If 2N force is applied on 2 kg mass due east and same magnitude of force due west, thechange in velocity of the body in 2 sec is

Explanation:

F=m(v-u)/t

F=2N

m=2kg

t=2s

2=2(v-u)/2

cross multiply

2*2=2(v-u)

4=2(v-u)

4/2=v-u

v-u=2m/s

v-u is the change is velocity.

The change in velocity of the body in 2 sec is 2m/s

According to Newton's second law which states that the change in momentum of an object is directly proportional to the applied force.

Mathematically:

[tex]F \ \alpha \ (\dfrac{v-u}{t} )[/tex]

[tex]F = m (\dfrac{v-u}{t} )[/tex]

where:

m is the mass

(v - u) is the change in velocity

t is the time

F is the applied force

Given the following:

mass m = 2kg

time t = 2secs

Force F = 2N

Required

Change in velocity (v-u)

Substitute the given parameters into the expression shown above:

[tex]2=2(\dfrac{v-u}{2})\\ 2 \times 2=2(v-u)\\4=2(v-u)\\v-u=\dfrac{4}{2}\\v-u=2m/s\\[/tex]

Hence the change in velocity of the body in 2 sec is 2m/s.

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