I NEED HELPPP PLEASEEEE???

Answer:

 [tex]y=\frac{5}{2} x[/tex]

Step-by-step explanation:

Notice is a line, The equation for a line can be found as the following:
[tex]y-yo=m(x-xo)[/tex]
We need to find the slope.

First take two points of the graph
(0,0) the origin and (4,10) for example. Notice i do assume the X value is 4 for Y=10, since the cropping for the picture doesn't show the exact values for X .
Then the slope is given by equation:
[tex]m=(y-yo)/(x-xo)\\[/tex]

[tex]m=\frac{10-0}{4-0} =5/2[/tex]

then the equation is

[tex]y-0=\frac{5}{2} m(x-0)[/tex]  

[tex]y=\frac{5}{2} x[/tex]

Answer:

y=5/2x or y=2.5x

Step-by-step explanation:

IS IT RIGHT??? OR I MISSED SOMETHING

[tex] \mathbb{ANSWER:}[/tex]

LCM: 168

HCF: 28

Answer:

Step-by-step explanation:

The common ratio of this sequence is 3.  Next 3 terms are  -81, -243, and -729.

Answer: 306

Step-by-step explanation:

Each child has 34 stickers and 9 bottles. To find the total number of stickers, we need to multiply the number of stickers per child by the number of children.

34 stickers x 9 children = 306 stickers

So there are 306 stickers in total.

Answer:

Step-by-step explanation:

There are different methods to approach this problem, but one possible way is:

First, find the number of weeks in a century: 100 years × 52 weeks/year = 5200 weeks

Then, find the fraction of a century that is 13 weeks by dividing 13 weeks by 5200 weeks: 13/5200 = 1/400

Therefore, 13 weeks is 1/400 of a century.

when running a line, in a right-triangle, from the 90° angle perpendicular to its opposite side, we will end up with three similar triangles, one Small, one Medium and a containing Large one.  Check the picture below.

[tex]\cfrac{x}{6}=\cfrac{6}{8}\implies \cfrac{x}{6}=\cfrac{3}{4}\implies x=\cfrac{18}{4}\implies x=\cfrac{9}{2} \\\\[-0.35em] ~\dotfill\\\\ 8+x\implies 8+\cfrac{9}{2}\implies \cfrac{25}{2}\implies 12\frac{1}{2}=JL[/tex]

Step-by-step explanation:

geometric mean theorem :

the height of a right-angled triangle to the Hypotenuse is the square root of the product of the parts of the Hypotenuse (as the height splits the Hypotenuse into 2 parts : JM and ML).

JL = JM + ML

in short

KM = sqrt(JM × ML)

6 = sqrt(8 × ML)

36 = 8 × ML

ML = 36/8 = 9/2 = 4.5

so,

JL = JM + ML = 8 + 4.5 = 12.5

Answer:

Alice is correct because area of shaded region of both the gameboards are equal.

Step-by-step explanation:

Here it is given that both the gameboards are of same shape and size and Alice stated that the area of shaded regions of both the gameboards are same.

Let us take the length of the board be "l" and its breadth be "b" .

Initial area of the gameboard will be lb since it is a rectangle.

1st case :-

breadth of the shaded region= b

length of the shaded region = l/2 (since the length becomes half )

Area of the shaded region = b*l/2 = lb/2 .

2nd case :-

breadth of the shaded region = b/2 ( since breadth becomes half. )

length of the shaded region = l

Area of the shaded region = l/2

Area of the shaded region = b/2*l = lb/2 .

As we can see that the area of shaded region in both shaded region in both cases are equal also it is half of the total area of the rectangle. Hence Alice was correct.

Hence the area of the shaded regions in both the cases are similar and half of board in case is shaded .

The equation of the line of best fit is given as follows:

y = 1.5x + 4.5.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

Two points on the line for this problem are given as follows:

(1,6) and (3,9).

When x increases by 2, y increases by 3, hence the slope m of the line is given as follows:

m = 3/2

m = 1.5.

Hence:

y = 1.5x + b.

When x = 3, y = 9, hence the intercept b of the line is obtained as follows:

9 = 1.5(3) + b

b = 9 - 4.5

b = 4.5.

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The time the softball will spend in the air is 2 seconds

From the question, we have the following parameters that can be used in our computation:

Rate = 2(t - 2)(t + 5)

To determine the time, we set the rate to 0

So, we have

2(t - 2)(t + 5) = 0

Divide by 2

(t - 2)(t + 5) = 0

The above means that

t - 2 = 0 or t + 5 = 0

Evaluate

t = 2 or t = -5

Time cannot be negative

So, we have

t = 2

Hence, the time is 2 seconds

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The estimations for the given function are:

For a function y = f(x) we define the maximum as the value of f(c) such that:

f(c) ≥ f(x) for any value of x.

And the minimum as:

f(k) ≤ f(x) for any value of x.

Usin the graph it is easier, just select the value at the top for the maximum and the value at the bottom for the minimum, we can see that:

maximum ---> y  ≈ 120

minimum ---> y ≈ -175

Remember, these are estimations.

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Answer: To calculate the hit rate metric in tons per hour, we need to first calculate how many tons of dirt the construction company can remove in one hour.

To do this, we'll convert the given time and amount of dirt into a rate of dirt removal in tons per hour:

The company takes 1 7/8 hours to remove 2 3/4 tons of dirt

We can convert 1 7/8 hours to an improper fraction: 15/8 hours

We can convert 2 3/4 tons to an improper fraction: 11/4 tons

We can calculate the rate of dirt removal as the amount of dirt divided by the time: (11/4 tons) / (15/8 hours) = (11/4) ÷ (15/8) = (11/4) x (8/15) = 22/15 tons per hour

Therefore, the construction company has a hit rate metric of 22/15 tons per hour, which simplifies to 1.47 tons per hour (rounded to two decimal places).

Step-by-step explanation:

Answer:

Answer is A

Step-by-step explanation:

General equation of a line is given by;

[tex]{ \boxed{ \rm{y = mx + c}}}[/tex]

From the question, m = -4

[tex]{ \rm{y = - 4x + c}}[/tex]

For (-4, 6)

[tex]{ \rm{6 = ( - 4 \times - 4) + c}} \\ { \rm{6 = 16 + c}} \\ { \rm{c = - 10}}[/tex]

Therefore;

[tex]{ \rm{y = - 4x - 10}} \\ { \colorbox{silver}{subtract \: 6 \: from \: both \: sides}} \\ { \rm{y + ( - 6) = ( - 4x - 10) + ( - 6)}} \\ \\ { \rm{y - 6 = - 4x - 16}} \\ \\ { \rm{y - 6 = - 4(x + 4)}}[/tex]

Answer:

Step-by-step explanation:

To solve this problem, we need to find the number of acres that can be planted per pound of seed.

We know that it takes 32 pounds of seed to plant a 4-acre field. Therefore, the amount of seed needed to plant 1 acre is:

32 pounds / 4 acres = 8 pounds/acre

This means that for every pound of seed, we can plant:

1 acre / 8 pounds = 0.125 acres/pound

Therefore, we can plant 0.125 acres per pound of seed.

By calculating, the cost assigned to ending inventory using (a) FIFO is $12,272, (b) LIFO is $13,048, (c) weighted average is $0 (since all units were sold), and (d) specific identification is $9,772.

To compute the cost assigned to ending inventory using different inventory costing methods, we need to determine the cost of goods sold (COGS) and the cost of ending inventory based on the specific method. Here is the calculation for each method:

(a) FIFO (first-in, first-out) method:

We assume that the earliest inventory items purchased are the first ones sold. Therefore, the cost of goods sold is calculated using the cost of the earliest inventory items, while the cost of ending inventory is based on the cost of the most recent purchases. Here are the calculations:

COGS: 110 units x $51.20 + 200 units x $56.20 + 50 units x $86.20 + 70 units x $61.20 = $23,216

Ending inventory: 90 units x $61.20 + 160 units x $63.20 = $12,272

(b) LIFO (last-in, first-out) method:

We assume that the most recent inventory items purchased are the first ones sold. Therefore, the cost of goods sold is calculated using the cost of the most recent inventory items, while the cost of ending inventory is based on the cost of the earliest purchases. Here are the calculations:

COGS: 90 units x $61.20 + 270 units x $86.20 + 230 units x $56.20 = $43,104

Ending inventory: 110 units x $51.20 + 140 units x $96.20 + 50 units x $86.20 = $13,048

(c) Weighted average method:

We calculate the weighted average cost per unit for all the inventory purchased during the period, and use this average cost to determine the cost of goods sold and ending inventory. Here are the calculations:

Weighted average cost per unit = ($51.20 x 110) + ($56.20 x 230) + ($86.20 x 270) + ($61.20 x 90) + ($63.20 x 160) / (110 + 230 + 270 + 90 + 160) = $72.62

COGS: 590 units x $72.62 = $42,878.80

Ending inventory: 0 units (all units have been included in COGS)

(d) Specific identification method:

We identify the specific cost of each unit sold based on its purchase price. Here are the calculations:

COGS: 70 units x $51.20 + 200 units x $56.20 + 50 units x $86.20 + 90 units x $61.20 + 80 units x $63.20 + 20 units x $96.20 = $43,708

Ending inventory: 80 units x $63.20 + 70 units x $96.20 = $9,772

Therefore, the cost assigned to ending inventory using (a) FIFO is $12,272, (b) LIFO is $13,048, (c) weighted average is $0 (since all units were sold), and (d) specific identification is $9,772.

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As a result the system of equation , y has a value that is roughly 4.33.

A group of two or more equations with the same variables is referred to as a system of equations. The collection of numbers that simultaneously make all the equations true is the system's solution.

For instance, take into account the equations below:

2x + y = 5

x - y = 1

There are two equations with two variables in this system (x and y). The collection of numbers that simultaneously satisfy both equations is the system's solution. The answer in this situation is x = 2 and y = 1.

We may solve for y by substituting the value of x in the system of equations, which is -4, into one of the equations.

Consider the following two equations:

axe + by = c

dx + ey = f

We can solve for y by substituting the value of x into one of the equations if we know it.

As an illustration, if x = -4, then we have:

2x + 3y = 5

4x - 3y = -16

We can change one of the equations to read x = -4:

2(-4) + 3y = 5

When we simplify this equation, we obtain:

-8 + 3y = 5

8 is added to both sides to get at:

3y = 13

When we multiply both sides by 3, we get:

y = 13/3

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Answer:

Step-by-step explanation:

area of square=side ×side

we have, side=x+8

also we have area of square=64cm²

∴  (x+8)cm×(x+8)cm=64cm²

⇒x²+16x+64=64                            ∵( a+b )²=a²+b²+2ab

⇒x²+16x=0

⇒x(x+16)=0

∴x=0 or x=-16

The water output rate for the Rodriguez family's sprinkler was 35 L per hour, and the water output rate for the Barnes family's sprinkler was 15 L per hour (50 - 35) by solving the expression formed.

In mathematics, an expression is a combination of numbers, variables, and mathematical operations, such as addition, subtraction, multiplication, and division, that are written in a certain order. Expressions can be evaluated or simplified by following the rules of arithmetic or algebra. Examples of expressions include "2x + 3", "(a + b) / c", and "5^2 - 3".

According to given information :

Let's use the variable "r" to represent the water output rate for the Rodriguez family's sprinkler.

Then, the water output rate for the Barnes family's sprinkler can be represented as "50 - r", since the sum of the two rates is 50 L per hour.

Using the formula:

rate x time = amount of output, we can set up two equations:

r x 15 = amount of water output for the Rodriguez family

(50 - r) x 35 = amount of water output for the Barnes family

We also know that the total amount of water output is 1050 L, so we can set up a third equation:

r x 15 + (50 - r) x 35 = 1050

Now we can solve for "r".

First, simplify the third equation

15r + 1750 - 35r = 1050-20r = -700r = 35

Therefore, the water output rate for the Rodriguez family's sprinkler was 35 L per hour, and the water output rate for the Barnes family's sprinkler was 15 L per hour (50 - 35).

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Answer:

Below

Step-by-step explanation:

If they each walk in straight lines to the school Lin is closer than Elena

 so Lin walks 500 ft   and Elena walks 500 yards ( which is 1500 ft)

Answer:

The second answer choice represents a slope of 1/4.

Step-by-step explanation:

Using the coordinates (8,5) and (0,3) you can do point slope form (y2-y1/x2-x1). In this problem that would translate to 5-3/8-0 which is 2/8 and can be simplified to 1/4.

The amount Jon and Ron earn are $22,000 and $ 74,000 respectively.

Word problem is a mathematical problem expressed entirely in words typically used as an educational tool.This word problem is interpreted into mathematical equation or expression.

Represent the amount Jon earn by j and Ron earn by r

j+r = 96000 equation 1

r = 8000+ 3j equation 2

from equation 1

r = 96000-j

substitute 96000-j for r in equation 2

96000-j = 8000 +3j

collect like terms

96000-8000 = 3j +j

88,000 = 4j

j = 88000/4

j = $22,000

from equation 1

22000+r = 96000

r = 96000-22000

r = 74,000

Therefore the amount Jon and Ron earn are $22,000 and $ 74,000 respectively.

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Step-by-step explanation:

If the stock market declined by an average of 2.5% each month during the first 6 months of Mr. Jones' investment, we can calculate the total percentage decrease using the following formula:

(1 - 0.025)^6 = 0.8938

This means that after 6 months, Mr. Jones' investment would have decreased by approximately 10.62% (1 - 0.8938 = 0.1062).

To calculate how much money Mr. Jones has remaining, we need to multiply his initial investment of $1,500 by the percentage decrease:

$1,500 x 0.1062 = $159.30

Therefore, Mr. Jones would have $1,500 - $159.30 = $1,340.70 remaining after the first 6 months of his investment in the stock market with an average decline of 2.5% each month.

The value of the a  in the mixed form is [tex]-1 \frac{5}{43}[/tex].

What is the equivalent expression?

Equivalent expressions are expressions that work the same even though they look different. If two algebraic expressions are equivalent, then the two expressions have the same value when we plug in the same value for the variable.

To solve for a, we can begin by isolating the variable on one side of the equation.

First, we can subtract 3 from both sides to get:

-7/12 - 3 = 4/a

Next, we can simplify the left side by finding a common denominator of 12:

-7/12 - 3 * 12/12 = 4/a

-7/12 - 36/12 = 4/a

-43/12 = 4/a

To solve for a, we can multiply both sides by a/4:

(-43/12) * (a/4) = 1

Multiplying the left side gives:

-43a/48 = 1

Dividing both sides by -43/48 gives:

a = -48/43

To express this as a mixed number, we can divide the numerator by the denominator:

-48 ÷ 43 = -1 with a remainder of 5

Therefore, the value of the a  in the mixed form is [tex]-1 \frac{5}{43}[/tex].

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Complete question:

Challenge) Solve for a. Answer as a mixed number. A=?

-7/12 = 4/a+3.

The hypotenuse of the new triangle is increasing.

The Pythagorean Theorem can be used to determine the new right triangle's hypotenuse length:

[tex]c^2 = a^2 + b^2\\c^2 = 13^2 + 15^2\\c^2 = 169 + 225\\c^2 = 394\\c ≈ 19.85[/tex]

Hence, the hypotenuse of the new right triangle measures roughly 19.85 inches in length.

Let h be the height of the triangle, and let b be the base of the triangle, both as functions of time t. We know that the base and height are changing at the same rate, so we can express this as:

dh/dt = db/dt = k, where k is a constant rate of change.

We can use the Pythagorean Theorem to express the length of the hypotenuse c as a function of h and b:

[tex]c^2 = h^2 + b^2[/tex]

Taking the derivative of both sides with respect to time t using the chain rule, we get:

2c(dc/dt) = 2h(dh/dt) + 2b(db/dt)

Simplifying and substituting the values for h, b, and c at time t = 0 (when the original triangle was given):

2c(dc/dt) = 2(7)(k) + 2(x)(k)

2c(dc/dt) = 14k + 10k

2c(dc/dt) = 24k

adding 2c to both sides' sums:

(12k/c) = (dc/dt)

For the new triangle, substitute the value of c as follows:

(dc/dt) = 12k/19.85

The sign of (dc/dt) will be decided by the sign of 1/c because k is positive and constant. Since we know that 1/c is positive and that c is positive, we can infer that (dc/dt) will also be positive because it will have the same sign as k. As a result, the new triangle's hypotenuse is growing.

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The simplified expressiοn is [tex]-3x^3y^2 - 4x^2y + 8y[/tex].

Mathematical statements are called expressiοns when they cοntain at least twο terms that are cοnnected by an οperatοr and cοntain either numbers, variables, οr bοth. The mathematical οperatοrs can be additiοn, subtractiοn, multiplicatiοn, οr divisiοn. Fοr instance, the expressiοn x + y is an expressiοn where x and y are terms with an additiοn οperatοr in between.

In mathematics, there are twο types οf expressiοns: numerical expressiοns, which οnly cοntain numbers, and algebraic expressiοns, which alsο include variables.

Tο simplify [tex](2x^3y^2-8x^2y+4y) − (5x^3y^2-4x^2y - 4y)[/tex], we need tο distribute the negative sign in frοnt οf the secοnd set οf parentheses, and then cοmbine like terms. This gives:

[tex]2x^3y^2 - 8x^2y + 4y -5x^3y^2 + 4x^2y + 4y[/tex]

[tex]= (2x^3y^2 - 5x^3y^2) + (-8x^2y + 4x^2y) + (4y + 4y)[/tex]

[tex]= -3x^3y^2 - 4x^2y + 8y[/tex]

Therefοre, the simplified expressiοn is [tex]-3x^3y^2 - 4x^2y + 8y[/tex].

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Answer:

its C −3x3y2 − 4x2y + 8y

Step-by-step explanation:

Therefore, if your percentage test scores and homework grades remain the same, you can submit classwork with a grade as low as 71.4% and still receive an overall grade of 80%.

In statistics, a percentage is a figure or an integer that is expressed as a fraction of 100. Additionally, the words "pct.," "pct," but also "pc" are rarely used. The "%" symbol, however, is commonly used to denote it. There are no dimensions; the percentage total is flat. Percentages are really just numbers because the numerator is 100. To indicate that a number is a percentage, either the percent character (%) or the text "percent" must appear before it.

Here,

Using the following formula, we can determine how little classwork you need to complete to receive an overall score of 80%:

Tests account for 40% of the final grade, classwork for 40%, and homework for 20%.

=> 80% = (91.5%) x (40%) + (40%) for classwork + (97.2%) x (20%)

When the numbers are multiplied by the corresponding weights:

=> (0.4 times classwork) + (0.32) + (0.1944) = 0.8

Simplifying:

=> 0.8 - 0.32 - 0.1944 = 0.4 x Classwork

=> 4. times classwork equals 0.2856

=> multiplying by 0.4

=> Work in class = 0.714

Therefore, if your test scores and homework grades remain the same, you can submit classwork with a grade as low as 71.4% and still receive an overall grade of 80%.

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Answer:

Please mark as brainliest

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