If a, b are real numbers and 7a + i(3a - b) = 14 - 6i , then find the values of a and b.

If a, b are real numbers and 7a + i(3a - b) = 14 - 6i, then find the values of a and b. Therefore, the value of a = 2 and the value of b = 12. 3.

The value of the variables 'a' and 'b' of the complex equation will be 2 and 12, respectively.

The complex number is the combination of the real part and the imaginary part. Then the complex number is given as a+bi where the value of i is √(-1) and the value of i² is -1.

The equation is given below.

7a + (3a - b)i = 14 - 6i

Compare the real part of the equation, then we have

7a = 14

a = 14 / 7

a = 2

Compare the imaginary part of the equation, then we have

3a - b = - 6

3 x 2 - b = -6

6 - b = - 6

b = 6 + 6

b = 12

The value of the variables 'a' and 'b' of the complex equation will be 2 and 12, respectively.

More about the complex number link is given below.

https://brainly.com/question/10251853

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PLEASE PLEASE HELP!!!!