If m2 DOC = 44º and m2 COB = 80°,
find the measure of the indicated arc in circle 0.
Find measure of arc DC.

Answer:

below

Step-by-step explanation:

that is the solution above

Answer:

(x - 2)/3

(x - 4)/-5 or (-x + 4)/5

Step-by-step explanation:

this is an inverse function, and to solve an inverse function you would :

swap x and g(x) without bringing the x coefficient with it, just simply swap the variables. Then, solve for g(x), and that's it

the first question's answer is :

g(x) = 3x + 2

x = 3(g(x)) + 2

x - 2 = 3(g(x))

(x - 2)/3 = g(x)

the second one is:

g(x) = 4 - 5x

x = 4 - 5(g(x))

x - 4 = -5(g(x))

(x-4)/-5 = g(x)

g(x) = 3x + 2

y = 3x + 2

x = 3y + 2

3y = x - 2

y = x/3 - 2/3

inverse g(x) = (x - 2) / 3

g(x) = 4 - 5x

y = 4 - 5x

x = 4 - 5y

5y = 4 - x

y = 4/5 - x/5

inverse g(x) = (4 - x) / 5

9514 1404 393

Answer:

  (x/y)^(m+n)

Step-by-step explanation:

  [tex]\displaystyle\frac{\left(x+\frac{1}{y}\right)^m\left(x-\frac{1}{y}\right)^n}{\left(y+\frac{1}{x}\right)^m\left(y-\frac{1}{x}\right)^n}=\left(\frac{x}{y}\right)^m\left(\frac{x}{y}\right)^n\\\\=\boxed{\left(\frac{x}{y}\right)^{m+n}}[/tex]

Answer:

135.7 yd²

Step-by-step explanation:

Surface area of the cone,

πr²+πrl

= π×3²+π×11.4×3

= 43.2π

= 135.7 yd² (rounded to the nearest tenth)

Answer:

Reject the null hypothesis because the value of null is outside the interval.

Step-by-step explanation:

Null hypothesis is a statement that is to be tested against the alternative hypothesis and then decision is taken whether to accept or reject the null hypothesis. The null hypothesis is rejected or accepted on the basis of level of significance. When the p-value Test statistics is greater than level of significance we fail to reject the null hypothesis and null hypothesis is then accepted. In the given case p-value is less than critical value then we should reject the null hypothesis.

Answer:

$0.75

Step-by-step explanation:

Given that

Number of bags of popcorn bought = 4

Total money spent = $3.00

To find:

Unit rate per bag of popcorn = ?

i.e. price of one bag of popcorn is to be find out.

Solution:

We can use ratio here to find the rate of one bag of popcorn.

4 bags bought at $3

4 bags : $3

Let us divide both the sides with 4.

[tex]\frac{4}4[/tex] bags : $ [tex]\frac{3}4[/tex]

OR

1 bag bought at $ 0.75

We can alternatively use unitary method.

4 bags are bought at $ 3

1 bag is bought at $ [tex]\frac{3}{4}[/tex]

1 bag is bought at $0.75.

So, unit rate per bag of popcorn is $0.75.

Step-by-step explanation:

cost of 5 pen is Rs 1200,

cost of 1 pen is 1200/5 = Rs 240

Answer:

Rs 240

Step-by-step explanation:

1200÷5=240

Answer:

[tex]y = 7 - 7x \\ y + 7x = 7 \\ 7x + y = 7[/tex]

Answer:

7x + y = 7

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = 7 - 7x ( add 7x to both sides )

7x + y = 7 ← in standard form

Answer:

The hypotenuse is the longest side in a triangle.

a^2=b^2+c^2.

14^2=9^2+c^2.

c^2=196-81.

c^2=115.

c=√115.

c=10.72~11cm

Answer:

B, C, and D........................

Answer:

well all of these look like a way so we have to use elimination method

A : random number tables : well it has random numbers so X out

B: PHONE NUMBERS: well phone numbers are random so X out

C: USing the internet : totally X out

D: books of random numbers: X out

so none of the above i guess

The only way that might not be used in generating random numbers is : (B). using phone numbers selected at random in a local phone book

Random numbers are numbers that occurs randomly without prediction. these numbers are impossible to predict using past values.

Random numbers are important for computer encryption and lotteries.

In conclusion, The only way that might not be used in generating random numbers is using phone numbers selected at random in a local phone book

Learn more about random numbers: https://brainly.com/question/10352102

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Answer: a. [tex]2.02\times10^6\ m[/tex]

b. [tex]9.901\times10^6\ m/s[/tex]

c. [tex]3.02\times10 ^{-3}\ km[/tex]

d. [tex]1.1\times10^{-3}\ mm[/tex]

Step-by-step explanation:

Scientific notation is a technique to express a very big or a very small number in the product of a decimal form of number ( between 1 and 10) and powers of 10.

a.  [tex]2,020,000 m\ = 2.02\times1,000,000=2.02\times10^6\ m[/tex]

b. [tex]9,901,000\ m/s =9.901\times1000000=9.901\times10^6\ m/s[/tex]

c. [tex]0.003020\ km=\dfrac{3020}{1000000}[/tex]

[tex]=3.02\times10 ^{-3}\ km[/tex]

d. [tex]0.001100\ mm=\dfrac{1100}{1000000}=\dfrac{11}{10000}[/tex]

[tex]1.1\times10^{-3}\ mm[/tex]

Answer:

−8x3−1

Step-by-step explanation:

let's simplify step-by-step.

3−8x3−4

=3+−8x3+−4

Combine Like Terms:

=3+−8x3+−4

=(−8x3)+(3+−4)

=−8x3+−1

Answer:

-1 - (2x^3)^3

Step-by-step explanation:

The equation is:

=> 3 - 8x^3 - 4

=> -1 - 8x^3

=> -1 - (2x^3)^3

Answer:

[tex]a_n = 8 + (n - 1) (-6)[/tex]

Step-by-step explanation:

Given

[tex]a_1 = 8[/tex]

Recursive: [tex]a_{n} = a_{n-1} - 6[/tex]

Required

Determine the formula

Substitute 2 for n to determine [tex]a_2[/tex]

[tex]a_{2} = a_{2-1} - 6[/tex]

[tex]a_{2} = a_{1} - 6[/tex]

Substitute [tex]a_1 = 8[/tex]

[tex]a_2 = 8 - 6[/tex]

[tex]a_2 = 2[/tex]

Next is to determine the common difference, d;

[tex]d = a_2 - a_1[/tex]

[tex]d = 2 - 8[/tex]

[tex]d = -6[/tex]

The nth term of an arithmetic sequence is calculated as

[tex]a_n = a_1 + (n - 1)d[/tex]

Substitute [tex]a_1 = 8[/tex] and [tex]d = -6[/tex]

[tex]a_n = a_1 + (n - 1)d[/tex]

[tex]a_n = 8 + (n - 1) (-6)[/tex]

Hence, the nth term of the sequence can be calculated using[tex]a_n = 8 + (n - 1) (-6)[/tex]

-4x^2-28x-68

hope this helped!

Step-by-step explanation:

Hello, there!!!

The answer is: -4x^2-28x-68.

See explanation in picture.

Hope it helps...

Equation:- 2y-x=10

For L to intersects Y axis then X cordinate must be zero

so put value of X as zero (0)

2y=10

So Y cordinate is equal to 5

Cordinate:- (0,5)

Answer:

The  p-value is  [tex]p-value = 0.62578[/tex]

Step-by-step explanation:

From the question we are told that    

    The  sample size of male infant is  [tex]n_1 = 12[/tex]

     The  sample size of female infant is [tex]n_2= 9[/tex]

     The sample mean of male infant is  [tex]\= x_1 = 7.70 \ lb[/tex]

      The sample mean of female infant is  [tex]\= x_2 = 7.80 \ lb[/tex]

     The population standard deviation is  [tex]\sigma = 0.5[/tex]

       The significance level is  [tex]\alpha = 0.05[/tex]

The null hypothesis is  [tex]H_o : \mu_ 1 = \mu_2[/tex]

The  alternative hypothesis is  [tex]H_1 : \mu_1 > \mu_2[/tex]

The  test statistics is mathematically represented as

            [tex]t =\frac{\= x_1 - \= x_2 }{\sqrt{\frac{\sigma }{n_1} } + \frac{\sigma }{n_2} } }[/tex]

=>          [tex]t = \frac{7.70 -7.80}{\sqrt{\frac{0.5 }{12} } + \frac{0.5 }{9} } }[/tex]

=>        [tex]t = -0.3207[/tex]

From the z-table  the p-value is  obtained, the value is  

     [tex]p-value = P(Z > -0.3207) = 0.62578[/tex]

     [tex]p-value = 0.62578[/tex]

Answer:

8

Step-by-step explanation:

Hello,

[tex]x=3y^2<=>y=\sqrt{\dfrac{x}{3}} \ \ for \ x\geq 0[/tex]

And for y = 2, x = 3 * 2 * 2 = 12 so first, let's compute

[tex]\displaystyle \int\limits^{12}_0 {\sqrt{\dfrac{x}{3}}} \, dx =\dfrac{1}{\sqrt{3}} \int\limits^{12}_0 {\sqrt{x}} \, dx\\\\=\dfrac{1}{\sqrt{3}} \left[ \dfrac{2}{3}x^{3/2}\right]_0^{12}\\\\=\dfrac{1}{\sqrt{3}} *\dfrac{2}{3}*12*\sqrt{12}\\\\=\dfrac{2*12*2*\sqrt{3}}{3*\sqrt{3}}\\\\=2*4*2=16[/tex]

The area which is asked is 12*2 - 16 = 24 - 16 = 8

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Using integrals, it is found that the area of the region enclosed by the curves in the interval is of 27 units squared.

In this problem:

Then, the integral for the area is:

[tex]A = \int_{0}^{2} 3y^2 dy[/tex]

[tex]A = y^3|_{y = 0}^{y = 3}[/tex]

[tex]A = 3^3 - 0^3[/tex]

[tex]A = 27[/tex]

The area of the region enclosed by the curves in the interval is of 27 units squared.

You can learn more about the use of integrals to calculate an area at https://brainly.com/question/15127807

Answer:

Solution : y = 4x - 8

Step-by-step explanation:

The first thing we want to do is isolate t², rather than t. Why? As you can see when we substitute t² into the second equation, it will be easier than substituting t, as t is present in the form t². So, let's isolate t² in the first equation --- ( 1 )

x = t² + 2,

t² = x - 2

Now let's substitute this value of t² in the second equation --- ( 2 )

y = 4t²,

y = 4(x - 2),

y = 4x - 8 ~ And hence our solution is option c.

Answer:

65 ft

Step-by-step explanation:

The area of a rectangle is

A = lw

6045 = 93*w

Divide each side by 93

6045/93 = 93w/93

65 =w

Answer:

[tex]\huge \boxed{\mathrm{65 \ feet}}[/tex]

Step-by-step explanation:

The area of a rectangle formula is given as,

[tex]\mathrm{area = length \times width}[/tex]

The area and length are given.

[tex]6045=93 \times w[/tex]

Solve for w.

Divide both sides by 93.

[tex]65=w[/tex]

The width of the rectangular garden is 65 feet.

[tex]\\ \sf\longmapsto \dfrac{5x+3}{7x+3}=\dfrac{3}{4}[/tex]

[tex]\\ \sf\longmapsto 4(5x+3)=3(7x+3)[/tex]

[tex]\\ \sf\longmapsto 20x+12=21x+9[/tex]

[tex]\\ \sf\longmapsto 12-9=21x-20x[/tex]

[tex]\\ \sf\longmapsto x=3[/tex]

[tex]\large\rm \longrightarrow \: {\purple{ \frac{(5x + 3)}{(7x + 3)} \: = \: \frac{3}{4} }} \\ [/tex]

⇛ Now , Cross Multiplying

[tex]\large\rm \longrightarrow \: {\blue{ 4 \: (5x + 3) \: = \: 3 \: (7x + 3)}}[/tex]

[tex]\large\rm \longrightarrow \: {\red{ 20x \: + \: 3 \: = \: 21 \: + \: 3}}[/tex]

[tex]\large\rm \longrightarrow \: {\orange{ 12 \: - \: 9 \: = \: 21x \: - \: 20x }}[/tex]

[tex]\large\rm \longrightarrow \:{\green{ 3 \: = \: x}}[/tex]

⇛ Hence , the value of x is 3

Answer:

there is a 20% chance of getting a red marble

Step-by-step explanation:

Answer:

there is a 1/5 percent chance or 20%

Step-by-step explanation:

Hope this helps!

answer:

2 on the picture is the amplitude

He must do a 8,00,000 sales to make total of 75000 for the year.

For salesman base salary = 35000, Salary to be atained is 75000. Having commission of 5% on every sales. Sales to be determine so the salesman attained 75000 for year.

In mathematics it deals with numbers of operations according to the statements.

Here, according to the statement.
Let x be sales,
35,000 + 5%x = 75,000
0.05x = 75000-35000
x = 40000/0.05
x = 8,00,000

Thus, he must do a 8,00,000 sales to make total of 75000 for the year

Learn more about arithmetic here:

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Answer:

16. f(y-2) = 2(y-2)²-5

= 2(y²-4y+4)-5

= 2y²-8y+8-5

= 2y²-8y+3

17. f(a+h)-f(a) = 2(a+h)²-5-(2a²-5)

= 2(a²+2ah+h²)-5-2a²+5

= 2a²+4ah+h²-2a²

= h²+4ah

Answer:

The previous palindrome date in all formats came 909 years ago on 11/11/1111. The next will come in 101 years on 12/12/2121 and after that there will not be another until 03/03/3030.

It depends how you format the date. If you do mm/dd/yyyy format

mm = month

dd = day

yyyy = year

then the last palindromic date was September 10th, 2019 since this would be written as 9/10/2019 in the mm/dd/yyyy format

Taking out the slash symbols, we have the number 9102019 which is the same when we reverse the digits.

The answer will be different if you have the date format as dd/mm/yyyy

Answer:

600

Step-by-step explanation:

[tex]p(x) = 1 + 6x - 5x^2[/tex]

x max = [tex]-b/2a[/tex]

a = -5

b = 6

-6/2(-5) = 6/10 = 3/5 = .6

.6 thousand = 600

600 speakers should be sold.

Alternatively, you can check the vertex of the parabola formed.

Answer:

2,200

Step-by-step explanation:

6.6 x 10^10

= 66,000,000,000

3 x 10^7

= 30,000,000

66,000,000,000 ÷ 30,000,000

2,200

Answer:

2200.

Step-by-step explanation:

6.6 / 3  *  10^10/10^7

= 2.2 * 10^3

= 2200

Answer:

a.

[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]

[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]

[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]

b.

[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]

Step-by-step explanation:

Given that:

C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)

a. Find a piecewise smooth parametrization of the path C.

r(t) = { 0

If C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1),

Then:

[tex]C_1 = (0,0) \\ \\ C_2 = (1,0) \\ \\ C_3 = (0,1)[/tex]

Also:

[tex]\mathtt{r_1 = (0,0) + t(1,0) = (t,0) }[/tex]

[tex]\mathbf{r_1 = (t,0) \implies t = 0 \ to \ 1}[/tex]

[tex]\mathtt{r_2 = (1,0) + t(-1,1) = (1- t,t) }[/tex]

[tex]\mathbf{r_2 = (2-t,t-1) \implies t = 1 \ to \ 2}[/tex]

[tex]\mathtt{r_3 = (0,1) + t(0,-1) = (0,1-t) }[/tex]

[tex]\mathbf{r_3 = (0,3-t) \implies t = 2 \ to \ 3}[/tex]

b Evaluate :

Integral of (x+2y^1/2)ds

[tex]\mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \int \limits ^1_{0} \ (t + 0) \sqrt{1} } \\ \\ \mathtt{ \int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \begin {pmatrix} \dfrac{t^2}{2} \end {pmatrix} }^1_0 \\ \\ \mathtt{\int \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \dfrac{1}{2}}[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits (x+2 \sqrt{y} \sqrt{(\dfrac{dx}{dt})^2 + (\dfrac{dy}{dt})^2 \ dt } }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \int \limits 2- t + 2\sqrt{t-1} \ \sqrt{1+1} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} \int \limits^2_1 2- t + 2\sqrt{t-1} \ dt }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2t - \dfrac{t^2}{2}+ \dfrac{2(t-1)^{3/2}}{3} (2) \end {pmatrix} ^2_1}[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{1}{2} (4-1)+\dfrac{4}{3} (1)^{3/2} -0 \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} 2 -\dfrac{3}{2} + \dfrac{4}{3} \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{12-9+8}{6} \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \sqrt{2} } \ \begin {pmatrix} \dfrac{11}{6} \end {pmatrix} }[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ \sqrt{2} }{6} \ (11 )}[/tex]

[tex]\mathtt{\int \limits _{c2} (x+ 2 \sqrt{y}) ds = \dfrac{ 11 \sqrt{2} }{6}}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 0+2 \sqrt{3-t} \ \sqrt{0+1} }[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits ^3_2 2 \sqrt{3-t} \ dt}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \int \limits^3_2 \begin {pmatrix} \dfrac{-2(3-t)^{3/2}}{3} (2) \end {pmatrix}^3_2 }[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [(0)-(1)]}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [-(1)]}[/tex]

[tex]\mathtt{\int \limits _{c3} (x+ 2 \sqrt{y}) ds = \dfrac{4}{3}}[/tex]

[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}}{6}+\dfrac{1}{2}+ \dfrac{4}{3}}[/tex]

[tex]\mathtt{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+3+8}{6}}[/tex]

[tex]\mathbf{\int \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}[/tex]