Answer:
The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)
Explanation:
The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.
If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.
If the gravitational field strength [tex]g[/tex] is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.
If [tex]m[/tex] denote the mass of this ball, the gravitational potential energy ([tex]\rm GPE[/tex]) of this ball at height [tex]h[/tex] would be [tex]{\rm GPE} = (m \cdot g) \cdot h[/tex], which is proportional to [tex]h\![/tex].
The value of [tex]g[/tex] near the surface of the earth is indeed approximately constant (typically [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex].)
At halfway between the top and bottom of this hill, the height of this ball would be [tex](1/2)[/tex] of its initial value (the value when the ball was at the top of the hill.) Because the [tex]\rm GPE[/tex] of this ball is proportional to its height, at halfway down the hill, the [tex]\rm GPE\![/tex] of this ball would also be [tex](1/2)\![/tex] its initial value.
However, if there was no friction on this ball (and that the ball did not deshape,) that [tex](1/2)[/tex] of the initial [tex]\rm GPE\![/tex] of this ball was not lost. Rather, these [tex](1/2)\![/tex] of the initial [tex]\rm GPE[/tex] would have been converted to the kinetic energy ([tex]\rm KE[/tex]) of this ball.
Hence, when the ball is halfway down the hill:
[tex]\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}[/tex].
[tex]\begin{aligned}& \text{KE halfway down the hill}\\ &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}[/tex].
In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.
What is the molar mass of Mg(HSO3)2?
Methane is combusted with Oxygen to produce Carbon Dioxide and Water. How many grams of oxygen are required to react with 55 grams of
Methane?
A.55 g
B.110 g
C.165 g
D.220 g
What is the formula for the sulfate ion?
What is the formula for the sulfite ion?
What is the formula for the hydrogen sulfate ion?
Sulfate - SO4^-2
Sulfite - SO3^-2
Hydrogen Sulfate - HSO4-
ASAP!!
Identify the limiting reactant when 6 moles of CaCl2 is combined with 6 moles of Al2O3.
Reaction: 3CaCI2 + Al2O3 -> 3CaO + 2AlCI3
Answer:
just downloud smart
Explanation:
thank me later
6. The drawing shows Samir riding his mountain bike.
i) Draw a circle around the places on the drawing where there
should be a lot of friction.
ii) Explain why there should be a lot of friction in these places.
Answer:
You Need To Upload The Photo Then I Will Help You :)
Explanation:
Please help asap. Brainliest to correct.
Which formula can be used to calculate the percent yield? (5 points)
Select one:
a. (Theoretical yield ÷ actual yield) x 100
b. (Actual yield ÷ theoretical yield) x 100
c. (Amount of reactants ÷ amount of products) x 100
d. (Amount of products ÷ amount of reactants) x 100
Answer:
I guess this answer is c
yh
Answer:
b. (Actual yield ÷ theoretical yield) x 100
Explanation:
The percent yield will be a ratio of collected or actual yield to the theoretical yield. Like any percentage, you are determining a part of a whole. You multiply by 100 to convert your decimal answer from the division into a percentage.
Which element's properties form the basis for all life?
Answer:
carbon
Explanation:
The properties of carbon forms the basis for all life. Explanation: The atoms of carbon are found in the molecules of all living species.
(R)-Limonene is found in many citrus fruits, including oranges and lemons. Draw its structures and identify the relationship between them.
Answer:
we cant draw jn this
Explanation:
because it contin citric acid
1 = 2 Amps, R = 3 Ohms, V = ? Volts
Answer:
6 volts
Explanation:
Use Ohm's Law:
V = IR
V = (2 amps)(3 ohms) = 6 volts
By the reaction between
H3PO4 and Ca(OH)2,
Can be formede:
a. Ca(HPo4)2,
b. СaHP4
c. Ca(H2PO4)2
d. Ca2HP02
e.Сa3(PO4)2
the correct answers : b, c, e
the question is:
I am preparing for an admittion test in chemistry, I face this kind of questions which I dont how to understand or if I should only memorize.
I appreciate all your help.
thank you alot.
Answer:
ANSWER is E
Explanation:
2H₃PO₄ + 3Ca(OH)₂→ 6H₂O + Ca₃(PO₄)₂
Answer:
First step is to find what the products would be. Since this seems to be a double displacement, you get: H3PO4(aq)+Ca(OH)2(aq)→ H2O(L)+Ca3(PO4)2(s)
You know the products because H has a charge of +1, so PO4 must have a charge of -3, and since OH has a charge of -1, Ca must be +2. Then make each compound have a net charge of 0. H20 is a liquid since aq solutions have liquid water. Ca3(PO4)2 is a solid, use the solubility rules.
Lastly, balance the equation: 2H3PO4(aq)+3Ca(OH)2(aq)→ 6H2O(L)+Ca3(PO4)2(s)
So the salt formed is Ca3(PO4)2
Why is ocean water near the equator warmer than ocean water at the poles?
O A. The sun's rays strike the water more directly near the equator.
O B. Deep sea vents pump steam into the conveyor belt near the
equator.
O C. The water is denser and saltier near the equator, so it holds more
heat.
D. Due to Earth's rotation, gyres near the equator flow clockwise.
SUBM
4. Describe a simple experiment that can be performed in the laboratory to demonstrate
the formation of iron (III) chloride from iron fillings.
Answer:
laboratory use the organic substances dissolve in water methanol or ethanol then Sinha to rise iron chloride solution is added a transient permanent coloration usually purple green or blue indicate the presence of a funnel or an hall
Balanced equation for Fe reacting with [tex]Cl_2[/tex]
[tex]2Fe + 3Cl_2[/tex] → [tex]2FeCl_3[/tex]
What are iron fillings?Iron filings are small shavings of ferromagnetic material.
When hydrochloric acid (HCl) reacts with iron filings (Fe) a dissolving metal reaction occurs with the Fe being converted to iron chloride ([tex]FeCl_2[/tex]) and hydrogen ([tex]H_2[/tex]).
The balanced equation is:
[tex]Fe + 2HCl[/tex] → [tex]FeCl_2 + H_2[/tex]
Note that reaction only produces [tex]FeCl_2[/tex] and not [tex]FeCl_3[/tex]. To make [tex]FeCl_3[/tex] you have to get more forcing and react Fe with chlorine gas ([tex]Cl_2[/tex]) at elevated temperature.
Since we are balancing equations here, below is the balanced equation for Fe reacting with [tex]Cl_2[/tex] (offered at no extra charge):
[tex]2Fe + 3Cl_2[/tex] → [tex]2FeCl_3[/tex]
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BRAINLIEST WILL BE GIVEN TO BEST ANSWERED!
What is the best explanation for why a magnet is different from a regular piece of metal?
A magnet has more electrons
The magnetic domains in a magnet are lined up with each other
Magnets are made of iron
A magnet has an electric field
Answer:
the second one
Explanation:
metal doesn't act like a magnet because the domains don't have a preferred direction of alignment. Magnets are all aligned in a specific direction.
In what type of reaction is water always a product
when hydrogen and oxygen combine then they form water as product
also in neutralization reaction water form as product
hope it helps
Water is always a product in a type of chemical reaction called a neutralization reaction.
A reaction is a process that involves the transformation of one or more substances into one or more different substances.
Neutralization reaction is type of reaction occurs when an acid and a base react together to form a salt and water. The general equation for a neutralization reaction is:
[tex]\rm acid + base \rightarrow salt + water[/tex]
In this type of reaction, the hydrogen ions ([tex]\rm H^+[/tex]) from the acid combine with the hydroxide ions ([tex]\rm OH^-[/tex]) from the base to form water ([tex]\rm H_2O[/tex]). The remaining ions from the acid and the base combine to form a salt.
Therefore, water is always a product in a neutralization reaction, which occurs when an acid and a base react together to form a salt and water.
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What is the mass of 5.55 moles of carbon monoxide
Answer:
[tex]\boxed {\boxed {\sf 155 \ g\ CO}}[/tex]
Explanation:
To convert from moles to mass, the molar mass must be used.
First, write the chemical formula for carbon monoxide. Since the carbon (C) comes first without a prefix, there is 1 carbon atom. The prefix mono- before oxide means 1, so there is also 1 oxygen (O) atom. The formula is CO.
Next, look up their molar masses on the Periodic Table.
C: 12.011 g/mol O: 15.999 g/molSince there is 1 atom of each, the molar masses can be added.
CO: 12.011 g/mol + 15.999 g/mol = 28.01 g/molUse this molar mass as a ratio.
[tex]\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]
Multiply by the given number of moles:5.55
[tex]5.55 \ mol \ CO *\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]
The moles of carbon monoxide cancel.
[tex]5.55 * \frac {28.01 \ g \ CO} {1 }[/tex]
Multiply.
[tex]155.4555 \ g \ CO[/tex]
The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, it is the ones place. The 4 in the tenths place tells us to leave the 5.
[tex]155 \ g\ CO[/tex]
5.55 moles of carbon monoxide is about 155 grams.
Is this statement true or false?
Gymnosperms reproduce using seeds, but angiosperms do not.
Answer:
FALSE!
Explanation:
Gymnosperms do use seeds but are exposed like the pine cones of pines. Angiosperms still have seeds, however, they flower or fruit.
Answer:
False
Explanation:
How many moles are contained in 325 gram sample of ammonium dichromate (NH4)2Cr2O7
Answer:
Hyba odpowiedzi c. Hyba
Mole can be defined as the number of molar mass units of the compound in the sample. The moles of ammonium dichromate in 325 grams sample is 1.29 mol.
What is molar mass?The molar mass can be given as the mass of each atom in the formula unit. The molar mass of ammonium chromate is given as:
[tex]\rm (NH_4)_2Cr_2O_7=2(N)+4\;\times\;2(H)+2(Cr)+7(O)[/tex]
Substituting the mass of each atom to identify the molar mass of ammonium chromate:
[tex]\rm (NH_4)_2Cr_2O_7=2(14)+4\;\times\;2(1)+2(52)+7(16)\\ (NH_4)_2Cr_2O_7=28+8+104+112\\ (NH_4)_2Cr_2O_7=252 \;g/mol[/tex]
The molar mass of ammonium dichromate s 252 g/mol. The moles of the compound in 325 g is given as:
[tex]\rm Moles=\dfrac{mass}{molar\;mass} \\\\Moles=\dfrac{325\;g}{252\;g/mol}\\\\ Moles=1.29\;mol[/tex]
The moles of ammonium dichromate in the sample are 1.29 mol. Thus, option c is correct.
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Which of the following answers is true for the following statement?
The conjugate acid of a strong base is:
O aweak acid
O an amphiprotic acid
O a polyprotic acid
O a lousy (or very weak) acid
O a strong acid
it is either "aweak acid or a lousy (or very weak) acid"
Which of the following components does a disc brake system use?
brake shoe
adjuster screw
wheel cylinder
caliper
The caliper is a component which is used by a disc brake system for performing its function.
What are the components of disc brake system?The disc braking system consist of components such as disc/rotor, a brake calliper and brake pads. When the brake pedal is pushed, brake fluid creates pressure that produces friction.
So we can conclude that the caliper is a component which is used by a disc brake system for performing its function.
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Most cooking utensils are made up of aluminum because aluminum is _____
Explanation:
Cooking utensils, such as pots, pans and menu trays, are often made from aluminium because it is lightweight and conducts heat well, making it energy-efficient for heating and cooling. These properties also make it a preferred material for packaging.
2 NaOH + H2SO4 → 2 H2O + Na2SO4
How many grams of water are produced from 203.50 grams of H2S04?
Answer:
[tex]m_{H_2O}=74.8gH_2O[/tex]
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible to realize there is a 1:2 mole ratio of sulfuric acid to water; thus, given the mass of the former and its molar mass (98.07 g/mol), it is possible to determine the mass of produced water as shown below:
[tex]m_{H_2O}=203.50gH_2SO_4*\frac{1molH_2SO_4}{98.07gH_2SO_4}*\frac{2molH_2O}{1molH_2SO_4} *\frac{18.02gH_2O}{1molH_2O}\\\\m_{H_2O}=74.8gH_2O[/tex]
Regards!
what is the total of the amount of energy that is reflected back into space
I need help with this pls help
Answer: true
Explanation:
The lithosphere ______ part of the earth’s crust.
A. Gaseous
B. Solid
C. Water
D. Liquid
Answer:
The lithosphere solid part of the earth's crust
3) How many grams of calcium hydroxide are necessary to create 49.5 mL of a 1.55 M solution?
Answer:
5.68g
Explanation:
Which statement best explains how weather is related to the water
cycle?
Answer:
Increased evaporationof water vapour from sea or land will increase rainfall
Answer:
Explanation:
increased evaporation of water vapor from sea to land will increase rainfall
What pair of properties do all solids have?
Answer:
Has definite shape and volume
Solids have high melting point
Explanation:
What volume, in mL, of 0.100 M NaOH is required to neutralize 35.0 mL of 0.102 M hydroiodic acid HI?
Answer:
35.7 mL NaOH
Explanation:
M1V1 = M2V2
M1 = 0.100 M NaOH
V1 = ?
M2 = 0.102 M HI
V2 = 35.0 mL
Solve for V1 --> V1 = M2V2/M1
V1 = (0.102 M)(35.0 mL) / (0.100 M) = 35.7 mL NaOH
calculate the percentage of sodium and carbon and oxygen in sodium carbonate
Phosphorus is implanted into silicon. The implant parameters are a dose of 1015cm-2at an energy of 150keV.a)Find the depth of the peak of the implant profile and its value at that depth.b)If the wafer originally had 1016cm-3of boron uniformly distributed throughout, find the depth(s) at which the concentration of phosphorus is equal to the concentration of boron.
Answer:
a) ≈ 4.99 / cm^3
b) 0.515 um
Explanation:
Given data:
energy = 150 Kev
dose of 10^15 cm^-2
A) find the depth of the peak of the implant profile and its value at that depth
expression for implant profile = written below in the attached file
value of the peak depth ≈ 4.99 / cm^3
B ) determine the depth at which the concentration of phosphorus is equal concentration of boron
= 0.515 um
attached below is the detailed solution to the problem