Answer:
A.) LGJ
Step-by-step explanation:
A primary credit cardholder's card has an APR of 22. 99%. The current monthly balance, before interest, is $4,528. 34. Determine how much more the cardholder will pay, making monthly payments of $200, until the balance is paid off, instead of paying off the current balance in full
The cardholder will pay an additional $1,471.66 in interest by making monthly payments of $200 until the balance is paid off instead of paying off the current balance in full.
First, we need to calculate the total interest that will accrue on the current balance of $4,528.34. We can do this using the formula
Interest = Balance x (APR/12)
where APR is the annual percentage rate and is divided by 12 to get the monthly interest rate. Plugging in the values, we get:
credit card Interest = $4,528.34 x (22.99%/12) = $87.80
So the total interest that will accrue on the current balance is $87.80.
Next, we need to calculate how long it will take to pay off the balance by making monthly payments of $200. We can use a credit card repayment calculator to do this, but we'll use a simplified formula here
Months = -log(1 - (Balance x (APR/12))/Payment) / log(1 + (APR/12))
where Payment is the monthly payment amount. Plugging in the values, we get
Months = -log(1 - ($4,528.34 x (22.99%/12))/$200) / log(1 + (22.99%/12)) = 29.6 months
So it will take about 30 months (or 2.5 years) to pay off the balance by making monthly payments of $200.
Finally, we can calculate how much more the cardholder will pay in total by subtracting the current balance from the total amount paid over 30 months
Total amount paid = $200 x 30 = $6,000
Total interest paid = $6,000 - $4,528.34 = $1,471.66
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On Sunday a local hamburger shop sold 356 hamburgers and cheeseburgers. The number of cheeseburgers sold was three times the number of hamburgers sold. How many hamburgers were sold on Sunday
The number of hamburgers sold on Sunday was 89
How many hamburgers were sold on SundayLet's assume that the number of hamburgers sold on Sunday was x.
According to the problem, the number of cheeseburgers sold was three times the number of hamburgers sold.
Therefore, the number of cheeseburgers sold can be expressed as 3x.
The total number of hamburgers and cheeseburgers sold was 356.
Therefore, we can write an equation to represent this information:
x + 3x = 356
Simplifying the left-hand side of the equation, we get:
4x = 356
Dividing both sides by 4, we get:
x = 89
Therefore, the number of hamburgers sold on Sunday was 89, and the number of cheeseburgers sold was 3 times that, or 267.
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scenic cinemas surveyed its audience and found that while most movie goers prefer weekends, seniors visit on weekdays. how should the theatre respond?
Scenic Cinemas should offer discounted weekday matinee showings for seniors and continue to focus on weekend showings for their broader audience.
How should Cinemas tailor their offerings to accommodate both preferences?Based on the survey results, it would be wise for Scenic Cinemas to tailor their offerings to accommodate both preferences.
One option would be to offer discounted weekday matinee showings targeted toward seniors. This could incentivize them to visit on weekdays while also offering them a more affordable option. At the same time, Scenic Cinemas could continue to focus on weekend showings to cater to their broader audience.
Another approach would be to offer more diverse programming during the weekdays, such as classic films or independent movies that may appeal more to seniors. This could create a niche for Scenic Cinemas and attract a more loyal customer base.
Ultimately, it's important for Scenic Cinemas to balance the needs of their different audience segments to maximize revenue and customer satisfaction. By offering targeted promotions and programming, they can ensure that both seniors and other moviegoers feel valued and have a reason to visit the theatre.
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Determine the equation of the hyperbola with and co-vertices (1, 5) and (-7, 5) and
asymptotes y = x+8 and y = -x +2.
The equation of the hyperbola is [tex](x + 3)^2/16 - (y - 5)^2/36[/tex] = 1.
What is hyperbola?The collection of all points in a plane such that the distance between any point on the curve and two fixed points (referred to as the foci) is constant is known as a hyperbola. Hyperbolas are a sort of conic section. A hyperbola contains two distinct branches and has the appearance of two curving branches that are mirror reflections of one another. A hyperbola's center, vertices, co-vertices, foci, and asymptotes are some of its most important characteristics. The center, which is the point around which the hyperbola is symmetric, is the midway of the line segment connecting the vertices.
Given that, the co-vertices are (1, 5) and (-7, 5).
Now, using the midpoint formula we have:
center = ((1+(-7))/2, (5+5)/2) = (-3, 5)
Now, the distance between center and vertex is a = 4.
Also, the distance between the center and each co-vertex is b = 6.
Now, the equation of the hyperbola is:
[tex](x - (-3))^2/4^2 - (y - 5)^2/6^2 = 1\\(x + 3)^2/16 - (y - 5)^2/36 = 1[/tex]
Hence, the equation of the hyperbola is [tex](x + 3)^2/16 - (y - 5)^2/36[/tex] = 1.
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What is the solution to the system of equations graphed below? A. (0,6) B. (6,0) C. (0,3) D. (1,5)
The correct option is - D. (1,5). The solution to the system of equations for the given graph is at (1,5).
Explain about the solution of system of equations:A collection of values for a variable that simultaneously fulfil each equation is the solution to a system of equations. A system of equations must be solved by identifying all possible sets of variable values that make up the system's solutions.
The points where the lines representing the intersections where two linear equations intersect are referred to as the conclusion of a linear equation. In other words, the set of all feasible values for the variables that satisfy the specified linear equation constitutes the solution set of both the system of linear equations.For the given graph, the solution of the system of equation is obtained as the point where the lines intersect.
The two lines in the graph intersect at the (1,5). Thus, the solution to the system of equations for the given graph is at (1,5).
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An expression is shown.
3(-12.5)
What is the value of the expression?
Answer: -37.5
Step-by-step explanation: You can simply do this in the calculator by doing 3 times -12.5. the parenthesis is a sign to multiply
Answer:
the answer is -75/2= - 37.5
What is the most upper (+3) or (-7)? Help please
Answer: Of the two numbers you provided, +3 is greater than -7. So, +3 is the most upper of the two numbers.
Answer: +3
Step-by-step explanation: Positive 3 is greater than negative 7. Therefore, +3 is the greater value.
Evaluate the following.
Write an exponential function of the form y = ab^x that has the given points
(−1,6 3/4), (2, 1-4)
Answer:
Step-by-step explanation:
y = abx
a is the y-intercept
y = 16bx
Now substitute 2 for x and 1296 for y
1296 = 16(b)2
81 = b2
b = 9
y = 16(9)x
Hugo made a bunch of batches of pancakes for his summer camp. For each batch, Hugo used 1/3 cup of milk. Hugo used a total of 3 cups of milk. Let b represent the number of batches Hugo mad
The number of batches of pancakes made by Hugo using 3 cups of milk is equal to 9 batches.
Number of cups of milk used by Hugo for each batch = 1/3 cup of milk ,
The total amount of milk used for b batches would be,
Total milk = (1/3) × b
The total milk used was 3 cups,
Substitute the value in the equation we have,
⇒ (1/3) × b = 3
Solve for b we get,
Multiply both sides of the equation by the reciprocal of 1/3,
Reciprocal of ( 1/3 ) = 3/1 or simply 3
⇒ (1/3) × b × 3 = 3 × 3
⇒ b = 9
Therefore, Hugo made 9 batches of pancakes.
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The above question is incomplete, the complete question is:
Hugo made a bunch of batches of pancakes for his summer camp. For each batch, Hugo used 1/3 cup of milk. Hugo used a total of 3 cups of milk. Let b represent the number of batches Hugo made . Find the value of b?
An article on the relation of cholesterol levels in human blood to aging reports that average cholesterol level for women aged 70-74 was found to be 230m/dl. If the standard deviation was 20mg/dl and the distribution normal, what is the probability that a given woman in this age group would have a cholesterol level
a) Less than 200mg/dl
b) More than 200mg/dl
c) Between 190mg/dl and 210mg/dl
d) Write a brief report on the guidance you would give a woman having high cholesterol level in this age group
a) The probability of a given woman in this age group having a cholesterol level less than 200mg/dl is 6.68%.
b) The probability of a given woman in this age group having a cholesterol level more than 200mg/dl is 93.32%.
c) The probability of a given woman in this age group having a cholesterol level between 190mg/dl and 210mg/dl is 15.87%.
d) If a woman in this age group has a cholesterol level higher than 230mg/dl, it is considered high and puts her at risk of heart disease
To calculate the probability of a given woman in this age group having a cholesterol level less than 200mg/dl, we need to find the z-score first. The z-score is the number of standard deviations that a given value is from the mean. The formula to calculate the z-score is:
z = (x - μ) / σ
where x is the given value, μ is the mean, and σ is the standard deviation.
For a cholesterol level of 200mg/dl, the z-score is:
z = (200 - 230) / 20 = -1.5
We can then use a z-table or calculator to find the probability of a z-score being less than -1.5, which is 0.0668 or approximately 6.68%.
Next, to find the probability of a given woman in this age group having a cholesterol level more than 200mg/dl, we can use the same process but subtract the probability of a z-score being less than -1.5 from 1 because the total probability is always 1.
So, the probability of a given woman in this age group having a cholesterol level more than 200mg/dl is:
1 - 0.0668 = 0.9332 or approximately 93.32%.
Finally, to find the probability of a given woman in this age group having a cholesterol level between 190mg/dl and 210mg/dl, we need to find the z-scores for both values.
For a cholesterol level of 190mg/dl, the z-score is:
z = (190 - 230) / 20 = -2
For a cholesterol level of 210mg/dl, the z-score is:
z = (210 - 230) / 20 = -1
We can then use the z-table or calculator to find the probability of a z-score being between -2 and -1, which is 0.1587 or approximately 15.87%.
Finally, a brief report on the guidance that you would give a woman having high cholesterol levels in this age group is:
It is essential to make lifestyle changes such as eating a healthy diet, exercising regularly, quitting smoking, and managing stress to lower cholesterol levels.
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given that the absolute value of the difference of the two roots of $ax^2 + 5x - 3 = 0$ is $\frac{\sqrt{61}}{3}$, and $a$ is positive, what is the value of $a$?
The value of "a" is approximately 1.83 given that the absolute value of the difference of the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive.
We are given that the absolute value of the difference between the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive. We need to find the value of "a".
Let the two roots of the equation be r1 and r2, where r1 is not equal to r2. Then, we have:
|r1 - r2| = √(61) / 3
The sum of the roots of the quadratic equation is given by r1 + r2 = -5 / a, and the product of the roots is given by r1 × r2 = -3 / a.
We can express the difference between the roots in terms of the sum and product of the roots as follows:
r1 - r2 = √((r1 + r2)² - 4r1r2)
Substituting the expressions we obtained earlier, we have:
r1 - r2 = √(((-5 / a)²) + (4 × (3 / a)))
Simplifying, we get:
r1 - r2 = √((25 / a²) + (12 / a))
Taking the absolute value of both sides, we get:
|r1 - r2| = √((25 / a²) + (12 / a))
Comparing this with the given expression |r1 - r2| = √(61) / 3, we get:
√((25 / a²) + (12 / a)) = √(61) / 3
Squaring both sides and simplifying, we get:
25 / a² + 12 / a - 61 / 9 = 0
Multiplying both sides by 9a², we get:
225 + 108a - 61a² = 0
Solving this quadratic equation for "a", we get:
a = (108 + √(108² + 4 × 61 × 225)) / (2 × 61)
Since "a" must be positive, we take the positive root:
a = (108 + √(108² + 4 × 61 × 225)) / (2 × 61) ≈ 1.83
Therefore, the value of "a" is approximately 1.83.
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The question is -
Given that the absolute value of the difference of the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive, what is the value of "a"?
What is the smallest positive integer divisible by 6 and 2 you can write using at least one 2 and one 6?
The smallest positive integer divisible by 6 and 2 that can be written using at least one 2 and one 6 is 6.
The smallest positive integer that is divisible by both 2 and 6 is their least common multiple (LCM), which is equal to the product of the highest power of each prime factor that appears in the factorization of 2 and 6.
The prime factorization of 2 is simply 2, while the prime factorization of 6 is 2 × 3. The highest power of 2 that appears in the factorization of 6 is just 2 itself, so the LCM of 2 and 6 is 2 × 3 = 6.
We are asked to write this integer using at least one 2 and one 6. We can do this by simply writing 6, which is the LCM of 2 and 6 and is divisible by both of them. Since 6 contains one 2 and one 6, this meets the requirement of the problem. Therefore, the smallest positive integer divisible by 6 and 2 that can be written using at least one 2 and one 6 is 6.
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Four friends want to play a game. In how many ways can the friends from teams, if both team dont have name
The friends can form teams in 6 different ways.
If the four friends want to form two teams, we can count the number of ways they can do this using combinations.
The number of ways to choose two people out of four is given by the combination formula,
C(4,2) = 4! / (2! * (4-2)!) = 6
We can list them as follows, where each team is represented by the letters A and B,
AB | CD
AC | BD
AD | BC
BC | AD
BD | AC
CD | AB
This means that there are 6 different ways the four friends can be split into two teams.
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1. two six-sided, fair dice are rolled. what are the probabilities of getting one even and one odd number?
The probability of getting one even and one odd number when rolling two six-sided, fair dice is 1/4.
How to find the probability of getting one even and one odd number?To calculate the probability of getting one even and one odd number, we can use the following approach:
There are three possible even numbers on each die (2, 4, and 6) and three possible odd numbers (1, 3, and 5).To get one even and one odd number, we need to choose one even number and one odd number from each die.The number of ways to choose one even number from the first die is 3, and the number of ways to choose one odd number from the second die is also 3.Therefore, the total number of ways to get one even and one odd number is 3 × 3 = 9.The probability of getting one even and one odd number is therefore 9/36 or 1/4 (since there are 36 possible outcomes in total).So the probability of getting one even and one odd number when rolling two six-sided, fair dice is 1/4 or 0.25.
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The area of (V is 624.36 square meters. The area of sector
SVT is 64.17 square meters. Find the indicated measure.
1. The radius of V is approximately 14.04 meters.2.The circumference of V is approximately 88.24 meters. 3.mST arc is 26.85 degrees. 4.the length of ST arc is approximately 6.61 meters. 5.34.69 meters. 6.88.24m.
Describe Sector?In geometry, a sector is a part of a circle enclosed by two radii and an arc. Essentially, a sector is a slice of a circle. The two radii that form the sector are equal in length and share a common endpoint, which is the center of the circle. The arc of the sector is a portion of the circumference of the circle and its length is proportional to the measure of the central angle that it subtends.
We can use the given information to solve for the following:
1. Radius of V:
The area of a circle is given by the formula A = πr². We are given the area of V as 624.36 square meters, so we can solve for the radius r as:
A = πr²
624.36 = πr²
r² = 624.36/π
r ≈ 14.04 meters
Therefore, the radius of V is approximately 14.04 meters.
2. Circumference of V:
The circumference of a circle is given by the formula C = 2πr. Using the radius we just found, we can solve for the circumference of V as:
C = 2πr
C = 2π(14.04)
C ≈ 88.24 meters
Therefore, the circumference of V is approximately 88.24 meters.
3. mST arc:
The area of the sector SVT is given as 64.17 square meters. The area of a sector is given by the formula A = (θ/360)πr², where θ is the central angle of the sector in degrees. We are not given the value of θ, but we can solve for it as:
A = (θ/360)πr²
64.17 = (θ/360)π(14.04)²
θ ≈ 26.85 degrees
Therefore, the central angle of the sector SVT is approximately 26.85 degrees, and mST arc is also 26.85 degrees.
4. Length of ST arc:
The length of an arc of a circle is given by the formula L = (θ/360)C, where θ is the central angle of the arc in degrees, and C is the circumference of the circle. We can use the values we have already calculated to solve for the length of ST arc as:
L = (θ/360)C
L = (26.85/360)(88.24)
L ≈ 6.61 meters
Therefore, the length of ST arc is approximately 6.61 meters.
5. Perimeter of shaded region (sector):
The perimeter of a sector is the sum of the length of the arc and the lengths of the two radii that form the sector. Using the values we have already calculated, we can solve for the perimeter of the shaded sector as:
Perimeter = L + 2r
Perimeter = 6.61 + 2(14.04)
Perimeter ≈ 34.69 meters
Therefore, the perimeter of the shaded region (sector) is approximately 34.69 meters.
6. Perimeter of unshaded region (remaining circle part):
The perimeter of a circle is given by the formula C = 2πr. Using the radius we previously calculated, we can solve for the perimeter of the unshaded region as:
Perimeter = 2πr
Perimeter = 2π(14.04)
Perimeter ≈ 88.24 meters
Therefore, the perimeter of the unshaded region (remaining circle part) is approximately 88.24 meters.
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NEED HELP NOW PLS!!!!!!!
AB and AD are tangent to circle C. Find x.
a numerical measure of linear association between two variables is the . a. z-score b. correlation coefficient c. variance d. standard deviation
The numerical measure of linear association is b. correlation coefficient.
What is the statistical term used to describe a quantifiable measure of the linear relationship between two variables?The correlation coefficient is a statistical measure that represents the degree of linear relationship between two variables. It takes values between -1 and 1, where -1 represents a perfect negative linear correlation, 0 represents no linear correlation, and 1 represents a perfect positive linear correlation.
A positive correlation means that when one variable increases, the other variable also tends to increase, while a negative correlation means that when one variable increases, the other variable tends to decrease.
The correlation coefficient is calculated using the formula:
[tex]r = (nΣxy - ΣxΣy) / sqrt[(nΣx^2 - (Σx)^2)(nΣy^2 - (Σy)^2)][/tex]
where r is the correlation coefficient, n is the sample size, Σxy is the sum of the products of the corresponding values of x and y, Σx and Σy are the sums of x and y respectively, and Σx^2 and Σy^2 are the sums of the squares of x and y respectively.
In summary, the correlation coefficient is a measure of the strength and direction of the linear association between two variables.
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Find the volume of this sphere using 3 for pie
The volume of this sphere is equal to 4,000 cm³.
How to calculate the volume of a sphere?In Mathematics and Geometry, the volume of a sphere can be calculated by using this mathematical equation (formula):
Volume of a sphere = 4/3 × πr³
Where:
r represents the radius.
Note: Radius = diameter/2 = 20/2 = 10 cm.
By substituting the given parameters into the formula for the volume of a sphere, we have the following;
Volume of a sphere = 4/3 × 3 × (10)³
Volume of a sphere = 4 × 1000
Volume of a sphere = 4,000 cm³
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super sleep hotel has 1,700 guests who stayed for two nights and rented 150 rooms. how many guest nights did the hotel have during this period?
In linear equation, 4,000 guest nights did the hotel have during this period.
What is a linear equation in mathematics?
A linear equation is an algebraic equation of the form y=mx+b. m is the slope and b is the y-intercept. The above is sometimes called a "linear equation in two variables" where y and x are variables.
According to question,
Guest nights = Number of guests × Number of nights
= 2,000 × 2
= 4,000
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The function f is given by f(x) = 10x + 3 and the function g is given by g(x) = 2×. For each question, show your reasoning
1. Which function reaches 50 first
2. Which function reaches 100 first?
1. x = 4.7 for f(x) and x = 25 for g(x), f(x) reaches 50 first.
2. x = 9.7 for f(x) and x = 50 for g(x), f(x) reaches 100 first.
1. Which function reaches 50 first?
To answer this, we need to solve for x in each function when the output is 50:
For f(x): 50 = 10x + 3
47 = 10x
x = 4.7
For g(x): 50 = 2x
x = 25
Since x = 4.7 for f(x) and x = 25 for g(x), f(x) reaches 50 first.
2. Which function reaches 100 first?
Similarly, we'll solve for x in each function when the output is 100:
For f(x): 100 = 10x + 3
97 = 10x
x = 9.7
For g(x): 100 = 2x
x = 50
Since x = 9.7 for f(x) and x = 50 for g(x), f(x) reaches 100 first.
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Find the volume
of the figure below:
Step-by-step explanation:
Use Pythagorean theorem to find the base of the right triangle
221^2 = 195^2 + b^2
b = 104 km
triangle area = 1/2 base * height = 1/2 * 104 * 195 = 10140 km^2
Now multiply by the height to find volume
10140 km^2 * 15 km = 152100 km^3
A side of the triangle below has been extended to form an exterior angle of 67°. Find the value of xx.
Since a side of the triangle below has been extended to form an exterior angle of 67°, the value of x is equal to 52°.
What is the exterior angle theorem?In Mathematics, the exterior angle theorem or postulate can be defined as a theorem which states that the measure of an exterior angle in a triangle is always equal in magnitude (size) to the sum of the measures of the two remote or opposite interior angles of that triangle.
By applying the exterior angle theorem, we can reasonably infer and logically deduce that the sum of the measure of the two interior remote or opposite angles in the given triangle is equal to the measure of angle x (∠x);
∠y + 67° = 180°
∠y = 180° - 67°
∠y = 113°
∠x = 180° - (15° + 113°)
∠x = 52°
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n.2 multi-step word problems with positive rational numbers jvu you have prizes to reveal! go to your game board. on friday night, suzie babysat her cousin for 3 1 2 hours and earned $8.50 per hour. on saturday, she babysat for her neighbors for 4 1 2 hours. if she made a total of $72.50 from both babysitting jobs, how much did suzie earn per hour on saturday?
Answer:
$9.50
Step-by-step explanation:
You want Suzie's hourly rate on Saturday if she babysat for 3.5 hours on Friday, earning 8.50 per hour, and for 4.5 hours on Saturday, earning a total of 72.50 from both jobs.
EarningsFor (hours, rates) of (h1, r1) and (h2, r2), Suzie's total earnings for the two jobs are ...
earnings = h1·r1 +h2·r2
Filling in the known values, we can find r2:
72.50 = 3.5·8.50 +4.5·r2
72.50 = 29.75 +4.5·r2 . . . . . . . simplify
42.75 = 4.5·r2 . . . . . . . . . . . subtract 29.75
9.50 = r2 . . . . . . . . . . . . divide by 4.5
Suzie earned $9.50 per hour on Saturday.
__
Additional comment
The steps of the "multistep" problem are ...
find Friday's earningssubtract that from the total to find Saturday's earningsdivide by Saturday's hours to find the hourly rateEffectively, these are the steps to solving the equation we wrote.
X and y represent positive integers such that 18x+11y= 2020. What is the greatest possible value of x+y
Answer:
To find the greatest possible value of x + y, we need to maximize the values of x and y such that they are still positive integers and satisfy the given equation 18x + 11y = 2020.
We can start by rearranging the equation to solve for y:
11y = 2020 - 18x
y = (2020 - 18x)/11
For y to be a positive integer, 2020 - 18x must be divisible by 11. We can test values of x starting from x = 1 and increasing by 1 until we find the largest possible value of x that satisfies this condition.
When x = 1, 2020 - 18x = 2002, which is divisible by 11. This gives us a value of y = 182/11, which is not a positive integer.
When x = 2, 2020 - 18x = 1984, which is divisible by 11. This gives us a value of y = 180/11, which is not a positive integer.
When x = 3, 2020 - 18x = 1966, which is divisible by 11. This gives us a value of y = 178/11, which is not a positive integer.
When x = 4, 2020 - 18x = 1948, which is divisible by 11. This gives us a value of y = 176/11, which is not a positive integer.
When x = 5, 2020 - 18x = 1930, which is divisible by 11. This gives us a value of y = 174/11, which is not a positive integer.
When x = 6, 2020 - 18x = 1912, which is divisible by 11. This gives us a value of y = 172/11, which is not a positive integer.
When x = 7, 2020 - 18x = 1894, which is divisible by 11. This gives us a value of y = 170/11, which is not a positive integer.
When x = 8, 2020 - 18x = 1876, which is divisible by 11. This gives us a value of y = 168/11, which is not a positive integer.
When x = 9, 2020 - 18x = 1858, which is divisible by 11. This gives us a value of y = 166/11, which is not a positive integer.
When x = 10, 2020 - 18x = 1840, which is divisible by 11. This gives us a value of y = 164/11, which is not a positive integer.
When x = 11, 2020 - 18x = 1822, which is divisible by 11. This gives us a value of y = 162/11, which is not a positive integer.
When x = 12, 2020 - 18x = 1804, which is divisible by 11. This gives us a value of y = 160/11, which is not a positive integer.
When x = 13, 2020 - 18x = 1786, which is divisible by 11. This gives us a value of y = 158/11, which is not a positive integer.
When x = 14, 2020 - 18x = 1768, which is divisible by 11. This gives us a value of y = 156/11, which is not a positive integer.
When x = 15, 2020 - 18x = 1750, which is divisible by 11. This gives us a value of y = 154/11, which is not a positive integer.
When x = 16, 2020 - 18x = 1732, which is divisible by 11. This gives us a value of y = 152/11, which is not a positive integer.
When x = 17, 2020 - 18x = 1714, which is divisible by 11. This gives us a value of y = 150/11, which is not a positive integer.
When x = 18, 2020 - 18x = 1696, which is divisible by 11. This gives us a value of y = 148/11, which is not a positive integer.
When x = 19, 2020 - 18x = 1678, which is divisible by 11. This gives us a value of y = 146/11, which is not a positive integer.
When x = 20, 2020 - 18x = 1660, which is divisible by 11. This gives us a value of y = 144
ALL MY POINTS TO WHOEVER ANSWERS THIS FIRST
IN ΔABC, m∠A=70° and m∠B=35°.
Select the traingle that is similar to ΔABC.
The answer is B
The internal angles of a triangle have to be 180
IN ΔABC, m∠A=70° and m∠B=35°.
70°+35°+x=180°
105°+x=180°
x=180°-105°
x=75°
Answer B meets the requirements because in ΔPQR m∠P=70° and m∠R=75°
70°+75°+x=180°
145°+x=180°
x=180°-145°
x=35°
The angles of both triangles measure the same
sue works 5 out of the 7 days of the week. how many possible schedules are there to work on tuesday or friday or both?
Sue works 5 out of 7 days a week, which implies that she has two days off. We need to discover how numerous conceivable plans there are for her to work on Tuesday or Friday or both.
There are two cases to consider:
1. Sue works on Tuesday as it were, Friday as it were, or both Tuesday and Friday.
2. Sue does not work on Tuesday or Friday.
For the primary case, there are three conceivable outcomes:
1. Sue works on Tuesday as it were and has Friday off.
2. Sue works on Friday as it were and has Tuesday off.
3. Sue works on both Tuesdays and Fridays.
For the moment case, there are two conceivable outcomes:
1. Sue works on one of the other 5 days of the week and has both Tuesday and Friday off.
2. Sue has Tuesday and Friday off.
In this manner, there are added up to 3 + 2 = 5 conceivable plans for Sue to work on Tuesday or Friday or both.
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∠A=6x−2
∘
start color #11accd, angle, A, end color #11accd, equals, start color #11accd, 6, x, minus, 2, degrees, end color #11accd \qquad \green{\angle B} = \green{4x +48^\circ}∠B=4x+48
∘
, angle, B, equals, start color #28ae7b, 4, x, plus, 48, degrees, end color #28ae7b
Solve for xxx and then find the measure of \blueD{\angle A}∠Astart color #11accd, angle, A, end color #11accd:
The given information describes the measures of two angles, A and B. Angle A is represented as ∠A and has a measure of 6x-2 degrees. Angle B is represented as ∠B and has a measure of 4x+48 degrees. These measures are respectively shown in the colors #11accd and #28ae7b.
The question gives us two equations, one for angle A and one for angle B, in terms of x. We will have to solve for x and then find the measure of angle A.
To solve for x, we can set the expressions for ∠A and ∠B equal to each other and solve for x
∠A = ∠B
6x - 2 = 4x + 48
Subtracting 4x from both sides we get
2x - 2 = 48
Adding 2 to both sides we get
2x = 50
Dividing by 2 we get
x = 25
Now that we have found the value of x, we can substitute it into the expression for ∠A
∠A = 6x - 2
∠A = 6(25) - 2
By multiplying 6 with 25 we get
∠A = 150 - 2
By Subtracting we get
∠A = 148
Hence, the measure of angle A is 148 degrees.
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What is the mean of this data set?
Please help
Answer:
Step-by-step explanation:
Find the area of the circle with a circumference of
. Write your solution in terms of
.
Area in terms of
: ______
the manager of a supermarket tracked the amount of time needed for customers to be served by the cashier. after checking with his statistics professor, he concluded that the checkout times are exponentially distributed with a mean of 5.5 minutes. what propotion of customers require more than 12 minutes to check out?
Approximately 0.357 or 35.7% of customers require more than 12 minutes to check out.
Since the checkout times are exponentially distributed with a mean of 5.5 minutes, we can use the exponential distribution formula to find the probability that a customer will take more than 12 minutes to check out:
P(X > 12) = 1 - P(X ≤ 12)
where X is the checkout time.
To find P(X ≤ 12), we can use the cumulative distribution function (CDF) of the exponential distribution, which is:
F(x) = 1 - e^(-λx)
where λ is the rate parameter of the distribution. For an exponential distribution with mean μ, the rate parameter λ is equal to 1/μ.
So, in our case, λ = 1/5.5 = 0.1818, and we can calculate P(X ≤ 12) as:
P(X ≤ 12) = F(12) = 1 - e^(-0.1818 × 12) ≈ 0.643
Therefore, the probability that a customer will take more than 12 minutes to check out is:
P(X > 12) = 1 - P(X ≤ 12) ≈ 1 - 0.643 ≈ 0.357
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1. Suppose we have the following annual risk-free bonds Maturity Price Coupon Rate YTM 1 98 0% 2.01% 2 101 2.48% 3 103 2.91% 4 101 2% 1.73% 5 103 5% 4.32% 39 a) Find the zero rates for all 5 maturities Note: for an extra challenge, try using lincar algebra to find == A + where 98 00 -- 3 103 0 2 2 5 5 0 104 2 0 0 0 0 0 0 1020 5 105 5 1 b) Suppose we have a risk-free security which pays cash flows of $10 in one year, $25 in two years, and $100 in four years. Find its price
a) The zero rates for the five maturities are: 1 year is 2.01%, 2 years is 2.48%, 3 years is 2.77%, 4 years is 1.73%, and 5 years is 4.32%.
b) The price of the security is $128.31.
a) To find the zero rates for all 5 maturities, we can use the formula for the present value of a bond:
PV = C / [tex](1+r)^n[/tex]
where PV is the present value,
C is the coupon payment,
r is the zero rate, and
n is the number of years to maturity.
We can solve for r by rearranging the formula:
r = [tex](C/PV)^{(1/n) }[/tex]- 1
Using the bond data given in the question, we can calculate the zero rates for each maturity as follows:
For the 1-year bond, PV = 98 and C = 0, so r = 2.01%.
For the 2-year bond, PV = 101, C = 2.48, and n = 2, so r = 2.48%.
For the 3-year bond, PV = 103, C = 2.91, and n = 3, so r = 2.77%.
For the 4-year bond, PV = 101, C = 2, and n = 4, so r = 1.73%.
For the 5-year bond, PV = 103, C = 5, and n = 5, so r = 4.32%.
Alternatively, we can use linear algebra to find the zero rates. We can write the present value equation in matrix form:
PV = A × x
where A is a matrix of coefficients, x is a vector of unknowns (the zero rates), and PV is a vector of present values.
To solve for x, we can use the equation:
x = ([tex]A^{-1}[/tex]) x PV
where ([tex]A^{-1}[/tex]) is the inverse of matrix A.
Using this method, we can solve for the zero rates as follows:
[2.01% ]
[2.48% ]
[2.77% ] = x
[1.73% ]
[4.32% ]
PV = [tex]A^{-1}[/tex] x [98]
[101]
[103]
[101]
[103]
PV = [-0.0201]
[ 0.0248]
[ 0.0277]
[-0.0173]
[ 0.0432]
b) To find the price of the security which pays cash flows of $10 in one year, $25 in two years, and $100 in four years, we can use the formula for the present value of a series of cash flows:
PV = [tex]C1/(1+r)^1 + C2/(1+r)^2 + C3/(1+r)^4[/tex]
where PV is the present value, C1, C2, and C3 are the cash flows, r is the zero rate, and the exponents correspond to the number of years until each cash flow is received.
Using the zero rates calculated in part (a), we can calculate the present value of each cash flow:
PV1 = $10 /(1+2.01 % [tex])^1[/tex] = $9.80
PV2 = $25/(1+2.48%[tex])^2[/tex] = $22.15
PV3 = $100/(1+1.73%[tex])^4[/tex] = $81.36
Then, the price of the security is the sum of the present values:
PV = $9.80 + $22.15 + $81.36 = $128.31
Therefore, the price of the security is $128.31.
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