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a) Name the graph?

b) In first 2 s the object is said to be in ______________ motion.

(uniform motion / uniform acceleration)

c) The portion BC of the graph represents which type of motion?

d) Find out acceleration in first 2 s?

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s[/tex]

v₂ = 4.2 m/s

b)

We will use the law of conservation of momentum here:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

[tex](1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)[/tex]

v₂ = 5 m/s

Answer:

Increases

Explanation:

In the Compton scattering experiment with x-rays,

The change in operation

[tex]\Delta \lambda = \frac{h}{m_oc} [1-cos\theta][/tex]

Now rest being constant, as \theta increases, cos\theta decreases

Hence, The change in wavelength will increase with the increase in \theta.

Hence, wavelength increases with an increase in the angle of scatttering.

Answer:

The parent nucleus splits into lighter daughter elements

Explanation:

Nuclear fission involves the splitting of nucleus of a lighter element with smaller particles

Answer:

a.  9.99625 cm b. 68 °C

Explanation:

(a) What is the length of the rod at the freezing point of water (0 0C)?

Before we find the length of the rod, we need to find the coefficient of linear expansion, α = (L - L₀)/[L₀(T - T₀)] where L₀ = length of rod at temperature T₀ = 10.0 cm, T₀ = 20 °C, L = length of rod at temperature T = 10.015 cm and T = 100 °C

Substituting the values of the variables into the equation, we have

α = (L - L₀)/[L₀(T - T₀)]

α = (10.015 cm - 10.0 cm)/[10.0 cm(100 °C - 20 °C)]

α = 0.015 cm/[10.0 cm × 80 °C]

α = 0.015 cm/[800.0 cm °C]

α = 0.00001875 /°C

We now find the length L₁ at T₁ = 0 °C from

L₁ = L₀(1 + α(T₁ - T₀))

So, substituting the values of the variables into the equation, we have

L₁ = L₀(1 + α(T₁ - T₀))

L₁ = 10.0 cm[1 +  0.00001875 /°C(0° C - 20 °C)]

L₁ = 10.0 cm[1 +  0.00001875 /°C × -20° C]

L₁ = 10.0 cm[1 - 0.000375]

L₁ = 10.0 cm[0.999625]

L₁ = 9.99625 cm

(b) What is the temperature if the length of the rod is 10.009 cm?

With length L₃ = 10.009 cm at temperature T₃, using

L₃ = L₀(1 + α(T₃ - T₀))

making T₃ subject of the formula, we have

L₃/L₀ = 1 + α(T₃ - T₀)

L₃/L₀ - 1 = α(T₃ - T₀)

T₃ - T₀ = (L₃/L₀ - 1)/α

T₃ = T₀ + (L₃/L₀ - 1)/α

substituting the values of the variables into the equation, we have

T₃ = 20 °C + (10.009 cm/10.0 cm - 1)/0.00001875 /°C

T₃ = 20 °C + (1.0009 - 1)/0.00001875 /°C

T₃ = 20 °C + 0.0009/0.00001875 /°C

T₃ = 20 °C + 48 °C

T₃ = 68 °C

Answer:

[tex]d=1.8\ g/cm^3[/tex]

Explanation:

Given that,

Mass, m = 27 grams

Volume of the substance, V = 15 cm³

We need to find the density of the substance. We know that, the density of an object is given by mass per unit volume. So,

[tex]d=\dfrac{m}{V}\\\\d=\dfrac{27}{15}\\\\d=1.8\ g/cm^3[/tex]

So, the density of the substance is equal to [tex]1.8\ g/cm^3[/tex].

Answer:

This is based upon the fact that meteorites are generally believed to have originated as solid debris from Larger bodies like meteoroid or asteroids

Explanation:

Iron meteorites are interpreted as deriving from the cooled metallic core of a larger asteroid , because meteorites are generally believed to have originated as solid debris from Larger bodies like meteoroid or asteroids that are located outside the planet but found their way into our planet .

I = 4 A

Explanation:

From Ohm's law, the voltage is given by

V = IR

or

I = V/R = (80 V)/(20 ohms)

= 4 A

Answer: 9 times yesterday's power output

Explanation:

Power is the rate at which a certain work is done. The unit of power is Watt and it's equal to work divided by the time taken to complete the work.

In this scenario, since the person did three times the work in one-third the time, then the power output will be:

= Work done / Time

= 3/⅓

= 3 × 3

= 9

Therefore, the power output must have been 9 times yesterday's power output.

Answer:

v1= 12.5miles, t= -7.25m, a= 0

v= 1/2at^2

v= 1/2×

Answer: hello the options related to your question is missing attached below are the missing options

answer : The molecules with the highest temperature will bounce off their neighbors, losing energy to them and so on until the system is at a new equilibrium with the piston moved out  ( option B )

Explanation:

What best describes the situation of what will happen next as explained in the question is in Option B

Because molecules with higher temperatures will always posses higher kinetic energy and they will collide more frequently with surrounding molecules passing on their energy in the process until the energy gets to the molecules closest to the piston. The molecules closest to the piston will then hit the piston until a new equilibrium is achieved

Answer:

Potential difference, V = -0.000224 Volts

Explanation:

Given the following data;

Quantity of charge = 6.93*10-4 C

Energy = -3.09 J

To find the electric potential V at that point?

Mathematically, the energy transferred per unit of charge is given by the formula;

E = QV

Where:

E is the energy

Q is the quantity of charge

V is the potential difference.

Substituting into the formula, we have;

[tex] -3.09 = 6.93*10^{-4} * V [/tex]

[tex] V = \frac {6.93*10^{-4}}{-3.09} [/tex]

Potential difference, V = -0.000224 Volts

Answer:

   i = 1.09 10⁴ A

Explanation:

For this exercise we will look for the resistance of the wire

          R = ρ L / a

the area of ​​the wire is

          a =ππ r² = π πd² / 4

we substitute

         R = ρ L 4 / π d²

          R = 1.72 10⁻⁸   20  4/π 8 10⁻⁴

         R = 5.47 10⁻⁴ Ω

to calculate the current we use ohm's law

           V = R i

            i = V / R

            i = 6 / 5.47 10⁻⁴

            i = 1.09 10⁴ A

Answer:

It’s like medium uk

Explanation:

The size of electron charge is estimated to be 1.6 × 10-¹⁹

Answer:

h = 0.46 m

Explanation:

According to the law of conservation of energy:

Potential Energy Lost by Roller Coaster = Kinetic Energy Gained by Roller Coaster

[tex]mgh = \frac{1}{2}mv^2\\\\2gh = v^2\\\\h = \frac{v^2}{2g}[/tex]

where,

h = height = ?

v = speed at bottom = 3 m/s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]h = \frac{(3\ m/s)^2}{(2)(9.81\ m/s^2)}[/tex]

h = 0.46 m

Answer:

=>8x+9x+5+3

=>8x+9x+5+3=>17x+8

Answer:

The initial speed of the second arrow is 33.8 m/s.

Explanation:

initial speed of first arrow, u = 34 m/s

Let the initial height of the second arrow is h.

Let they both reaches at maximum height H.

Let the time taken by the first arrow is t and the second arrow is t - 0.0204

Let the initial speed of the second arrow is u'.

Use first equation of motion for the first arrow.

v = u - gt

0 = u - gt

34 = gt ..... (1)

For the second arrow

v =u' - g (t - 0.0204)

0 = u' - gt + 9.8 x 0.0204

u' = 34 - 0.1999 = 33.8 m/s

Answer:

a. V = 100 voltios

b. Para 120 V → [tex]R_{2} = 4 \Omega[/tex]

c. Para 110 V → [tex]R_{2} = 2 \Omega[/tex]

Explanation:

a. La tensión se puede calcular mediante la ley de Ohm:

[tex] V = IR [/tex]

V: es el voltaje o tensión =?

I: es la corriente = 5 A

R: es la resistencia = 20 Ω

Entonces, la tensión es:

[tex]V = IR = 5 A*20 \Omega = 100 V[/tex]

b. La resistencia adicional es la siguiente:

[tex] R_{2} + R_{1} = \frac{V}{I} [/tex]

[tex]R_{2} = \frac{V}{I} - R_{1} = \frac{120 V}{5 A} - 20 \Omega = 4 \Omega[/tex]

c. La resistencia adicional para operar a 110 voltios es:

[tex]R_{2} = \frac{V}{I} - R_{1} = \frac{110 V}{5 A} - 20 \Omega = 2 \Omega[/tex]

Espero que te sea de utilidad!

Answer:

The question above would be written again but this time with options attached to it for comprehension sake:

Which of the following best describes the formation of surf?

A.  Waves energy, rebounding from its impact with shore, crashes into oncoming waves, causing them to break.

B. Entering shallow water forces wave energy upward, making the wave crest unstable and causing it to break.

C. A wave encountering shallow water begins to slow at its bottom, while the top of the wave continues at its previous speed. This causes the wave to break.

D. As waves enter shallow water, the distance between wave crests (wavelength) shortens, increasing the tendency to break.

The correct answer is option C (A wave encountering shallow water begins to slow at its bottom, while the top of the wave continues at its previous speed. This causes the wave to break).

Explanation:

Surf could mean crashing waves or breaking waves. Generally, the wave speed is constant in the same medium, however, the wave speed decreases as it enters shallow water which is largely due to the water depth which is relatively small, especially when it encounters the bottom of the shallow water. While the top of the wave overtakes the bottom of the wave, making sure the top of the wave continues at its previous speed.

Answer:

gsg

Explanation:

The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.

The basic principle of charges is that, two like charges repel and unlike charge attracts. That is: two negative charged bodies or two positively charged bodies will repel each other and one negative charged body attracts a positively charged body.

In both cases attraction or repulsion the charged particles exerts a force with each other called the electrostatic force. The electrostatic force between two charges is directly proportional to the magnitude of charges and inversely proportional to the distance between them.

The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.

Find more on electrostatic repulsion:

https://brainly.com/question/24013868

#SPJ2

Answer: same force in opposite direction.

Explanation: Charges of opposite sign attracts each other and charges with same sign repel each other. Because only sign of negative charge changes, and absolute value of charge remains same, value of force is same but is in opposite direction.

Answer:

A) same force, but in the opposite direction

Explanation:

he's right

When you double capacitance and inductance, the new resonace frequency becomes f0/2.

The resonace frequency of RLC series circuit, is the frequency at which the capacitivity reactance is equal to inductive reactance.

Xc = Xl

[tex]\frac{1}{2\pi f_0C} = 2\pi f_0 L\\\\4\pi^2 f_0^2 LC = 1\\\\f_0^2 = \frac{1}{4\pi^2 LC} \\\\f_0 = \sqrt{\frac{1}{4\pi^2 LC} } \\\\f_0 = \frac{1}{2\pi } \frac{1}{\sqrt{LC} }[/tex]

where;

When you double capacitance and inductance, the new resonace frequency becomes;

[tex]f_0 = \frac{1}{2\pi } \frac{1}{\sqrt{LC} }\\\\f_1 = \frac{1}{2\pi } \frac{1}{\sqrt{2L (2C)} } \\\\f_1 = \frac{1}{2\pi } \frac{1}{\sqrt{4LC} }\\\\f_1 = \frac{1}{2}( \frac{1}{2\pi } \frac{1}{\sqrt{LC} })\\\\f_1 = \frac{1}{2} (f_0)[/tex]

Thus, When you double capacitance and inductance, the new resonace frequency becomes f0/2.

Learn more about resonance frequency here: https://brainly.com/question/9324332

Explanation:

.Flame retar,dant plastic additi,ves are compounds added to plastics and other materials to inhibit, suppress or de,lay combustion. These compounds are useful in impending burning in the ign,ition phase of fire. They do not prevent char,ring or melting nor do they increase the heat resistance of a material

Answer:

here's an explanation but not the answer

please kindly send No or Yes understand.

Explanation:

A 10-N force is applied to push a block across a friction free surface for a displacement of 5.0 m to the right.

See Answer

See Answer

A 10-N frictional force slows a moving block to a stop after a displacement of 5.0 m to the right.

Answer:

Linear magnification = 1/3

Explanation:

Given:

Convex mirror

Object's distance from pole = 2f

Find:

Linear magnification

Computation:

Object distance, u = −2f

So,

1/v + 1/u = 1/f

1/v + 1/(-2f) = 1/f

1/v = 1/f + 1/2f

BY taking LCM

1/v = 3 / 2f

v = 2f / 3

Magnification, M = -v / u

So,

Magnification, M = (2f / 3) / 2f

Magnification, M = 2f / 6f

Magnification, M = 2 / 6

Linear magnification = 1/3

Answer:

391.5 J

Explanation:

The amount of work done can be calculated using the formula:

Looking at the formula, we can see that the mass of the object does not affect the work done on it.

Substitute the force applied and the displacement of the object into the equation.

The amount of work done on the object is 391.5 J in order to move it 4.5 meters with an applied force of 87 Newtons.

Mass doesn't matter on amount of work done .We can calculate amount of work done through Force and Displacement

[tex]\boxed{\sf W=Fd}[/tex]

[tex]\\ \sf\longmapsto Work\:Done=87(4.5)[/tex]

[tex]\\ \sf\longmapsto Work\:done=391.5J[/tex]

Answer:

The uniy which is accepted all over the world is called SI unit.

Explanation:

The system of measurement that is agreed by the international convention if scientists that is held in paris of France to adopt an international unit is called SI unit unit.

Answer:

a) 3.9 x 10⁻⁵ kg

Explanation:

The amount of mass required to produce the energy can be given by Einstein's formula:

[tex]E = mc^2\\\\m = \frac{E}{c^2}[/tex]

where,

m = mass required = ?

E = Energy produced = 3.5 x 10¹² J

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]m = \frac{3.5\ x\ 10^{12}\ J}{(3\ x\ 10^8\ m/s)^2} \\\\m = 3.9\ x\ 10^{-5}\ kg[/tex]

Hence, the correct option is:

a) 3.9 x 10⁻⁵ kg

Answer:

C. Visible light

Explanation:

Visible light is responsible for the colors of objects.

Hope it will help :)❤