I need help with question 8 i just need the answer I just want to see if I’m right
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Answer:
No
Explanation:
The function is one-to-one if when we draw a horizontal line in the graph, the line crosses the function once. In this case, we get:
Since the line crosses the graph twice, the given function is not one-to-one.
So, the answer is No.
Related Questions
What is a slope in math?
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When comparing the variation between a variable and a result, the slope gives the relationship between the changes in both quantities.
It is mathematically defined as
[tex]\text{Slope = }\frac{Change\text{ in y}}{\text{Change in x}}\text{ = }\frac{\Delta y}{\Delta x}[/tex]what is the value of x?(6x+38)
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[tex]\begin{gathered} 2(4x-55)+2(3x+25)=360 \\ 8x-110+6x+50=360 \\ 14x-60=360 \\ \text{Solve for x:} \\ 14x=420 \\ x=\frac{420}{14} \\ x=30 \end{gathered}[/tex]----------------------------------------------------------------------------------------------
[tex]\begin{gathered} 11x-54=3x+120 \\ 8x=174 \\ x=\frac{174}{8}=21.75 \end{gathered}[/tex]Galaxy A has 8 × 10^8 stars. Galaxy B has 6 x 10^10 stars. Choose which galaxy has more stars. Then fill in the blank with a number written in standard notation.
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Given:
Galaxy A has 8 × 10^8 stars. Galaxy B has 6 x 10^10 stars.
We will write the numbers multiplied by ten raised to the same exponent
so,
[tex]\begin{gathered} 8\times10^8=8\times10^8 \\ 6\times10^{10}=6\times100\times10^8=600\times10^8 \end{gathered}[/tex]now, we will compare the numbers: 8 and 600
It is clear 600 is greater than 8
so, the answer will be option Galaxy B
Divide the number of stars of B by A
So,
[tex]\frac{6\times10^{10}}{8\times10^8}=\frac{600\times10^8}{8\times10^8}=\frac{600}{8}=75[/tex]
Galaxy B has 75 times as many stars as Galaxy A
A teacher wants to buy graph paper and printer paper. The printer paper costs $2 a pack, while the graphing paper cost $3 a pack. She wants to buy at least 7 packs of paper, but wants to spend at most $30. Write a system of inequalities for the situation.
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Given:
A teacher wants to buy graph paper and printer paper.
Let the number of packs of the graph paper = x
And the number of packs of the printer paper = y
The printer paper costs $2 a pack, while the graphing paper cost $3
so, the total cost will be: 2y+3x
She wants to buy at least 7 packs of paper
[tex]x+y\ge7[/tex]And wants to spend at most $30.
[tex]2y+3x\le30[/tex]so, the system of inequalities for the situation will be as follows:
[tex]\begin{gathered} x+y\ge7 \\ 2y+3x\le30 \end{gathered}[/tex]please help I've been trying to get this for a really long time thank you
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Let:
[tex]\begin{gathered} x=2y+2_{\text{ }}(1) \\ -3x+6y=-6_{\text{ }}(2) \end{gathered}[/tex]Replace the value of x into (2)
[tex]\begin{gathered} -3(2y+2)+6y=-6 \\ -6y-6+6y=-6 \\ -6y+6y=6-6 \\ 0=0 \end{gathered}[/tex]Therefore, the system has infinitely many solutions
The slope of a line and one point on the line are given . Write the equation of the line in slope-intercept form. (Hint: it may be helpful to first write it in point slope form y-y1=m(x-x1) and then convert it to the slope intercept form)
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Using the slope-point formula for the equation of a line we get:
[tex]y-1=-\frac{1}{2}(x-(-4))\text{.}[/tex]Taking the above equation to its slope-intercept form we get:
[tex]\begin{gathered} y-1=-\frac{1}{2}(x+4), \\ y-1=-\frac{1}{2}x-\frac{4}{2}, \\ y-1=-\frac{1}{2}x-2, \\ y=-\frac{1}{2}x-1. \end{gathered}[/tex]Answer:
[tex]y=-\frac{1}{2}x-1.[/tex]1. It takes Keimon 36 minutes to ride his car 28 miles. At this rate, how longwill it take him to ride 38 miles? (YOUR ANSWER MUST BE IN HOURS)
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it is given keimon travels 28 miles in 36 minutes
so its speed is = distance/ time
= 28 / 36
= 7/9 miles per minute
the time to travel 38 miles will be = distance/ speed
[tex]=\frac{38}{\frac{7}{9}}=\frac{38\times9}{7}=\frac{342}{7}[/tex]so the time is 342/7 minutes
now we will convert it into hours
60 minutes = 1 hours
1 minute = 1/60 hours
342/7 minutes =
[tex]\begin{gathered} =\frac{1}{60}\times\frac{342}{7} \\ =0.81 \end{gathered}[/tex]it will take 0.81 hours to ride 38 miles.
X+YQuestion 24Page 1 of 4LineGuide?Every computer that a business owner purchases will lose most of its value after 5 years of use. The owner plans to purchase a computerfor $2,100 and replace it after 4 years.Part AMethod 1 of determining the computer's value is to reduce its value by a constant amount after each year of use. This method values thecomputer at $0 after 5 years of use.Which function, f(n), represents the value of the computer after n years of use for Method 1?f(n) = 420nf(n) = 525nf(n) = 2,100 - 420nd f(n) = 2,100 - 525n
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EXPLANATION
Let's see the facts:
Useful life= 5 years
Computer Price = $2100
Replacing time = 4 years
Si, the initial price is $2,100 and we can assevere that we must subtract the depreciation component to this number in order ti reduce its value by a constant amount.
f(n) = 2,100 - ...
The next term to consider is constant decreasing amount is 420n or 525n. How can we get the right term?
It's simple, just replacing the variable n by 5 and looking if f(n) is equal to $0.
f(5) = 2,100 - 420*(5) = 0 Rigth reasoning!
f(5) = 2,100 - 525*(5) = -525 It's not equal to zero!
The function f(n) that represents the value of the computer after n years of uses is f(n) = 2,100 -420n
Is Figure B a scale copy of Figure A? berhentian 6 2. 8 3 4 2 1 6 3 Figure A Figure B
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If two figures are scale copies of each other, then the corresponding sides should have the same ratio.
Find the quotient of the sides of figure A to the corresponding sides of figure B. If they all have the same ratio, then figure B is a scale copy of figure A:
[tex]\begin{gathered} \frac{8}{4}=2 \\ \frac{4}{2}=2 \\ \frac{6}{3}=2 \\ \frac{2}{1}=2 \\ \frac{6}{3}=2 \end{gathered}[/tex]Since all the ratios are equal to 2, the answer is:
[tex]\text{Yes. Figure B is a scale copy of figure A.}[/tex]15Find the volume of the following triangular prism. *5 in6.1in13 in7 in215.5 cubic inches220.5 cubic inches225.5 cubic inches227.5 cubic inches
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Volume V = Area of triangle x Height
. = (7x5/2) • 13
. = (17.5) • 13
. = 227.5
Then ANSWER IS
Prism volume V= 227.5 cubic inches
rite the following ratio as a fraction in lowest terms.54to56
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We want to write the ratio of 54 to 56 as a fraction in lowest terms. To do this we have to factorize the numbers and simplify the equals factors:
[tex]\begin{gathered} \frac{54}{56}=\frac{2\cdot27}{2\cdot28}=\frac{27}{28}=\frac{3\cdot3\cdot3}{4\cdot7} \\ In\text{ the last, we cannot simplify the factors, so the lowest terms are:} \\ \frac{54}{56}=\frac{27}{28} \end{gathered}[/tex]Use substitution in the system of equations. What is the value of x in both equations?A. 3B. -6C. 6D. 2
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Given the following question:
[tex]\begin{gathered} 3x+2y=-12 \\ x=4y-18 \end{gathered}[/tex][tex]\begin{gathered} 3x+2y=-12 \\ x=4y-18 \\ \text{ Substitute x=4y - 18 into the first equation:} \\ 3(4y-18)+2y=-12 \\ 18-4=14y \\ 14y-54=-12 \\ -12+54=42 \\ y=3 \\ \text{ Substitute to find x} \\ x=4\times3-18 \\ 4\times3=12 \\ 12-18=-6 \\ x=-6,y=3 \\ x=-6 \end{gathered}[/tex]Option B is your answer.
Suppose you won a free ticket to a three-hour Katy Perry concert. At the box office, the ticket would cost $140.00. If you do not go tothe concert, you could instead work on a project for which you are being paid $31.00 per hour.The opportunity cost of going to the Katy Perry concert is $______
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Simply put, opportunity cost is the loss you incur for choosing something because of other alternatives.
Now, if you choose to go to the Katy Perry concert, the ticket costs $140. But you aren't paying because you got it for free!
On the other hand, if you don't go, you can word on a project at $31 per hour for 3 hours, that would give you:
31 * 3 = $93
Thus, you can earn a potential $93 by not going to the concert. If you choose to go to the concert, you are forgoing the potential of earning $93!
Thus, we can say:
The opportunity cost of going to the Katy Perry concert is $93
can you please help me
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The number of outfits can be determined from the fundamental principle of counting as,
[tex]\begin{gathered} \text{Number of outfits=Number of shirts}\times Number\text{ of shorts}\times Number\text{ of pair of socks} \\ =5\times4\times6 \\ =120 \end{gathered}[/tex]Thus, option (B) is the correct solution.
Hello! I was wondering if if you could solve this becuseI I just want to check my work because I already did it and I want to be sure it's right.
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Explanation
[tex]\begin{gathered} \frac{2p^5+6p^3}{2p} \\ \end{gathered}[/tex]Step 1
factorize the numerator
[tex]\begin{gathered} \frac{2p^5+6p^3}{2p}=\frac{2p^5+2\cdot3p^3}{2p} \\ \frac{2p^5+6p^3}{2p}=\frac{2p^{4+1}+2\cdot3p^{2+1}}{2p} \\ \frac{2p^5+6p^3}{2p}=\frac{2pp^4+2p\cdot3p^2}{2p} \\ \frac{2p^5+6p^3}{2p}=\frac{2p(p^4+3p^2)}{2p} \end{gathered}[/tex]Step 2
the 2p in the numerator cancels the 2p in the denominator,so
[tex]\begin{gathered} \frac{2p(p^4+3p^2)}{2p}=p^4+3p^2 \\ \\ p^4+3p^2 \end{gathered}[/tex]I hope this helps you
a rectangular school gym has a length of [tex]x + 14[/tex]and a width of [tex]x - 20[/tex]which measure does[tex](x + 14)( x - 20)[/tex]represent?
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Given:
Sides of rectangle
x+14
x-20
Required:
To tell which does equation show
Explanation:
Represent (area) is a quantity used to indicate the extent of a surface or plane figure
Required answer:
(area)
Use the given statement to represent a claim. Right it’s compliment and state which is H And H 0 a
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Solution
Use the given statement to represent a claim:
[tex]\mu\ge514[/tex]The alternative hypothesis Ha is the complement of the null hypothesis. It is a statement that must be true if H0 is false and it contains a statement of strict inequality, such as >, ≠, or <
The complement of the claim is less than 514 and opposite to the alternative hypothesis.
[tex]\begin{gathered} H_0=null\text{ hypothesis} \\ H_a=alternative\text{ hypothesis} \end{gathered}[/tex]The null hypothesis is typically abbreviated as H0 and the alternative hypothesis as H1.
H0 is true if and only if H1 is false.
[tex]\begin{gathered} H_0\text{ : }\mu\ge514 \\ H_a\text{ :}\mu<514 \end{gathered}[/tex][tex]\mu<514[/tex]Find the probability that a randomly chosen point is the figure lies in the shaded region. Give all answers in fraction and percent forms. help with #7
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In order to determine the probability that a randomly chosen point lies in the shaded region of the figure we just have to divide the area of the shaded region by the total area.
As you can see in figure #7, the shaded area is the region bounded by the box and out of the two circles, then in order to determine the magnitude of the shaded resion we just have to subtract the area of the two circles from the area of the rectangle, like this:
Area of each circle
Each circle has a diameter of 2, then the radius of each circle is 1 (2/2), by replacing the radius r into the following formula, we can calculate the area of each circle:
[tex]\begin{gathered} A=\pi r^2 \\ A=\pi(1)^2 \\ A\approx3.14 \end{gathered}[/tex]Then the area of each circle is abot 3.14, by multiplying this area by 2 we can determine the total area of the two circles like this:
[tex]At=2\times3.14=6.28[/tex]Then the area of the two circles is 6.28.
The area of the rectangle can be calculated by multiplying the width and the length of the rectangle, to get:
[tex]Ar=4\times3=12[/tex]Then, the area of the shaded area is:
As = 12 - 6.28
As = 5.72
By dividing the area of the shaded area by the area of the rectangle we get the probability like this:
[tex]P=\frac{5.72}{12}=0.48[/tex]Then, the probability that a randomly chosen point lies in the shaded region is 0.48 (48%)
What is the surface area for each part of the figure? What is the total surface area of the figure?
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Solution:
Given:
A composite figure showing a square-based pyramid, a square prism, and a cube.
To get the surface area, we find the surface area of each part separately.
For the square-based pyramid,
[tex]\begin{gathered} It\text{ has four triangles and a square base.} \\ \text{The square base is not part of the surface of the whole shape however.} \\ \\ \text{Hence, the area of the pyramid is;} \\ 4\times\text{area of triangle} \\ b=6 \\ h=4 \\ A=\frac{1}{2}bh \\ \text{Hence,} \\ \text{Area}=4\times\frac{1}{2}\times6\times4=48 \\ A=48ft^2 \end{gathered}[/tex]The surface area of the pyramid is 48 square feet.
For the square prism,
It has 6 faces. However, only four are the surface of the composite shape. The other two faces are inside the shape and will not count as a surface.
Hence,
[tex]\begin{gathered} \text{Area of front and back face;} \\ A=l\times b \\ A=20\times6=120 \\ \text{For the two faces;} \\ A=2\times120=240ft^2 \\ \\ \text{Also, the area of the top and bottom face,} \\ A=20\times6=120 \\ \text{For the two faces;} \\ A=2\times120=240ft^2 \\ \\ \text{Hence, the surface area of the square prism is 240+240} \\ =480ft^2 \end{gathered}[/tex]Therefore, the area of the square prism is 480 square feet.
For the cube;
The cube has 6 faces.
However, only 5faces are part of the surface of the composite shape. One face is within the shape.
Hence,
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There are 24 parents and 8 teachers at a PTO meeting.They are breaking into discussion groups that have 6parents and 2 teachers. How many different groupscan be made?
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Answer:
3,768,688 different ways
Explanation:
The number of ways to select x elements from a group of n elements is calculated as
[tex]\text{nCx}=\frac{n!}{x!(n-x)!}[/tex]In this case, we want to select 6 parents from a group of 24 and select 2 teachers from the 8 teachers, so
[tex]\begin{gathered} 24C6=\frac{24!}{6!(24-6)!}=134596 \\ 8C2=\frac{8!}{2!(8-2)!}=28 \end{gathered}[/tex]Therefore, the groups can be made in 3,768,688 different ways because
24C6 x 8C2 = 134,596 x 28 = 3,768,688
8 teachers into groups of 2:
2,4,6,8 = 4 groups
6 parents into 2 groups, there are 24 parents:
So 6•4=24
Find the mean, median, and mode of the list of values. Round to the nearest tenth if necess17, 9, 35, 26, 38, 33, 9,9
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We have the following list of values:
17, 9, 35, 26, 38, 33, 9,9
rearrange them: 9,9,9,17,26,33,35,38
the population size is 8, so we can calculate the mean as it follows
[tex]\operatorname{mean}=\frac{9+9+9+17+26+33+35+38}{8}=22[/tex]mean = 22
using the list of values, we can find that the median is
[tex]\operatorname{median}=\frac{17+26}{2}=21.5[/tex]median = 21.5
and, mode = 9
because the value 9 is 3 times on the list
Can anyone help me with number 5 simplifying negative square roots
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What is the quotient of (xº+3x?-4x-12)-(4+5x+6)?A: X + 2B: X-2C: x + 6D: X-6
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You have the following polynomial of Degree 3:
[tex]x^3+3x^2-4x-12[/tex]And the other polynomial (of Degree 2) is:
[tex]x^2+5x+6[/tex]The Quotient is defined as the result of a Division. Then, you can find it as following:
1. You can express the Division as following:
[tex]=\frac{x^3+3x^2-4x-12}{x^2+5x+6}[/tex]2. Now you can factor the numerator and the denominator:
a. For the numerator:
- Make two groups of two terms using parentheses:
[tex]=(x^3+3x^2)-(4x+12)[/tex]- Factor the Greatest Common Factor out (of each group):
[tex]=x^2(x+3)-4(x+3)[/tex]- Combine the factors together:
[tex]=(x^2-4)(x+3)[/tex]- Since, by definition:
[tex]a^2-b^2=(a+b)(a-b)[/tex]You can simplify it as following:
[tex]=(x-2)(x+2)(x+3)[/tex]b. For the denominator, find two numbers whose sum is 5 and whose product is 6. These would by 3 and 2. Then:
[tex]undefined[/tex]What is the slope of the line?
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Two points on the line are (3,0) and (0,-4.5)
The slope m of a line
= (y2 - y1)/(x2 - x1)
= (-4.5 - 0)/(0 - 3)
= -4.5/-3
= 1.5
The slope is 1.5
Solving the linear equations variable on one side
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The pick up fee is $2.50.
After each mile, $1.95 is added.
That is, after the first mile, we have;
[tex]\begin{gathered} \text{Fe}e=\text{ 2.50 + 1.95(1)} \\ \text{After the second mile, we have;} \\ Fee=\text{ 2.50+1.95(2)} \end{gathered}[/tex]Isaac total charge = $27.46;
Generally, let the number of miles driven by the taxi be x, then we have;
[tex]1.95x+2.50=27.46[/tex]Solving for the number of miles Isaac travelled, we have;
[tex]\begin{gathered} 1.95x=27.46-2.50 \\ 1.95x=24.96 \\ x=\frac{24.96}{1.95} \\ x=12.8\text{miles} \end{gathered}[/tex]CORRECT OPTION:
[tex]1.95x+2.50=27.46;\text{ Isaac traveled 12.8 miles.}[/tex]can u pls help me with this question i also want the answer
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Given:
The graph show relationship between the length of hallway Denise covers in tiles (x)
And the number of tiles needed (y)
AS shown: the relation begins from the point (0,0)
And the relation is linear
so, the relation between x and y are proportional
So, the answer is yes
Now, we need to get the relation:
The general form of the proportional relationship is : y = kx
So, using one point from the line to get the value of k
so, the line passing through the point ( 4 , 20 )
when x = 4 , y = 20
so,
[tex]\begin{gathered} 20=k\cdot4 \\ \\ k=\frac{20}{4}=5 \end{gathered}[/tex]So, the relation between x and y is :
[tex]y=5x[/tex]So, the constant is 5
write the equation for the line using the given information. Write the equation in slope intercept form Y=mx+b write the equation of the line with slope =6 and passing through the point (-4 -9)
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m = 6 and the line passes through (-4,-9)
Then, we have: -9 = 6*(-4) + b
b - 24 = -9
b = 24 - 9 = 15
Therefore, the equation for the line is y = 6x + 15
Write an equation in each sentence. Analyze and solve.3. Find three consecutive integers whose sum is 99. Find the integers.
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Given that the Sum of three consecutive integers is:
[tex]99[/tex]Let be:
- The first integer:
[tex]n[/tex]- The second integer:
[tex]n+1[/tex]- And the third integer:
[tex]n+2[/tex]By definition, the Sum is the result of an Addition.
Therefore, in this case, you can set up the following equation:
[tex]n+(n+1)+(n+2)=99[/tex]When you solve for "n", you get:
[tex]n+n+1+n+2=99[/tex][tex]3n+3=99[/tex][tex]3n=99-3[/tex][tex]3n=96[/tex][tex]\begin{gathered} n=\frac{96}{3} \\ \\ n=32 \end{gathered}[/tex]Now that you know that first integer, you can determine that the other consecutive integers are:
[tex]n+1=32+1=33[/tex][tex]n+2=32+2=34[/tex]Hence, the answer is:
[tex]\begin{gathered} 32 \\ 33 \\ 34 \end{gathered}[/tex]Salma has completed 22 deliveries so far this week. She needs to make 55 deliveries for the week. What percentage of her deliveries has Salma completed?
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The number of deliveries completed by Salma = 22.
Total deliveries to be completed = 55.
Percentage of delivery is calculated as,
[tex]\begin{gathered} \text{Percentage of delivery = }\frac{22}{55}\times100. \\ \text{Percentage of delivery = 20 \%} \end{gathered}[/tex]Thus the percentage of delivery completed is 20%.
A line passes through (2, (2, – 1) and (4, 5) . Which answer is the equation of the line? 0-3x + 5y = 13 6 -3x + y = 17 0-3x + 5y = -13 0-3x + y = -7
Answers
A line passes through
(2, -1) and (4, 5)
We can say, given:
[tex]\begin{gathered} (x_1,y_1)=(2,-1) \\ \text{and} \\ (x_2,y_2)=(4,5) \end{gathered}[/tex]The equation of a line is given as:
[tex]y=mx+b[/tex]Where
m is slope and b is y-intercept
Now, finding the slope using the slope formula:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{5+1}{4-2} \\ m=\frac{6}{2} \\ m=3 \end{gathered}[/tex]So, the equation becomes:
y = 3x + b
Putting a point in (x,y), such as (4,5), we have:
y = 3x + b
5 = 3(4) + b
5 = 12 + b
b = 5 - 12
b = -7
Thus,
equation of the line >>> y = 3x - 7
Re-arranging in standard form >>> -3x + y = -7
Last Answer choice is right.