospheric pressure in the lab is measured as 765 torr, and the equilibrium vapor pressure
of water at 298 K is 24 torr,
45
46
Gas
Water
Calculate the following.
() The number of moles of h2 produced in the reaction

Answers

Answer:

The pressure of  H₂(g) = 741 torr

Explanation:

Given that:

The atmospheric pressure measured in the lab  = 765 torr

The vapor pressure of water = 24 torr

By applying Dalton's Law of Partial Pressure :

Making The Pressure inside the tube due to the H₂(g) the subject of the formula :

we have:

= (765 -24) torr

= 741 torr

According to ideal gas law and Dalton's law of partial pressure, 0.0136 moles of hydrogen are produced in the reaction.

What is ideal gas law?

The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.It is applicable to ideal gases which have hypothetical existence.Law was proposed by Benoit Paul Emile Clapeyron.

In the given problem, according to Dalton's law of partial pressure, pressure =765-24=741 torr

Substituting the given values in the ideal gas equation, n=PV/RT

n=741×45.6×10[tex]^-3[/tex]/8.314×298=0.0136 moles.

Thus 0.0136 moles of hydrogen are produced in the reaction.

Learn more about ideal gas law,here:

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oil has a density of 8.5kg/L. what is the volume of 5.4kg oil

Answers

Answer:

0.64 L

Explanation:

Step 1: Given data

Density of oil (ρ): 8.5 kg/LMass of oil (m): 5.4 kgVolume of oil (V): ?

Step 2: Calculate the volume corresponding to 5.4 kg of oil

Density is an intrinsic property and it is equal to the quotient between the mass and the volume.

ρ = m/V

V = m/ρ

V = 5.4 kg/(8.5 kg/L) = 0.64 L

What is the IUPAC name for the following compound?
CH3-CH2-CH2-CH2-CH2-CH2 -CH2-CH3
Enter the name of the molecule.

Answers

8 carbon chain, octane

You are given 127 g H2CO3 (Carbonic Acid) and a volume of 800 mL of water, what will the final concentration of your solution be? (The final unit is the Molar (M), but do not include it.) (Round to 3 decimal places.)

Answers

Answer:

2.562

Explanation:

First we convert 127 g of H₂CO₃ to moles, using its molar mass:

127 g ÷ 62 g/mol = 2.05 mol H₂CO₃

Then we convert 800 mL to L:

800 mL / 1000 = 0.800 L

Finally we can calculate the concentration of the solution as molarity:

molarity = moles / litersmolarity = 2.05 mol / 0.800 L = 2.562 M

Where are new volcanoes in the Hawaiian island chain forming

Answers

the next volcano in the Hawaiian chain should form east or south of the Island of Hawai'i. Abundant evidence indicates that such a new volcano exists at Lö'ihi

Answer:

The Hawaiian Islands are a very small section of a huge chain of volcanic islands that crosses the northern half of the Pacific Ocean, called the Hawaiian-Emperor Volcanic Island Chain, which is over 6,000 kilometres long. The chain is linear, with a large bend in the middle: the southern half is called the Hawaiian Ridge and the northern half is called the Imperial Seamount.

Explanation:

The water cycle is a necessary process that moves water through an ecosystem. The part of the water cycle when water vapor changes back into a liquid in the atmosphere and begins forming clouds is called
A. condensation
B. transpiration
C. evaporation
D. precipitation

Answers

Answer:

A

Explanation:

How many particles are in 9.58 x 1023 of potassium sulfate (K2SO4)? (5.77 x 1047 particles)

Answers

Answer:

[tex]5.77x10^{47}particles.[/tex]

Explanation:

Hello!

In this case, since we are given 9.58x10²³ moles of potassium sulfate, it is possible to compute the particles according to the Avogadro's number:

6.022x10²³

As shown below:

[tex]9.58x10^{23}mol*\frac{6.022x10^{23}}{1mol}\\\\5.77x10^{47}particles.[/tex]

Best regards!

True or False: The specialized cells in a UNICELLULAR organism perform
specialized jobs.
Your answer

Answers

The answer would be true

Answer:

True

Explanation:

? I JUST DONT UNDERSTAND

Answers

Answer:

5SiO2 + 2CaC2 → 5Si + 2CaO + 4CO2

Explanation:

When you are balancing an equation, you use coefficients to change the number of atoms of each type that are on each side of the equation.

You cannot change subscripts, the small numbers to the right of the substances. You can only add coefficients, the large numbers to the left of substances.

A balanced equation has the same number and type of atoms on both sides of the equation (the reactants on the left, the products on the right).

To begin, this equation has:

1 Si

2 O

1 Ca

2 C  

on the left and

1 Si

1 Ca

3 O

1 C

on the right. Those numbers don't match!

By adding coefficients we end up with 5 Si, 10 O, 2 Ca and 4 C on both sides.

hellpppppppp me pleaseeeeeeeee
what element is this?????/

Answers

Answer:

Helium

Explanation:

Answer:

the element is helium as it's mass number is 4 and number of electrons is equal to it's atomic no. which is 2

Calculate the speed of a marble that rolls 9 cm in 4 seconds

Answers

Answer:

2.25

Explanation:

9/4

Balance equation mg3n2+h2so4=mgso4+(nh4)2​

Answers

Answer:

Mg₃N₂  +  4 H₂SO₄  ⇒  3 MgSO₄  +   (NH₄)₂SO₄

Explanation:

To balance an equation, you need to make both sides of the equation have equal number of each element.  Also, I think that you didn't write the whole equation since the reaction you gave is not likely.

Mg₃N₂  +  4 H₂SO₄  ⇒  3 MgSO₄  +   (NH₄)₂SO₄

Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and TrisH (an acid). The MW of Tris base is 121.14 g/mol; the MW of TrisH is 157.6 g/mol (the extra weight is due to the Cl- counterion that is present in the acid). The Ka of the acid is 8.32 X 10-9. Assume that you have TrisH in solid form (a powder), unlimited 1M HCl, unlimited 1 M NaOH and an unlimited supply of distilled water. How would you prepare 1 L of a 0.02 M Tris Buffer, pH

Answers

Solution :

The reaction :

[tex]$\text{TrisH}^+ + \text{H}_2\text{O} \rightarrow \text{Tris}^- +\text{H}_3\text{O}^+$[/tex]

We have

[tex]$K_a = \frac{[\text{Tris}^-]\times[\text{H}_3\text{O}^-]}{[\text{TrisH}^+]}$[/tex]

     [tex]$=\frac{x^2}{0.02-x}$[/tex]

     [tex]$= 8.32 \times 10^{-9}$[/tex]

Clearing x, we have [tex]$x=1.29 \times 10^{-5}$[/tex] moles of acid

Now to reach pH = [tex]$7.8 (\text{ pOH} = 14-7.8 = 6.2)$[/tex], we must have an [tex]$OH^-$[/tex] concentration of

[tex]$[OH^-] = 10^{-pOH}$[/tex]

          [tex]$=10^{-6.2}$[/tex]

         [tex]$=6.31 \times 10^{-7}$[/tex] moles of base

We must add enough NaOH of 1 M to neutralize the acid calculated above and also add the calculated base.

[tex]$n \ NaOH = 1.29 \times 10^{-5} + 6.31 \times 10^{-7}$[/tex]

               [tex]$=1.35 \times 10^{-5}$[/tex] moles

Vol [tex]$NaOH = 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \ mL}{1 \ mol}$[/tex]

                 = 0.0135 L

Tris mass [tex]$H^+ = 0.02 \text{ mol} \times 157.6 \ g/mol$[/tex]

                        = 3.152 g

To prepare the said solution we must mix

-- [tex]$3.152 \ g \text{ TrisH}^+$[/tex]

-- [tex]$0.0135 \ mL \ NaOH \ 1M$[/tex]

-- [tex]$\text{Gauge to 1000 mL with H}_2\text{O}$[/tex]

Zinc metal reacts with copper sulfate through the following
reaction:
Zn + CuSO4 → Cu + ZnSO4
The percent yield for a reaction in which 32.5 g of Zn is reacted
in excess CuSO4 solution is 85.0 %. What is the actual yield of
copper of this reaction?
g

Answers

Answer:26.9

Explanation:

hi, if your looking for extra points (50+) and br ainiest here is ur chance, answer this question correctly plz

Answers

Answer:

it should be C. the filtering of ground water. have a good day!

Sam and Jane have been investigating the amount of copper sulphate that can be dissolved in water at different temperatures .They added copper sulphate till it could not be dissolved any further and also measured the mass of copper. The results are below. What conclusions can you make from results?

Answers

Answer:

This question is so confusing, I'm sorry

Predict the product of the following Wittig reaction: You may want to draw out the reaction of a separate piece of paper before submitting your response. 2-butanone reacts with (C2H5O)2P=O--CHC.Hs with added heat in a potassium salt solution
a) Potassium diethyl phosphate
b) (z)-stilbene
c) 2-methylbut-1-enyl-benzene
d) 2-methylbutene diethyl phosphate

Answers

Answer:

c) 2-methylbut-1-enyl-benzene

Explanation:

From the information given:

Wittig reaction is essential for the creation of carbon-carbon bonds which results in the production of alkenes. The presence of the ketone compound ( 2-butanone) is because of its high electrophilic character of the carbonyl carbon. The reaction between 2-butanone with triethylamine in the presence of potassium salt is to catalyze the reaction. This reaction proceeds to yield the product 2-methylbut-1-enyl-benzene.

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