If ABCD is a parallelogram, AD = 14, EC = 11, mZABC = 64°, mZDAC = 71°, and mZBDC = 25,
find each measure.
А
a) BC =
d) mZABD =
B
b) AC =
e) m ACD =
E
D
С
c) m DAB
f) mZADB =​

Answers

Answer 1

Find attached to this answer the diagram of the Quadrilateral

Question:

If ABCD is a parallelogram, AD = 14, EC = 11, m∠ABC = 64°, m∠DAC = 71°, and m∠BDC = 25, find each measure.

a) BC =

b) AC =

c) m∠DAB =

d) m∠ABD =

e) m∠ACD =

f) m∠ADB =​

Answer:

a) BC = 11

b) AC = 22

c) m∠DAB = 116°

d) m∠ABD = 39°

e) m∠ACD = 45°

f) m∠ADB =​ 25°

Step-by-step explanation:

a) BC

In the question above, EC = 11

We can see that EC and BC are equal sides of a diagonal line that has been divided into two equal parts in a Quadrilateral.

Hence, In a quadrilateral ABCD,

EC = BC

Hence BC = 11

b) AC

AC is one of the diagonal lines that divided parallelogram ABCD

AC = BC + EC

AC = 11 + 11

AC = 22

c) m∠DAB

m∠ABC = 64°

m∠ADC = 64°

For the two angles above, a diagonal bisects through those angles.

Also the sum of angles in a triangle = 180°

Hence,

180° = 1/2m∠ABC + 1/2m∠ADC +

m∠DAB

m∠DAB = 180° - ( 1/2 (64) + 1/2(64))

m∠DAB = 180 ° - 64°

m∠DAB = 116°

d) m∠ABD

Since,

m∠ABC = 64° and m∠BDC = 25

m∠ABC = m∠BDC + m∠ABD

64 = 25+ m∠ABD

m∠ABD = 64° - 25°

m∠ABD = 39°

e) m∠ACD

In the above question,

m∠ABC = 64°,

m∠ADC = m∠ABC, this is because, opposite angles in a quadrilateral are congruent and equal to each other.

Hence, m∠ADC = 64°

m∠DAC = 71°,

In a triangle , all the angles in a triangle = 180°

Hence,

180° = m∠DAC + m∠ADC + m∠ACD

180° = 71° + 64 ° + m∠ACD

m∠ACD = 180° -(71 + 64)°

m∠ACD = 180° - 135°

m∠ACD = 45°

f) m∠ADB

Since

m∠DAB = 116°

m∠ABD = 39°

The sum of angles in a triangle = 180°

180° = m∠ABD + m∠DAB + m∠ADB

180° = 39 ° + 116° + m∠ADB

m∠ADB = 180° - ( 116 + 39)°

m∠ADB = 25 °

If ABCD Is A Parallelogram, AD = 14, EC = 11, MZABC = 64, MZDAC = 71, And MZBDC = 25,find Each Measure.a)
Answer 2

a) BC = 11

b) AC = 22

c) m∠DAB = 116°

d) m∠ABD = 39°

e) m∠ACD = 45°

f) m∠ADB =​ 25°

Given : AD=14 , EC=11, m∠ABC= 64°, m∠DAC=71° and m∠BDC=25°

To find:  BC =?  , AC =? , m∠DAB =?, m∠ABD =?  ,m∠ACD =?  ,m∠ADB =​?

Consider the figure given below ABCD is a parallelogram

To find a) BC

Given, EC = 11

As seen in figure that EC and BC are equal sides of a diagonal line that has been divided into two equal parts in a Parallelogram.

Hence, In a Parallelogram ABCD,

EC = BC

Hence BC = 11

To find b) AC

AC is one of the diagonal lines that divided parallelogram ABCD

AC = BC + EC

AC = 11 + 11

AC = 22

To find c) m∠DAB

Given, m∠ABC = 64°

m∠ADC = 64°

(For the two angles above, a diagonal bisects through those angles)

Also From Angle sum property;

Hence,

180° = 1/2m∠ABC + 1/2m∠ADC +  m∠DAB

m∠DAB = 180° - ( 1/2 (64) + 1/2(64))

m∠DAB = 180 ° - 64°

m∠DAB = 116°

To find d) m∠ABD

Since,

m∠ABC = 64° and m∠BDC = 25  

m∠ABC = m∠BDC + m∠ABD

64 = 25+ m∠ABD

m∠ABD = 64° - 25°

m∠ABD = 39°

To find e) m∠ACD

Given,  m∠ABC = 64°;

m∠ADC = m∠ABC, this is because, opposite angles in a quadrilateral (here parallelogram) are congruent and equal to each other

Hence, m∠ADC = 64°

m∠DAC = 71°,

In a triangle , all the angles in a triangle = 180°(Angle sum property)

Hence,

180° = m∠DAC + m∠ADC + m∠ACD

180° = 71° + 64 ° + m∠ACD

m∠ACD = 180° - (71 + 64)°

m∠ACD = 180° - 135°

m∠ACD = 45°

To find f) m∠ADB

Since  ,m∠DAB = 116°  and m∠ABD = 39°

From Angle sum property;

180° = m∠ABD + m∠DAB + m∠ADB

180° = 39 ° + 116° + m∠ADB

m∠ADB = 180° - ( 116 + 39)°

m∠ADB = 25 °

Learn more:

https://brainly.com/question/23163052

If ABCD Is A Parallelogram, AD = 14, EC = 11, MZABC = 64, MZDAC = 71, And MZBDC = 25,find Each Measure.a)

Related Questions

Out of 600 people sampled, 66 preferred Candidate A. Based on this, estimate what proportion of the entire voting population (p) prefers Candidate A.

Required:
Use a 90% confidence level, and give your answers as decimals, to three places.

Answers

Answer:

11% of the Total the entire voting population

Step-by-step explanation:

Let's bear in mind that the total number of sample candidates is equal to 600.

But out of 600 only 66 preffered candidate A.

The proportion of sampled people to that prefer candidate A to the total number of people is 66/600

= 11/100

In percentage

=11/100 *100/1 =1100/100

=11% of the entire voting population

expand(x+y2)2 plzzzzzzzzzzzzzzzz​

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Answer:

[tex](x + {y}^{2}) = {x}^{2} + 2x {y}^{2} + {y}^{4} [/tex]

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During a quality assurance​ check, the actual contents​ (in grams) of six containers of protein powder were recorded as 1530​, 1532​, 1495​, 1508​, 1528​, and 1511. ​(a) Find the mean and the median of the contents. ​(b) The third value was incorrectly measured and is actually 1515. Find the mean and the median of the contents again. ​(c) Which measure of central​ tendency, the mean or the​ median, was affected more by the data entry​ error?

Answers

Answer:

Step-by-step explanation:

Given the values of the actual content of protein powder recorded as shown:

1530​, 1532​, 1495​, 1508​, 1528​, and 1511

a) We are to find the mean and median of the contents.

Mean is the average sum of the numbers. It is expressed mathematically as xbar = ΣXi/N

Xi are individual values

N is the total number of values present.

N = 6

xbar = (1,530​+1,532​+1,495​ +1,508​+1,528+1,511)/6

xbar = 9104/6

xbar = 1517.33

Median of the data is the value at the middle after rearrangement. On rearranging from lowest to highest:

1,495, 1508, 1511, 1528, 1530, 1532

The two values at the centre are 1511 and 1528.

Median = 1511+1528/2

Median = 1519.5

b) If the third value was incorrectly measured and is actually 1515, then our new data will become.

1530​, 1532​, 1515​, 1508​, 1528​, and 1511

xbar = (1,530​+1,532​+1,515​ +1,508​+1,528+1,511)/6

xbar = 9124/6

xbar = 1520.67

For median:

We arrange first

1508, 1511, 1515, 1528, 1530, 1532

The two values at the centre are 1515 and 1528.

Median = 1515+1528/2

Median = 1521.5

c) To know the measure of central tendency that was most affected, we will look at the difference in the values gotten for both mean and median.

∆Mean = 1520.67-1517.33

∆Mean = 3.34

∆Median = 1521.5 - 1519.5

∆Median = 2.0

It can be seen that the measure of central tendency with greater deviation is the mean. Therefore, the mean is more affected by the data entry error.

What point lies on the line described by the equation below? Y+3=2 (x-1

Answers

Answer:

[tex]\boxed{(1, -3)}[/tex]

Step-by-step explanation:

[tex]y+3=2 (x-1)[/tex]

Put equation in slope-intercept form.

[tex]y=mx+b[/tex]

[tex]y=2(x-1)-3[/tex]

[tex]y=2x-2-3[/tex]

[tex]y=2x-5[/tex]

Let x = 1

[tex]y=2(1)-5[/tex]

[tex]y=2-5[/tex]

[tex]y=-3[/tex]

The point (1, -3) lies on the line.

Two passenger trains traveling in opposite directions meet and pass each other. Each train is 1 12 mi long and is traveling 50 mph. How many seconds after the front cars of the trains meet will their rear cars pass each other?

Answers

Answer:

Time taken = 6 sec (Approx)

Step-by-step explanation:

Given:

Total distance = 1/12 mi = 0.083333

Speed of train = 50 mph = 50 / 3600 = 0.01388889 mps

Find:

Time taken

Computation:

Time taken = Total distance / Speed

Time taken = Total distance / Speed of train

Time taken = 0.0833333 / 0.01388889

Time taken = 6 sec (Approx)

Let a and b be real numbers where a=/b=/c=/0 which of the following functions could represent the graph below?

Answers

Answer: The second option;  y =  (x - a)^2*(x-b)^4

Step-by-step explanation:

Ok, we have that a and b are real numbers different than zero.

In the graph, we can see that the line touches the x-axis in two values. Now, if we would have an equation like:

y = x*(x - a)^3*(x - b)^3

then when x = 0 we would have:

y = 0*(0-a)^3*(0-b)^3 = 0

But in the graph, we can see that when x = 0, the value of y is different than zero, so we can discard options 1 and 3.

So the remaining options are:

y = (x - a)^2*(x-b)^4

y = (x - a)^5*(x - b)

Now, another thing you can see in the graph is that it is always positive.

Particularly the second option allows negative values for y because it has odd powers, then we can also discard this option.

(For example, if x > a and x < b we would have a negative value for y)

Then the only remaining option is y =  (x - a)^2*(x-b)^4

Answer:

B.y =  (x - a)^2*(x-b)^4

Step-by-step explanation:

EDGE 2020 Brainliest please

When randomly selecting an adult, let B represent the event of randomly selecting someone with type B blood. Write a sentence describing what the rule of complements below is telling us. P B or B = 1 Choose the correct answer below. A. It is impossible that the selected adult has type B blood or does not have type B blood. B. It is certain that the selected adult has type B blood. C. It is certain that the selected adult has type B blood or does not have type B blood. D. It is certain that the selected adult does not have type B blood.

Answers

Answer: The rule of complements is apprising us that, the person selected will.eithwr have a type B blood or will not have a type B blood

Step-by-step explanations:

Find explanations in the attachment

determining probability of events. please help! ​

Answers

Answer:

23/90

Step-by-step explanation:

55/90 + 12/90 = 67/9090 - 67 = 2323/90

23/90 balls are green or white

i hope this helps!

The half-life of iron-52 is approximately 8.3 hours. Step 1 of 3: Determine a so that A(t)=A0at describes the amount of iron-52 left after t hours, where A0 is the amount at time t=0. Round to six decimal places.

Answers

Answer:

Step-by-step explanation:

Given the half like of a material to be 8.3 hours and the amount of iron-52 left after t hours is modeled by the equation [tex]A(t) = A_0 a^{t}[/tex], we can get A(t) as shown;

At t = 8.3 hours, A(8.3) = 1/2

Initially at t = 0; A(0) = 1

Substituting this values into the function we will have;

[tex]\frac{1}{2} = 1 * a^{8.3}\\\\Taking \ the \ log \ of\ both \ sides;\\\\log(\frac{1}{2} ) = log(a^{8.3} )\\\\log(\frac{1}{2} ) = 8.3 log(a)\\\\\fr-0.30103 = 8.3 log(a)\\\Dividing\ both\ sides\ by \ 8.3\\\\\frac{-0.30103}{8.3} = log(a)\\\\log(a) = - 0.03627\\\\a =10^{-0.03627} \\\\a = 0.919878 (to\ 6dp)[/tex]

Solve the following system of equations. Express your answer as an ordered pair in the format (a,b). 3x+4y=17 -4x-7y=-18

Answers

Answer:

Step-by-step explanation:

3x+4y = 17 _______ equation 1

-4x -7y= -18 _______ equation 2

muliply by 4 in equation 1

12x + 16y = 68 ______ equation 3

multiply by 3 in equation 2

-12x - 21y = -54 ________ equation 4

add equation 3 & 4

- 5y = 14

y = - 14/5

substitute y in equation 1

3x + 4 (-14/5) =17

3x = 17+ (56/5)

3x =( 85 + 56) / 5

3x = 141/5

x = 47/5

hence (a,b) = (47/5, -14/5)

In 2009, a school population was 1,700. By 2017 the population had grown to 2,500. Assume the population is changing linearly. How much did the population grow between 2009 and 2017?

Answers

Answer:

100

Step-by-step explanation:

The population is changing linearly. This means that the population is increasing by a particular value n every year.

From 2009 to 2017, there are 8 increases and so, the population increases by 8n.

The population increased from 1700 to 2500. Therefore, the population increase is:

2500 - 1700 = 800

This implies that:

8n = 800

=> n = 800/8 = 100

The average population growth per year is 100.

Answer:

100

Step-by-step explanation:

aaaaa

Wholemark is an internet order business that sells one popular New Year greeting card once a year. The cost of the paper on the which the card is printed is $0.05 per card, and the cost of printing is $0.15 per card. The company receives $2.15 per card sold. Since the cards have the current year printed on them, unsold cards have no salvage value. Their customers are from the four areas: Los Angeles, Santa Monica, Hollywood, and Pasadena. Based on past data, the number of customers from the each of the four regions is normally distributed with mean 2,000 and standard deviation of 500. (Assume these four are independent.)
What is the optimal production quality for the card? (Use Excel's NORMSINV{} function to find the Z-score. Round intermediate calculations to four decimal places. Submit your answer to the nearest whole number.)

Answers

Answer:

The optimal production quantity is 9,322 cards.

Step-by-step explanation:

The information provided is:

Cost of the paper = $0.05 per card

Cost of printing = $0.15 per card

Selling price = $2.15 per card

Number of region (n) = 4

Mean demand = 2000

Standard deviation = 500

Compute the total cost per card as follows:

Total cost per card = Cost of the paper + Cost of printing

                                = $0.05 + $0.15

                                = $0.20

Compute the total demand as follows:

Total demand = Mean × n

                       = 2000 × 4

                       = 8000

Compute the standard deviation of total demand as follows:

[tex]SD_{\text{total demand}}=\sqrt{500^{2}\times 4}=1000[/tex]

Compute the profit earned per card as follows:

Profit = Selling Price - Total Cost Price

         = $2.15 - $0.20

         = $1.95

The loss incurred per card is:

Loss = Total Cost Price = $0.20

Compute the optimal probability as follows:

[tex]\text{Optimal probability}=\frac{\text{Profit}}{\text{Profit+Loss}}[/tex]

                               [tex]=\frac{1.95}{1.95+0.20}\\\\=\frac{1.95}{2.15}\\\\=0.9069767\\\\\approx 0.907[/tex]

Use Excel's NORMSINV{0.907} function to find the Z-score.

z = 1.322

Compute the optimal production quantity for the card as follows:

[tex]\text{Optimal Production Quantity}=\text{Total Demand}+(z\times SD_{\text{total demand}}) \\[/tex]

                                               [tex]=8000+(1.322\times 1000)\\=8000+1322\\=9322[/tex]

Thus, the optimal production quantity is 9,322 cards.

A national survey of 1000 adult citizens of a nation found that 25​% dreaded​ Valentine's Day. The margin of error for the survey was 3.6 percentage points with 90​% confidence. Explain what this means.

Answers

Answer:

There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.

Step-by-step explanation:

The summary of the statistics from the information given is ;

At 90% confidence interval, 25​% dreaded​ Valentine's Day and the margin of error for the survey was 3.6 percentage points

SO;

[tex]C.I = \hat p \pm M.O.E[/tex]

[tex]C.I = 0.25 \pm 0.036[/tex]

C.I = (0.25-0.036 , 0.25+0.036)

C.I = (0.214, 0.286)

The 90% confidence interval for the proportion of the adult citizens of the nation that dreaded Valentine’s day is 0.214 and 0.286.

There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.

Which is the value of this expression when p = 3 and q = negative 9? ((p Superscript negative 5 Baseline) (p Superscript negative 4 Baseline) (q cubed)) Superscript 0 Negative one-third Negative StartFraction 1 Over 27 EndFraction StartFraction 1 Over 27 EndFraction One-third Edge 2020

Answers

Answer:

I am pretty sure that the answer is D. The value should be 1.

Step-by-step explanation:

Answer:

Answer is D

Step-by-step explanation:

On Edge 2020

If I set my alarm to read 8:10 when it is really 8:00 (i.e., it is 10 minutes fast) and the alarm goes off each day when it reads 8:10, it will be ___________ but not ___________.

Answers

Answer:

If I set my alarm to read 8:10 when it is really 8:00 (i.e., it is 10 minutes fast) and the alarm goes off each day when it reads 8:10, it will be reliable but not valid.

Step-by-step explanation:

If I set my alarm to wake me earlier than I need to be woken, it might be in order to give me enough time to adjust to the alarm, and be awake enough to get out of bed before the normal time I need to be out of bed. This method is very reliable, as there is a very little probability of me waking up late, since I have a 10 minutes head start everyday to get out of bed. The problem is that this method is not valid, since I now actually wake earlier than I am supposed to. The extra 10 minutes can actually lead to a disorientation with time.

I toss an unfair coin 12 times. This coin is 65% likely to show up heads. Calculate the probability of the following.
a. 11 heads:
b. 2 or more heads:
c. 7 heads:
d. 9 tails:
e. 8 or less heads:

Answers

Answer:

a. 0.0368

b. 0.99992131

c. 0.2039

d. 0.0048

e. 0.6533

Step-by-step explanation:

Let the probability of obtaining a head be p = 65% = 13/20 = 0.65. The probability of not obtaining a head is q = 1 - p = 1 -13/20 = 7/20 = 0.35

Since this is a binomial probability, we use a binomial probability.

a. The probability of obtaining 11 heads is ¹²C₁₁p¹¹q¹ = 12 × (0.65)¹¹(0.35) = 0.0368

b. Probability of 2 or more heads P(x ≥ 2) is

P(x ≥ 2) = 1 - P(x ≤ 1)

Now P(x ≤ 1) = P(0) + P(1)

= ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹

= (0.65)⁰(0.35)¹² + 12(0.65)¹(0.35)¹¹

= 0.000003379 + 0.00007531

= 0.0007869

P(x ≥ 2) = 1 - P(x ≤ 1)

= 1 - 0.00007869

= 0.99992131

c. The probability of obtaining 7 heads is ¹²C₇p⁷q⁵ = 792(0.65)⁷(0.35)⁵ = 0.2039

d. The probability of obtaining 7 heads is ¹²C₉q⁹p³ = 220(0.65)³(0.35)⁹ = 0.0048

e. Probability of 8 heads or less P(x ≤ 8) = ¹²C₀p⁰q¹² + ¹²C₁p¹q¹¹ + ¹²C₂p²q¹⁰ + ¹²C₃p³q⁹ + ¹²C₄p⁴q⁸ + ¹²C₅p⁵q⁷ + ¹²C₆p⁶q⁶ + ¹²C₇p⁷q⁵ + ¹²C₈p⁸q⁴

= = ¹²C₀(0.65)⁰(0.35)¹² + ¹²C₁(0.65)¹(0.35)¹¹ + ¹²C₂(0.65)²(0.35)¹⁰ + ¹²C₃(0.65)³(0.35)⁹ + ¹²C₄(0.65)⁴(0.35)⁸ + ¹²C₅(0.65)⁵(0.35)⁷ + ¹²C₆(0.65)⁶(0.35)⁶ + ¹²C₇(0.65)⁷(0.35)⁵ + ¹²C₈(0.65)⁸(0.35)⁴

= 0.000003379 + 0.00007531 + 0.0007692 + 0.004762 + 0.01990 + 0.05912 + 0.1281 + 0.2039 + 0.2367

= 0.6533

Complete the table.PLSSS HELP ILL GIVE BRAINLIEST.PLS PLS PLS PLS

Answers

Answer:

0, 22, 44, 66

Step-by-step explanation:

Given the equation for the model, [tex] d = 11t [/tex] , you can complete the table above by simply plugging in each value of "t" has given in the table to solve for "d".

*When t (seconds) = 0, distance (feet) would be:

[tex] d = 11(0) [/tex]

[tex] d = 0 [/tex]

*When t (seconds) = 2, distance (feet) would be:

[tex] d = 11(2) [/tex]

[tex] d = 22 [/tex]

*When t (seconds) = 4, distance (feet) would be:

[tex] d = 11(4) [/tex]

[tex] d = 44 [/tex]

*When t (seconds) = 6, distance (feet) would be:

[tex] d = 11(6) [/tex]

[tex] d = 66 [/tex]

What are the trigonometric ratios? Write all six.

Answers

Step-by-step explanation:

Check that attachment

Hope it helps :)

Hey! :)

________ ☆ ☆_________________________________________

Answer:

There are six trigonometric ratios, which will be under “Explanation”

Step-by-step explanation:

Trigonometric ratios are a measurements of a right triangle.

Here are the all the six trigonometric ratios.

1. cotangent (cot)

2. cosecant (csc)

3. cosine (cos)

4. secant (sec)

5. sine (sin)

6. tangent (tan)

Hope this helps! :)

_________ ☆ ☆________________________________________

By, BrainlyMember ^-^

Good luck!

If 2/3 of a certain number is subtracted from twice the number, the result is 20. Find the number.​

Answers

Let x be the number.

Set up an equation:

2x - 2/3x = 20

Simplify:

1 1/3x = 20

Divide both sides by 1 1/3

X = 15

The number is 15

Answer: 60
Step by Step Explanation:
Let the number be x
So, x-2/3x=20
=> x/1 - 2/3x = 20
=> (3x - 2x)/3 = 20
=> x/3 = 20
=> x= 20*3
=> x=60
Checking if the solution is correct:
So substitute the value of x in x-2/3x=20
As we know x=60
So, => 60 - 2/3*60 = 20
=> 60 - 40 = 20
As 20 = 20
So this answer is correct

A firm has 18 senior and 22 junior partners. A committee of three partners is selected at random to represent the firm at a conference. In how many ways can at least one of the junior partners be chosen to be on the committee?

Answers

Answer:

Answer is 24288.

Step-by-step explanation:

Given that there are 18 senior and 22 junior partners.

To find:

Number of ways of selecting at least one junior partner to form a committee of 3 partners.

Solution:

At least junior 1 member means 3 case:

1. Exactly 1 junior member

2. Exactly 2 junior member

3. Exactly 3 junior member

Let us find number of ways for each case and then add them.

Case 1:

Exactly 1 junior member:

Number of ways to select 1 junior member out of 22: 22

Number of ways to select 2 senior members out of 18: 18 [tex]\times[/tex] 17

Total number of ways to select exactly 1 junior member in 3 member committee: 22 [tex]\times[/tex] 18 [tex]\times[/tex] 17 = 6732

Case 2:

Exactly 2 junior member:

Number of ways to select 2 junior members out of 22: 22 [tex]\times[/tex] 21

Number of ways to select 1 senior member out of 18: 18

Total number of ways to select exactly 2 junior members in 3 member committee: 22 [tex]\times[/tex] 21 [tex]\times[/tex] 18 = 8316

Case 3:

Exactly 3 junior member:

Number of ways to select 3 junior members out of 22: 22 [tex]\times[/tex] 21 [tex]\times[/tex] 20 = 9240

So, Total number of ways = 24288

Richard is buying a subscription for video game rentals. The plan he has chosen has an
initial fee of $20 plus $2 per video game rented. This plan can be represented by the
function f(x) = 2x + 20. How much money will Richard pay this month if he rents 5 video
games?​

Answers

Answer:

Richard will pay $30.

Step-by-step explanation:

Because "x" is equivalent to the amount of video games he rents, you would replace "x" with 5. Do the math, and you would get 10+20=30! Hope this helps!

he will pay $30 this month

What is the slope of the line passing through the points (6,7) and (1,5)

Answers

Answer:

2/5

Step-by-step explanation:

(7-5)/(6-1)

consider the distribution of monthly social security (OASDI) payments. Assume a normal distribution with a standard deviation of $116. if one-fourth of payments are above $1214,87 what is the mean monthly payment?

Answers

Answer:

$1137

Step-by-step explanation:

Solution:-

We will define the random variable as follows:

                       X: Monthly social security (OASDI) payments

The random variable ( X ) is assumed to be normally distributed. This implies that most monthly payments are clustered around the mean value ( μ ) and the spread of payments value is defined by standard deviation ( σ ).

The normal distribution is defined by two parameters mean ( μ ) and standard deviation ( σ ) as follows:

                       X ~ Norm ( μ , σ^2 )

           

We will define the normal distribution for (OASDI) payments as follows:

                       X ~ Norm ( μ , 116^2 )

We are to determine the mean value of the distribution by considering the area under neat the normal distribution curve as the probability of occurrence. We are given that 1/4 th of payments lie above the value of $1214.87. We can express this as:

                      P ( X > 1214.87 ) = 0.25

We need to standardize the limiting value of x = $1214.87 by determining the Z-score corresponding to ( greater than ) probability of 0.25.

Using standard normal tables, determine the Z-score value corresponding to:

                     P ( Z > z-score ) = 0.25 OR P ( Z < z-score ) = 0.75

                     z-score = 0.675

- Now use the standardizing formula as follows:

                     [tex]z-score = \frac{x - u}{sigma} \\\\1214.87 - u = 0.675*116\\\\u = 1214.87 - 78.3\\\\u = 1136.57[/tex]

Answer: The mean value is $1137

Find the valuds to complete the table

Answers

Answer:

Where is the table

Step-by-step explanation:

I cant answer without it

What is the given table?

Given the function below, find value (s) of x if f(x)=7

Answers

Two answers are:   -1 and 1

Explanation:

f(x) and y are often used interchangeably. We are asked to find the x value(s) when y = 7.

Circle the rows where 7 shows up in the y column. You should find that x = -1 and x = 1 are circled as well.

So f(x) = 7 leads to x = -1 or x = 1. In other words, f(-1) = 7 and f(1) = 7 also.

For the function given the value of x can be two, one is 1 and the other one is -1 if the f(x)=7

What is a Function?

A function relates an input to an output means it is a kind of relationship between the variable y and x. It is denoted through f(x).

What is a Variable?

A variable is defined as a quantity that may assume any one of a set of values.

How to find the value of x in a function?

In the question the function is given as:

Function is denoted through f(x) and f(x) shows the value of x. We know that the value of f(x)=7 which is given in the question. So we will take the value of x in the front of 7 which is written in the y column. We have got two values in this which are 1 and -1. So they both will be the values of x.

Hence the value of x for the function given in the question are -1 and 1

Learn more about functions at https://brainly.com/question/25638609

#SPJ2

f(n)=4n-3 find the 15th term of the sequence defined by the explicit rule

Answers

Answer:

57

Step-by-step explanation:

f(15)=4(15)-3

f(15)=60-3

f(15)=57

Hope that helps, tell me if you need more help

Answer:

57

Step-by-step explanation:

If you plug 15 into the equation, you get f(15)=4(15)-3

60-3

57

:)

Twice a number plus three times a second number is twenty two. Three times the first number plus four times the second is thirty one. Find the numbers

Answers

2x+3y=22
3x+4y=31

8x+12y=88
-9x-12y=-93
x=5
y=4

5 and 4.

Answer:

The numbers are 5 and 4

Step-by-step explanation:

Let the first number be x

Let the second number be y

For the first equation

2x + 3y = 22

For the second equation

3x + 4y = 31

Multiply the first one by 3 and the second one by 2

That's

First equation

6x + 9y = 66

Second equation

6x + 8y = 62

Subtract the second equation from the first one

That's

6x - 6x + 9y - 8y = 66 - 62

y = 4

Substitute y = 4 into 2x + 3y = 22

That's

2x + 3(4) = 22

2x = 22 - 12

2x = 10

Divide both sides by 2

x = 5

Hope this helps you

the result of two forces acting on a body has a magnitude of 80 pounds. The angles between the resultant and the forces are 20 degrees and 52 degrees. find the magnitude of the large force

Answers

Answer:

Larger force= 66.28 pounds

Step-by-step explanation:

The angle of the resultant force 80 pounds = 180-(52+20)

The angle of the resultant force 80 pounds = 180-72

The angle of the resultant force 80 pounds = 108°

The larger force is the force with 52°

Let the larger force be x

Magnitude of the larger force

x/sin52 = 80/sin108

X= sin52 *(80/sin 108)

X= 0.7880*(80/0.9511)

X = 0.7780*(84.1131)

X = 66.28 pounds

Use the given categorical data to construct the relative frequency distribution. Natural births randomly selected from four hospitals in a highly populated region occurred on the days of the week​ (in the order of Monday through​ Sunday) with the frequencies 53​, 63​, 68​, 58​, 61​, 43​, 54. Does it appear that such births occur on the days of the week with equal​ frequency?

Answers

Answer: Yes

Step-by-step explanation:

See explanations in the attached document

What is the inverse of the logarithmic function

f(x) = log2x?


f –1(x) = x2


f –1(x) = 2x


f –1(x) = logx2


f –1(x) = StartFraction 1 Over log Subscript 2 Baseline x EndFraction

Answers

Answer:

B. edge 2021

B. is correct for the next one too.

Step-by-step explanation:

B. is the correct answer for the first one
B. is also the correct answer for the second one

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