If the frequency of wave is 400 Hz and its wavelength is 2.5 m,
what is the velocity?

Answers

Answer 1
1000 m/s

You have the wavelength and frequency, you just need to solve for velocity. You can do this by multiplying each side of the equation by frequency.

Related Questions

how atoms are in one mole of patassuim

Answers

Answer:

There are 6.022 × 10²³ atoms of potassium in every mole of potassium.

1) A man leans against the wall and...
a) The man's shoulder pushes against the wall
b) The wall pushes against the man
c) Bricks in the wall push against each other
d) The ground pushes against the man, supporting him.

Answers

Answer:

I thinks its a, but its really about gravity im not sure

Explanation:

:)

What is the frequency of a wave with a wavelength of 0.5 m and speed of 50 m/s

Answers

Answer: 25 m/s

Explanation:

To calculate the speed of a wave, simply multiply its wavelength and its frequency (given that you are provided with the two variables).

This makes sense, since the unit for speed (m/s) matches that of the product of wavelength (m) and frequency (Hz). Keep in mind that one Hz is equivalent to one inverse second (

s

1

or

1

s

).

If you multiply m (the unit for wavelength) with

1

s

(the unit for frequency), you will get m/s, the unit for speed.

Now multiply!

.5 m * 50 Hz = 25 m/s

25 m/s is your final answer!

Consider a Carnot heat-engine cycle executed in a closed system using 0.025 kg of steam as the working fluid. It is known that the maximum absolute temperature in the cycle is twice the minimum absolute temperature, and the net work output of the cycle is 60 kJ. If the steam changes from saturated vapor to saturated liquid during heat rejection, determine the temperature of the steam during the heat rejection process. The temperature of the steam during the heat rejection process is

Answers

Answer:

The temperature of the steam during the heat rejection process is 42.5°C

Explanation:

Given the data in the question;

the maximum temperature T[tex]_H[/tex] in the cycle is twice the minimum absolute temperature T[tex]_L[/tex] in the cycle

T[tex]_H[/tex]  = 0.5T[tex]_L[/tex]

now, we find the efficiency of the Carnot cycle engine

η[tex]_{th[/tex] = 1 - T[tex]_L[/tex]/T[tex]_H[/tex]

η[tex]_{th[/tex] = 1 - T[tex]_L[/tex]/0.5T[tex]_L[/tex]

η[tex]_{th[/tex] = 0.5

the efficiency of the Carnot heat engine can be expressed as;

η[tex]_{th[/tex] = 1 - W[tex]_{net[/tex]/Q[tex]_H[/tex]

where W[tex]_{net[/tex] is net work done, Q[tex]_H[/tex] is is the heat supplied

we substitute

0.5 = 60 / Q[tex]_H[/tex]

Q[tex]_H[/tex] = 60 / 0.5

Q[tex]_H[/tex] = 120 kJ

Now, we apply the first law of thermodynamics to the system

W[tex]_{net[/tex] = Q[tex]_H[/tex] - Q[tex]_L[/tex]

60 = 120 -  Q[tex]_L[/tex]

Q[tex]_L[/tex] = 60 kJ

now, the amount of heat rejection per kg of steam is;

q[tex]_L[/tex] = Q[tex]_L[/tex]/m

we substitute

q[tex]_L[/tex] = 60/0.025

q[tex]_L[/tex] = 2400 kJ/kg

which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)

q[tex]_L[/tex] = h[tex]_{fg[/tex] = 2400 kJ/kg

now, at  h[tex]_{fg[/tex]  = 2400 kJ/kg from saturated water tables;

T[tex]_L[/tex] = 40 + ( 45 - 40 ) ( [tex]\frac{2400-2406.0}{2394.0-2406.0}\\}[/tex] )

T[tex]_L[/tex] = 40 + (5) × (0.5)

T[tex]_L[/tex] = 40 + 2.5

T[tex]_L[/tex] = 42.5°C  

Therefore, The temperature of the steam during the heat rejection process is 42.5°C  

plz help me with my career!!!
part one...

Answers

Answer:

#1 Yes

Explanation: #1: The rest of them are used mainley by farmers, and crops are used by common citizens in the world.

Question 1: Crops.

Question 2: Diagnostic Services.

Question 3: A cable company needs to lay new fiber optic cable to reach its customers across a large lake.

Question 4: A bachelor's degree in energy research.

Question 5: Environmental Resources.

If any of these answers are incorrect, please tell me, so I can fix my mistake. Thank you.

Fat Albert (the TV show character) runs up the stairs on Monday. On Tuesday, he walks up the same set of stairs. Which day did he do more work?

Answers

Answer:

Tuesday bc instead of running he/she was walking bc he/she might not have as much energy

Explanation:

To understand the relationship between the force and the potential energy changes associated with that force and to be able to calculate the changes in potential energy as definite integrals. Imagine that a conservative force field is defined in a certain region of space. Does this sound too abstract

Answers

Answer:

This does not sound too abstract

Explanation:

An example of an Imaginative conservative force field defined in terms of a certain region of space is : A gravitational field and it can be expressed as

[tex]Fx = - \frac{dU_{x} }{dx}[/tex]  and this is because the potential energy in a gravitational field is determined only by the initial and final position of the objects found with the Gravitational field

To determine the change in potential energy  ΔU we will integrate the above equation

hence :  ΔU = [tex]\int\limits^2_1 {F} \, ds[/tex]  

Hence this does not sound too abstract

You are in the passenger side of a car that is moving very fast and the driver turns quickly to the left. Your body feels like it is being pulled to the right. Explain why there is no real force pulling you to the right and how does this concept relate to Newton's 1st Law of Motion?

Answers

Answer:

when driving straight the inside of a car is not moving it is still. when the car turns left, it disrupts the current state of flow. thus flinging you towards the right. "every action has an equal and/or opposite reaction.

An electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields are perpendicular to each other, what is the electron's speed

Answers

Answer:

v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

[tex]qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s[/tex]

So, the speed of the electron is 2591.83 m/s.

In an effort to be the star of the half-time show, the majorette twirls a highly unusual baton made up of four mases fastened to the ends of light rods. Each rod is 1.0 m lone. Find the moment of inertia of the system about an axis perpendicular to the page and passing through the point where the rods cross.

Answers

Answer:

"0.25 kg-m²" is the appropriate answer.

Explanation:

The diagram of the question is missing. Find the attachment of the diagram below.

According to the diagram, the values are:

m₁ = 0.2

m₂ = 0.3

m₃ = 0.3

m₄ = 0.2

d₁ = d₂ = d₃ = d₄ = 0.5 m

As we know,

The moment of inertia is:

⇒  [tex]I=\Sigma M_id_i^2[/tex]

then,

⇒  [tex]I=m_1d_1^2+m_2d_2^2+m_3d_3^2+m_4d_4^2[/tex]

⇒     [tex]=d^2(m_1+m_2+m_3+m_4)[/tex]

On substituting the values, we get

⇒     [tex]=0.5^2\times (0.2+0.3+0.3+0.2)[/tex]

⇒     [tex]=0.25\times 1[/tex]

⇒     [tex]=0.25 \ Kg-m^2[/tex]

a uniform metre rule is pivoted at its centre and weights of 5 N and 12 N are hung at the 3 cm and 5 cm marks respectively. how far from the pivot must a 25 N weight be hung to balance the metre rule horizontally? ​

Answers

In order to balance the stick on the pivot, the total "moments" must be equal on both sides.  A "moment" is (a weight) x (its distance from the center).

for the 5N weight: Moment = (5N) x (3 cm) = 15 N-cm

for the 12N weight: Moment = (12N) x (5 cm) = 60 N-cm

Sum of the moments trying to pull the stick down on that side = 75 N-cm

Whatever we hang on the other side has to provide a moment of 75 N-cm in the other direction.  We have a 25N weight. Where should we hang it ?  

(25N) x (distance from the pivot) = 75 N-cm

Distance from the pivot = (75 N-cm) / (25 N)

Distance from the pivot =  3 cm

Answer:

The distance do a 25N be hung from the pivot is 31.2cm

A wave with a speed of 9 m/s and a frequency of 0.5 Hz has a λ of what?

Answers

Wave speed = (wavelength) x (frequency)

Wavelength = (wave speed) / (frequency)

Wavelength = (9 m/s) / (0.5 Hz)

Wavelength = 18 m

A wave takes 0.5 seconds to complete one cycle. Which characteristic of the wave does this description represent? A. period B. wavelength C. amplitude D. frequency​

Answers

Answer:

period

Explanation:

A wave takes 0.5 seconds to complete one cycle. It is called the time period of the wave. It is the time taken by the wave to complete one cycle.

The relation between the time period and the frequency is given by :

T = 1/f

Where

f is frequency of the wave

Hence, the correct option is (a) "period".

Mars orbits the sun at less then 60% of the speed of earth. True or false?

Answers

Answer:

True im pretty sure

Explanation:

Answer:

False

Explanation:

The answer is false, I tested it on IXL

A bicycle wheel has a diameter of 63.0 cm and a mass of 1.75 kg. Assume that the wheel is a hoop with all of the mass concentrated on the outside radius. The bicycle is placed on a stationary stand and a resistive force of 121 N is applied tangent to the rim of the tire. (a) What force must be applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2

Answers

Answer:

F2 = 834 N

Explanation:

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now moment of inertia of the wheel which is assumed to be a hoop is given by; I = m(r1)²

Where r1 = (d1)/2 = 0.63/2

r1 = 0.315 m

Thus, I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

I•α = F1•r1 - F2•r2

Where F2 is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

Thus;

0.1736 × 4.4 = (121 × 0.315) - (0.0448F2)

>> 0.76384 = 38.115 - (0.0448F2)

>> 0.0448F2 = 38.115 - 0.76384

>> F2 = (38.115 - 0.76384)/0.0448

>> F2 = 833.73 N

Approximately; F2 = 834 N

The force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N

What is force?

Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.

We are given the following for the bicycle;

Diameter; d1 = 63 cm = 0.63 m

Mass; m = 1.75 kg

Resistive force; F1 = 121 N

For the sprocket, we are given;

Diameter; d2 = 8.96 cm = 0.0896 m

Radius; r2 = 0.0896/2 = 0.0448 m

Radial acceleration; α = 4.4 rad/s²

Now the moment of inertia of the wheel which is assumed to be a hoop is given by;

[tex]I=mr_1^2[/tex]

Where

r1 = 0.315 m

I = 1.75 × 0.315²

I = 0.1736 Kg.m²

The torque is given by the relation;

[tex]I\alpha=F_1\times r_1-F_2\times r_2[/tex]

Where [tex]F_2[/tex]  is the force that must be applied by the chain to give the wheel an acceleration of 4.40 rad/s².

0.1736 × 4.4 = (121 × 0.315) - (0.0448[tex]F_2[/tex])

0.76384 = 38.115 - (0.0448[tex]F_2[/tex])

[tex]F_2= \dfrac{38.115-0.7638}{0.0448}[/tex]

[tex]F_2=833.73\ N[/tex]  

Approximately; F2 = 834 N

Thus the force applied by a chain passing over a 8.96-cm-diameter sprocket in order to give the wheel an acceleration of 4.40 rad/s2 is F2 = 834 N

To know more about Force follow

https://brainly.com/question/25239010

How do the sclera and the cornea compare?
The sclera is the inside layer at the back of the eyeball, and the cornea is on the outside of the eyeball.
The sclera focuses light that enters the eye, and the cornea controls how much light enters the eye.
The sclera does not alloy light to enter the eyeball
and the cornea allows light to enter the eyeball.
The sclera is the outer surface of the eyeball
and the cornea fills the inside of the eyeball.

Answers

Answer:

The sclera focuses light that enters the eye, and the cornea controls how much light enters the eye.  

Explanation:

Which one is it? Help ASAP

Answers

Answer:

extreme heat, because no physical damage can demagnetize a magnet

Explanation:

Answer:

the 3rd one

Explanation:

The power of an engine is a measure of
A) the total amount of work it can perform.
B) the rate at which it can perform work.
C) its ability to outperform a horse.
D) its volume.

Answers

Answer:

d

Explanation:

Answer:

C

Explanation:

Horsepower refers to the power an engine produces. It's calculated through the power needed to move 550 pounds one foot in one second or by the power needs to move 33,000 pounds one foot in one minute. The power is gauged by the rate it takes to do the work.

Ps:Can I be brainliest.

Have a nice day

What happens to voltage if the resistance goes up

Answers

Answer:

This means that if the voltage is high the current is high, and if the voltage is low the current is low. Likewise, if we increase the resistance, the current goes down for a given voltage and if we decrease the resistance the current goes up.

Part D Here is one last question as a final check on your understanding of your work for this problem, looking at this problem as an example of the Conservation of Energy. The action in this problem begins at location A , with the block resting against the uncompressed spring. The action ends at location B, with the block moving up the ramp at a measured speed of 7.35 m/s . From A to B, what has been the work done by non-conservative forces, and what has been the change in the mechanical energy of the block-Earth system (the ramp is a part of the Earth)

Answers

Answer:

The answer is "39.95 J".

Explanation:

Please find the complete question in the attached file.

[tex]\to W_{AC}=(\mu \ m \ g \ \cos \theta ) d[/tex]

            [tex]=(0.45 \times 1.60 \times 9.8 \times \cos 26^{\circ}) 6.30 \\\\=(7.056 \times \cos 26^{\circ}) 6.30 \\\\=6.34189079\times 6.30\\\\=39.95 \ J\\\\[/tex]

[tex]\therefore \\\\\bold{\Delta E =39.95 \ J}[/tex]

A block with mass m1m1m_1 is placed on an inclined plane with slope angle ααalpha and is connected to a second hanging block that has mass m2m2m_2 by a cord passing over a small, frictionless pulley. The coefficient of static friction is μsμsmu_s and the coefficient of kinetic friction is μkμkmu_k. Find the smallest value of m2 when the blocks will remain at rest if they are released from rest.

Answers

Answer:

Explanation:

m₂ is hanging vertically and m₁ is placed on inclined plane . Both are in limiting equilibrium so on m₁ , limiting friction will act in upward direction as it will tend to slip in downward direct . Tension in cord connecting the masses be T .

For equilibrium of m₁

m₁ g sinα= T + f where f is force of friction

m₁ g sinα= T + μsx m₁ g cosα

m₁ g sinα -  μs x m₁ g cosα = T

For equilibrium of m₂

T = m₂g

Putting this value in equation above

m₁ g sinα -  μs x m₁ g cosα = m₂g

m₂ = m₁ sinα -  μs x m₁ cosα

Aunt Jane weights 45 Newtons. What is her mass?

Answers

Answer:

10.116 Pounds/45 newtons = 10.1164024 pounds/force

Explanation:

Divide the newtons by the rate of acceleration, which will give you the mass of the object. The mass will be in kilograms, because a single newton represents the amount of force needed to move one kilogram one meter. For our example, we will divide 10 N by 2 m/s/s, which give us a mass of 5 kg

HELP PLEASE DUE IN 3 MINUTES

Answers

Answer:

tectonic plate movement

Explanation:

A 31.0-kg child on a 3.00-m-long swing is released from rest when the ropes of the swing make an angle of 27.0° with the vertical.
(a) Neglecting friction, find the child's speed at the lowest position.
(b) If the actual speed of the child at the lowest position is 2.20 m/s, what is the mechanical energy lost due to friction?

Answers

Answer:

a)  v = 2.53 m / s, b)  ΔEm = -24.32 J

Explanation:

a) For this exercise we can use the conservation of energy,

starting point. Highest point

           Em₀ = U = m g h

final point. Lower of the trajectory

           Em_f = K = ½ m v²

as there is no friction energy is conserved

           Em₀ = Em_f

           mgh = ½ m v²

           v² = 2gh

we are used trigonometry to find the height

           h = L - L cos tea

we substitute

           v = [tex]\sqrt{2gL (1- cos \theta)}[/tex]

let's calculate

           v = [tex]\sqrt { 2 \ 9.8 \ 3.00 \ ( 1- cos \ 27) }[/tex]

           v = 2.53 m / s

b) The loss of mechanical energy due to friction

          ΔEm = Em_f -Em₀

          ΔEm = ½ m v² - m g h

          ΔEem = ½ m v² - m g L (1-cos θ)

let's calculate

          ΔEm = ½ 31.0  2.20² - 31  9.8  3.00 (1-cos 27)

           ΔEm = 75.02 - 99.34

           ΔEm = -24.32 J

the negative sign indicates that power has been requested

Two blocks are placed at the ends of a horizontal massless board, as in the drawing. The board is kept from rotating and rests on a support that serves as an axis of rotation. The block on the right has a mass of 5.8 kg. Determine the magnitude of the angular acceleration when the system is allowed to rotate.

Answers

Answer:

The answer is "[tex]- 0.5747\ \frac{rad}{s^2}[/tex]"

Explanation:

Let

[tex]M_L = 12\ kg\\\\M_R = 5.8\ kg[/tex]

While it is in balance, its net force mostly on a machine is zero where the board will rotate an upward torques were given by:

[tex]\to M_L \times g \times R_L - M_R \times g \times R_R = \tau[/tex]

[tex]\to 12 \times 9.8 \times 0.6 - 5.8 \times 9.8 \times 1.4 = \tau[/tex]

[tex]\to \tau= 70.56-79.576\\\to \tau = -9.016[/tex]

let,

[tex]\tau = I \alpha[/tex]

where

[tex]\alpha =[/tex]angular acceleration

I = moment of inertia of the system

[tex]\to I = M_L \times r \times L_2 + M_R \times r \times R_2\\\\\to I = 12 \times 0.6 \times 0.6 + 5.8 \times 1.4 \times 1.4\\\\\to I= 4.32+11.368\\\\\to I = 15.688\ kg\ m2\\\\[/tex]

 Calculating the angular acceleration:

[tex]\alpha = \frac{\tau}{I}\\\\[/tex]

    [tex]= \frac{-9.016}{15.688}\\\\=- 0.5747\ \frac{rad}{s^2}\\\\[/tex]

Fossil clues are one of the _____________ clues that support the theory of continental drift.
A. crust B. resource C. climate D. rock

Answers

Answer:

a

Explanation:

I think don't get mad if I'm wrong

Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader

Answers

Answer:

7.55 g

Explanation:

Using the relation :

Δt = temperature change = (6° - 0°) = 6°

Q = quantity of heat

C = specific heat capacity = 4190 j/kg/k

1000 J = 1kJ

333 KJ = 333000 j

The quantity of ice that will melt ;

= 0.419 * 6 * 100 / 333000

= 2514000 / 333000

= 7.549 g

The mass of ice that will melt :

2.514 / 0.333

= 7.549 g

What is an electric current?

a
a potential difference
b
a piece of wire
c
A flow of charge within a circuit
d
A light bulb
What is an electric current?

a
a potential difference
b
a piece of wire
c
A flow of charge within a circuit
d
A light bulb

Answers

Answer:

c

Explanation:

mark brainleyest plz if right

Sound waves have the ability to cause objects to vibrate. If a paperback book is placed near a speaker and the volume of the speaker is amplified, the book can be torn apart into small pieces.

Answers

Answer:

yes with a lot of time it eventualy could be, but in short term no

Explanation:

What are the units of work?

Answers

In the case of work (and also energy), the standard metric unit is the Joule (abbreviated J). One Joule is equivalent to one Newton of force causing a displacement of one meter. In other words, The Joule is the unit of work (if that helped any!)
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