If the length of a box is reduced to one-third of its original value and the width and height are doubled, by what factor has the volume changed?

In order to determine the amount of time it would take the arrow to travel upward, we would have to first determine its initial velocity by using the second equation of motion.

Note: Since the arrow was projected upward, the acceleration due to gravity would be negative because it indicates deceleration.

From the second equation of motion, we have:

S = ut - ½gt²

39.9 = u(1.87) - ½ × (-10) × 1.87²

39.9 = 1.87u + 17.49

1.87u = 39.9 - 17.49

1.87u = 22.41

u = 22.41/1.87

Initial velocity, u = 11.98 m/s.

Now, we can calculate the amount of time it would take the arrow to travel upward by applying the first equation of motion:

V = u + at

0 = 11.98 + (-10)t

10t = 11.98

t = 11.98/10

Time, t = 1.198 seconds.

In order to calculate the maximum height, we would apply the second equation of motion:

S = ut + ½gt²

S = 11.98(1.198) + ½ × (-10) × 1.198²

S = 14.35 - 7.18

Maximum height, S = 7.17 meters.

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Answer:

The FM carrier waves should have different frequencies than the carrier waves, not different amplitudes.

Explanation:

The label at the top of the diagram should be “FM Radio,” not “Cell Phone.

Answer:

I think it's B but I'm not 100% sure

The magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

The total displacement of the player is calculated as follows.

Apply cosine rule as shown below;

d² = d₁² + d₂² - 2d₁d₂ cos(θ)

d² = (24.1)² + (7.9²) - (2 x 24.1 x 7.9) cos(52.5)

d² = 411.42

d = √411.42

d = 20.28 m

Apply sine rule as shown below;

d/sinD = d₂/sinD₂

20.28/sin(52.5) = 7.9/sinD₂

25.562 = 7.9/sinD₂

sinD₂ = 7.9/25.562

sinD₂ = 0.309

D₂ = sin⁻¹(0.309)

D₂ = 18⁰

angle with x axis =  18⁰ + θ

                            =  18⁰ +  52.5⁰

                            = 70.5⁰

Thus, the magnitude of the total displacement is 20.28 m.

The angle of the total displacement with the x axis is 70.5⁰.

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Answer:

PN=P1+P2+P3.......................PN

Answer:

[tex]{ \tt{displacement = velocity \times time }} \\ { \tt{ = 2.4 \times 46}} \\ { \tt{ = 110.4 \: m}}[/tex]

The sum of the vectors is shown in the image attached to this answer.

A vector quantity is a quantity that has both magnitude and direction. In effect, as we try to obtain the combination of the vector we also have to consider the direction. The vectors are often shown  by the use of a bold face or by the use of an arrow over the sign of the vector.

Now looking at this vectors, we know that the sum of the vectors can only be obtained geometrically but the arrows of the vectors must have to point in the appropriate directions for the correct  sum to be obtained.

Thus the sum of the vectors is shown in the image attached to this answer.

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(a) The expression for the horizontal acceleration of the cart is

a = (T - μN)/Mc.

(b) The expression for the vertical acceleration of the hanging mass is

a = (T - Mhg)/Mh.

(c) The expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).

The horizontal acceleration of the cart is calculated as follows;

The horizontal acceleration of the cart is determined from the net horizontal force acting on the system.

T - μN = Mca

where;

a = (T - μN)/Mc

T - Mhg = Mha

where;

a = (T - Mhg)/Mh

If the acceleration of the cart and the hanging mass are equal, our final equation becomes;

From first equation;

a = (T - μN)/Mc

Mca = T - μN

Mca + μN = T

From second equation;

a = (T - Mhg)/Mh

Mha = T - Mhg

Mha + Mhg = T

Solve the two equation together;

Mca + μN = Mha + Mhg

Mca - Mha = Mhg - μN

a(Mc - Mh) = Mhg - μN

a = (Mhg - μN) / (Mc - Mh)

Thus, the expression for the acceleration of both cart and the hanging mass is a = (Mhg - μN) / (Mc - Mh).

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The spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

The angular speed of the ball is calculated as follows;

ω = 2π/T

ω = (2π) / (0.13)

ω = 48.33 rad/s

The spring constant is calculated as follows;

ω = √(k/m)

ω² = k/m

ω²m = k

(48.33² x 0.232) = k

542 N/m

v = ωL

v = 48.33 x 0.56 m

v = 27.1 m/s

h = v²/2g

h = (27.1²) / (2 x 9.8)

h = 37.5 m

Thus, the spring constant is 542 N/m.

The height the ball reaches is 37.5 m.

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The time taken by the ball to reach the maximum height when ball is thrown straight upward is t = 1.5s.

To find the time we must know the distance so to calculate the distance using formula,

v² = u² + 2 as

where,

v is final velocity

u is initial velocity

a is acceleration due to gravity

s is distance

As, we can see,

u = v = 30m/s

a = - 9.8 m/s²

s = ?

So, putting the values we get,

30²m/s = 30²m/s + 2 (9.8 m/s²) s

s = 30²m/s / 30²m/s + 2 (-9.8 m/s²)

s = 19.6

Now after getting to know the distance we can use the formula,

s = d/t

Where,

s is speed

d is distance

t is time

So, putting the values,

t = 30 / 19.6

t = 1.5s

Hence, the time taken by the ball to reach the maximum height is 1.5s.

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The precise way a researcher measures and defines a variable is known as the operational definition.

The researcher measures the dependent variable and the independent variable is manipulated and controlled by the researcher ( Experimenter ). The concept of operational definition is applied in various fields such as Philosophy, Science, Business, computing etc.

To explain this clearly, let's consider an example in which the researcher tries to define sleep deprivation. In this sleep deprivation is the independent variable and factors causing sleep deprivation such as food, lifestyle, etc are dependent variables.

Therefore, the precise way a researcher measures and defines a variable is known as the operational definition.

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if a fighter hits a punching bag and brings it from rest up to a speed of 40 m/s in 0.08 s, Then the force of impact on the punching bag if its mass is 100 kg would be 50000 Newtons,

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The impact of the force on the punching bag = momentum/time

                                                                           =100×40 / 0.08

                                                                           =5000 Newtons

Thus, the force of impact on the punching bag would be 50000 Newtons.

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The maximum speed of the stone tied to the string is 5.32 m/s.

The mass of the stone is m = 1.2 kg.

The mass is tied to a string and it swung in a vertical radius of r = 0.85 cm.

The tension on the string is T = 40 N.

The centripetal force of a body moving in a circle of radius r is given as:

T = ( mv² / r )

Where T is the tension, m is the mass of the body and r is the radius of the circle.

Then,

v² = ( T × r ) / m

v = √ [ T × r / m ]

v = √ [ 40 × 0.85 / 1.2 ]

v = √ [ 34 / 1.2 ]

v = √28.3

v = 5.32 m/s

The maximum speed of the stone before the string breaks is 5.32 m/s.

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The correct answer is :

In octal,

Decimal         16  17   18  19  20  21  22 23  24  25  26  27  28  29  30 31  32

Octal             20  21  22  23 24  25 26 27  30  31   32  33  34  35  36 37  40

Hexadecimal 10   11   12  13  14   15  16  17   18   19   1A   1A   1C  1D  1E  1F  20

Decimal   8  9  10 11  12 13  14  15  16  17  18  19  20 21  22  23 24 25 26 27 28

Base13     8  9  A  B  C  10  11  12  13   14  15  16  17  18  19   1A  1B  1C 20 21 22

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The time taken for the object to travel the given height is determined as 12.48 seconds.

Time of motion of an object is the total time taken by the object to travel a given height or distance.

The time of motion of the boulder is calculated as follows;

h = vt + ¹/₂gt²

where;

1300 = 43t  +  0.5(9.8)t²

1300 = 43t + 4.9t²

4.9t² + 43t - 1300 = 0

solve the quadratic equation using formula method as shown below;

a = 4.9, b = 43, c = -1300

t = 12.48 seconds

Thus, the time taken for the object to travel the given height is determined as 12.48 seconds.

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The speed of the ball at launch is 23m/s.

After 0.5 seconds, the ball initially passed the pole.

Then it will again reach the top of the pole after 4.1 seconds.

Consequently, the ball's travel time above the pole is

Δt  = 4.1 - 0.5 = 3.6sec

Now the time it will take to reach the highest point from the top of the pole is given as t = Δt/2 = 1.8sec.

Now the total time to reach the top from the bottom is given as 2.3sec.

After 0.5 seconds, the ball initially passed the pole.

Consequently, the ball's travel time above the pole is

[tex]v_{f} - v_{i} = at[/tex]

[tex]v_{i}=22.54m/s[/tex]

also the speed after 0.5 s is

[tex]v_{f} = 17.64m/s[/tex]

So, the speed of the ball at launch is 23m/s.

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Answer: 0.15 Tm, 150000000 km

Explanation:

150,000,000,000m  to km=150000000 km (divide by 1000)

150,000,000,000m  to Tm=0.15 Tm

The correct answer is to describe an object's perceived size and describing its position in space. Degrees (°) are used to express angles. A complete circle has 360 °, whereas a straight angle has 90 °. For instance, there is a 90° angle between the horizontal direction (toward the horizon) and the vertical direction (directly above you). The full moon's angular diameter in the sky is around 1/ 2°.

Triangle Units

Divide a complete circle into 360 degrees. Divide a degree into 60 arcminutes, also known as minutes of arc (abbreviated as 60 arcmins or 60'). Divide an arcminute into 60 arcseconds, also known as seconds of arc (abbreviated as 60 arcsec or 60).

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For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.

The supplied problem informs us that a ball was dropped and is supposed to be falling freely. Since the problem does not specify whether any other forces were present to influence the ball's motion, we must assume that the initial speed is v0=0 m/s.

Free-falling accelerates at a rate of 9.8 m/s2, which is referred to as the acceleration owing to gravity because it is being drawn towards the center of the earth. This indicates that a=9.8m/s2 is the value of the initial and final accelerations.

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Answer: Bias

Explanation:

To determine how classroom temperature affected test performance of students an experiment was conducted with each group of students in hot room, cold room and a room with normal temperature.

• Dependent variable- Test performance

• Independent variable- Room temperature

• Control variables/Constants - Group of students

• Control group – Students in the room with normal temperature

Test performance depends on the temperature of the room.

Room temperature is an independent variable that does not depend on any factor

Students were the constants in the experiment

Among the students, students in normal temperature room is the control group as they were placed just to check the correctness of the experiment.

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A master's thesis and a dissertation are typically required for clinical psychology programs. Each of these typically takes one to two years.

Psychology doctoral degrees provide students with the training they need to pursue careers in academic research, professional practice, or both. The most common academic degrees awarded are the Doctor of Philosophy (PhD) or the Doctor of Psychology (PsyD). There are notable disparities between the types of training and professional goals of those with these degrees, even though each is intended to engage students in deep knowledge and abilities within an area of psychology. Understanding these variations is the first step in determining which curriculum is the greatest fit for a particular student.

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The narration style in the para is third person omniscient

As it narrates the whole incident which is going on.

What is third person omniscient?

The most flexible and open POV available to writers is third person omniscient. An omniscient narrator is one who has all knowledge and all sight, as the name suggests.

The narrator may occasionally access the consciousness of a few or many different characters while the narration is taking place outside of any one particular character.

Some authors employ this viewpoint to build a more "godlike" or purposefully "authorial" persona that enables them to offer dispassionate commentary on the action. Detailed location descriptions that contribute to the mood or atmosphere of a scene may be an example of this, as well as philosophical tangents that serve to develop concepts that only loosely link to the action of the story.

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The centripetal acceleration of the Ferris wheel with radius of 14.0 m is determined as 2.57 m/s².

Centripetal acceleration,  is the acceleration of a body moving a circular path.

The centripetal acceleration of the Ferris wheel is calculated as follows;

a = v²/r

where;

a = (6²) / (14)

a = 2.57 m/s²

Thus, the centripetal acceleration of the Ferris wheel is determined as 2.57 m/s².

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The complete question is below:

A Ferris wheel has a radius of 14 m, the linear speed of a passenger on the rim is 6 m/s .Find the centripetal acceleration of the Ferris wheel.

2,302.74 J is the heat generated.

Current electricity is the electricity produced by the movement of electrons. Static electricity is the electricity that accumulates on a substance's surface. Power plants and batteries are used to produce the current electricity.

Electric current in a wire, where electrons serve as the charge carriers, is a measurement of the amount of charge that moves through any point of the wire in a given amount of time.

The mass of the aluminum is m = 0.25 kg.

The difference in temperature is T=10 C.

The following is a list of aluminum's specific heat capacities:

c=921.096 J/kg∘C

Therefore, we apply the following formula in this instance:

Q=mcΔT

We replace with:

Q=(0.25kg)(921.096J/kg∘C)(10∘C)

Thus, we will receive the heat produced:

Q=2,302.74 J

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Answer:

The more mass the more kinetic energy it has

Explanation:

like a plastic ball and a metal one the metal one will fall faster.

hope this helps

The mass of the cart is 30kg

Using Newton's formula which states that Force is given as product of mass and acceleration.

The force is given to be 60N

The acceleration is given to be 2 m/s^2

Using the formula

F=ma

Putting the values of formula,

60 = m x 2

m = 30 kg

Hence the mass of the cart is 30kg

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