Answer:
The appropriate alternative is option C "[tex]5.09\times 10^{14} \ s[/tex]".
Explanation:
The given value is:
Energy of photon,
E = [tex]3.37\times 10^{-19} \ J[/tex]
As we know,
h = [tex]6.626\times 10^{-34} \ Js[/tex]
Now,
The frequency of the light will be:
⇒ [tex]E=hv[/tex]
On substituting the given values, we get
⇒ [tex]3.37\times 10^{-19}=6.626\times 10^{-34}\times v[/tex]
On solving, we get
⇒ [tex]v=5.09\times 10^{14} \ s[/tex]
If the energy of a photon of light is 3.37 x 10⁻¹⁹ J, then the frequency of the light is 5.09 x 10¹⁴ per sec.
How we calculate frequency?Frequency of light will be calculated by using the below formula:
E = hυ, where
E = energy of photon = 3.37 x 10⁻¹⁹ J
h = plank's constant = 6.626 × 10⁻³⁴ Js
Putting these values on the above equation and calculate for the frequency as:
υ = 3.37 x 10⁻¹⁹ J / 6.626 × 10⁻³⁴ Js = 5.09 x 10¹⁴ per sec
Hence, option (C) is correct i.e. 5.09 x 10¹⁴ per sec.
To know more about frequency, visit the below link:
https://brainly.com/question/254161
Write the formulas for the following ionic compounds.
potassium iodide
magnesium phosphide
silver sulphide
iron(III) bromide
magnesium hydroxide
sodium sulphate
lead (IV) nitrate
ammonium carbonate
Answer:
1) KI
2) Mg3P2
3) Ag2S
4) FeBr3
5) Mg(OH)2
6) Na2SO4
7) Pb(NO3)4
8) (NH4)2CO3
PLEASEEEE HELP URGENTTTT
Answer:
i don't see the question
Explanation:
Why does air with higher amounts of water vapor have a lighter density?
Answer:
moist air is less dense than dry air because water has a lower molecular weight than nitrogen and oxygen
Answer:
Water vapor is a relatively light gas when compared to diatomic Oxygen and diatomic Nitrogen. Thus, when water vapor increases, the amount of Oxygen and Nitrogen decrease per unit volume and thus density decreases because mass is decreasing.