If each contour line represents 50 meters, what is a reasonable height of the mountain peak in the topographic map? Record your answer and fill in the bubbles on your answer document. Be sure to use the correct

Answers

Answer 1

Answer:

Explanation:

Answer: None of the above I got it right on my test


Related Questions

If energy is conserved, then:
O A. initial (PE + KE) = final (PE + KE).
O B. the initial KE must be zero.
O C. the momentum does not change.
O D. PE(before) = KE(before).

Answers

Answer is A mark me brainliest

If energy is conserved, then initial (PE + KE) = final (PE + KE). So, the correct option is A.

What is meant by Law of Conservation of Energy ?

The law of conservation of energy states that, energy can neither be created nor be destroyed, but can be transformed from one form to another.

Here,

According to law of conservation of energy,

The total energy of an isolated system remains constant. That means, the total energy of the system in the initial state will be same as that in the final state.

The total mechanical energy is the sum of kinetic energy and potential energy.

TE = KE + PE

Therefore, the energy to be conserved in the system,

Initial TE = Final TE

So, Initial (KE + PE) = Final (KE + PE)

Hence,

If energy is conserved, then initial (PE + KE) = final (PE + KE).

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What is the net force acting on a 52 kg object that has a velocity of 8.0 m/s and is moving in a circle of radius 1.6 m? a. 4000N b. 20880N c. 2500N d. 3500N

Answers

Σf = m a
Σf = m v^2 / r
Σf = 52 8^2 / 1.6
Σf = 2080 N
The net force acting of the object will be "2080 N".

Given values are:

Mass, m = 52 kgVelocity, v = 8.0 m/sRadius, r = 1.6 m

As we know the formula,

→ [tex]\Sigma f = ma[/tex]

or,

→ [tex]\Sigma f = \frac{mv^2}{r}[/tex]

By putting the values, we get

         [tex]= \frac{52\times 8^2}{1.6}[/tex]

         [tex]= \frac{52\times 64}{1.6}[/tex]

         [tex]= 2080 \ N[/tex]

Thus the response above is appropriate.

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