if predators and habitat do not change, which shade of frogs will have the greatest fitness

She need to release the cluch slowly and apply force on the accelator other than place her vehicle's gear in Drive and accelerate

We drive a car by applying pressure on the accelator, remove foot from the brakes and releasing cluch slowly. When the vehicle get speed, we have to change the gear.

So we can conclude that She need to release the cluch slowly and apply force on the accelator for driving a car.

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The speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.

The speed of the sound wave can be determined by applying echo formula as shown below;

v = 2d/t

where;

Substitute the given parameters and solve for speed.

v = (2 x 1.2)/(0.00695

v = 345.32 m/s

Thus, the speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.

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Answer:

what are your answer choices if you have any?

Explanation:

(my ask question thingy isnt working)

Answer:

m = 100 kg

Explanation:

F = ma

120 = m × 1.2

m = 120 ÷ 1.2

m = 100 kg

Answer:

the answer is. C.

Explanation:

[tex] 0.36 \times 30 = 10.8[/tex]

the solution

For a photon with wavelength 11. 0 nm,  the side length LL of the box is mathematically given as

L=1.414*10^{-27}m

Generally, the equation for the change in energy is mathematically given as

[tex]dE=\frac{hc}{\lambda}[/tex]

Therefore

[tex]\frac{hc}{\lambda}=\frac{6h^2}{8ml}\\\\L=\sqrt{6h\lambda}{8mc}\\\\L=\sqrt{\frac{6(6.626*10^{-34})*11.0*10^{-9}}{8(9.11*10^31)(3*10^8)}}[/tex]

L=1.414*10^{-27}m

In conclusion,  the side length LL of the box is

L=1.414*10^{-27}m

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The side length of the box for a photon of wavelength 11. 0 nm will be [tex]\rm L = 1.414 \times 10^{-27}[/tex] m.

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The change in the energy of the photon is found as;

[tex]\rm dE = \frac{hc}{\lambda} \\\\ \frac{hc}{\lambda} =\frac{6h^2}{8ml} \\\\ L= \sqrt{\frac{6h\lambda}{8mc} } \\\\ L = \sqrt{\frac{6 \times 6.626 \times 10^{-34}\times 11 \times 10^{-9}}{8 \times 9.11 \times 10^{31} \times 3 \times10^8} } \\\\ L= 1.414 \times 10^{-27} \ m[/tex]

Hence  the side length of the box for a photon of wavelength 11. 0 nm will be [tex]\rm L = 1.414 \times 10^{-27}[/tex] m.

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Explanation:

The metre is currently defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second.

Hope it helps

Have a great day

TC

:DD

Answer:

At position "B" the northern hemisphere is tilted the most from the earth-sun direction and will experience the shortest hours of daylight, (and also the most indirect sun rays).

Explanation:

formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.

The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

Given data :

Distance of star from earth = 4.3 light years

Observers time = 3.7 years

Observers time = 3.7 * 365 * 24 * 60 * 60

Distance of star from earth = 4.3 * 9.46 * 10¹⁵

The velocity the spacecraft must travel will be calculated using the equation

V = distance / time

   = ( 4.3 * 9.46 * 10¹⁵ ) / ( 3.7 * 365 * 24 * 60 * 60 )

   = 3.49 * 10⁸ m/s

Hence we can conclude that The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

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Attached below is the missing detail related to the question

The constant velocity must the spacecraft travels from the earth will be 3.49×10⁸ m/sec.

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Distance of earth from stars = 4.3 light year

The given time = 3.7 year

One year converted into the second as;

[tex]\rm 1 \ year = 3.7 \times 365 \ days \ \times 24 \ hour \times 60 \ minute \times 60 \ sec \\\\ 1 year = 116 \times 10^6 \ sec[/tex]

1 light-year into a kilometer as;

[tex]\rm 4.3 \ light year = 4.3 \times 9.46 \times 10^{15 metre} \\\\[/tex]

At what constant velocity must a spacecraft travel from the earth if it is to reach the star in 3. 7 years,

The velocity of the spacecraft's travel from the earth will be;

[tex]\rm V = \frac{d}{t} \\\\ V= \frac{4.3 \times 9.46 \times 10^{15}}{3.7 \times 365 \times 24 \times 60 \times 60 } \\\\\ V= 3.49 \times 10^8 \ m/sec[/tex]

Hence the constant velocity must the spacecraft travels from the earth will be  3.49×10⁸ m/sec.

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Answer:

0.142 m/s

Explanation:

You solve it by conservation of momentum.

Before the impact the total momentum is, considering right the positive direction,

[tex]m_1v_1+m_2v_2 =6\cdot10^-^3\times 40.4\ kg\cdot m/s + 1.7\times 0 \ kg\cdot m/s =242.4\cdot 10^-^3\ kg\cdot m/s[/tex]

After the impact, we have a single body of mass [tex]m_1+m_2[/tex] and thus a single value of speed, V.

[tex](m_1+m_2)V =1.703 kg \cdot V[/tex]

Since no external forces are applied, the two quantities are equal after the impact. That allows us to solve for V

[tex]V= (242.4\cdot10^-^3 \ kg\cdot m/s )\div (1.703\ kg)=142.337\cdot10^-^3 m/s = 0.142 m/s[/tex]

Answer: Mass Number

Explanation:

Atomic number is the number of just protons;

Nuclear Model is a theoretical description of what an atom looks like;

Energy levels are the energy states that electrons are in;

However, mass number is by definition the number of protons + number of neutrons. :)

The student's claim did not follow the scientific method of discovery, hence, it is an opinion not a scientific claim.

The scientific method is a procedure employed by scientific towards understanding the world around them as well giving explanation for phenomena in the natural world.

The scientific method involves:

Since the student in question just put forward an opinion without testing it out using the scientific method, the statement is not a scientific claim.

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A star will ultimately become a black hole when it collapses due to end of fuel.

When a star burns through the last of its fuel, the object may collapse, or fall into itself. For smaller stars which are about three times the sun's mass, the new core will become a white dwarf but when a larger star collapses, it turns into a black hole.

So we can can conclude that a star will ultimately become a black hole when it collapses due to end of fuel.

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Answer:

d (density) = M / V

V = M / d = 500 kg / (11400 kg / m^2 = .044 m^3

Let's see

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{4}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi\dfrac{2}{\sqrt{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=\dfrac{4\pi}{\sqrt{g}}[/tex]

So

[tex]\\ \rm\rightarrowtail g=\dfrac{16\pi ^2}{T^2}[/tex]

Answer:

g' = 1.09 m/s²

T = 12 s

Explanation:

Gravity due to acceleration

Time period

The main environmental effects of ozone depletion could include the following:

Ozone depletion is the gradual thinning of the ozone layer in the upper atmosphere as a result of the relelase of chemical compounds or gases.

Ozone layer helps prevent the Earth surface against incoming ultraviolet radiations that could cause damage to our environment.

Therefore, the main environmental effects of ozone depletion could include the following:

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The following are some of the primary environmental implications of ozone depletion and increased risk of skin cancer, sunburns, rapid aging, and the immune system being weakened.

The progressive weakening of the ozone layer in the upper atmosphere as a result of the release of chemical compounds or gases is known as ozone depletion.

The ozone layer protects the Earth's surface from harmful UV rays that may harm our environment. As a result, the primary environmental effects of ozone depletion could include:

1. An increased risk of skin cancer

2. Sunburns

3. Rapid aging

4. The immune system is weakened.

Hence increased risk of skin cancer is the main environmental effect of ozone depletion.

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Answer:B

Explanation:  

A has about 248 hp  but B has about 683 hp. 2016 is younger too. good day

a) The frequency of the wave is 4.0 Hz

b) The period T of the wave is 0.25s

c) The speed of the wave is 12m/s

Given the data in the question;

Frequency is simply the number of occurrences of a repeating phenomenon per unit time.

Period is the time needed for a complete cycle of vibration to pass a given point.

It is expressed as;

[tex]T = \frac{1}{f}[/tex]

Where f is the frequency

Speed is simply the distance traveled in a given interval of time or time ratio.

It is expressed as;

[tex]v = \lambda * f[/tex]

Where [tex]\lambda[/tex] is wavelength and f is frequency

a) Frequency

We said frequency is the number of occurrences of a repeating phenomenon per unit time.

Since the wave oscillates 4.0 times a second

Hence, the frequency of the wave is 4.0 Hz

b) Period

[tex]Period\ T = \frac{1}{f} \\\\Period\ T = \frac{1}{4.0Hz}\\\\Period\ T = \frac{1}{4.0s^{-1}}\\\\Period\ T = 0.25s[/tex]

Therefore, the period T of the wave is 0.25s

c) Speed

[tex]v = \lambda * f\\\\v = 3.0m * 4.0Hz\\\\v = 3.0m * 4.0s^{-1}\\\\v = 12ms^{-1}\\\\v = 12m/s[/tex]

Therefore the speed of the wave is 12m/s.

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The rotational inertia about an axis tangent to the sphere of the given mass and radius is ⁷/₅MR².

According to parallel axis theorem, the moment of inertia of a body about any axis is equal to the sum of the product of its mass and the square of the distance between the two parallel axis and the moment of inertia of the body about a parallel axis passing through its centre of mass.

The moment of inertia of the sphere about its parallel axis passing through its centre of mass = ²/₅MR²

The product of its mass and the square of the distance between the two parallel axis = MR²

Moment of inertia about an axis tangent to the sphere = MR² + ²/₅MR²

                                                                                           = ⁷/₅MR²

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The rotational inertia of a sphere of given mass and radius along a tangent axis is [tex]\rm \frac{7}{5} MR^2[/tex].

The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.

The given data in the problem is;

M is the sphere's mass.

R is the radius of a sphere

According to the parallel axis theorem,The rotational inertia of a sphere of given mass and radius along a tangent axis is found as;

[tex]\rm I=MR^2+\frac{2}{5} MR^2 \\\\ I=\frac{7}{5} MR^2[/tex]

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Let's look at relationship

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}[/tex]

[tex]\\ \rm\rightarrowtail T\propto \sqrt{m}[/tex]

Hence

[tex]\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}[/tex]

[tex]\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}[/tex]

[tex]\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}[/tex]

[tex]\\ \rm\rightarrowtail m_2=0.889[/tex]

Hence

Answer

Mass needs to added =0.889-0.500=0.389kg

Explanation:

Magnetic circuit, closed path to which a magnetic field, represented as lines of magnetic flux, is confined.

In contrast to an electric circuit through which electric charge flows, nothing actually flows in a magnetic circuit.

Explanation:

Hope it helps you (`▿▿▿▿´ƪ)

The orientation with the largest magnetic torque on the dipole is Orientation B (See attached image).

The torque on the dipole is defined as:

τ = µ×B,

where B is the external magnetic field.

The magnitude of this torque is µB sinθ, where θ is the angle between B and µ

Magnetic Torque is highest when;

→     →

µ ⊥ β

That is when θ  = 90°. Hence B is the correct answer. Please see attached image.

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Answer:

b

Explanation:

Answer:

M = 328.70g

Explanation:

From the given values:

V = 346 cm³

M of 1 cm³ of Polythene = 0.95g or 95/100g

Solve:

M = (95×346)

10

= 32870

100

M = 328.70g

Answer:

0.40s. He's dead, Jim.

Explanation:

The block accelerates at a rate of [tex]9.81 ms^-^2[/tex]. The moment it's 14 meters from the ground, it has traveled 39 meters, in about [tex]39=\frac12(9.81)t^2 \rightarrow 2.82 s[/tex].

For the man to dodge, the time left is the distance the block takes to go down to 2 meters from ground, or 51 meters from its starting point. Which translates in [tex]51=\frac12(9.81)t^2\rightarrow 3.22s[/tex]

He has thus less than half a second ([tex]0.40s[/tex] to be exact) to dodge.

Answer:

Each body spray cost $ 21.25

Explanation:

Answer:

Because Geography says the higher one goes the colder it gets

Answer:

The nature of convection.

Explanation:

Warm air rises; cold air falls, so the freezer at the top provides cold air for the other compartments at the bottom.

Answer:Cars enter a car wash at a mean rate of 4 cars per half an hour. 

Explanation:

The probability that, in any hour, exactly 22 cars will enter the car wash will be 0.0920.

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1.

Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

The  mean rate of car is,[tex]\rm \lambda = 66 \ car/hour[/tex]

[tex]P(x=K) = \frac{8^k e^{-8}}{k\!}\\\\P(x=22) = \frac{66^{22} e^{-22}}{22\!}\\\\ P(x=22)=\frac{0.000000000000691\times 1.07\times 10^{40}}{22} \\\\\ P(x=22)=0[/tex]

Hence the probability that, in any hour, exactly 22 cars will enter the car wash will be 0

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For a  flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω, the rate of energy being delivered is mathematically given as

P= 53 W

Generally, the equation for the Battery power  is mathematically given as

P = I (dt)V

Therefore

P= 2.50 A * 21.2V

P= 53 W

In conclusion, rate of energy being delivered

P= 53 W

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A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0.The power developed will be 53 Watt.

Electric power is the product of the voltage and current. Its unit is the watt. It is the rate of the electric work done.

The given data in the problem is;

V is the voltage = 21.2 volt (V)

I is the electric current = 2.50 ampere (A)

The formula for the power is given as;

[tex]\rm P= V I \\\\\ P= 2.50 \times 21.2 \\\\ P=53 \ watt[/tex]

Hence electric power developed will be 53 Watts.

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