Answer:
Molarity = moles ÷ liters
to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)
Na = 22.989769
Br = 79.904
molar mass of NaBr = 102.893769
6.6g ÷ 102.893769 = 0.064143826 moles of NaBr
0.064143826 moles ÷ 0.60 liters = 0.1069 molar concentration or 11 %
mplete the following Charles' Law calculations. If the current temperature is 25 degrees C and you have a 2L balloon, identify the new volume of the balloon if you increase the temperature to 30 degrees C. Remember to change Celsius to Kelvin: K= C + 273.
Answer:
New volume = 2.03 L
Explanation:
Given that
Initial temperature, T₁ = 25°C = 298 K
Initial volume, V₁ = 2L
Final temperature, T₂ = 30°C = 303 K
We need to find the final volume. The mathematical form of Charle's law is given by :
[tex]\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}[/tex]
Put all the values,
[tex]V_2=\dfrac{2\times 303}{298}\\\\V_2=2.03\ L[/tex]
so, the new volume is equal to 2.03 L.
What is the balanced chemical equation for silicon + oxygen?
Answer:
SiO2
Explanation:
Si + O2 → SiO2
what is the molar mass of barium hydroxide
Answer:
171.34 g/mol
Explanation:
Ba molar mass = 137.328 g/mol
O molar mass = 15.999 g/mol * 2 = 31.9980 g/mol
H molar mass = 1.008 g/mol * 2 = 2.0160 g/mol
137.328 + 31.9980 + 2.0160 = 171.3420 = 171.34 g/mol
The ionization potential of Be atom is more than expected because it has -
(a) half filled valence p orbitals
(b) fully filled valence s orbitals
(c) both a and b
Answer:
(b) fully filled valence s orbitals
Explanation:
Electron configuration of Be: 1s22s2
2s2 is fully filled
a transverse wave moves a medium at an abtuse angle to the wave , true or false ?
Answer:
True! A transverse wave does move a medium at an obtuse angle to the wave!!
Answer:
False
Explanation:
How many grams of KCl, are soluble in 100 g of water at 60 ºC?
a)15g
b)35g
c)45g
d)90g
45 g
the solubility of KCl in water at 60 degree c is 45.5g per 100g of water
which shows a disaccharide
Answer: It is :B:
Explanation: also sub to technoblade
SOMEONE HELP ME
1. How many grams of C are present in 4.86 grams of carbon dioxide
?
grams C.
2. How many grams of carbon dioxide contain 1.73 grams of O ?
grams carbon dioxide.
Answer:
1. 1.33 gram of carbon
2. 2.38g of carbon dioxide
Explanation:
From the given information:
Total amount of CO₂ = 4.86 grams
Atomic mass of C = 12 g/mole
molar mass of CO₂ = 44 g/mole
∴
The mass of the Carbon (C) in grams is:
[tex]= Total\ amount \ of \ CO_2 \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]
[tex]= 4.86 \ g \times \dfrac{12 \ g/mol}{44 \ g/mol}[/tex]
= 1.33 gram of carbon
2.
Here, the total amount of CO₂ = unknown
Atomic mass of O₂ = 32 g/mole
molar mass of CO₂ = 44 g/mole
amount of oxygen = 1.73 g
∴
The mass of CO₂ = [tex]Total \ amount \ of \ O_2 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]
[tex]=1.73 \times \dfrac{44 \ g/mol}{32\ g/mol}[/tex]
= 2.38 g of carbon dioxide
The oceanic crust is destroyed at convergent boundaries because it_______________________ *
a) diverges to form a rift valley
b) goes into a subduction zone where it is melted by the hot magma
c) transforms
d) the rock crumbles at an ocean ridges
Answer: I believe the answer is d) the rock crumbles at an ocean ridges
Explanation:
State the number of protons, electrons and neutron
Answer:
You didn't show which element it is. The proton is the atomic number, the electron is the same number of protons, and the neutron is the atomic mass rounded to the nearest whole number minus the proton.
Explanation:
Forensic biologist Warren is examining a substance found at a crime scene. Using a chemical test, he determines that glycogen is
present in the substance. What does this mean for his investigation?
The substance is from an animal source.
The substance is the poison ricin.
The substance is from a plant source.
The substance is a lipid.
Answer: the substance is from an animal source
Explanation:
please need help..
no attachments thankyou
1. A sample of a chemical compound has 2.96g carbon, 0.414g hydrogen, 0.675g oxygen and 2.96 sulphur.
calculate it's empirical formula.
2.if it's mass was 972g, determine its molecular formula.
Answer:
1. The empirical formula => C₆H₁₀OS₂
2. Molecular formula => C₃₆H₆₀O₆S₁₂
Explanation:
1. Determination of the empirical formula.
Carbon (C) = 2.96 g
Hydrogen (H) = 0.414 g
Oxygen (O) = 0.675 g
Sulphur (S) = 2.96 g
Divide by their molar mass
C = 2.96 / 12 = 0.247
H = 0.414 / 1 = 0.414
O = 0.675 / 16 = 0.042
S = 2.96 / 32 = 0.0925
Divide by the smallest
C = 0.247 / 0.042 = 6
H = 0.414 / 0.042 = 10
O = 0.042 / 0.042 = 1
S = 0.0925 /0.042 = 2
Therefore, the empirical formula is
C₆H₁₀OS₂
2. Determination of the molecular formula.
Molar mass of compound = 972 g/mol
Empirical formula => C₆H₁₀OS₂
Molecular formula =>?
Molecular formula = [C₆H₁₀OS₂]ₙ
Molecular formula = molar mass of compound
Thus,
[C₆H₁₀OS₂]ₙ = 972
[(12×6) + (10×1) + 16 + (32×2)]n = 972
[72 + 10 + 16 + 64]n = 32
162n = 972
Divide both side by 162
n = 972 / 162
n = 6
Molecular formula = [C₆H₁₀OS₂]ₙ
Molecular formula = [C₆H₁₀OS₂]₆
Molecular formula = C₃₆H₆₀O₆S₁₂
What is the molarity of 2.5 moles of NaOH in a 2.6L solution
Answer:
Molarity =Moles of solute/Volume of Solution (L)
Molarity=2.5/2.6
=0.962M
Which of the following compounds would have the lowest
solubility?
ОНczА
O Nm3R
O Bv3(AX)2
O Hn(EX2)2
O MRD2
Scientist use models of the solar system to
1 avoid the use of incorrect data
2 prevent duplication of their ideals
3 help explain their ideas
4 make theories non-testable
Why is it dangerous to stand under tall trees and building during thunder?
Question 2 (1 point)
An object's gravitational force depends primarily on the object's
a
density
mass
b
oc
momentum
Answer: An object's gravitational force depends primarily on the object's mass.
Explanation:
According to the Universal law of gravitation, every object whether is it is having large r small mass tends to exert a force on every other object, therefore this force is known as gravitational force.
Formula to calculate gravitational force is as follows.
[tex]F = \frac{G \times m_{1} \times m_{2}}{r^{2}}[/tex]
where,
F = Gravitational force
G = Gravitational constant = [tex]6.674 \times 10^{-11} m^{3}/kg s^{2}[/tex]
[tex]m_{1}[/tex] = mass of object 1
[tex]m_{2}[/tex] = mass of object 2
r = distance between the centers of the objects
Therefore, it means that gravitational force of an object primarily depends on an object's mass.
Thus, we can conclude that an object's gravitational force depends primarily on the object's mass.
Which of the following microorganisms is most likely to get its main source of nutrition from a host?
Bacteria
Parasite
T-cell
Virus
Answer:
A Parasite.
Explanation:
Viruses and bacteria can survive in most areas without a host. Parasites however need a host to survive. Some parasites include: tapeworm, roundworms, flukes, and protozoa.
A 81 gram solution of silver nitrate contains
16 grams of AgNO3. What is the percent by
mass of silver nitrate in this solution?
Answer in units of %.
Answer:
19.75 %
Explanation:
The percent by mass of silver nitrate in the solution can be calculated using the following formula:
% AgNO₃ = Mass of AgNO₃ / Mass of solution * 100%As all the required data is already given by the problem, we can now proceed to calculate the percent by mass:
% AgNO₃ = 16 g / 81 g * 100 %% AgNO₃ = 19.75 %- Standard state refers to
a) 1 atm and 25°C
b) 1 atm and 100°C
c) 1 atm and gaseous reactants
d) None of these
Answer: The standard state refers to 1 atm and [tex]25^{o}C[/tex].
Explanation:
It is known that a chemical/substance can either be present in a solid, liquid or gaseous state.
So, when the phase of a substance like solid, liquid or gas is present at 1 atmosphere pressure and at a temperature of [tex]25^{o}C[/tex] then it known as standard state of substance.
Thus, we can conclude that standard state refers to 1 atm and [tex]25^{o}C[/tex].
Help!!!
1.
Q: How does the distillation apparatus remove impurities from water?
Q: Why does water vapour condense in the condenser tube?
Q: As the boiling animation neared the end, what does the change in the proportion of particle types in the boiling flask indicate about the impurities?
Answer:
Q1) Distillation relies on evaporation to purify water
Explanation:
contaminated water is heated to form steam. inorganic compounds and large non-volatile organic molecules do not evaporate with the water and are left behind. The steam then cools and condenses to form purified water
A molecule or ion that donates the hydrogen in a hydrogen bond is a hydrogen bond donor.
a. True
b. False
Answer: The statement 'a molecule or ion that donates the hydrogen in a hydrogen bond is a hydrogen bond donor' is true.
Explanation:
A molecule or ion that donates hydrogen in a hydrogen bond is called a hydrogen donor.
For example, [tex]NH_{3} + H_{2}O \rightarrow NH^{+}_{4} + OH^{-}[/tex]
Here, [tex]NH_{3}[/tex] is donating the hydrogen ion to water molecule. Whereas water is accepting the hydrogen ion so water is a hydrogen bond acceptor. Therefore, hydrogen bond is formed by [tex]NH_{3}[/tex].
Thus, we can conclude that the statement 'a molecule or ion that donates the hydrogen in a hydrogen bond is a hydrogen bond donor' is true.
A reservoir is filled with 4 billion cubic feet of polluted water that initially contains 0.4% pollutant. Every day 400 million cubic feet of pure water enters the reservoir and the well-mixed solution flows out at the same rate. When will the pollutant concentration in the lake be reduced to 0.2%
Answer:
Thus, the pollutant concentration in lake will be reduced to 0.2% after 6.931471 days
Explanation:
From the information given:
A(t) = amount of pollutant for time (t)
A 4 billion cubic ft is the same as 4000 million cubic ft:
∴
The Initial amount of pollutant is [tex]A_o = (\dfrac{0.4}{100})\times 4000[/tex]
[tex]A_o = 16 \ million \ cubic \ feet[/tex]
However;
the pollutant rate (input) = 400 × 0 = 0
the pollutant rate (output) = [tex]400( \dfrac{A(t)} {4000})[/tex]
[tex]= 1( \dfrac{A(t)} {10})[/tex]
The net rate = [tex]A'(t) = 0 - 1( \dfrac{A(t)} {10})[/tex]
[tex]\implies A'(t) = - 1( \dfrac{A(t)} {10})[/tex]
[tex]\implies \dfrac{1}{A(t)}A'(t) = -(\dfrac{1}{10})[/tex]
[tex]\implies \int (\dfrac{1}{A(t)}A'(t) ) dt = \int -(\dfrac{1}{10}) dt[/tex]
[tex]\implies In (A(t)) = -(\dfrac{1}{10})t + c[/tex]
[tex]\implies A(t) = e^{-(\dfrac{1}{10})t+c}[/tex]
[tex]\implies A(t) = Ce^{-\dfrac{1}{10}^t}[/tex]
A(0) = 16
[tex]\implies Ce^{ -(1/20)^0} = 16 \\ \\ C = 16[/tex]
[tex]\implies A(t) = 16e^{(-1/10)t}[/tex]
[tex]0.2\% \ pollutant = (\dfrac{0.2}{100})*4000 =8 \ million \ cubic \ feet[/tex]
A(t) = 8
[tex]\implies 16e^{(-1/10)t}= 8 \\ \\ \implies e^{1/10)t} = 2 \\ \\ (\dfrac{1}{10} )^t = In(2) \\ \\ t = 10\ In(2) \\ \\ \mathbf{ t = 6.931471}[/tex]
Rocky objects that are massive enough will have a spherical shape due to the force of gravity. (no links or else I will report you)
True
False
For the following reaction conditions select the correct statement regarding the reaction below.
OH Cl OTs OTs N TsCl W X Y Z N
a. W is the correct product.
b. X is the correct product.
c. Y is the correct product.
d. Z is the correct product since pyridine acts as a nucleophile.
e. Both X and Y are both formed in this reaction as a racemic mixture
Answer:
B
Explanation:
The appropriate diagram of the question is shown in the first image attached below.
From the diagram, we see the reaction of Cyclopentanol taking place under Tscl pyridine. We are to show the reaction mechanism and determine from the options, which appropriate product fits in.
So, from the reaction, the hydroxyl substituent reacts with Tscl where cl is being lost. This process is followed by an attack of N substituent on the pyridine with the Hydrogen atom and cleaves off for the structure to form a stable structure. The stereochemistry of the compound remains unchanged and it maintains its stick formula.
Thus, X is the appropriate and the correct product.
8. Calculate (H^+), (OH^-), pOH and the pH for a 0.00024 M solution of calcium hydroxide. Must show work!
Answer:
1. [H⁺] = 2.0×10¯¹¹ M
2. [OH¯] = 4.8×10¯⁴ M
3. pOH = 3.3
4. pH = 10.7
Explanation:
From the question given above, the following data were obtained obtained:
Molarity of Ca(OH)₂ = 0.00024 M
We'll begin by calculating the concentration of the hydroxide ion [OH¯]. This can be obtained as follow:
Ca(OH)₂ (aq) —> Ca²⁺ + 2OH¯
From the balanced equation above,
1 mole of Ca(OH)₂ produced 2 moles of OH¯.
Therefore, 0.00024 M Ca(OH)₂ will produce = 2 × 0.00024 = 4.8×10¯⁴ M OH¯
Thus, the concentration of the hydroxide ion [OH¯] is 4.8×10¯⁴ M
Next, we shall determine the pOH of the solution. This can be obtained as follow:
Concentration of the hydroxide ion [OH¯] = 4.8×10¯⁴ M
pOH =?
pOH = –Log [OH¯]
pOH = –Log 4.8×10¯⁴
pOH = 3.3
Next, we shall determine the pH of the solution. This can be obtained as follow:
pOH = 3.3
pH =?
pH + pOH = 14
pH + 3.3 = 14
Collect like terms
pH = 14 – 3.3
pH = 10.7
Finally, we shall determine the concentration of hydrogen ion [H⁺]. This can be obtained as follow:
pH = 10.7
Concentration of hydrogen ion [H⁺] =?
pH = –Log [H⁺]
10.7 = –Log [H⁺]
Divide both side by –1
–10.7 = Log [H⁺]
Take the antilog of –10.7
[H⁺] = Antilog (–10.7)
[H⁺] = 2.0×10¯¹¹ M
SUMMARY:
1. [H⁺] = 2.0×10¯¹¹ M
2. [OH¯] = 4.8×10¯⁴ M
3. pOH = 3.3
4. pH = 10.7
structure of potassium trioxalatoaluminate(iii)?
Answer:
K3[Al(C2O4)3] is the answer
Please help. Will give brainliest
Answer:
the answer to this is 71.0 grams of chlorine
Identify whether each compound is a straight chain, branched chain, or cycloalkane.
ОН
сн.
CH,
ж
E
НО шин-
-- ОН
нс
НО
"ОН
Answer:
Branched chain
Cycloalkane
Straight chain
Explanation:
For many purposes we can treat butane as an ideal gas at temperatures above its boiling point of . Suppose the pressure on a sample of butane gas at is cut in half. Is it possible to change the temperature of the butane at the same time such that the volume of the gas doesn't change? yes no If you answered yes, calculate the new temperature of the gas. Round your answer to the nearest °C.
Answer:
A. Yes
B. The new temperature of the gas is -116 °C
Note: The question is incomplete. The complete question is given below :
For many purposes we can treat butane C H10) as an ideal gas at temperatures above its boiling point of - 1. °C. Suppose the pressure on a 500 mL sample of butane gas at 41.0°C is cut in half. Iyes Is it possible to change the temperature of the butane at the same time such that the volume of the gas doesn't change? yes no If you answered yes, calculate the new temperature of the gas. Round your answer to the nearest °C.
Explanation:
A. According to the pressure law of gases,for a fixed mass of gas the pressure of a gas is directly proportional to its Kelvin temperature once the volume is kept constant. This means that a change in temperature can bring about a change in pressurein a gas at constant volume.
B. From the pressure law of gasese: P1/T1 = P2/T2
Where initial pressure = P1, final pressure = P2
Initial temperature = T1, final temperature = T2
For the butane gas;
P1 = P
P2 = P/2
T1 = 41°C = (273 + 41 ) K = 314 K
T2 = ?
From the equation, T2 = T1 × P2 / P1
T2 = 314 × P/2 /P
T2 = 157 K
T2 = (157 - 273) °C = -116 °C
Therefore, the new temperature of the gas is -116 °C