if a circle has a diameter of 16ft what's the area

The system of inequalities that represents the possible ways Dakota can mix the cereals is:

6a + 8b < 200

7a + 5b <= 150

Dakota wants the bowl of cereal to contain no more than 200 milligrams of sodium and 150 calories.

The first inequality represents the limit on the sodium content, which cannot exceed 200 milligrams. Cereal A has 6 milligrams of sodium per gram, and Cereal B has 8 milligrams of sodium per gram.

Therefore, 6a + 8b represents the total sodium content in milligrams for a mixture of grams of Cereal A and b grams of Cereal B.

The second inequality represents the limit on the calorie content, which cannot exceed 150 calories. Cereal A has 7 calories per gram, and Cereal B has 5 calories per gram.

Therefore, 7a + 5b represents the total calorie content in calories for a mixture of grams of Cereal A and b grams of Cereal B.

Therefore, the system of inequalities that represents the possible ways Dakota can mix the cereals is:

6a + 8b < 200

7a + 5b <= 150

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The probability of Ian standing in the center of the picture with Cameron on his right is approximately 0.000002756 or 1 in 362,880.

To calculate the probability of Ian standing in the center of the picture with Cameron on his right, we need to consider the total number of possible arrangements and the number of favorable arrangements that satisfy the given condition.

Since there are 9 members in the baseball team, there are 9 possible positions for Ian to stand.

Once Ian is placed in the center, there are 8 remaining positions for Cameron to stand.

To calculate the probability, we need to determine the number of favorable arrangements where Ian stands in the center and Cameron is on his right.

Since Ian must stand in the center, there is only 1 position for Ian. Once Ian is in the center, there is only 1 position for Cameron to stand on his right.

Therefore, the number of favorable arrangements is 1.

The total number of possible arrangements is given by the number of permutations of 9 members, which is 9!.

So, the probability is calculated as:

Probability = Number of favorable arrangements / Total number of possible arrangements

= 1 / 9!

To simplify this, we can write 9! as [tex]9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1.[/tex]

Therefore, the probability is:

Probability [tex]= 1 / (9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)[/tex]

= 1 / 362,880

≈ 0.000002756.

Hence, the probability of Ian standing in the center of the picture with Cameron on his right is approximately 0.000002756 or 1 in 362,880.

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The sample space for rolling a fair nine-sided die is  {1, 2, 3, 4, 5, 6, 7, 8, 9}.

Option C is the correct answer.

We have,

The sample space is the set of all possible outcomes of a random experiment.

In this case, we are rolling a nine-sided die, which means that the possible outcomes are the numbers 1 to 9.

Therefore,

The sample space for rolling a fair nine-sided die is {1, 2, 3, 4, 5, 6, 7, 8, 9}.

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With regard to the cost of both cars, the option that is True is "I should buy the blue car because by the time five years have passed, I will have saved almost $2,000."  (Option A)

From the graph,

Step 1: Note that by the 5th year  the cost spent on maintenance for the blue car is $9000

Step 2:  while that of the yellow car is $11,000.

Step 3: This means that the owner would have saved $2000 since he or she does not wish to keep both cars beyond 5 years period.

Note that this is called cost analysis.

A cost-benefit analysis, also known as a benefit-cost analysis, is a method for analyzing the strengths and weaknesses of options.

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Therefore, the slope of the curve y = 6x^2 + 6/x at the point (3, 56) is 34.

Let's go through the calculation again to find the correct slope.

To find the slope of the curve at the point (3, 56), we need to take the derivative of the function y = 6x^2 + 6/x and evaluate it at x = 3.

Taking the derivative of y with respect to x, we can differentiate each term separately:

d/dx (6x^2) = 12x

d/dx (6/x) = -6/x^2

Now, combining the derivatives, we have:

y' = 12x - 6/x^2

Substituting x = 3 into the derivative expression:

y'(3) = 12(3) - 6/(3^2)

= 36 - 6/9

= 36 - 2/3

= 34 2/3

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The domain and the range of the graph given will be 0 ≤ x ≤ 95 and 0 ≤ y ≤ 20.

Given is a graph, we need to find the domain and the range of the graph given,

So,

The domain is all the input values that mean all the values of x,

Here we see the values of x are lies between 0 to 95, so the domain is 0 ≤ x ≤ 95

And the range is all the output values that mean all the values of y,

Here we see the values of y are lies between 0 to 20, so the range is 0 ≤ x ≤ 20.

Hence the domain and the range of the graph given will be 0 ≤ x ≤ 95 and 0 ≤ y ≤ 20.

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To get the function g, shift f down by 7 units and to the right by 2 units.

From the question, we have the following parameters that can be used in our computation:

The functions f(x) and g(x)

Where, we have

f(x) = x²

g(x) = (x - 2)² - 7

From the above equations, we can see that

The function f(x) is translated right by 2 units

The function f(x) is translated down by 7 units

This means that

To get the function g, shift f down by 7 units and to the right by 2 units.

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The probability that at least one bit is 0 is 63/64 or approximately 0.9844.

Now, For the probability that at least one bit is 0, we have to calculate the probability that all bits are 1 and then subtract it from 1.

Hence, Let us assume that each bit has an equal probability of being 0 or 1, the probability that a single bit is 1 is,

1/2

And, the probability that a single bit is 0 is also 1/2.

Hence, The probability that all 6 bits are 1 is,

⇒ (1/2)⁶ = 1/64.

Therefore, the probability that at least one bit is 0 is,

⇒ 1 - 1/64 = 63/64.

So, the probability that at least one bit is 0 is 63/64 or approximately 0.9844.

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Answer:

Step-by-step explanation:

CIOCCA

Answer:$90.72

Step-by-step explanation:

3ft= 12×3=36

18×7×36
=126×36

=4,536

4,536×0.02

=$90.72

We can use the transformation y = (x - a) / (b - a) to generate a random variable y that is linear in x and uniformly distributed over (0, 1).

To find a random variable y that is linear in x and uniformly distributed over (0, 1), we can use the following transformation:
y = (x - a) / (b - a)
This transformation maps the interval (a, b) to the interval (0, 1) and ensures that the distribution of y is uniform.
To see why this is the case, we can use the formula for the probability density function (pdf) of a uniform distribution:
f(x) = 1 / (b - a)
This means that the probability of x being between any two values c and d is proportional to the length of the interval (d - c) and is given by:
P(c < x < d) = (d - c) / (b - a)
Now, let's find the pdf of y using the transformation above:
F(y) = P(y < Y) = P((x - a) / (b - a) < y) = P(x < (b - a) * y + a)
We can differentiate this to get the pdf of y:
f(y) = dF(y) / dy = f(x) / (b - a) = 1 / (b - a)
This shows that the distribution of y is indeed uniform over (0, 1).

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The first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex] are fx(x, y) = 4x³ and fy(x, y) = [tex]-36xy^8[/tex].

To find the first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex], we need to take the partial derivative with respect to each variable separately while treating the other variable as a constant.
The partial derivative of f(x, y) with respect to x (fx) is obtained by differentiating [tex]x^4[/tex] with respect to x, which gives [tex]4x^3[/tex]. The second term [tex]-4xy^9[/tex] does not involve x, so it drops out in the differentiation process. Therefore, fx(x, y) = [tex]4x^3[/tex].
Similarly, the partial derivative of f(x, y) with respect to y (fy) is obtained by differentiating [tex]-4xy^9[/tex] with respect to y, which gives [tex]-36xy^8[/tex]. The first term x^4 does not involve y, so it drops out in the differentiation process. Therefore, fy(x, y) = [tex]-36xy^8[/tex].
In summary, the first partial derivatives of the function f(x, y) = [tex]x^4 - 4xy^9[/tex] are fx(x, y) = 4x³ and fy(x, y) = [tex]-36xy^8[/tex].

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The formula for the area of a parallelogram can be used to derive the formula for the area of a circle. Is A) No. therefore, These are two different geometric shapes with different formulas for finding their areas.

(A) No, the formula for the area of a parallelogram cannot be used to derive the formula for the area of a circle. These are two different geometric shapes with different formulas for finding their areas.

The formula for the area of a parallelogram is A = base x height, while the formula for the area of a circle is A = π[tex]r^2[/tex], where r is the radius of the circle.

There are other methods to derive the formula for the area of a circle, such as using calculus or using approximations with polygons, but using the formula for a parallelogram is not one of them.

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Based on the information provided, with leading and countercyclical variables reaching a trough, we can expect that:
D. Aggregate economic activity will start increasing.

Leading variables are indicators that change before the overall economy changes, and countercyclical variables move in the opposite direction of the general economic trend.

When these variables reach a trough, it suggests that the lowest point of economic activity has been reached.

As a result, we can expect that aggregate economic activity will start increasing, signaling the end of a recession and the beginning of an expansion phase.

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The problem you have given me is to solve problem 9.1 using Euler's method. Problem 9.1 involves finding the solution to the differential equation y' = x^2 + y^2 with the initial condition y(0) = 1.

To solve this problem using Euler's method, we will first need to choose a step size h. Let's choose h = 0.1.

Then, we can use the formula y_n+1 = y_n + hf(x_n, y_n), where y_n is the approximation of y at the nth step and f(x_n, y_n) is the slope of the tangent line at (x_n, y_n).

Using this formula, we can calculate the values of y at each step. Starting with y_0 = 1 and x_0 = 0, we have: y_1 = y_0 + hf(x_0, y_0) = 1 + 0.1(0^2 + 1^2) = 1.1 y_2 = y_1 + hf(x_1, y_1) = 1.1 + 0.1(0.1^2 + 1.1^2) = 1.243 y_3 = y_2 + hf(x_2, y_2) = 1.243 + 0.1(0.2^2 + 1.243^2) = 1.430 y_4 = y_3 + hf(x_3, y_3) = 1.430 + 0.1(0.3^2 + 1.430^2) = 1.668 y_5 = y_4 + hf(x_4, y_4) = 1.668 + 0.1(0.4^2 + 1.668^2) = 1.964 We can continue this process to find more approximations of y.

The exact solution to this differential equation is y = tan(x + C), where C is a constant. The value of C can be found using the initial condition y(0) = 1, which gives us C = pi/4. Therefore, the exact solution is y = tan(x + pi/4).

In summary, using Euler's method with a step size of h = 0.1, we have found approximations of y for the differential equation y' = x^2 + y^2 with the initial condition y(0) = 1. The exact solution is y = tan(x + pi/4).

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a. A and K are independent.

b.[tex]P(A) = (100!/A!(100-A)!)(-1)^A(p^A)\sum[(100 C K)((1-p)^{(100-K)})][/tex] (summing over K) and [tex]PK(K) = (100 C K)((1-p)^{(100-K)})\sum[(100!/A!(100-A)!)(-1)^A(p^A)][/tex] (summing over A)

c. The probability P[<2, K=50].

What is probability?

Probability is a measure of the likelihood or chance of an event occurring. It quantifies the uncertainty associated with an outcome in a specific situation or experiment.

a. To determine if A and K are independent, we need to check if the joint PMF can be expressed as the product of the marginal PMFs.

Given the joint PMF:

[tex]P(A,K) = (100!/A!(100-A)!)(-1)^A(100 C K)(p^A)((1-p)^{(100-K)})[/tex]

If A and K are independent, the joint PMF should be equal to the product of the marginal PMFs:

P(A,K) = P(A)*PK(K)

Let's check if this holds true by calculating the marginal PMFs.

b. Marginal PMFs:

P(A) = ∑PK(A,K) (summing over K)

[tex]P(A) = \sum[(100!/A!(100-A)!)(-1)^A(100 C K)(p^A)((1-p)^{(100-K)})][/tex] (summing over K)

[tex]P(A) = (100!/A!(100-A)!)(-1)^A(p^A)\sum[(100 C K)((1-p)^{(100-K)})][/tex] (summing over K)

PK(K) = ∑P(A,K) (summing over A)

[tex]PK(K) = \sum[(100!/A!(100-A)!)(-1)^A(100 C K)(p^A)((1-p)^{(100-K)})][/tex] (summing over A)

[tex]PK(K) = (100 C K)((1-p)^{(100-K)})\sum[(100!/A!(100-A)!)(-1)^A(p^A)][/tex] (summing over A)

c. To find P[<2, K=50], we need to substitute p = 0.5 and evaluate the joint PMF for A < 2 and K = 50:

P[<2, K=50] = P(0, 50) + P(1, 50)

[tex]P(0, 50) = (100!/0!(100-0)!)(-1)^0(100 C 50)(0.5^0)((1-0.5)^{(100-50)})\\\\P(1, 50) = (100!/1!(100-1)!)(-1)^1(100 C 50)(0.5^1)((1-0.5)^{(100-50)})[/tex]

Simplifying these expressions will give the probability P[<2, K=50].

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CORREL determines how two sets of data from a sample vary simultaneously. Option 3, "CORREL", is the correct answer.

The correlation coefficient between two cell ranges is returned by the CORREL function. To ascertain the connection between two properties, use the correlation coefficient.

The measure that determines how two sets of data from a sample vary simultaneously is called correlation.

Option 3, "CORREL", is the correct answer. Correlation measures the strength and direction of the linear relationship between two variables. It indicates how much one variable changes when the other variable changes, and is typically measured using a correlation coefficient, such as Pearson's correlation coefficient.

The other options listed are also measures of the relationship between two variables, but they measure different aspects of this relationship:

- STDEV.P is the population standard deviation, which measures the spread of a population of values around its mean.

- COVARIANCE.S is the sample covariance, which measures how two variables vary together in a sample.

- STDEV.S is the sample standard deviation, which measures the spread of a sample of values around its mean.

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In this case, the margin of error for a 99% confidence interval is $0.814.

To calculate the margin of error for a 99% confidence interval, we need to use the formula:
Margin of error = Z × (standard deviation / sqrt(sample size))
where Z is the z-score for the desired confidence level. For a 99% confidence interval, the z-score is 2.576.
Plugging in the given values, we get:
The margin of error = 2.576 × (1.46 / √(30))
Simplifying this expression, we get:
Margin of error = 0.814
Therefore, in this case, the margin of error for a 99% confidence interval is $0.814. This means that we can be 99% confident that the true average cost of a latte in the population falls within $3.55 ± $0.814. In other words, the true average cost of a latte in the population could be as low as $2.736 or as high as $4.364, based on the sample data.

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Thus, the general solution of the given differential equation is y = Ce^(-1/(x+2)) + 2, where C is a constant, and the constant solution is y = 2.

To find the general solution of the given differential equation, we need to transform it into a separable equation. To do this, we can square both sides of the equation to get rid of the square root:
(dy/dx) = (y-2)/(x+2)^2

Now, we can separate the variables by multiplying both sides by (x+2)^2 and dividing both sides by (y-2):
(1/(y-2)) dy = (1/(x+2)^2) dx

Integrating both sides, we get:
ln|y-2| = -1/(x+2) + C

where C is the constant of integration. Solving for y, we get:
y = Ce^(-1/(x+2)) + 2

This is the general solution of the given differential equation. However, we also need to check for constant solutions. If y is a constant, then dy/dx = 0. Substituting this into the original equation, we get:
0 = (y-2)/(x+2)

Since (x+2) is never equal to zero, this implies that y-2 = 0, or y = 2. Therefore, the constant solution is y = 2.

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A rocket is launched from a tower. the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. using this equation, the time that the rocket will hit the ground is 9.99 s.

To solve the resulting quadratic equation, we must replace the height of the rocket with 0

That simply indicates that we are addressing:

0=-16x²+149x+108

We can resolve this using the quadratic formula.

x = -b±√b²-4ac/2a

where a is the -16 coefficient of x2.

B is 149, which is x's coefficient.

The last number, c, is 108.

By changing the values, we obtain that:

x = 9.99

        or

x = -0.68

Time cannot be negative, thus we can only utilize the first value.

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complete question:

A rocket is launched from a tower. the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. y=-16x^2+149x+108

The top 10% of professors spend above $125.94 each week on entertainment. To find the z-score for the top 10% of professors, we need to find the z-value that corresponds to the 90th percentile.

To find out the amount of money spent by the top 10% of professors on entertainment each week, we need to use the z-score formula and the standard normal distribution table.

The z-score formula is:

z = (x - μ) / σ

where:

x = the amount spent on entertainment

μ = the mean amount spent on entertainment

σ = the standard deviation

To find the z-score for the top 10% of professors, we need to find the z-value that corresponds to the 90th percentile. The 90th percentile can be calculated as follows:

90th percentile = mean + z-score * standard deviation

From the standard normal distribution table, we can find that the z-score corresponding to the 90th percentile is 1.28.

So,

90th percentile = 95.25 + 1.28 * 27.32 = 125.94

Therefore, the top 10% of professors spend above $125.94 each week on entertainment.

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The derivative of the function f(x) = cos(3x/4) is -3/4 sin(3x/4).

To find the derivative of a function, we can use the power rule and the chain rule. In this case, the power rule states that the derivative of cos(3x/4) is equal to the derivative of cos(u), where u = 3x/4. The derivative of cos(u) is equal to -sin(u), so the derivative of cos(3x/4) is equal to -sin(3x/4). Using the chain rule, we also need to multiply this by the derivative of the inside function, which is 3/4. Therefore, the derivative of f(x) = cos(3x/4) is -3/4 sin(3x/4).

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We need a sample size of at least 97 to estimate the population mean with a margin of error of 2 or less and a .95 probability when the population standard deviation equals 11.

To estimate a population mean with a certain level of confidence and a specific margin of error, we use a formula that requires knowledge of the population standard deviation. In this case, we are given that the population standard deviation is 11. The formula we use is:

n = [(z*σ)/E]^2

Where:

n = sample size needed
z = the z-score corresponding to the desired level of confidence (in this case, .95 corresponds to a z-score of 1.96)
σ = the population standard deviation (in this case, 11)
E = the desired margin of error (in this case, 2)

Substituting in the values given, we get:

n = [(1.96*11)/2]^2
n = 96.04

We round up to the nearest whole number, since we need a whole number of participants. Therefore, we need a sample size of at least 97 to estimate the population mean with a margin of error of 2 or less and a .95 probability when the population standard deviation equals 11.

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The complete table for the function are

x  -2  -1  0  1  2  3

y  2   -1  -2  1 2  7

The estimated values of the function are x = -1.4 and x = 1.4

From the question, we have the following parameters that can be used in our computation:

The function equation and the incomplete table of values

This is given as

y = x² - 2

From the table, the missing values are at

x = -2, x = -1, 1 and x = 3

So, we have

y = (-2)² - 2 = 2

y = (-1)² - 2 = -1

y = (1)² - 2 = -1

y = (3)² - 2 = 7

From the table, we can see that

When y = 0, the values of x are

x = -1.4 and x = 1.4

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The balloon's vertical distance ( height ) above the ground level is approximately 125.25 feet.

Given that, Enola measures a 22° angle of depression to a landmark that's 310 feet away, measuring horizontally.

This forms a right triangle, the landmark, and the vertical distance (h), the angle of depression (θ) is given as 22 degrees.

The horizontal distance (d) between the balloon and the landmark is given as 310 feet.

Hence, using the trigonometric ratio:

tan(θ) = opposite / adjacent

Plug in the values:

tan(22°) = h / 310

Solve for h

h = tan(22°) × 310

h = 125.25 ft

Therefore, its height from the ground is 125.25 ft.

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Answer:

i think its 14

Step-by-step explanation:

The interval that represents a similar percentage of emus is 3 to 3.5 meters.

The percentage of ostriches with stride lengths between 4.5 and 5.25 meters using a graph of the normal curve.

The population of ostriches can know that approximately 34% have stride lengths between 4.5 and 5.25 meters.

To describe these values in terms of the mean and standard deviation can use the following formula for a standard normal distribution:

z = (x - μ) / σ

z is the z-score, x is the value we're interested in, μ is the mean and σ is the standard deviation.

The z-scores for 4.5 and 5.25 use the mean and standard deviation of the population of ostriches:

z1 = (4.5 - 4.5) / 0.75

= 0

z2 = (5.25 - 4.5) / 0.75

= 1

The range of 4.5 to 5.25 meters corresponds to z-scores between 0 and 1.

The interval that represents a similar percentage of emus can use the same z-scores.

Since the mean stride length of the emus is 3 meters with a standard deviation of 0.5 meters can use the formula above to find the corresponding values of x:

x1 = μ + z1 × σ

= 3 + 0 × 0.5

= 3

x2 = μ + z2 × σ

= 3 + 1 × 0.5

= 3.5

The interval that represents a similar percentage of emus is 3 to 3.5 meters.

The percentage of ostriches with stride lengths between 4.5 and 5.25 meters using a graph of the normal curve.

The total area under the normal curve is equal to 1 so if 34% of the ostriches have stride lengths in this range the area under the curve between 4.5 and 5.25 standard deviations from the mean is also 0.34.

A standard normal distribution table or a calculator can find that the z-scores that correspond to an area of 0.34 between them are approximately -0.43 and 0.43.

The graph of the normal curve for the population of ostriches would show that the area between z = -0.43 and z = 0.43 is 0.34.

This interval corresponds to stride lengths between:

μ + (-0.43) × σ = 4.13 meters

μ + (0.43) × σ = 4.87 meters

The range of 4.5 to 5.25 meters.

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Answer: The trapezoid's area is 265 [tex]unit^{2}[/tex]

Definition of a trapezoid - A trapezoid, also known as a trapezium, is a flat closed shape having four straight sides, with one pair of parallel sides.

The parallel sides of a trapezium are known as the bases, and its non-parallel sides are called legs. A trapezium can also have parallel legs. The parallel sides can be horizontal, vertical, or slanting.

The perpendicular distance between the parallel sides is called the altitude.

The area of trapezium is given as : [tex]\frac{1}{2}[/tex] × sum of the parallel sides × distance between the parallel sides

Given:  the base lengths of trapezoid are 24 unit and 29 unit and height is 10 unit.

The area of trapezoid = [tex]\frac{1}{2}[/tex] × (24+29) × 10 = 265 [tex]unit^{2}[/tex]

Final answer : The area of trapezoid is 265[tex]unit^{2}[/tex]

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