If the domain (or pre-image) of a function that is translated up 5 is (-1, 8), (-2,4), (-1, -7), what is
the range (or image)?

Answer:

y = 12

Step-by-step explanation:

y = kx

-4 = k * 2

k = -4/2 = -2

y = -2x

y = -2 * (-6)

y = 12

Answer:

t + 25 = 26

t = 26 - 25

t = 1

I hope it's helps you

Answer: C=5

Hope this helps!

Answer:

okkkkkkk ty for he points

Step-by-step explanation:

Answer:

Ty

Step-by-step explanation:

Answer:

c is the right answer

Step-by-step explanation:

Answer: Pythagorean theroem

Step-by-step explanation:

The easiest method to use in terms of a missing side as long as you know at least two other variables whether its another side or angle

Answer:

David can run 28.7 miles in 3.5 hours.

Step-by-step explanation:

8.2mph × 3.5hours = 28.7miles

good luck, i hope this helps :)

Answer: 17 pounds

Step-by-step explanation:

Answer:

I think 4.32...............

Answer(s):

[tex]\displaystyle y = 4cos\:(2x - \frac{\pi}{2}) - 1 \\ y = 4sin\:2x - 1[/tex]

Explanation:

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{\pi}{4}} \hookrightarrow \frac{\frac{\pi}{2}}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

OR

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 4[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 4cos\:2x - 1,[/tex] in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex] which means the C-term will be positive, and perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{\frac{\pi}{4}} = \frac{\frac{\pi}{2}}{2}.[/tex] So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2cos\:(2x - \frac{\pi}{2}) - 1.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\frac{\pi}{4}, -5],[/tex] from there to [tex]\displaystyle [\frac{3}{4}\pi, -5],[/tex] they are obviously [tex]\displaystyle \pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -1,[/tex] in which each crest is extended four units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

setup below, you'll have to do the final calculation

Step-by-step explanation:

first perform the operation in parenthesis

2+39= 41

then do the multiplication 3 x 41

in general do calculations in this order

1. Parenthesis

2. Multiplication

3. Division

4. Addition

5. Subtraction

working from left to right

Answer:

Fahad is taller with 31 centimeters

Step-by-step explanation:

1090mm=109cm

Fahad is taller than Fareed by 31 centimeters.

1090 mm = 109 cm

140 cm - 109 cm = 31 cm

Hope this helps; please mark brainliest!

Have an amazing day!

Answer:

x-intercept: -4

y-intercept: 24/5

Step-by-step explanation:

Firstly you have to isolate the y:

-6x + 5y = 24

5y = 6x + 24

y = (6x +24)/5

Now, just think about the graph: when the function touch the x-axis, the value of y is equal to 0, and when the function touch the y-axis, the value of x is 0, so just put they in the function:

y = (6•0 + 24)/5

y = 24/5

0 = (6x + 24)/5

5•0 = 6x +24

0 = 6x +24

-6x = 24

x = 24/-6

x = -4

Answer:

Step-by-step explanation:

Area of triangle with angle of 30°:

[tex]A_1=\frac12\cdot 5^2\cdot\sin(30^o)=\dfrac{25}4=6.25[/tex]

Area of triangle with angle of 50°:

[tex]A_2=\frac12\cdot 5^2\cdot\sin(50^o)=\dfrac{25}2\cdot0.766=9.575[/tex]

Area of the rest of the figure:

[tex]A_3=\dfrac{(360-30-50)^o}{360^o}\cdot\pi\cdot5^2=\dfrac79\cdot\pi\cdot25 =61.087[/tex]

Therefore:

                  [tex]A=A_1+A_2+A_3=6.25+9.575+61.087=76.912[/tex]

Answer:

stocks, bonds, mutual funds, and collectables

Step-by-step explanation:

Answer:   1132.616

lol-

Answer:5 3/20

Step-by-step explanation:

6 8/20 0- 1 5/20= 5 3/20

Answer:

(Choice A) A More rainfall relates to more mosquitoes, as long as rainfall is less than 2 cm²

Step-by-step explanation:

The given function for the number of mosquitoes, (by analysis of the options) is, g(x) = 4·x - x²

Where;

x = The amount of rainfall

g(x) = The number of mosquitoes in millions

The given function can be expressed as follows;

g(x) = 4·x - x² + 0

The maximum point is given by g'(x) = d(4·x - x²)/dx = 4 - 2·x = 0

At the maximum (turning point), we have;

4 - 2·x = 0

4 = 2·x

x = 4/2 = 2

The level of rainfall that gives the maximum number of mosquitoes is, x = 2 cm²

The number of mosquitoes increases from zero rainfall up to the maximum number of 4 million mosquitoes at 2 cm² rainfall and then decreases to zero as the rainfall increases further more than 2 cm², as shown in the attached  graph of the function g(x) that models the number of mosquitoes created with MS Excel

Therefore, the true statement is (Choice A) more rainfall relates to more mosquitoes, as long as (the level of) rainfall is less than (the maximum) 2 cm².

Answer:

a: 8.2

b:11.2

A: 37

Answer:

B = 49.1°

C = 93.9°

c = 77.9

Step-by-step explanation:

Given:

a = 47, b = 59, and A = 37°

Required:

B, C, and c

Solution:

✔️To find B, apply the law of sines:

[tex] \frac{sin(A)}{a} = \frac{sin(B)}{b} [/tex]

Plug in the values

[tex] \frac{sin(37)}{47} = \frac{sin(B)}{59} [/tex]

Cross multiply

[tex] 47*sin(B) = sin(37)*59 [/tex]

Divide both sides by 47

[tex] \frac{47*sin(B)}{47} = \frac{sin(37)*59}{47} [/tex]

[tex] sin(B) = 0.7555 [/tex]

[tex] B = sin^{-1}(0.7555) [/tex]

[tex] B = sin^{-1}(0.7555) [/tex]

B = 49.0690779° ≈ 49.1° (nearest tenth)

✔️C = 180° - (A + B) (sum of triangle)

C = 180° - (37° + 49.1°)

C = 93.9°

✔️To find c, apply the law of sines:

[tex] \frac{sin(B)}{b} = \frac{sin(C)}{c} [/tex]

Plug in the values

[tex] \frac{sin(49.1)}{59} = \frac{sin(93.9)}{c} [/tex]

Cross multiply

[tex] c*sin(49.1) = sin(93.9)*59 [/tex]

Divide both sides by sin(49.1)

[tex] c = \frac{sin(93.9)*59}{sin(49.1)} [/tex]

c = 77.8766982

c ≈ 77.9 (nearest tenth)

Answer:

$250....................

Answer:

tysm!!

Step-by-step explanation:

[tex]have[/tex]  [tex]a[/tex]  [tex]great[/tex]  [tex]day[/tex] [tex]:)[/tex]

AAAAAAA THANK YOU :D

Answer:

I think 12 * 12/ 60 = ?

12*12= 144

144/ 60= ?

Answer:

360°

Step-by-step explanation:

I think

1/2 base ×height

1/2×60×12

30×12

=360

Answer:

1) 2 nonreal complex roots

2) 1 Real Solution

3) 16

4) Reflected, narrower by a factor of 2/5, slides right 4 units and slides up 6 (units)

Step-by-step explanation:

1) The graph does not intercept the x-axis, therefore, there are no real solutions at the point y = 0

We get;

y = a·x² + b·x + c

At y = 6, x = -2

Therefore;

6 = a·(-2)² - 2·b + c = 4·a - 2·b + c

6 = 4·a - 2·b + c...(1)

At y = 8, x = 0

8 = a·(0)² + b·0 + c

∴ c = 8...(2)

Similarly, we have;

At y = 8, x = -4

8 = a·(-4)² - 4·b + c = 16·a - 4·b + 8

16·a - 4·b = 0

∴ b = 16·a/4 = 4·a

b = 4·a...(3)

From equation (1), (2) and (3), we have;

6 = 4·a - 2·b + c

∴ 6 = b - 2·b + 8 = -b + 8

6 - 8 = -b

∴ -b = -2

b = 2

b = 4·a

∴ a = b/4 = 2/4 = 1/2

The equation is therefor;

y = (1/2)·x² + 2·x + 8

Solving we get;

x = (-2 ± √(2² - 4 × (1/2) × 8))/(2 × (1/2))

x =( -2 ± √(-12))/1 = -2 ± √(-12)

Therefore, we have;

2 nonreal complex roots

2) Give that the graph of the function touches the x-axis once, we have;

1 Real Solution

3) The given function is f(x) = 2·x² + 8·x + 6

The general form of the quadratic function is f(x) = a·x² + b·x + c

Comparing, we have;

a = 2, b = 8, c = 6

The discriminant of the function, D = b² - 4·a·c, therefore, for the function, we have;

D = 8² - 4 × 2 × 6 = 16

The discriminant of the function, D = 16

4.) The given function is g(x) = (-2/5)·(x - 4)² + 6

The parent function of a quadratic equation is y = x²

A vertical translation is given by the following equation;

y = f(x) + b

A horizontal to the right by 'a' translation is given by an equation of the form; y = f(x - a)

A vertical reflection is given by an equation of the form; y = -f(x) = -x²

A narrowing is given by an equation of the form; y = b·f(x), where b < 1

Therefore, the transformations of g(x) from the parent function are;

g(x) is a reflection of the parent function, with the graph of g(x) being narrower by 2/5 than the graph of the parent function. The graph of g(x) is shifted right by 4 units and is then slides up by 6 units.

Answer:

The distance from the base of the building to the base of the ladder is 13.56 feet.

Step-by-step explanation:

This can be solved using Pythagorus theorem.

If the length of the ladder is taken as the hypotenuse and the distance from the building as the base of the triangle then the altitude can be found out by using

c²= a²+b²

Where c is the hypotenuse and b is the base and a is the altitude

Putting the values

25²= a²+ 21²

a²= 25²-21²

a²= 625-441

a²= 184

a= √184= 13.56 feet

The distance from the base of the building to the base of the ladder is 13.56 feet

Answer:

70

Step-by-step explanation:

(Not the most streamlined way but.)

Knowing that if he had 5 tests, and a mark of 85, we can determine the total average grade Bill received. 85*5=425

Then subtract the known grades

425-(90+85+100+80)=x

425-(355)=x

70=x

Bill would have scored 70 on that 5th test