If RS = 7, ST = 3x, and RT = x + 9, what is RT?

The students and courses have one to many relationship.

A one to many relationship is such kind of relation which exist when a particular function is linked to many other functions. It means that many elements of the set A is related to a single element of the set B.

In this case, the course is only one but the students studying the course are more in number. The same course is studied by many student but in different manner but the course is same. This is why we conclude that the relationship between the students and the course is one to many.

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The inequality to represent the perimeter of the triangle is given by (2n + 3) + (2n + 2) + n ≤ 30

Side a + side b + side c ≤ perimeter of the triangle

(2n + 3) + (2n + 2) + n ≤ 30

2n + 3 + 2n + 2 + n ≤ 30

5n + 5 ≤ 30

substract 5 from both sides

5n ≤ 30 - 5

5n ≤ 25

n ≤ 25/5

n ≤ 5 cm

The largest possible lengths of the sides is:

Side a = (2n + 3)cm

= 2(5) + 3

= 10 + 3

= 13 cm

Side b = (2n + 2) cm

= 2(5) + 2

= 10 + 2

= 12 cm

Side c = n cm

= 5 cm

So therefore, the largest possible length of the triangle is 13 cm

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The number of centimeter cubes to be added to make the cuboid is; 30 cubes.

From the given plan, side elevation and front elevation, we can see that the number of cubes needed to make the shape is 18 blocks.

From the front elevation, 12 blocks is required (4 * 3 blocks).

From the side elevation, 6 blocks are required which gives us a total of 18 blocks.

The number of blocks needed to make the given cuboid is;

Volume of cuboid = 4 * 4 * 3 = 48 cm cubes.

Therefore the number of cubes to be added = Volume cubes - Number of cubes from elevation

The number of cubes to be added = 48 cubes - 18 cubes

The number of cubes to be added = 30 cubes.

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For the given triangles ΔTRS and ΔQRP , the required step to prove both the triangles are congruent is ∠TRS ≅ ∠QRP.

As given in the question,

Two triangles ΔTRS and ΔQRP,

It is given that :

Line segment SR ≅ Line segment PR

Line segment SP bisects Line segment TQ

⇒ line segment TR ≅ line segment RQ

∠TRS ≅ ∠PRQ ( by vertically opposite angle )

By Side angle side theorem we have ,

ΔTRS ≅ ΔPRQ

Therefore, for the given triangles ΔTRS and ΔQRP ,the required step to prove both the triangles are congruent is ∠TRS ≅ ∠QRP.

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The value of their horizontal change is 2.7 feet

The equation of the function is given as

y = -8/3x + 40

From the question, the distance travelled by the rider is given as

Distance = 8 feet downward

This means that

Horizontal change = slope

A linear equation is represented as

y = mx + c

Where

Slope = m

By comparing y = mx + c and y = -8/3x + 40, we have

Slope = m = 8/3

This gives

Horizontal change = 8/3

Evaluate

Horizontal change = 2.7

Hence, the horizontal change is 2.7 feet

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The speed of the wind is 50 mile per hour  .

In the question ,

it is given that

the speed of the plane is [tex]=[/tex] 200 miles per hour .

let the speed of the wind is = "w"

So ,the speed of the plane with wind is [tex]=[/tex] 200 + w

and the speed of the plane against  wind is [tex]=[/tex] 200 - w

we know that , distance [tex]=[/tex] speed × time

the plane flew "500 miles" with wind ,

which means ,

500 [tex]=[/tex] (200 + w) × t      .....(1)

and the plane flew 300 miles against the wind ,

which means ,

300 [tex]=[/tex] (200 - w) × t       ......(2)

adding both the equations ,

we get

800 [tex]=[/tex] t ( 200 [tex]+[/tex] w [tex]+[/tex] 200 - w)

800 = t × 400

t = 2

Substituting  , t = 2 in 500 [tex]=[/tex] (200 + w) × t      

we get

500 = (200 + w) × 2

500/2 = 200 + w

250 = 200 + w

w = 250 - 200

w = 50

Therefore , The speed of the wind is 50 mile per hour  .

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Answer:

  27

Step-by-step explanation:

You want a 2-digit number that is 3 times the sum of its digits, where the units digit is 5 more than the tens digit.

Let t represent the tens digit. Then the units digit is (t+5) and the sum of digits is ...

  t +(t +5) = 2t+5

The value of the number is ...

  10t +(t+5) = 11t +5

The value is 3 times the sum of digits, so we have ...

  11t +5 = 3(2t +5)

  11t +5 = 6t +15

  5t = 10 . . . . . . . . . . subtract (6t+5)

  t = 2

  (t+5) = 7

The number is 27.

The simplified form of the given expression; negative 1 and 2 over 3 minus 9 and 2 over 5 as required is; -166/15 (negative 166 over 15).

It follows from the task content that the simplified form of the given expression is to be determined.

Since the given expression is; -1 ⅔ - 9 ⅖.

First, the mixed numbers as in the task content must be converted to fractions so that we have;

- 1 ⅔ = -5/3 and

9 ⅖ = 47/5

Therefore, the required evaluation is; -5/3 - 47/5

= -25/15 - 141/15

= (-25 - 141) / 15

= -166/15

Therefore, the required simplified form of the expression is; negative 166 over 15.

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Answer:

X=

Step-by-step explanation:

Let's solve your equation step-by-step.

2x−84=108x

Step 1: Subtract 108x from both sides.

2x−84−108x=108x−108x

−106x−84=0

Step 2: Add 84 to both sides.

−106x−84+84=0+84

−106x=84

Step 3: Divide both sides by -106.

−106x

−106

=

84/−106x=−42/53

The value of side AC is AC = 3.

What is right triangle?

A right triangle, also known as a right-angled triangle, an orthogonal triangle, or historically a rectangled triangle, is a triangle with one right angle, meaning that its two sides are perpendicular. Trigonometry's foundation is the relationship between the right triangle's sides and other angles.

The given triangle  ΔABC is a right angled triangle.

So, to find the side AC we can use the cosine ratio,

[tex]cosB = \frac{Adjacent side}{Hypotenuse}\\ cos65 = \frac{AC}{AB} \\cos65 = \frac{AC}{7} \\AC = 7(c0s(65)\\AC = 7(0.4226)\\AC = 2.9583[/tex]

AC ≈ 3.

Hence, the length of side AC is 3.

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The standard deviation and variance of the distribution's 96% confidence intervals are 9.841 and 5.704, respectively.

A normal distribution sample of size 50 has an expected higher rate of 20 and a sample mean of 5.

n = 50 makes up the sample size.

Furthermore, the sample variance is s² = 20

The following is the formula for both the variance confidence interval:

σ² = [tex](\frac{(n-1)s^2}{X^2_{{n-1};{1-\alpha /2}}}, \frac{(n-1)s^2}{X^2_{{n-1};{\alpha/2}}})[/tex]

Here, [tex]{X^2_{{n-1};{1-\alpha /2}}}[/tex] is the critical value at the status of significance [tex]\alpha[/tex] & degree of freedom n - 1.

The 90% confidence interval's lower bound for variance is stated as,

[tex]\frac{(n-1)s^2}{ {X^2_{{49};{0.95}}}}[/tex] = (49 × 20) ÷ (30.114)

= 32.54

The 90% confidence interval's upper bound for variance is stated as,

[tex]\frac{(n-1)s^2}{ {X^2_{{49};{0.95}}}}[/tex] = (49 × 20) ÷ (10.117)

= 96.86

Consequently, the confidence level for the distribution's variance is (96.86, 32.54).

Additionally, the range of the distribution's standard deviation inside the 90% confidence interval is (√96.86, √32.54), that's the same as (9.841, 5.704).

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The addition of the decimals given as 3.8 and 2.7 will be 6.5.

Decimals simply means the numbers that are not whole numbers. They consist of whole numbers and fractions. Examples include 3.6, 2.1 eyc.

In this case, we want to find the value of 3.8 and the addition to 2.7. This will be:

= 3.8 + 2.7

= 6.5

Therefore, the value is 6.5.

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Answer:

See below

Step-by-step explanation:

Horizontal lines have ZERO slope

Vertical lines have 'undefined' slope

for this example  x = 1/2    includes the point and has undiefined slope

The property that is used to multiply two binomials (3x+5)(2x+7)=2x(3x+5)+7(3x+5) is distributive property.

In this question we have been given an expression.

We need to identify the property that is used to multiply two binomials.

(3x+5)(2x+7)=2x(3x+5)+7(3x+5)

Consider two binomials,

(3x+5)(2x+7)

= (2x+7)(3x+5)                     ...............(commutative property)

= 2x(3x+5)+7(3x+5)            ................(distributive property)

Therefore, the property that is used to multiply two binomials (3x+5)(2x+7)=2x(3x+5)+7(3x+5) is distributive property.

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Triangle ADC and ΔBDC are congruent.     then DE ≅ CE

What do you mean by congruent?

Given,

        AD ≅ BC

      ∠BCD ≅ ∠ADC

In triangle ADC and ΔBDC

                    AD ≅ BC    ( GIVEN )

      ∠BCD ≅ ∠ADC          ( GIVEN )

             DC = DC             ( Common line)

so  triangle ADC and ΔBDC are congruent.

             then DE ≅ CE

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Option A: Multiply the top equation by 3, multiply the bottom equation by -2, then add the equations will eliminate the variables.

Rewriting the equation -

2x + 8y = -3 : Equation 1

3x + 6y = -4 : Equation 2

Multiplying equation 1 with and equation 2 with -2.

6x + 24y = -9 : Equation 3

-6x - 12y = 24 : Equation 4

Adding the equation 3 and equation 4. This will eliminate the variable x.

12y = 15

y = 5/4

So, option 1 will eliminate the variable x on solving we get the value of y as 5/4.

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The interquartile range of the reaction times is 0.528 or 52.80%

A normal model is represented as (μ, σ). Therefore for (1.5, 0.18), the mean (μ) = 1.5 and the standard deviation (σ) = 0.18

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

The z score shows by how many standard deviations the raw score is above or below the mean. It is given as:

The interquartile range is x = 1.45 and x = 1.75

For x = 1.45

[tex]Z=\frac{X-\mu}{\sigma}[/tex]

Z=(1.45-1.5)/0.18

 = -0.28

For x = 1.75

Z=(1.75-1.5)/0.18

 = -1.39

From the normal distribution table,

P(1.45 < x < 1.75) = P(-0.28 < z < 1.39)

                            = P(z < 1.39) - P(z< - 0.28)

                            = 0.9177 - 0.3897

                           = 0.528

                          = 52.8%

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The triangle with vertices (−2, 1), (1, 1), and (1, 0) is similar to

This is a term used in geometry to mean that the respective sides of the triangles are proportional and the corresponding angles of the triangles are congruent

Hence assuming the corresponding angles of the triangle are congruent then the side should be in proportions.

Examining the vertices shows that; Triangle W with vertices (−4, 2), (2, 2), and (2, 0) is in proportion to the given vertices (−2, 1), (1, 1), and (1, 0)

The difference is a scale factor of 2

(−2, 1) * 2 =  (−4, 2)

(1, 1) * 2 = (2, 2)

(1, 0) * 2 = (2, 0)

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Answer:

-3.5

Step-by-step explanation:

-4x-1+1≤ 13+1

-4x/-4 ≤ 14/-4

x≤ -3.5

8 is the  sum of the exponents of the prime factors of the square root of the largest perfect square that divides 12!

We are asked the sum of the exponents of the prime factors of the square root of the largest perfect square that divides 12!.

As, the largest perfect square that divides 12! is

2^10 * 3^4 *5^2 = 2073600.

Now, the square root of the number 2073600 is,

1440

Now, we have to find the prime factorization of 1440

1440 = 2×2×2×2×2×3×3×5

Now, in the prime factorization of 1440

the exponent of 2 is 5, exponent of 3 is 2 and the exponent of 5 is 1.

So, the sum of the exponents of the prime factors be 5+2+1 = 8

Hence, 8 is the  sum of the exponents of the prime factors of the square root of the largest perfect square that divides 12!

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The number of donuts that can be purchased for $10 is 20.

The total cost of Mrs. Goodwin's donut purchase varies directly with the number of donuts purchased. The total cost of 15 donuts was $7.5. We need to find out the number of donuts that can be purchased for $10.

Let the number of donuts, price, and constant of proportionality be represented by the variables "n", "p", and "k", respectively.

The price is directly proportional to the number of donuts purchased.

p ∝ n

We will remove the proportionality sign.

p = k*n

7.5 = k*15

k = 1/2

The equation is p = (1/2)n. We will now calculate the number of donuts that can be purchased for $10.

p = (1/2)n

10 = (1/2)n

n = 10*2

n = 20

Hence, the number of donuts that can be purchased for $10 is 20.

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The solution is 1790 grams

The amount of bismuth left after 10 days if the half life is 5 days will be

1790 grams

What is half-life of an element?

The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay. The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.

Half-life (symbol t½) is the time required for a quantity (of substance) to reduce to half of its initial value

The decay constant λ is = 0.693/t½

where t½ is the half-life of the element

Given data ,

Let the half life of the element be represented as t½

The value of t½ = 5 days

Now , the initial amount of bismuth N₀ = 7160 grams

The number of days t = 10 days

The amount of bismuth left after 10 days = N( t )

Now , the value of N( t ) is given by the formula ,

N( t ) = N₀ ( 1/2 )^ t/ t½

Substituting the values in the equation , we get

N( t ) = 7160 ( 1/2 )^10/5

N( t ) = 7160 ( 1/2 )²

N( t ) = 7160 / 4

N( t ) = 1790 grams

Therefore , the value of N( t ) is 1790 grams

Hence , the amount of bismuth left is 1790 grams

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The mean will be the middle number or 12.1.

According to our question-

The median is the middle number  in the data set when the data set is written from least to greatest.

least to greatest 4.8, 6.9, 12.1, 14.8, 16.2

Hence, The mean will be the middle number or 12.1.

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The different ways of solving percent increase or percent decrease problems has been described below

What is percentage?

Suppose there is a number and the number has to be expressed as a fraction of 100. The fraction is called percentage.

One way to solve the percentage increase or decrease problem is by multiplying the original number by the percentage given and then adding the result with the original number.

Another method is by multiplier method

Here, the original number is taken as 1 and the given percentage has to be converted to decimal and then  1 and the percentage obtained as decimal is added or subtracted. The result obtained has to be multiplied by the original number to get the required number after increase or decrease

For the first method

Suppose the number is n and it is increased by p%

Required result is

[tex]n + \frac{p}{100}\times n\\n( 1 + \frac{p}{100})[/tex]

For the second method

Suppose the number is n and it is increased by p%

Here n is taken as 1 and p% is converted to decimal

then 1 and p% in decimal form is added

we get (1 + 0._p)

Now the result is obtained is multiplied by n

Required result is

n(1 + 0._p)

[tex]n(1 + \frac{p}{100})[/tex]

In this way the two methods are related

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The equations that can be used to solve for y, the length of the room

First and foremost, we can begin solving this equation by noting the formula for calculating the area of a rectangle. This formula is given as follows:

Area of a rectangle = Length × Width

Since the width of the room is 5 feet less than the length of the room, we will have the resulting equation as the area of the rectangle:

y( y - 5) = 750

When this equation is fully expressed, we will get the following equations:

Therefore, options, B, C, and E are correct.

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Answer:

17

Step-by-step explanation:

4x-10=58(alternate interior angles)

4x=68

x=17

The analyst should use the alpha aesthetic. The alpha aesthetic makes some points on a plot more transparent than others to call out specific data points.

A set of points plotted on a horizontal and vertical axis is known as a scatter plot. Because they can demonstrate the degree of correlation, if any, between the values of observed quantities or phenomena, scatter plots are crucial in statistics (called variables). In an effort to demonstrate the degree to which one variable is influenced by another, scatter plots are used to plot data points on a horizontal and vertical axis. The values of the columns set on the X and Y axes determine the position of the marker that represents each row in the data table.

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Answer:

4/7

Step-by-step explanation:

32:56

32÷2=16

56÷2=28

16:28

16÷2=8

28÷2=14

8:14

8÷2=4

14÷2=7

4:7

32:56 ~ 32/56

=4/7