Answers
Explanation
Step 1
free body diagram
so, for m1
m1= 10 kg
so,
[tex]\begin{gathered} \sum ^{forces}_{\text{ y}}=T_1-mg=ma \\ T_1=m_1(a+g)\Rightarrow equation(1) \\ T_1=10(a+g) \end{gathered}[/tex]and for m2
[tex]\begin{gathered} \sum ^{forces}_{\text{ x}}=m_2g\sin (37)-T_1=m_2a \\ \text{solve for T}_1 \\ T_1=m_2g\sin (37)-m_2a \\ \text{replace} \\ T_1=(3.6\text{ kg)(9.8 }\frac{m}{s^2})\sin 37-3.6a \\ T_1=21.23\text{ -}3.6a\Rightarrow eq(2) \end{gathered}[/tex]Step 2
now, replace in equaiotn (1) and solve for a
[tex]\begin{gathered} T_1=m_1(a+g)\Rightarrow equation(1) \\ 21.23\text{ -}3.6a=10(a+g) \\ 21.23\text{ -}3.6a=10a+10g \\ -7.2a=10a-98.1 \\ -17.2a=-98.1 \\ a=-\frac{98.1}{-17.2} \\ a=5.703\text{ }\frac{m}{s^2} \end{gathered}[/tex]finally, replace in equation (2) to find Tension
[tex]\begin{gathered} T_1=21.23\text{ -}3.6a \\ T_1=21.23\text{ -}3.6(5.703) \\ T_2=3.891\text{N} \end{gathered}[/tex]I hope this helps you
Related Questions
The velocity of a wagon increases from 3 m/s to 9 m/s as it
accelerates uniformly down a hill. The average velocity of the
wagon is
m/s.
Answers
Answer:
6 m/s
Explanation:
The equation that relates time, distance, and acceleration is:
a = (vf - vi)/t
where a is acceleration (m/s^2), time is time (seconds) and vf and vi are the initial (vi) and final (vf) velocities (m/s).
Average velocity is (vf + vi)/2
We are given that:
vi = 3 m/s
vf = 9 m/s
Average velocity for the wagon is thus:
is (9 + 3)/2 = 6 m/s
A father fashions a swing for his children out of a long rope that he fastens to the limb of a tall tree. As one of the children swings from this rope that is 5.70 m long, his tangential speed at the bottom of the swing is 9.10 m/s.What is the centripetal acceleration, in m/s2, of the child at the bottom of the swing?
Answers
Given,
The length is r=5.70 m
The tangential speed is r=9.10 m/s
The centripetal acceleration is:
[tex]\begin{gathered} a=\frac{v^2}{r} \\ \Rightarrow a=\frac{9.10^2}{5.70} \\ \Rightarrow a=\frac{14.52m}{s^2} \end{gathered}[/tex]The acceleration is:
[tex]a=14.52m/s^2[/tex]Analyze the devices invented by Bernard Leon and Jamie metz and identify the flaws in the system in terms of energy inputs and outputs.
Answers
The overbalanced wheel with attached spokes is a weakness in the system that Bernard Leon and Jamie Metz invented in terms of energy inputs and outputs.
The ability to exert a force that causes an item to move is what is meant by the definition of energy as the power to accomplish work. Even though the definition is unclear, the meaning is clear: energy is simply the force that moves things. Potential energy and kinetic energy are the two categories of energy.Therefore, we can say that the wheel is unbalanced. The wheel is designed to turn clockwise just after the weighted spoke reaches the top of the wheel, and the spoke flips outward to the right exerting the force downward toward the ground. Some energy will be lost from friction as the mechanism rubs on the inner spoke, and more energy will be lost when it transferred into sound and thermal energy. Perpetual motion machines are one of the most frequently proposed perpetual motion machines designed.
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a brick is thrown upward from the top of a building at an angle of 25 degreees to the horizontal and with an initial speed of 15 m/s. if the brick is in flight for 3.0 s, how tall is the buiding
Answers
Angle 32rad turn during that time if the angular accelaration is constant.
What is accelaration?
acceleration, rate at which the velocity changes with time, in terms of both speed and the direction. A point or else it's an object moving in a straighten line is accelerated if it is speeds up or slows down. Motion on a circle is the accelerated even if the speed is constant, because of the direction is continually changing.
Sol- In an uniformly accelerated circular motion, the angle traveled by the object is given by-
∆=wf+wo/2×t
Here wf is the final angular speed .
It is the initial angular speed and t is the time of the motion. Replacing the given values-
∆= 12 rad/s + 4 rad/s /2 (4s)
∆= 32rad .
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A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it is released.
How fast was the rock thrown?
Answers
From Kinematics, the equation for final velocity is
v = [tex]v_{0}[/tex] +at
where [tex]v_{0}[/tex] is the initial velocity, 'a' is the acceleration of the rock, and t is the time taken.
Given, that the rock is thrown upwards and it takes time t = 2.4s to reach a maximum height. So, its acceleration is a= -g= -9.8 m/[tex]s^{2}[/tex] and final velocity is v = 0m/s. To find initial velocity of the rock, rearrange above velocity equation.
⇒[tex]v_{0}[/tex] = v - at
⇒[tex]v_{0}[/tex] = 0 - (-9.8m/[tex]s^{2}[/tex] × 2.4s)
∴ [tex]v_{0}[/tex] = 23.52 m/s.
Thus, the rock was thrown with a velocity 23.52 m/s.
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You are visiting a friend from elementary school who now lives in a small town. One local amusement is the ice-cream parlor, where Stan, the short-order cook, slides his completed ice-cream sundaes down the counter at a constant speed of 2.0 m/s to the servers. (The counter is very well polished for this purpose.) If the servers catch the sundaes 7.0 cm from the edge of the counter, how far do they fall from the edge of the counter to the point at which the servers catch them?
Answers
The edge counter is 0.0060 meters or 0.60 cm far as they fall from the edge of the counter to the point at which the servers catch them.
What is Potential energy?Potential energy is a form of stored energy that is dependent on the arrangement of a system's components. When stretched or squeezed, a spring has higher potential energy.
When lifted above the ground, a steel ball has more potential energy than when it is brought to rest on the ground. It is capable of performing more work in the increased position.
From the given data of the question,
x = v/t
t = x/v (1)
y = -1/2gt²
Substitute value of t from (1)
y = -1/2 g(x/v)²
y = -1/2 (9.8)(0.70/2.0)²
y = 0.0060 meters, or,
y = 0.60 cm.
Therefore, it is 0.60 cm far from the edge of the counter.
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a girl delivering newspapers travels three blocks west, four blocks north, and then six blocks east. a. what is her resultant displacement? b. what is the total distance she travels?
Answers
After a girl delivering newspapers travels three blocks west, four blocks north, and then six blocks east, her total displacement is 5 blocks. While the total distance covered is 13 blocks.
What is displacement?A displacement is a vector in geometry and mechanics whose length is the smallest distance between the beginning and final positions of a moving point P.
If an item moves relative to a reference frame, such as a lecturer moving to the right of a whiteboard or a passenger moving toward the back of an airliner, the object's location changes. This shift in location is referred to as displacement.
Displacement (change in position) = Last position – initial position
To Calculate displacement, let displacement be (d)
d = -3i + 4j + 6i (-i because she turned west, +i because she turned east)
d = 3i + 4j
d = √(3² + 4²)
d = √(9 + 16)
d = √25
d = 5 blocks.
Total distance (Td_ = Sum of all the blocks traveled.
Td = 3 + 4 + 6
Td = 13 blocks.
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Applying Concepts Does a car's speedometer show instantaneous speed, average speed, or velocity? Explain.
Answers
Answer:
The speedometer of a car reveals information about the instantaneous speed of your car. It shows your speed at a particular instant in time.
Explanation:
if a cylindrical space station 275 mm in diameter is to spin about its central axis, at how many revolutions per minute ( rpmrpm ) must it turn so that the outermost points have an acceleration equal to gg ?
Answers
Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm
What is Rotation speed ?
The rate at which the Aeroplan should begin rotating into takeoff attitude is known as V r.
V r, the rotational speed, cannot be lower than V1. A subsequent rejected takeoff may not be achievable within the remaining runway length and is likely to result in a Runway Excursion if it is more than V1 and it is discovered that, at V r, rotation cannot be completed.
V r depends on the weight of the aircraft and the flap position, but it can also change according on temperature, pressure, and altitude.
Gravitational acceleration = g = 9.8 m/s2
Diameter of the space station = D = 275 m
Radius of the space station = R
R = D/2
R = 275/2
R = 137.5 m
Angular speed of the space station = [tex]\omega (rad/s[/tex])
Centripetal acceleration at the outermost points = ac = g = 9.8 m/s2
ac = [tex]\omega2R\\[/tex]
9.8 =[tex]\omega2(137.5)[/tex]
[tex]\omega \\[/tex]= 0.267 rad/s
Converting from rad/s to rpm, (1 revolution = [tex]2\pi radians[/tex] , 1 minute = 60 seconds)
\omega = 0.267 [tex]\times (\frac{60}{2\pi })[/tex]
\omega = 2.55 rpm
Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm
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What conditions must be met in order for work to be done?
Check all that apply.
A. The applied force must make the object move.
B. At least part of the applied force must be in the same direction as
the movement of the object.
c. The output force must be greater than the input force.
D. The work must be greater than the momentum. you
Answers
Answer: B) force must be in the same direction as movement
Explanation:
what is the maximum speed (umax) that the missile could achieve in level flight? (hint: (1) when thrust is equal to the drag, there is no acceleration which means maxi speed. we assumed no drag, so it means when maxi speed is reached, the thrust is 0. (2) at this point, air reaches its maximum temperature, and no fuel injection is needed.) b) what would the velocity be of the gas exiting the nozzle (i.e., ue) at this maximum operating flight speed? c) sketch (qualitatively) the ramjet cycles for both cases (u
Answers
a) maximum speed (umax) that the missile could achieve in level flight = 2123 m/s
b) velocity of the gas exiting the nozzle (i.e., ue) at this maximum operating flight speed = 2120 m/s
The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
Given data:
Pressure ratio = 45.5
TSFC = 5.27 * 10⁻⁵ kg/N
Cp = 1150 J/Kg
Wair = 25.5
Ta = 240K
Δhe = 4.4 KJ/kg
Tmax = 2200 K
(a) Maximum speed (Umax):
Ramjet's energy equation:
T₀₂ = Ta + (μ² / 2μ)
[tex]Umax = \sqrt{2Cp (Tmax - Ta})[/tex]
[tex]Umax = \sqrt{2* H50(2200 - 240)}\\ \\Umax = \sqrt{2 * 1150 * 1960}[/tex]
Therefore, Umax = 2123 m/s
(b) Velocity of exiting gas (Ue)
No fuel is provided, thus air expands back to its initial speed i.e., (Ue = U)
The specific thrust = [1 + f] Ue - U = 0
Therefore, Ue = 2120 m/s
(c) T-S diagram of Ramjet cycle:
The T-S schematics for Ramjet at U < Umax and U = Umax are based on the aforementioned two components ( 'a' and 'b')
Ramjets' maximum operating speed is significantly constrained by their maximum operating temperature.
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when 1 kg of water and 1 kg of wood absorb the same amount of heat, the change in temperature of water is less than the changes in temperature of the wood. which statement helps to explain this difference?
A. The latent heat of fusion of water is less than of wood.
B. Intermolecular forces in water are less than those in wood.
C. Intermolecular forces in water are greater than those in wood.
D. The latent heat of fusion of water is greater than that of wood.
Answers
When 1 kg of water and 1 kg of wood absorb the same amount of heat, the change in the temperature of the water is less than the change in temperature of the wood because the intermolecular forces in water are greater than those in wood.
What are intermolecular forces?Intermolecular forces are the forces of attraction that exist between the molecules of the same substance.
Intermolecular forces help to keep the molecules of a substance.
The stronger the intermolecular forces between molecules of a substance, the more heat energy it will require to separate the molecules of the substance.
The molecules of water have in addition to the covalent bond between the atoms of hydrogen, hydrogen bonds that exists between its molecules.
These intermolecular forces present in water are responsible for the high heat capacity of water.
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What is "velocity"?
A. Velocity is a scalar quantity that tells the acceleration of an object over a period of time.
B. Velocity is a vector quantity that tells the distance an object has traveled over a period of time.
C. Velocity is a vector quantity that tells the force of an object over a period of time.
D. Velocity is a scalar quantity that tells the distance an object has traveled over a period of time.
Answers
Answer:
The answer is the letter B
Explanation:
Because velocity is a vector quality since to define it is necessary to specify its size (equivalent to speed) and its direction and the letter B tells then velocity is a vector quality that tells the distance an object has traveled over a period of time.
I think than is the letter B
Velocity is a vector quantity that tells the distance an object has traveled over a period of time. So, option (B) is correct.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction is displacement.
Hence, velocity is a vector quantity which can tell displacement of a body , that is, distance between initial and final position - which is equal to from the distance an object has traveled over a period of time.
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a single-turn circular loop of radius 5.5 cm is to produce a field at its center that will just cancel the earth's field of magnitude 0.7 g directed at 70 below the horizontal north direction. find the current in the loop.
Answers
The current in the loop will be 6.13 A.
What is a magnetic field ?The magnetic field is the area in and around a magnet that is subject to the effects of magnetism. We employ the magnetic field as a tool to describe the distribution of the magnetic force in the vicinity and inside something magnetic in nature.
According to the question,
Radius of loop,
r =5.5 cm or,
r = 0.055 m
Earth's magnetic field, = 0.7G = 0.7 × 10⁻⁴ T
Number of turns, N = 1
We know the relation,
B = µ₀ ×N×I/2r
B = [tex]B_{e\\}[/tex]
then,
[tex]B_{e\\}[/tex] = µ₀ ×N×I/2r
By substituting the values,
0.7 × 10⁻⁴ = 4π × 10⁻⁷×1 × I / 2× 0.055
hence,
The current will be
I = 2× 0.055 × 0.7 × 10⁻⁴/ 4π ×10⁻⁷×1
I = 6.13A
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a rock of mass m is released from rest above an airless spherical planet of mass m and radius r. the rock is released from a height r above the surface of the planet (a distance 2r from the center of the planet). what is the correct expression for the final kinetic energy of the rock just before it hits the surface of the planet?
Answers
E1 = [tex]E_{f}[/tex]
[tex]\frac{-GMM}{2R}[/tex] = [tex]\frac{-GMM}{R}[/tex] + [tex]\frac{1}{2} mv^{2}[/tex]
= [tex]\frac{GMM}{2R}[/tex] = [tex]\frac{1}{2} mv^{2}[/tex]
V = [tex]\sqrt{GM/R[/tex]
By the law of conservation of energy, the initial potential energy, and the final kinetic energy are equal. When an object hits the ground, its kinetic energy is converted into heat and sound energy. Energy from motion is called kinetic energy. object in motion.
Both vertical and horizontal movement has kinetic energy. Kinetic energy depends on the mass and velocity of the object. The basic reason for the existence of halves in the kinetic energy formula actually comes from special relativity from a more complete version of the kinetic energy formula. Briefly, this ½mv2 kinetic energy formula can be viewed as an approximation of special relativity.
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cepheid stars are useful to astronomers as indicators of group of answer choices white-dwarf star behavior. the mechanics of eclipsing variable stars. distance, particularly to stars in our galaxy and to nearby galaxies. stars with very high speed motion.
Answers
Option b cepheid stars are useful to astronomers as indicators of distance, particularly to stars in our Galaxy and to nearby galaxies.
An astronomer is a scientist who focuses on the stars, planets, galaxies and other extraterrestrial natural phenomena. The study of astronomy includes everything in the cosmos that is outside of our solar system. This includes celestial bodies that we can see with our unaided eyes, such as the Sun, Moon, planets, and stars. Additionally, it contains celestial bodies like distant galaxies and minute particles that we can only see with telescopes or other tools. On a more urgent level, astronomy aids in our research into how to extend the survival of our species. Studying the Sun's impact on Earth's climate and how it will effect weather, water levels, etc., for instance, is crucial. The broad discipline of natural science known as astronomy is concerned with celestial objects, such as those in the solar system, galaxies, and extragalactic objects. The majority of the fieldwork participants are students who specialize in this broad discipline.
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how far from the front of the car will the cm be when two people sit in the front seat 2.30 mm from the front of the car, and three people sit in the back seat 3.40 mm from the front? assume that each person has a mass of 60.0 kgkg . express your answer to three significant figures and include the appropriate units.
Answers
The center of mass exists a position defined relative to an object or system of objects.
The proper significant figures and proper rounding of digits exists 2.603 m.
What is meant by center of mass?The unique location where the weighted relative position of the scattered mass adds to zero is known as the center of mass in physics. Here is where a force can be applied to produce a linear acceleration without also producing an angular acceleration.
A position established in relation to an object or set of objects is the center of mass. It represents the system's average location as weighted by each component's mass. The center of mass for straightforward stiff objects with homogeneous density is found at the centroid.
Given:
Mass of car, m = 1150 kg
Distance, d = 2.35 m
The new position of center of mass will be:
[tex]$=\frac{1150 \times 2.35+160 \times 2.7+240 \times 3.75}{240+260+1150} \\[/tex]
simplifying the above equation, we get
= (2702.5 + 432 + 900) / 1650
= 4034.5 / 1650
= 2.603 m
Therefore, the proper significant figures and proper rounding of digits exists 2.603 m.
The complete question is:
The CM of an empty 1150 kg car is 2.35 m behind the front of the car. How far from the front of the car will the CM be when two people sit in the front seat 2.70 m from the front of the car, and three people sit in the back seat 3.75 m from the front? Assume that each person has a mass of 80.0 kg.
express answers in proper significant figures and proper rounding of digits.
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HELP!
Emily is riding her skateboard down the sidewalk at 2 m/s when she suddenly hits a rock, causing the skateboard to stop. According to Newton's first law of motion, what happens to Emily?
a
Emily accelerates forward.
b
Emily moves forward at 2 m/s.
c
Emily moves forward at less than 2 m/s.
d
Emily stops with her skateboard.
Answers
Answer: (b)
Explanation:
According to the law of conservation of momentum.
B. Emily moves forward at 2 m/s.
A force of 10 n stretches a particular spring by 2 cm. How far would a 20 n force stretch that same spring?.
Answers
x2 = 4cm.
20N stretches the same spring 4cm.
What is Hooke's law?The displacement or size of a deformed object is directly proportional to the deforming force or load for relatively small deformations.The spring constant k, is a measure of the spring's stiffness. It varies depending on the spring and material. The greater the spring constant, the stiffer the spring and more difficult to stretch.The force exerted on the spring, F1 = 10N
In the spring, 1st stretch, x1 = 2cm
The force exerted on the spring, F2 = 20N
In the spring, 2ns stretch, x2 = ?
We have to find x2,
The spring constant value for the same spring must be the same. Hooke's law expresses the relationship between force and spring constant as follows:
F=kx.
F1/x1 = F2/x2
By substituting values,
10 / 2 = 20 / x2
x2 = 40/10
x2 = 4cm
As a result, the 20 N force stretches by 4 cm.
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a car rounds an unbanked curve of radius 86 m. if the coefficient of static friction between the road and car is 0.51, what is the maximum speed (in m/s) at which the car can traverse the curve without slipping?
Answers
The maximum speed at which the car can transverse the curve without slipping is 20.7 m/s.
What is speed and what would be the maximum speed for the car not to slip?Speed is a scalar quantity which represents the distance travelled per unit time during the motion of the body.Here in the question is given radius 86 meters, and coefficient of static friction 0.51 and the car needs to transverse the curve without slipping.So we will use the formula v = ( u x g x r )^1/2 = 0.51 x 86 x 9.8. Here g will be taken as 9.8m/s^2 .Multiplying we will get the value 429.786 and square root of this would be 20.7 , so the velocity or the maximum speed of the car would 20.7 m/s at which car can transverse without slipping.To know more about speed visit:
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what is the maximum speed with which a 1200- kgkg car can round a turn of radius 95.0 mm on a flat road if the coefficient of static friction between tires and road is 0.60?
Answers
The maximum speed will be 0.74m/s
What is friction force?Friction, the force that resists a solid object from sliding or rolling over another. Frictional forces, such as the traction required to walk without slipping, can be beneficial, but they also present significant resistance to motion. About 20% of a car's engine power is expended to overcome the frictional forces of moving parts.
The speed that corresponds to the maximum centripetal force (Fₓ) that could be provided by the friction is given as:
f = Fₓ
f = μN is the friction force. where, μ is the coefficient of static friction and this is the maximum force the friction can provide.
Fₓ = mv²/r
N = mg (flat road)
Thus:
μ mg = mv²/r
So, according to the given question:
μ = 0.60
m = 1200kg
r = 95.0 mm or 95×10⁻³m
μ mg = mv²/r
0.60 × 9.8 = v²/ 95×10⁻³
v² = 558.6 ×10⁻³
v = 0.74m/s
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A river has current of 4 m/s south with respect to the shore.
A swimmer is swimming in the river (which is redundant).
If the swimmer is swimming 2 m/s north with respect to the water, what is his velocity relative to the shore?
If the swimmer is swimming 3 m/s south with respect to the water, what is his velocity relative to the shore?
PLEASE ANSWER FAST I HAVE TO SUBMIT THIS QUESTION TODAY!!
Answers
The velocity of the swimmer relative to the shore is 2 m/s south by vector addition
What is vector addition ?
Vector addition means putting two or more vectors together. In the addition of vectors, we are adding two or more vectors using the addition operation in order to obtain a new vector that is equal to the sum of the vectors. Vector addition finds its application in physical quantities where vectors are used to represent velocity, displacement, and acceleration.
We can solve this problem by using vector addition.
In fact, we can take north as positive direction, and we can write the following:
vc = - 4m/s is the velocity of the current (which is negative, since it is south)
v s= +2m/s is the velocity of the swimmer (which is positive, since it is north)
Therefore, the velocity of the swimmer relative to the shore is
v = vs + vc = 2+(-4) = - 2m/s
And the negative sign means the direction is south, so the answer is
v = 2 m/s south
The velocity of the swimmer relative to the shore is 2 m/s south by vector addition
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A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision
Answers
The magnitude of their common velocity if they move together after collision is 12.9 m/s.
What is the final velocity after collision?
The final velocity after collision is calculated by applying the principle of conservation of linear momentum as shown below.
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
m₁ is the mass of the carm₂ is the mass of the pedestrianu₁ is the initial velocity of the caru₂ is the initial velocity of the pedestrianv is the their common velocity after collision(20)(16) + (5)(0.5) = v(20 + 5)
322.5 = 25v
v = 322.5/25
v = 12.9 m/s
Thus, the car and the pedestrian moved together after the collision suggestion an inelastic collision.
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The complete question is below:
A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision if the mass of the pedestrian is 5 kg.
If a car of mass 20 kg with a velocity of 16 m/s collides with a pedestrian, then the magnitude of common velocity, if they move after the collision of masses, is 12.9 m/s.
What is Collision?Any situation in which two or more bodies quickly exert forces on one other is referred to be a collision. The most common usage of the word "collision" relates to instances where two or more objects collide violently, while the scientific usage of the word does not refer to the amount of force involved.
According to the question, the given values are :
Mass of the car, m = 20 kg
The velocity of the car, u₁ = 16 m/s
The velocity of the pedestrian, u₂ = 0.5 m/s.
m₁ u₁ + m₂ u₂ = v (m₁ + m₂)
(20) × (16) + (5) × (0.5) = v(20 + 5)
322.5 = 25 × v
v = 322.5/25
v = 12.9 m/s
Hence, the magnitude of common velocity is 12.9 m/s.
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The complete question is :
A car of mass 20 kg moving with a velocity of 16 m/s collides with a pedestrian moving at a velocity of 0.5 m/s in the same direction, calculate the magnitude of their common velocity if they move together after a collision if the mass of the pedestrian is 5 kg.
an air-track glider attached to a spring oscillates between the 15.0 cm mark and the 66.0 cm mark on the track. the glider completes 12.0 oscillations in 41.0 s. what is the period of oscillations?
Answers
The time period is 3.3 s, frequency is 0.303 Hz, amplitude is 0.25 m, and maximum speed is 0.47575 m/s.
Based on the given information,
• The air-track glider connected with a spring oscillates between the 10 cm mark and the 60 cm mark.
• In 33 seconds, the glider completes 10 oscillations.
Here we have to find the period, frequency,amplitude and maximum speed of glider.
The time period of one oscillation is 33s/10 = 3.3s
The frequency f is the reciprocal of the time period.
f= 1/T =1/3.3 S = 0.303 Hz
The amplitude A is
A = 1/2 (60cm - 10cm)
= 25cm
Maximum speed of glider is
V max = 2π/t (0.25m)
V max = 0.47575m/s
Thus, time period is 3.3 s, frequency is 0.303 Hz, amplitude is 0.25 m, and maximum speed is 0.47575 m/s.
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Laser light passing through two small slits produces a bright fringe centered at the midpoint on a distant screen because?.
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Laser light passing through two small slits produces a bright fringe centered at the midpoint on a distant screen because the light waves travel the same distance from each slit to the midpoint.
Considering that light is composed of both electric and magnetic fields, it often acts as an electromagnetic wave. Magnetic fields oscillate perpendicularly to the wave propagation direction and are perpendicular to one another. They are called transverse waves as a result of this. The following are a few traits of light:
When dealing with light waves, the sine waveform is used. One complete sweep from 0 to 360 degrees makes up the waveform's period. The wavelength and frequency of light waves are two crucial properties. The wavelength is the distance separating the wave's peaks. Light waves have wavelengths that are on the order of nanometers.
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a small sphere is launched horizontally with a speed v0 toward a target a horizontal distance d away. the sphere lands on the target that is at height h below the height from which the sphere was launched. if the sphere were launched again, but with a speed 2v0 , how high above the target would the sphere have to be launched horizontally to hit the same target, still a horizontal distance d away? responses
Answers
The sphere has to be launched 4 times the initial height, h, to hit the same target.
What is the time of motion of the first sphere?The time taken for the first sphere to hit the target is calculated as follows;
d = V₀t₁
where;
V₀ is the initial horizontal velocityd is the horizontal distance travelled by the spheret is the time of motiont₁ = d/V₀
The height travelled by the ball;
h = ¹/₂gt₁²
t₁² = 2h/g
t₁ = √(2h/g)
The time of motion of the second sphere when it is launched at a speed of 2V₀.
t₂ = d/2V₀
t₂ = ¹/₂(d/V₀)
t₂ = ¹/₂(t₁)
The height of fall of the second sphere;
¹/₂(t₁) = √(2h/g)
[¹/₂(t₁)]² = 2h/g
t₁²/4 = 2h/g
t₁² = 4(2h/g)
Thus, the height the sphere need to be launched in order to hit the same target is determined by applying kinematic equation.
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You push with 310N of force to move a 25 kg box across the floor. If the coefficient of kinetic friction between the box and the floor is .21, what is the net force on the box?
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The net force will be the difference between the applied force and frictional force which is 258.6 N
What is Force ?Force can be simply defined as push or pull. It is the product of mass and acceleration. It is a vector quantity and it is measured in Newton.
If you push with 310N of force to move a 25 kg box across the floor. If the coefficient of kinetic friction between the box and the floor is .21
The normal force N on the box = mg
N = mg
N = 25 × 9.8
N = 245 N
The frictional force f = μN
where μ = coefficient of friction
f = 0.21 × 245
f = 51.45 N
The net force on the box = F - f
Where F = force applied
f = frictional force
Net force = 310 - 51.45
Net force = 258.6 N
Therefore, the net force on the box is 258.6 N
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josh and taylor, standing face-to-face on frictionless ice, push off each other, causing each to slide backward. josh is much bigger than taylor. after the push, which of the two is moving faster?
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After the push, Taylor will be moving faster because he has a smaller mass.
What is the force applied by each person?The force exerted by each person is determined by applying Newton's second law of motion.
F = ma
where;
m is the mass of the persona is the acceleration of the personThe force applied by each person depends on the mass and acceleration.
mass of Josh > mass of Taylor
Since Josh has a greater mass, he will be able impact more force on Taylor causing Taylor to move faster after the push.
Thus, the speed of each person after the push, depends on the force received by each person at the opposite end.
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A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 96 ft/s. How high will it go? Use -32 ft/s? forthe acceleration caused by gravity. Ignore air resistance.
Answers
Given,
The initial height of the soccer ball, h₁=6 ft
The initial velocity of the ball, u=96 ft/s
The acceleration due to gravity, g=-32 ft/s
When the ball reaches the maximum height, its velocity will reduce to zero.
Thus the velocity of the ball when it is at its maximum height is v=0 ft/s
From the equation of motion,
[tex]v^2-u^2=2gh_2[/tex]Where h₂ is the total height covered by the ball from its initial height to reach its maximum height.
On substituting the known values,
[tex]\begin{gathered} 0-96^2=2\times-32\times h_2 \\ \Rightarrow h_2=\frac{-96^2}{2\times-32} \\ =144\text{ ft} \end{gathered}[/tex]Thus the maximum height reached by the ball is,
[tex]\begin{gathered} H=h_1+h_2 \\ =6+144 \\ =150\text{ ft} \end{gathered}[/tex]Thus the maximum height reached by the ball is 150 ft.
A student learns that a certain comet in the solar system is considered a short-period comet. Based on this knowledge, what is the student most justified in concluding?.
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A student learns that a certain comet in the solar system is considered a short-period comet The comet originates in the Kuiper belt is the student most justified in concluding.
The Sun and the things that circle it make up the gravitationally bound solar system. It was created 4.6 billion years ago when a massive interstellar molecular cloud collapsed because to gravity. The Sun is the system's primary mass source, while Jupiter is home to the majority of the system's leftover mass. Our Sun is called Sol after the Latin word for Sun, "solis," and anything connected to the Sun is referred to as "solar" as a result. The only known example of a habitable planet, the only star we can see up close, and the only planets we can explore with spacecraft are all found in the Solar System. Understanding the genesis and evolution of planets depends on solar system study.
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