If it is known that the cardinality of the set A X A is 16. Then the cardinality of A is: Select one: a. None of them b. 512 c. 81 d. 4 e. 18

Probit coefficients are typically estimated using:

A. the method of maximum likelihood.

The method of maximum likelihood is used to estimate the probit coefficients. This method aims to find the coefficients that maximize the likelihood of observing the given sample data. It involves an iterative process to identify the most likely parameter values for the model, making it suitable for nonlinear models like the probit model. Maximum likelihood estimation is a widely used method in econometric analysis due to its desirable properties, such as consistency and asymptotic efficiency.

In summary, probit coefficients are estimated using the method of maximum likelihood, which provides the most accurate and efficient estimates for this type of model.

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a)An equation of / is y = 2x + 1.

b) The exact length of AC is 2√17.

c) The exact length of BM is √17.

d) The coordinates of B are (5, 4).

(a) Since / is the perpendicular bisector of AC, it passes through the midpoint M of AC. The coordinates of M can be found by taking the average of the x-coordinates and the average of the y-coordinates of A and C, respectively:

x-coordinate of M = (-3 + 5)/2 = 1

y-coordinate of M = (4 + 2)/2 = 3

Therefore, the coordinates of M are (1, 3). Since / is perpendicular to AC, its slope is the negative reciprocal of the slope of AC:

slope of AC = (2 - 4)/(5 - (-3)) = -1/2

slope of / = 2 (negative reciprocal of -1/2)

Using the point-slope form of the equation of a line with the point M, we get:

y - 3 = 2(x - 1)

Simplifying and rearranging, we get:

y = 2x + 1

Therefore, an equation of / is y = 2x + 1.

(b) The length of AC can be found using the distance formula:

AC = √[(5 - (-3))^2 + (2 - 4)^2] = √64 + 4 = √68 = 2√17

Therefore, the exact length of AC is 2√17.

(c) Since BM is a median of triangle ABC, it divides AC into two equal parts. Therefore, BM has length half of AC:

BM = AC/2 = (1/2)(2√17) = √17

Therefore, the exact length of BM is √17.

(d) Since B lies on line /, its x-coordinate is 5 (since / passes through point (5, 2)). To find the y-coordinate, we can substitute x = 5 into the equation of /:

y = 2x + 1 = 2(5) + 1 = 11

Therefore, the coordinates of B are (5, 11).

Alternatively, we can use the fact that B lies on the circumcircle of triangle ABC (since angle ABC is a right angle) to find its coordinates. The circumcenter of triangle ABC is the midpoint of AC (which is also the intersection of the perpendicular bisectors of AC), so the coordinates of the circumcenter are (1, 3). The radius of the circumcircle is half of AC, so it is √17. Therefore, the equation of the circumcircle is:

(x - 1)^2 + (y - 3)^2 = 17

Since B lies on the circumcircle, its coordinates satisfy this equation. Substituting x = 5, we get:

(5 - 1)^2 + (y - 3)^2 = 17

16 + (y - 3)^2 = 17

(y - 3)^2 = 1

y - 3 = ±1

Solving for y, we get y = 2 or y = 4. Since B lies on line /, its y-coordinate must be greater than 2, so y = 4. Therefore, the coordinates of B are (5, 4).

(e) There are two possible positions of B, which are reflections of each other across the line /. One position has coordinates (5, 11), as found in part (d), and the other has coordinates (-3, 2). To find the coordinates of the second position, we can reflect point A across line / to get the point B':

B' has the same x-coordinate as A, which is -3. To find its y-coordinate, we can use the equation

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The surface area of the entire prism is 294 ft².

The surface area of the entire prism can be found by summing the areas of the triangular and rectangular faces of the prism.

Since we have two triangular faces and  3 rectangular faces. Thus,

surface area of the entire prism = 2*( 1/2bh) + 3*(L*W)

where b = 6, h = 4, L = 18 and W = 5

surface area of the entire prism = 2*( 1/2 * 6*4) + 3*(18*5)

surface area of the entire prism = 24  + 270

surface area of the entire prism = 294 ft²

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Answer:

h = -1.25

Step-by-step explanation:

isolate the variable by dividing each side by factors that don't contain the variable.

The area of the triangles are: (a) 8.4 square units. (b) 526.1 square units. (c) 96.7 square units.

(a) Area = (1/2)ab*sin(y)

where y is the angle opposite to side c.

using the law of sines:

b/sin(B) = a/sin(a)

b/sin(16°) = 6/sin(16°)

b = 6*sin(16°)/sin(16°) = 6 units

Now, the sum of the angles in a triangle is 180°:

y = 180° - a - B

y = 180° - 16° - 16°

y = 148°

Finally,

Area = (1/2)66*sin(148°)

Area ≈ 8.4 square units

Therefore, the area of the triangle is approximately 8.4 square units.

(b) using the law of sines:

b/sin(B) = c/sin(y)

b/sin(180°-a-B) = 27.55/sin(56°)

b/sin(76°) = 27.55/sin(56°)

b ≈ 21.94 units

Now,

Area = (1/2)48sin(56°)*21.94/sin(76°)

Area ≈ 526.1 square units (rounded to the nearest tenth)

Therefore, the area of the triangle is approximately 526.1 square units.

(c) using the law of cosines:

b^2 = a^2 + c^2 - 2accos(B)

12.5^2 = 14^2 + c^2 - 214ccos(53°)

c ≈ 13.3 units

Now, the sum of the angles in a triangle is 180°:

y = 180° - a - B

y = 180° - 53° - arcsin(c*sin(53°)/14)

y ≈ 74.8°

Finally,

Area = (1/2)1413.3*sin(74.8°)

Area ≈ 96.7 square units

Therefore, the area of the triangle is approximately 96.7 square units.

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The statement that describe the situation are;

E. While on the first roller coaster, the height switches from positive to negative approximately every 40 seconds,

D.While on the second roller coaster, the height switches every 80 seconds.

Since Function is a type of relation, or rule, that maps one input to specific single output. It is Linear function which is a function whose graph is a straight line

While on the first roller coaster, we can see that the function modeling Michael's height switches from positive to negative approximately every 40 seconds, meaning he changes from being at a height above the platform to below the platform approximately every 40 seconds.

While on the second roller coaster, we can see that this change occurs every 80 seconds.

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a.   (-∞,3) - f(x) is decreasing

   (3,∞) - f(x) is rising.

b. Local minima at x=3. No local Minima

c. The function f(x)=x²-6x is always concave upwards.

d. Concave up and does not change concavity, so, No Inflection points.

f(x)= x²-6x

f'(x) = 2x-6

f"(x) = 2

Critical point f'(x)=0

2x-6=0

x=3

Thus, we have two sub intervals over the entire number line. (-∞,3) , (3,∞)

a) sub-interval      x-value           f'(x)                           verdict

         (-∞,3)                1             2(1)-6=-4<0             f(x) is decreasing  

          (3,∞)                4            2(4)-6=2>0              f(x) is increasing

b) At x=3; Before x=3, f(x) decreasing and after x=3, f(x)

is increasing, thus Local minima at x=3.

No local Minima

c) Since f"(x)=2 Always, the function f(x)=x²-6x is always concave upwards

d) Inflection points

Since graph of function f(x)=x²-6x have only been concave up and does not change concavity,

No Inflection points.

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The missing angle outside the triangle is 137 degrees.

The missing angle in the triangle can be found as follows:

Vertically opposite angles are congruent.

Therefore,

180 - 45  -  60  = (sum of angles in a triangle)

180 - 105 = 75 degrees

Therefore,

180 - 75 - 68 = 37 degrees

Using the exterior angle theorem,

The exterior angle theorem states that the measure of an exterior angle is equal to the sum of the measures of the two remote interior angles of the triangle.

Hence,

let

x = missing angle

100 + 37 = x

x = 137 degrees

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The inverse of matrix A is:

A^-1 = |-3 -2|

|-2 -1|

Using Adjoint of a Matrix A=2 -1 0

0 1 2

1 1 0

The first step is to find the determinant of the matrix A:

|A| = 2(10 - 21) - (-1)(10 - 12) + 0(11 - 10)

= 4 + 2 + 0

= 6

Next, we need to find the adjoint of matrix A, which is the transpose of its cofactor matrix. The cofactor matrix is obtained by taking the determinant of the submatrix obtained by removing each element of the original matrix in turn and multiplying it by (-1)^(i+j), where i and j are the row and column indices of the removed element, respectively.

Cofactor matrix of A is

| 1 2 -1|

|-2 0 2|

|-1 2 1|

Taking the transpose of the cofactor matrix, we get the adjoint matrix of A as follows:

A^T = | 1 -2 -1 |

| 2 0 2 |

|-1 2 1 |

To find the inverse of A, we use the formula:

A^-1 = (1/|A|) A^T

Substituting the values, we get:

A^-1 = (1/6) | 1 -2 -1 |

| 2 0 2 |

|-1 2 1 |

Using Gauss Jordan A= |1 3|

|2 5|

We can find the inverse of a matrix using Gauss-Jordan elimination method as follows:

|1 3|1 0| |1 3|0 1|

|2 5|0 1|-> |0 1|-2/3 -1/3|

Therefore, the inverse of matrix A is:

A^-1 = |-2/3 -1/3|

| 1/3 1/3|

Using Equations and Identity Matrix A= |1 -2|

|2 -3|

We can find the inverse of a matrix A using the equations AX=I, where I is the identity matrix and X is the matrix that represents the inverse of A. The solution is given by:

|1 -2| |x11 x12| |1 0|

|2 -3| |x21 x22| = |0 1|

Multiplying the matrices, we get:

x11 = -3

x12 = -2

x21 = -2

x22 = -1

Therefore, the inverse of matrix A is:

A^-1 = |-3 -2|

|-2 -1|

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To orthogonally diagonalize the matrix A, we will follow these steps:
1. Find the eigenvalues of matrix A.
2. Find the eigenvectors corresponding to each eigenvalue.
3. Normalize the eigenvectors to form an orthogonal basis.
4. Construct the orthogonal matrix Q and the diagonal matrix D.

To orthogonally diagonalize the matrix A, we need to find the eigenvalues and eigenvectors of A.

A = [[3, -1], [-1, 3]]

The characteristic polynomial of A is:

det(A - λI) = det([[3-λ, -1], [-1, 3-λ]]) = (3-λ)² - 1 = λ² - 6λ + 8 = (λ-2)(λ-4)

So the eigenvalues are λ₁ = 2 and λ₂ = 4.

To find the eigenvectors, we need to solve the system of equations:

(A - λ₁I)x = 0 and (A - λ₂I)x = 0

For λ₁ = 2, we have:

(A - 2I)x = [[1, -1], [-1, 1]]x = 0

This system has two linearly independent solutions:

v₁ = [1, 1] and v₂ = [-1, 1]

For λ₂ = 4, we have:

(A - 4I)x = [[-1, -1], [-1, -1]]x = 0

This system has one linearly independent solution:

v₃ = [1, -1]

To orthogonalize the eigenvectors, we need to normalize them and put them as columns of an orthogonal matrix Q.

Q = [[1/√2, -1/√2, 0], [1/√2, 1/√2, 0], [0, 0, 1]]

The diagonal matrix D has the eigenvalues on the diagonal:

D = [[2, 0], [0, 4]]

Finally, we can check that QTAQ = D:

QTAQ = [[1/√2, -1/√2, 0], [1/√2, 1/√2, 0], [0, 0, 1]]T[[3, -1], [-1, 3]][[1/√2, -1/√2, 0], [1/√2, 1/√2, 0], [0, 0, 1]] = [[2, 0, 0], [0, 4, 0], [0, 0, 4]] = D

Therefore, matrix A is orthogonally diagonalized by Q and D.

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The Area of Trapezium is 50, 267 mm².

We have,

base 1 = 224 mm

base 2 = 77 mm

Height = 334 mm

Now, Area of Trapezium

= 1/2 (Sum of parallel side) x height

= 1/2 (224 + 77) x 334

= 1/2 x 301 x 334

= 50, 267 mm²

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a. This is a combination because the order in which the students are chosen does not matter, only the group of four students is selected.
b. There are 4845 different ways that 4 students can be chosen from a group of 20.

a. This is a combination because the order of the chosen students does not matter. In a permutation, the order matters, whereas in a combination, it does not.

b. To find the number of different ways 4 students can be chosen from a group of 20, use the combination formula:

C(n, k) = n! / (k!(n-k)!)

Where n = the total number of students (20), k = the number of students to be chosen (4), and ! denotes factorial.
The number of different ways 4 students can be chosen from a group of 20 can be calculated using the combination formula:

nCr = n! / r!(n-r)!

Where n is the total number of students (20) and r is the number of students being chosen (4).

So,

20C4 = 20! / 4!(20-4)!
C(20, 4) = 20! / (4!(20-4)!)
C(20, 4) = 20! / (4! * 16!)
C(20, 4) = 2,432,902,008,176,640,000 / (24 * 20,922,789,888,000)
C(20, 4) = 4845

There are 4,845 different ways to choose 4 students from a group of 20.

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Answer:

1. D

2.C

3. A

4. B

Step-by-step explanation:

times each of the numbers by however many r in the brackets

3×2=6

3×-1=-3

so the answer to 1 will be (6)

(-3)

There are 181,440 ways to arrange the letters in "competition" with the constraint that "ie" must appear together. This can be answered by the concept of Permutation.

To arrange the letters in the word "competition" with the constraint that "ie" must appear together, first consider "ie" as a single unit.

There are now 10 distinct elements to arrange: C, O, M, P, T, T, I, O, N, and the combined "ie". There are 9! (9 factorial) ways to arrange these elements. However, we need to account for the repetition of the letters O and T, which appear twice each.

To correct for this, divide the total arrangements by the repetitions:

9! / (2! × 2!) = 181,440 ways

So, there are 181,440 ways to arrange the letters in "competition" with the constraint that "ie" must appear together.

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The cash payment equivalent to making monthly payments of $1074 for 5 years with an interest rate of 11% per annum compounded semi-annually is $49,701.

To find the cash payment, we can use the Present Value of the Annuity formula:

PV = PMT * [(1 - (1 + r)⁻ⁿ) / r]

Where:
PV = Present Value (cash payment)
PMT = Monthly payment ($1074)
r = Monthly interest rate
n = Number of payments (5 years * 12 months = 60)

First, we need to find the monthly interest rate. Since the interest is compounded semi-annually, we'll divide the annual interest rate by 2, and then convert it to a monthly rate:

Semi-annual interest rate = 11% / 2 = 5.5% = 0.055
[tex](1 + 0.055)^{(1/6)} - 1[/tex] ≈ 0.008944 (rounded to 6 decimal places)

Now we can plug the values into the Present Value of Annuity formula:

PV = 1074 * [(1 - (1 + 0.008944)⁻⁶⁰) / 0.008944]
PV ≈ 1074 * [1 - (0.5861) / 0.008944]
PV ≈ 1074 * 46.2768
PV ≈ 49,701

The cash payment equivalent is approximately $49,701 (rounded to the nearest dollar).

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(a) There are 8 elements in the power set P(A). (b)There are 9 elements in A X A. (c) There are 512 distinct relations on A.

(a) To find the number of elements in the power set P(A) for a set A with 3 elements, you can use the formula 2^n, where n is the number of elements in A. In this case, n = 3, so the power set P(A) has 2^3 = 8 elements.

(b) To find the number of elements in A X A (the Cartesian product), you simply multiply the number of elements in A by itself. Since A has 3 elements, there are 3 x 3 = 9 elements in A X A.

(c) To find the number of distinct relations on A, you need to calculate the number of subsets of A X A. The number of elements in A X A is 9, so the number of distinct relations on A is equal to the number of elements in the power set of A X A. Using the formula 2^n again, there are 2^9 = 512 distinct relations on A.

In summary:
(a) The power set P(A) has 8 elements.
(b) A X A has 9 elements.
(c) There are 512 distinct relations on A.

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If the price level in Canada falls and the price level in the United States does not change, Canadian-manufactured sofas are relatively less expensive, so Sherri will likely purchase a Canadian manufactured sofa.

This is because the decrease in price level in Canada would make Canadian goods more affordable, including Canadian manufactured sofas. This makes them a more attractive option for Sherri than U.S. manufactured sofas which would still be relatively more expensive even if their price level did not change. Answer D is correct in this scenario. However, if U.S. manufactured sofas were initially more expensive than Canadian sofas, then answer B could also be correct. Overall, Sherri's decision would depend on the initial price difference between Canadian and U.S. manufactured sofas, as well as her personal preferences and any other relevant factors.

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There will be approximately 4621 fish in the lake after 7 months

To solve this problem, we can use the formula for exponential growth:

[tex]N = N0 * (1 + r)^t[/tex]

where N is the final population size, N0 is the initial population size, r is the monthly growth rate (in decimal form), and t is the number of m

onths.

In this case, the monthly growth rate is 6% or 0.06, and the monthly loss rate is 500 fish. So the net monthly growth rate is:

[tex]r_{net}[/tex] = 0.06 - 500/N0

Plugging in the given values, we have:

[tex]r_{net}[/tex]= 0.06 - 500/3500

= 0.0457

Now we can use the formula above to find the population size after 7 months:

[tex]N = 3500 * (1 + 0.0457)^7[/tex]

= 4621.42

So the final population size after 7 months, rounded to the nearest whole number, is:

N ≈ 4621

Therefore, there will be approximately 4621 fish in the lake after 7 months, taking into account both the monthly growth rate and the monthly loss rate.

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The probability P(56< X ≤ 6) is 0.0398. ​To draw a normal curve with the area corresponding to the probability shaded we would shade the area to the right of 56 and to the left of 6 on the curve.

To compute the probability P(56< X ≤ 6), we first need to standardize the values using the formula:
z = (x - μ) / σ
where x is the value we want to find the probability for, μ is the mean, and σ is the standard deviation.

For 56:
z = (56 - 45) / 10 = 1.1

For 6:
z = (6 - 45) / 10 = -3.9

Now, we can look up the probabilities for these values of z in a standard normal distribution table or use a calculator to find the area under the curve between these two values:
P(56< X ≤ 6) = P(1.1 < Z ≤ -3.9)

Using a standard normal distribution table or a calculator, we find that:
P(56< X ≤ 6) = 0.0398 (rounded to four decimal places)

To draw the normal curve with the shaded area corresponding to this probability, we can use a graphing calculator or a standard normal distribution table. The area between 56 and 6 corresponds to the area to the right of 56 minus the area to the right of 6. So, we would shade the area to the right of 56 and to the left of 6 on the curve, which would look like this:
[insert normal curve with shaded area between 56 and 6]

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The answer is not provided in the options given. The closest option is 0.172, but the correct answer is 0.155 (rounded to three decimal places).

To calculate the standard deviation of X, we first need to find the mean or expected value of X. We can do this by integrating the given pdf over the range 0.90 to 1.80:

E(X) = ∫[0.90,1.80] x*f(x) dx

= ∫[0.90,1.80] x*(265/652)*x^3 dx

= (265/652) * ∫[0.90,1.80] x^4 dx

= (265/652) * [x^5/5] from x=0.90 to x=1.80

≈ 1.315

Next, we can calculate the variance of X using the formula:

Var(X) = E(X^2) - [E(X)]^2

To find E(X^2), we integrate the pdf squared over the same range:

E(X^2) = ∫[0.90,1.80] x^2*f(x) dx

= ∫[0.90,1.80] x^2*(265/652)*x^3 dx

= (265/652) * ∫[0.90,1.80] x^5 dx

= (265/652) * [x^6/6] from x=0.90 to x=1.80

≈ 1.464

Var(X) = E(X^2) - [E(X)]^2

≈ 1.464 - 1.315^2

≈ 0.024

Finally, we take the square root of the variance to obtain the standard deviation:

sigma = sqrt(Var(X))

≈ sqrt(0.024)

≈ 0.155

Therefore, the answer is not provided in the options given. The closest option is 0.172, but the correct answer is 0.155 (rounded to three decimal places).

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Answer:  16.8 feet

Note: your teacher may not want you to enter "feet" and instead may just want the number only.

===================================================

Work Shown:

tan(angle) = opposite/adjacent

tan(40) = h/20

20*tan(40) = h

h = 20*tan(40)

h = 16.7819926 which is approximate

h = 16.8

The streetlamp is approximately 16.8 ft tall.

When using your calculator, make sure it's in degree mode. One way to check is to compute something like tan(45) and you should get 1 as a result.

Step-by-step explanation:

The relation R defined as R = {(x,x) : 1 € Z} on Z, where Z is the set of integers, is a relation where an element in Z is related to itself if and only if it is equal to 1.

To determine whether the relation R is reflexive, symmetric, and transitive, we need to consider the properties of relations.

A relation is reflexive if every element in the set is related to itself. In this case, since R contains only pairs of the form (x,x), we can say that R is reflexive if and only if 1 € Z. That is, if and only if 1 is an integer, then R is reflexive. Since 1 is an integer, R is reflexive.

A relation is symmetric if for any two elements (a, b) in the relation, (b, a) is also in the relation. Since R only contains pairs of the form (x,x), it is symmetric if and only if for any integer x, (x,x) is in the relation, then (x,x) is also in the relation. Therefore, R is symmetric.

A relation is transitive if for any three elements (a, b), (b, c) in the relation, (a, c) is also in the relation. In this case, since R only contains pairs of the form (x,x), we can say that R is transitive if and only if for any integers x, y, z such that (x, y) and (y, z) are in R, then (x, z) is also in R. However, since there are no pairs (x, y) and (y, z) in R except for when x=y=z=1, there are no pairs (x, z) in R for which transitivity needs to be checked. Therefore, we can say that R is transitive vacuously.

In conclusion, the relation R defined as R = {(x,x) : 1 € Z} on Z is reflexive, symmetric, and transitive.

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[tex]$f(x) = q_a$[/tex] for all [tex]$x \in (a-1, a+1)$[/tex]. Since a was arbitrary, it follows that f is constant on any open interval. Since f is continuous, it follows that f is constant on [tex]$\mathbb{R}$[/tex].

Let a be any real number in R. Since f is continuous, the intermediate value theorem implies that the image of any closed interval under f is also an interval. Therefore, [tex]$f([a-1, a+1])$[/tex] is an interval in [tex]$\mathbb{Q}$[/tex]. Since the only intervals in [tex]$\mathbb{Q}$[/tex] are single points, [tex]$f([a-1, a+1]) = {q_a}$[/tex] for some rational number [tex]$q_a$[/tex].

Now let b be any real number with [tex]$b > a+1$[/tex]. By the intermediate value theorem, there exists some [tex]$x \in [a, b]$[/tex] such that [tex]$f(x) = \frac{q_a+q_b}{2}$[/tex]. But since f takes only rational values, [tex]$f(x) = q_a$[/tex]. This argument applies to all real numbers b with [tex]$b > a+1$[/tex], so [tex]$f(x) = q_a$[/tex] for all [tex]$x > a+1$[/tex]. Similarly, we can show that [tex]$f(x) = q_a$[/tex] for all [tex]$x < a-1$[/tex].

Therefore, [tex]$f(x) = q_a$[/tex] for all [tex]$x \in (a-1, a+1)$[/tex]. Since a was arbitrary, it follows that f is constant on any open interval. Since f is continuous, it follows that f is constant on [tex]$\mathbb{R}$[/tex].

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The size of the angle X is calculated to be equal to 47.4° to the nearest tenth of degree using trigonometric ratios cosine

The trigonometric ratios is concerned with the relationship of an angle of a right-angled triangle to ratios of two side lengths.

The basic trigonometric ratios includes;

sine, cosine and tangent.

Given the triangle STU;

cos X = ST/SU {adjacent/hypotenuse}

cos X = 8.8/13

X = cos⁻¹(8.8/13) {cross multiplication}

X = 47.3963°

Therefore, the measure of the angle X is calculated to be equal to 47.4° to the nearest tenth of degree using trigonometric ratios cosine

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The given equation is a constant function with a horizontal line passing through (0, 1). Here option E is the correct answer.

The given equation, f(x) = 1, represents a constant function, where the output or value of the function is always equal to 1 for any input value of x. This is a special case of a linear function, where the slope is zero and the y-intercept is a non-zero constant value.

Among the four given options, none of them is a constant function. A reciprocal function, y = 1/x, has a variable slope and a vertical asymptote at x = 0. A square root function, y = √x, has a non-linear shape and a domain of x ≥ 0. An absolute value function, y = |x|, has a V-shaped graph and is symmetric around the y-axis. A cube root function, y = ∛x, is also non-linear and has a domain of all real numbers.

Therefore, the correct answer is not listed among the options, and the function f(x) = 1 does not belong to any of the parent functions mentioned. It is a simple constant function with a horizontal line as its graph, passing through the point (0, 1) on the y-axis.

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Complete question:

Which type of parent function does the equation f(x) = 1 represent?

A. Reciprocal

B. Square root

C. Absolute value

D. Cube root

E. None of these

The surface area of the tissue box is 240 cm².

Option B is the correct answer.

We have,

The tissue box can be considered a triangular prism.

The formula for the surface area of the tissue box can be made as:

The perimeter of the triangular base x height of the box.

Now,

Perimeter

= 8 + 6 + 10

= 24 cm

And,

The surface area of the tissue box.

= 24 x 10

= 240 cm²

Thus,

The surface area of the tissue box is240 cm².

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Answer:

63 mph

Step-by-step explanation:

10.5 × 6 is 63

you multiply by the fraction of the hour so you can get how fast the car is going in miles per an hour

Answer:

The average speed of the car = 63miles per hour

Step-by-step explanation:

Given, the total distance traveled by the car= 10.5 miles

total time is taken by the car to cover 10.5 miles = 1/6 hour

formula to calculate average speed

average speed = total distance/total time

average speed = 10.5/(1/6)

                          = 10.5×6

                          = 63 miles per hour

therefore, the average speed of the car is 63 miles per hour

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The distance from y to W is sqrt(10), which is the exact answer using radicals.

Let's start by finding the projection of y onto the subspace W spanned by v1 and v2. The projection of y onto W is given by:

projW(y) = ((y · v1)/||v1||^2)v1 + ((y · v2)/||v2||^2)v2

where · denotes the dot product and || || denotes the norm or length of a vector.

Using the given information, we have:

v1 = [1 0 1 0], v2 = [0 1 0 1], and y = [2 4 0 0]

We can calculate the dot products and norms as follows:

||v1||^2 = 1^2 + 0^2 + 1^2 + 0^2 = 2

||v2||^2 = 0^2 + 1^2 + 0^2 + 1^2 = 2

y · v1 = 2(1) + 4(0) + 0(1) + 0(0) = 2

y · v2 = 2(0) + 4(1) + 0(0) + 0(1) = 4

Therefore, the projection of y onto W is:

projW(y) = ((2/2)[1 0 1 0]) + ((4/2)[0 1 0 1])

= [1 0 1 0] + [0 2 0 2]

= [1 2 1 2]

The closest point to y in W is the projection projW(y), so we have:

v = [1 2 1 2]

The distance from y to W is the length of the vector y - v, which we can calculate as:

||y - v|| = ||[2 4 0 0] - [1 2 1 2]||

= ||[1 2 -1 -2]||

= sqrt(1^2 + 2^2 + (-1)^2 + (-2)^2)

= sqrt(10)

Therefore, the distance from y to W is sqrt(10), which is the exact answer using radicals.

Complete question: Let [tex]$y=\left[\begin{array}{r}13 \\ -1 \\ 1 \\ 2\end{array}\right], y_1=\left[\begin{array}{r}1 \\ 1 \\ -1 \\ -2\end{array}\right]$[/tex], and [tex]$v_2=\left[\begin{array}{l}5 \\ 1 \\ 0 \\ 3\end{array}\right]$[/tex] . Find the distance from y to the subspace W of [tex]$\mathrm{R}^4$[/tex] spanned by [tex]$v_1$[/tex] and [tex]$v_2$[/tex], given that the closest point to [tex]$y$[/tex] in [tex]$W$[/tex] is [tex]$\hat{y}=\left[\begin{array}{r}11 \\ 3 \\ -1 \\ 4\end{array}\right]$[/tex].

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Answer:

I beleive c. i had the same question last year, and i believe i got the answer right. so sorry if its wrong. hope this helps.

Step-by-step explanation: