The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.
The freezing point is the temperature at which the substance changes its phase from liquid to solid.
The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.
024 (part 1 of 3) 10.0 points
A 2.0 kg block is pushed 3.0 m at a constant
velocity up a vertical wall by a constant force
applied at an angle of 29.0° with the horizon-
tal, as shown in the figure.
The acceleration of gravity is 9.81 m/s².
2 kg
3 m
29°
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.30, find
a) the work done by the force on the block.
Answer in units of J.
The work was done by the force on the block of 2 kg with an acceleration gravity of 9.81 [tex]m/s^2[/tex] and at an angle of [tex]29^o[/tex] 42.83 J.
What is work done?When an object is moved over a distance by an external force, at least some of that force must be applied in the direction of the displacement. This is known as work in physics. Work may be estimated if the force acting along the path is constant by multiplying the length of the path by the component of the force acting along the path.
To express this formally, the work W is equal to the force f times the length d, or W = fd. The work is W = fd cos if the force is applied at an angle to the displacement.
Given:
The mass, m = 2 kg,
The acceleration, g = 9.81 [tex]m/s^2[/tex],
θ = angle between block and surface kinetic friction = μ
Calculate the work done by the formula given below,
[tex]W_{fy}[/tex] = F sinθ
[tex]W_{fy}[/tex] = ([tex]mgsin[/tex]θ)/ (sinθ - μ * cosθ)
Substitute the values
[tex]W_{fy}[/tex] = [tex](2*9.81 sin29^{o} )/sin29^o - 0.30cos29^o[/tex]
[tex]W_{fy}[/tex] = 42.83 J
Therefore, the work done by the force on the block of 2 kg with an acceleration gravity of 9.81 [tex]m/s^2[/tex], and at an angle of [tex]29^o[/tex] is 42.83 J.
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Sarah wanted to find out the power consumption of the bulb in her bicycle light. She found that at a voltage of 9 V, an ammeter in the bulb circuit gave a reading of 1.5 A. What was the bulb's power in watts?
Answer:
P=VI=(9)(1.5)= 13.5 watts
Explanation:
The power of the bulb is 13.5W.
What is Power?Power is defined as the amount of energy transferred or changed per unit time. The unit of power is the watt, which is equal to one joule per second. power is sometimes called activity. Power is a scalar quantity.
The formula of the power is P = E/t,
where P means power in Watt
E means energy in Joules
t means time in seconds.
This formula states that power is the consumption of energy per unit of time.
In above given information, P is also expressed as
P=VI
where V is the voltage in Volts and
I is the current in Amperes.
So, P= 9*1.5 = 13.5 Watts
Thus, the power of the bulb is 13.5W.
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A butterfly flutters at a rate of 18 feet per minute. This is an example of
A butterfly flutters at a rate of 18 feet per minute. This is an example of speed .
Speed is defined as. The rate of change of position of an object in any direction. Speed is measured as the ratio of distance to the time in which the distance was covered.
In the above question " A butterfly flutters at a rate of 18 feet per minute " , it can be observed that there is a magnitude as well as unit .
here , the magnitude is 18 and the unit is feet per minute , which is a unit of speed as the SI unit of speed is m/s .
hence , this is an example of speed as speed is been measured by this unit .
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A car, initially at rest, travels from 0 m/s to 18.4 m/s in 27.8 s. What is the car's acceleration?
Take into account that the acceleration of the car can be calculated by using the following expression:
[tex]a=\frac{v-v_o}{t}[/tex]where,
vo: initial speed = 0m/s
v: final speed = 18.4m/s
t: time = 27.8s
Replace the previous values of the parameters into the formula for a and simplify:
[tex]a=\frac{18.4\frac{m}{s}-0\frac{m}{s}}{27.8s}\approx0.66\frac{m}{s^2}[/tex]Hence, the acceleration of the car is approximately 0.66m/s^2
If your mass is 63.7 kg, and you are standing 7.5 m away from a boulder witha mass of 0.750.6 kg, what is the gravitational force between you and theboulder ? Newtona taw of gravitation is gravity = amputa, The gravitationalconstant Gis 6.67 10-11 Nm/kgA. 9.82* 10-NB. 7.37* 10-NC. 552* 10-ND. 1.10*10N
The gravitational force is given as:
[tex]F=G\frac{m_1m_2}{r^2}[/tex]Plugging the values given we have:
[tex]\begin{gathered} F=(6.67\times10^{-11})\frac{(63.7)(9750.6)}{(7.5)^2} \\ F=7.37\times10^{-7} \end{gathered}[/tex]Therefore the answer is B.
An object is taken to Mars. It’s mass is 15kg, it’s weight on Mars is 55.5N
What is the gravitational field strength on Mars?
Answer:
Approximately [tex]3.7\; {\rm N \cdot kg^{-1}}[/tex] (or equivalently, [tex]3.7\; {\rm m\cdot s^{-2}}[/tex].)
Explanation:
Gravitational field strength measures the force (weight) that the field exerts on object of unit mass (e.g., [tex]1\; {\rm kg}[/tex].)
Divide the weight of the object by its mass to find the gravitational field strength at the position.
In this question, [tex]\text{weight} = 55.5\; {\rm N}[/tex] while [tex]\text{mass} = 15\; {\rm kg}[/tex]. Therefore, the gravitational field strength will be:
[tex]\begin{aligned} & (\text{gravitational field strength}) \\ =\; & \frac{(\text{weight})}{(\text{mass})} \\ =\; & \frac{55.5\; {\rm N}}{15\; {\rm kg}} \\ =\; & 3.7\; {\rm N \cdot kg^{-1}} \end{aligned}[/tex].
A bullet is fired with an initial velocity of 100 m/s at an angle of 30° from the level ground. Determine the amount of time the bullet spends in the air.
In order to calculate the amount of time, first let's calculate the vertical speed of the bullet:
[tex]\begin{gathered} V_y=V\cdot\sin (\theta) \\ V_y=100\cdot\sin (30\degree) \\ V_y=100\cdot0.5 \\ V_y=50\text{ m/s} \end{gathered}[/tex]Since the displacement of the bullet is zero (it starts from the ground and finishes at the ground), let's use the following formula to find the time:
[tex]\begin{gathered} \Delta S=V_0t+\frac{at^2}{2} \\ 0=50\cdot t+\frac{(-9.8)t^2}{2} \\ 0=50t-4.9t^2 \\ 4.9t^2=50t \\ 4.9t=50 \\ t=\frac{50}{4.9} \\ t=10.2\text{ seconds} \end{gathered}[/tex]A car accelerates uniformly from rest to a speed of 55.0 mi/h in 11.0 s.(a) Find the distance the car travels during this time. m(b) Find the constant acceleration of the car.m/s²
We know that
• The initial speed is zero (it starts from rest).
,• The final speed is 55 mi/h.
,• The time elapsed is 11 seconds.
To find the distance traveled, let's use the following formula.
[tex]v^2_f=v^2_0+2ad[/tex]But first, we have to transform 55 mi/h into m/s. We know that 1 mile is equivalent to 1609.34 meters, and 1 hour is equivalent to 3600 seconds.
[tex]55\cdot\frac{mi}{h}\cdot\frac{1609.34m}{1mi}\cdot\frac{1h}{3600\sec}\approx24.6\cdot\frac{m}{s}[/tex]Then, we find the acceleration because we need it to find the distance traveled.
[tex]\begin{gathered} v_f=v_0+at \\ 24.6\cdot\frac{m}{s}=0+a\cdot11\sec \\ a=\frac{24.6\cdot\frac{m}{s}}{11s} \\ a\approx2.2\cdot\frac{m}{s^2} \end{gathered}[/tex](b) The constant acceleration is 2.2 m/s^2.Now we are able to find the distance traveled.
[tex]\begin{gathered} v^2_f=v^2_0+2ad\to(24.6\cdot\frac{m}{s})^2=0^2+2(2.2\cdot\frac{m}{s^2})d \\ 605.16\cdot\frac{m^2}{s^2}=4.4\cdot\frac{m}{s^2}\cdot d \\ d=\frac{605.16\cdot\frac{m^2}{s^2}}{4.4\cdot\frac{m}{s^2}} \\ d\approx137.5m \end{gathered}[/tex](a) The distance the car travels during this time is 137.5 meters.A car slows down with constant acceleration from a speed of 31 m/s to a speed of 12 m/s over 380 m.
1. what is the value of the acceleration?
2. how long does this take
1 ) The value of the acceleration of the car that slows down constantly from a speed of 31 m/s to a speed of 12 m/s over 380 m = - 1.1 m / s²
2 ) Time taken = 17.67 s
s = ( u + v ) t / 2
s = Displacement
u = Initial velocity
v = Final velocity
t = Time
u = 31 m / s
v = 12 m / s
s = 380 m
380 = ( 31 + 12 ) t / 2
t = 760 / 43
t = 17.67 s
v = u + a t
a = Acceleration
12 = 31 + 17.67 a
a = - 19 / 17.67
a = - 1.1 m / s²
Therefore,
The value of the acceleration = - 1.1 m / s²It takes 17.67 sTo know more about acceleration
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A red stop light has a frequency of 4.40x10^14Hz. Determine the wavelength.
Wavelength and Frequency:
The relationship between wavelength and frequency of light is inversely proportional.
Mathematically,
[tex]\lambda=\frac{c}{f}[/tex]Where λ is the wavelength, f is the frequency, and c is the speed of light.
The speed of light is 3×10⁸ m/s
For the given case, the frequency is 4.40×10¹⁴ Hz
[tex]\lambda=\frac{c}{f}=\frac{3.0\times10^8}{4.40\times10^{14}}=6.81\times10^{-7}\; m[/tex]Therefore, the wavelength of the red stop light is 6.81×10⁻⁷ m
Divers in Acapulco dive from a cliff that is 65 m high. If the rocks below the cliff extend outward for 25 m, how fast must the diver be going when he jumps if he just barely clears the rocks ?
Given,
The height of the cliff, h=65 m
The extension length of the cliff, i.e., the range of the jump, R=25 m
From the equation of motion, the height of the jump is given by,
[tex]h=\frac{1}{2}gt^2[/tex]Where g is the acceleration due to gravity and t is the time of flight of the diver.
On substituting the known values,
[tex]\begin{gathered} 65=\frac{1}{2}\times9.8\times t^2 \\ t=\sqrt[]{\frac{2\times65}{9.8}} \\ =3.64\text{ s} \end{gathered}[/tex]Thus the time of flight of the diver is 3.64 s
The initial velocity of the diver is given by the equation,
[tex]v=\frac{R}{t}[/tex]On substituting the known values,
[tex]\begin{gathered} v=\frac{25}{3.64} \\ =6.87\text{ m/s} \end{gathered}[/tex]Thus the diver has to jump with an initial velocity of 6.87 m/s
1. A charge of −0.0004 C is a distance of 3 meters from a charge of 0.0003 C. What is the magnitude of the force between them?
q1= charge 1 = -0.0004C
q2= charge 2 = 0.0003c
r = distance = 3 m
F = k (q1*q2) / r^2
Where:
F= force
k= constant = 9 x 10^9 kgm^3/s^2m^2
Replacing:
F = 9x10^9 ( -0.0004 * 0.0003 ) / 3^2
F= 120 N
What is the kinetic energy of a car that is traveling at 14.1 m/s if it has a mass of 1487 kg? Submit your answer in exponential form.
ANSWER:
1.48 x 10^5 K
STEP-BY-STEP EXPLANATION:
Given:
Velocity (v) = 14.1 m/s
Mass (m) = 1487 kg
The kinetic energy is calculated using the following formula:
[tex]E=\frac{1}{2}mv^2[/tex]We substitute and determine the value of the energy
[tex]\begin{gathered} E=\frac{1}{2}\cdot1487\cdot\left(14.1\right)^2 \\ \\ E=147815.235=1.48\cdot10^5\text{ J} \end{gathered}[/tex]The kinetic energy is equal to 1.48 x 10^5 joules.
Q3) Find the heat energy required to increase the temperature of 3.5 kg of steel from 500 °C to 600 °C.
Answer:
157.5 KJ
Explanation:of
Specific heat capacity of steel is 450 J/ kg-°C.
So to raise temperature of 3.5 kg of steel from 500°C to 600°C is
= ( 450 * 3.5 * ( 600-500 ) )
= 157500
Nora rides a bicycle for 5 min on a curvy road at a constant speeed of 10 m/s . Describe noras ride in terms of speed , velocity, and acceleration
Given:
The time period for which Nora rides the bicycle, t=5 min
The speed of the bicycle, s=10 m/s
To find:
The description of the ride.
Explanation:
The speed is a scalar quantity and has only magnitude. The velocity and acceleration are vector quantities and have magnitude and direction.
When the bicycle is traveling on a curved path at a constant speed, there will be an acceleration acting on it which keeps it on its path. This acceleration is called the centripetal acceleration.
The centripetal acceleration changes only the direction of the velocity and not the magnitude. Thus the speed will be constant. But the velocity will be changing at a constant acceleration.
How do I solve this? Note, option C is not the answer.
The correct statement is the the acceleration of object 1 is greater than the acceleration of object 2.
What is the velocity time graph?The velocity time graph shows the motion of an object. The velocity is plotted on the vertical axis and the time is plotted on the horizontal axis. We know that the slope of the velocity time graph is the acceleration of the motion.
Let us recall that we would focus our answer on the ideas that can be immediately derived from the graph as we have it in the question. Let us consider the acceleration of object 1 and object 2.
For object 1;
m = y2 - y1/x2 - x1
m = 0 - 40/ 4 - 0
m = - 10 m/s^2
For object 2;
m = y2 - y1/x2 - x1
m = 40 - 0/ 4 - 0
m = 10m/s^2
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What would be the effect of adding a proton to a nucleus?A. It would increase the strong nuclear force and increase theelectrostatic force.B. It would decrease the strong nuclear force and decrease theelectrostatic force.C. It would increase the strong nuclear force and decrease theelectrostatic force.D. It would decrease the strong nuclear force and increase theelectrostatic force.
Adding protons to the nucleus would increase the electrostatic repulsion and increase the strong nuclear force.
Correct option : A
The speed of sound in air is 340 m/s. What is the wavelength of a soundwave that has a frequency of 502 Hz?
The formula for calculating velocity of wave is expressed as
v = fλ
where
v = velocity of the wave
λ = wavelength
f = frequency of the wave
From the information given,
v = 340
f = 502
Substituting these values into the formula, we have
340 = 502λ
Dividing both sides of the equation by 502,
340/502 = 502λ/502
λ = 0.68 m
The wavelength is 0.68 m
During a nascar race a car goes 37 m/s around a curved section of the track that has a radius of 250 m. What is the car's acceleration?
Answer: the car's acceleration is 5.476 m/s^2
Explanation:
We want to calculate the centripetal acceleration of the car. The formula for calculating centripetal acceleration is expressed as
A = V^2/R
where
A = centripetal acceleration
V is the velocity of the car
R is the radius of the car
From the information given,
V = 37 m/s
R = 250m
By substituting these values into the formula,
A = (37 m/s)^2/250m
A = 1369m^2/s^2/250m
A = 1369/250 * m^2/ms^2
the m would cancel out. One m remains in the numerator. Thus,
A = 5.476 m/s^2
the car's acceleration is 5.476 m/s^2
Valeria rolls a 5.0-kg red bocce ball down the lane for the Bocce Ball league championship. One blue ball is in her way and Valeria hits it head-on with a velocity of 9.0 m/s (red ball). Valeria's red ball acquires a new velocity of 7.0 m/s. What is the velocity of the blue bocce ball?
The mass of a bocce ball, m=5.0 kg
The initial velocity of the red ball, u=9.0 m/s
The velocity of the red ball after the collision, v₁=7.0 m/s
The mass of the blue ball will be the same as the red ball. And let us assume that the blue ball will be zero before the collision, i.e., it was at rest before the collision.
From the law of conservation of momentum, the total momentum of a system will always remain constant.
Thus,
[tex]\begin{gathered} mu=mv_1+mv_2 \\ u=v_1+v_2 \end{gathered}[/tex]Where v₂ is the velocity of the blue ball after the collision.
On substituting the known values,
[tex]\begin{gathered} 9.0=7.0+v_2 \\ v_2=9.0-7.0=2.0\text{ m/s} \end{gathered}[/tex]Thus the velocity of the blue ball after the collision is 2.0 m/s.
In addition to the title on the axis, what else must be included so that someone knows how to interpret the graph?
Answer:
Explanation:
Need to scale
Protons have a _____ charge and are held together by ______.
By definition, protons are charged particle with positive charge. Protons are held toguether at the atomic nuclues do the strong nuclear force.
Then, you have:
Protons have a positive charge and are held toguether by the strong nuclear force.
What is the answer? I am trying to do some exercise
Answer:
fourth quadrant.
Explanation:
First, let us see how many 2 pi radians are there in 40 pi /7. The answer is found by dividing 40 pi / 7 by 2 pi
[tex]\frac{40\pi}{7}\div2\pi=\frac{40\pi}{7}\times\frac{1}{2\pi}[/tex][tex]=\frac{40\pi}{7}\times\frac{1}{2\pi}=\frac{20}{7}=2R6[/tex]Meaning ( 40 pi / 7 ) / ( 2pi ) = 2 Remainder 6
Meaning there are 2 complete revolutions in ( 40 pi / 7 ).
How about the revolution that is incomplete?
Now,
[tex]\frac{40\pi}{7}-2(2\pi)=\frac{40}{7}\pi-4\pi[/tex][tex]=\frac{12}{7}\pi[/tex][tex]=1.71\pi[/tex]Which if we plot, looks like
Meaning that 40 pi / 7 lies in the fourth quadrant.
A pulley system gets 80Joules of work after 200Joules of work is put in. What is the efficiency of the pulley system.
ANSWER
[tex]\begin{equation*} 40\% \end{equation*}[/tex]EXPLANATION
The efficiency of the pulley system is given by:
[tex]E=\frac{Output\text{ }work}{Input\text{ }work}*100[/tex]Hence, the efficiency of the pulley system is:
[tex]\begin{gathered} E=\frac{80}{200}*100 \\ E=40\% \end{gathered}[/tex]That is the answer.
how much energy is given to 5 coloumb of charge passing through a 12 voltage battery?
Answer:
V (Joules / Coulomb) definition of voltage
E = Joules energy expressed in Joules
V Q = energy expressed in Joules and Coulombs
E = 12 Joules / Coulomb * 5 Coulomb = 60 Joules
A voltage of 12 V is applied across a circuit with one 3 0hm resistor in series and three 3 Ohm resistors in parallel. What is the total resistance in the circuit? Select one:a.1/3 Ohmsb.9 Ohmsc.3.33 Ohmsd.4 Ohms
ANSWER
d.
EXPLANATION
Let's draw the circuit first,
So, first, we have to solve the parallel,
[tex]R_{parallel}=\frac{1}{\frac{1}{R}+\frac{1}{R}+\frac{1}{R}}=\frac{1}{\frac{1}{3}+\frac{1}{3}+\frac{1}{3}}=\frac{1}{\frac{3}{3}}=1\Omega[/tex]The equivalent resistance is,
[tex]R_{eq}=R_{parallel}+R=1\Omega+3\Omega=4\Omega[/tex]Hence, the total resistance in the circuit is 4 Ohms.
if a mechanic pushes A (0.1M2) with a force of 200N, what will be the pressure? Show your working
Answer:
Explanation:
Given:
A = 0.1 m²
F = 200 N
_________
p - ?
Pressure:
p = F / A
p = 200 / 0.1 = 2 000 Pa
a pole-vaulter runs down a track, plants one end of the pole into the ground, and then jumps in the air while bending the pole. As the pole unbends, it creates force that launches the pole-vaulter up and over the bar using your knowledge of potential and kinetic energy, describe how the pole is like a spring.
When the pole is lifted, it could be able to supply energy to the pole - vaulter much like that of a spring that launches the pole vaulter upwards.
How does the pole vault work?We know that the pole vault is one of the popular sports especially in the Unites States. It is a competition that takes place even at the Olympic level and has a lot of athletes that do compete in the competition.
We know that as the pole unbends, it creates force that launches the pole-vaulter up and over the bar using your knowledge of potential and kinetic energy.
This implies that there are a series of energy conversions that do take place in the pole vault as it is in operation as we can see here. Thus, it is the series of the energy conversions that takes place in the pole vaulting that enables the athlete to be able to launch high in the game as we see.
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A box is lifted to a height of 6 meters in 3 seconds. If the lift required 400 watts of power, what was the weight of the box?200 N250 N300 N350 N
Given:
The height through which the box was lifted, h=6 m
The time it took to lift the box, t=3 s
The power dissipated in lifting the box, P=400 W
To find:
The weight of the box.
Explanation:
The power is described as the time rate of transfer of energy.
Thus the power is given by,
[tex]P=\frac{W}{t}[/tex]Where W is the work done in lifting the box.
The work done is given by,
[tex]W=F\times h[/tex]Where F is the weight of the box.
Thus the power dissipated in lifting the box is given by,
[tex]P=\frac{Fh}{t}[/tex]On substituting the known values,
[tex]\begin{gathered} 400=\frac{F\times6}{3} \\ \Rightarrow F=\frac{400\times3}{6} \\ =200\text{ N} \end{gathered}[/tex]Final answer:
The weight of the box is 200 N
Thus the correct answer is option A.
a 150 N force is used to pull a wooden box across a wooden surface at a constant velocity. what is the mass of the box?
Answer:
The mass of the box:
m = 60 kg
Explanation:
Given:
F = 150 N
g = 10 m/s²
_________
m - ?
Coefficient of friction wood on wood:
μ = 0.25
Friction force:
F₁ = μ*m*g
Newton's Third Law:
F = F₁
F = μ*m*g
The mass of the box:
m = F / ( μ*g) = 150 / (0.25*10) = 60 kg