The maximum total number of observations with a deviation of at least 5 is 1.
If the sum of deviations of 100 observations from 20 is 5, then the maximum total number of them, such that each of which is at least 5, can be found by considering the minimum deviation for the other observations.
Since we want the maximum total number of observations with a deviation of at least 5, let's assume all other observations have a deviation of 0 (meaning they are equal to 20). Let x be the number of observations with a deviation of at least 5. Then, the sum of deviations can be represented as:
5x + 0(100-x) = 5
Solving for x, we get:
5x = 5
x = 1
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What is the correct answer?
The numbers in order from least to greatest are -20, -9, -5, -2, 2.2, 2.5, 2.7
The absolute value of 34 is |34|
The winner of the tournament is Whitney who scored -16.
February 2nd was warmer with a high temperature of 48 °F.
Chicken salad > Hamburger
What is the number system?A system of writing numbers is known as a number system. It is the mathematical notation for consistently employing digits or other symbols to represent the numbers in a particular set.
It represents the arithmetic and algebraic structure of the numbers and gives each number a distinct representation.
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Luca runs 8 miles each week. Type an equation to represent the total number of miles Luca runs given the number of weeks. Let m represent the total number of miles Luca runs and let w represent the number of weeks
Answer:
m=8w
Step-by-step explanation:
8 miles times the number of weeks he runs = the total miles he ran
8w = m
We know that we need the total number of miles, so m needs to be isolated on one side of the equation.
We also know that every week, she runs 8 miles.
So we can multiply 8 by w to get our other side.
~~~Harsha~~~
Solve And Fill In The Boxes
Answer:
Step-by-step explanation:
subtract (x - 13) and 52 and you will get x-56Answer: The angles are supplementary, the value of x is 141
Step-by-step explanation:
Because this shows a straight line with two angles, one being algebraic (albeit unrelated to finding if the angles are supplementary) this tells you that the value of x is found by using an equation like this:
[tex]\left(x-13\right)=180-52[/tex]
You can then subtract 52 from 180, giving you
[tex]\left(x-13\right)=128[/tex]
Now you can add 13 to both sides
[tex]x-13+13=128+13[/tex]
[tex]x=141[/tex]
Calculate the area and circumference of a circle with diameter 8cm
Tell me if the photo below is the answer for this question
The area and circumference of the circle are 16π cm² and 8π cm respectively.
What is the area and circumference of the circle?A circle is simply a closed 2-dimensional curved shape with no corners or edges.
The area of a circle is expressed mathematically as;
A = πr²
The circumference of a circle is expressed mathematically as;
C = 2πr
Where r is radius and π is constant pi.
Given the diameter of the circle as 8 cm, we can find the radius by dividing the diameter by 2:
r = 1/2 × diameter
r = 1/2 × 8cm
r = 4cm
Using the radius, we can now calculate the area and circumference of the circle:
Area of circle = πr²
A = π(4 cm)²
A = 16π cm²
Circumference of circle = 2πr
C = 2π(4 cm)
C = 8π cm
Therefore, the circumference of the circle is 8π cm.
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Why do we prefer Logistic Regression over Linear Regression for classification problems? O (1), (2) & (3) The predicted values are much more interpretable as they lie in the range of 0 to 1. The sigmoid curve fits the data better than a straight line. Linear regression minimizes the mean squared error whereas logistic regression uses maximum likelihood estimation to estimate parameters.
Logistic Regression is preferred over Linear Regression for classification problems for several reasons.
Firstly, the predicted values in Logistic Regression are much more interpretable as they lie in the range of 0 to 1, which represents the probability of a certain outcome occurring. In contrast, Linear Regression predicts continuous values which are difficult to interpret as probabilities.
Secondly, the sigmoid curve used in Logistic Regression fits the data better than a straight line used in Linear Regression. This is because the sigmoid curve captures the non-linear relationships between the input variables and the output variable, which is often the case in classification problems.
Lastly, Logistic Regression uses maximum likelihood estimation to estimate parameters, whereas Linear Regression minimizes the mean squared error. Maximum likelihood estimation is a more appropriate method for estimating parameters in classification problems as it takes into account the binary nature of the output variable. Linear Regression, on the other hand, does not consider this binary nature and may not produce accurate results in classification problems.
In summary, Logistic Regression is preferred over Linear Regression for classification problems because of its interpretable predicted values, better fit to non-linear relationships, and appropriate method of estimating parameters using maximum likelihood estimation.
We prefer Logistic Regression over Linear Regression for classification problems for the following reasons:
1) Predicted values in Logistic Regression are more interpretable as they lie in the range of 0 to 1, representing probabilities of class membership, while Linear Regression predicts continuous values which may not directly indicate class membership.
2) The sigmoid curve in Logistic Regression fits the data better for classification problems, as it represents a natural threshold between classes, while a straight line from Linear Regression may not provide clear separation between classes.
3) Logistic Regression uses maximum likelihood estimation to estimate parameters, which makes it more suitable for classification problems as it finds the best fit for the probability of class membership. Linear Regression minimizes the mean squared error, which focuses on minimizing the distance between predicted and actual values, but does not directly optimize for class membership probabilities.
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A rectangle is 8 millimetres wide and 27 millimeters long. What is the area of this rectangle
As per the given information, the total length of a rectangle is 216mm²
Length of the rectangle = 8 mm = 5.2 cm
Width of the rectangle = 27 mm = 2.0 cm
A quadrilateral, also known as a four-sided polygon, is characterised by four right angles, each of which is 90 degrees, and opposing sides that are parallel and of equal length. It is a four-sided geometric object having right angles at each of its four corners and opposing sides that are parallel and of equal length.
Using the formula for area of rectangle -
Area of rectangle = Length x width
Substituting the values -
Area = 27 x 8
= 216
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Find the mean,median,mode an range of the data set after you perform the given operation on each data value? 9,7,12,13,9,3; add 5
A. Mean: 8.8, Median: 9, mode: 9, Range: 10
B. Mean: 8.8, Median: 9, mode: 9, Range: 5
C. Mean: 13.8, Median: 14, Mode: 14, Range 5
D. Mean: 13.8, Median: 14, Mode: 14, Range 10
The mean, median, mode and range of the data set after you perform the given operation on each data value include the following: C. Mean: 13.8, Median: 14, Mode: 14, Range 15.
How to calculate the mean for the set of data?In Mathematics and Geometry, the mean for this set of data can be calculated by using the following formula:
Mean = [F(x)]/n
For the total number of data, we have;
Total, F(x) = 9 + 7 + 12 + 13 + 9 + 3
Total, F(x) = 53
Mean = 53/6
Mean = 8.8.
By adding 5 to the mean, we have the following:
Mean = 8.8 + 5 = 13.8
Mode = 9 + 5 = 14
Median = (9 + 9)/2 + 5 = 14.
Range = (13 - 3) + 5 = 15
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match the correct term with its definition chord [ choose ] tangent [ choose ] secant [ choose ] diameter [ choose ]
Chord [a straight line segment that joins two points on the circumference of a circle]
Tangent [a straight line that touches a circle or sphere at a single point]
Secant [a straight line that intersects a circle at two points]
Diameter [a straight line passing through the center of a circle and connecting two points on the circumference]
In geometry, there are several terms related to circles, such as chord, tangent, secant, and diameter. Here are their definitions:
Chord: A chord is a line segment connecting any two points on the circumference of a circle. It is the longest segment that can be drawn inside a circle.
Tangent: A tangent is a line that touches the circumference of a circle at only one point, called the point of tangency. It is perpendicular to the radius at the point of tangency.
Secant: A secant is a line that intersects a circle at two points. It can be a line that passes through the center of the circle, in which case it is the diameter of the circle.
Diameter: The diameter is the longest chord of a circle, and it passes through the center of the circle. It is twice the length of the radius.
Understanding these terms is important in solving problems related to circles and their properties. For example, in finding the length of an arc or the area of a sector, we need to know the chord or diameter of the circle, and the angle or central angle subtended by the arc or sector. In constructing tangents to circles, we need to know the point of tangency and the radius or diameter of the circle.
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due in a few minuets Determine the number of solutions that 5x^2 + 3x + 8 has without solving the equation.
There are two solutions does the equation have.
We have to given that;
The equation is,
⇒ 5x² + 3x + 8
Now, We can see that;
The degree of equation is, 2
Hence, There are two solution of the equation are possible.
Thus, There are two solutions does the equation have.
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In the year 2000, the average car had a fuel economy of 22.74 MPG. You are curious as to whether this average is different from today. The hypotheses for this scenario are as follows: Null Hypothesis: H = 22.74, Alternative Hypothesis: ui # 22.74. You perform a one sample mean hypothesis test on a random sample of data and observe a p-value of 0.6901. What is the appropriate conclusion? Conclude at the 5% level of significance. 1) We did not find enough evidence to say the true average fuel economy today is greater than 22.74 MPG. 2) We did not find enough evidence to say the true average fuel economy today is less than 22.74 MPG. 3) The true average fuel economy today is significantly different from 22.74 MPG. 4) The true average fuel economy today is equal to 22.74 MPG. 5) We did not find enough evidence to say a significant difference exists between the true average fuel economy today and 22.74 MPG.
Based on the given scenario, the appropriate conclusion is option 5) "We did not find enough evidence to say a significant difference exists between the true average fuel economy today and 22.74 MPG." This conclusion is drawn from the fact that the p-value of 0.6901 is greater than the 5% level of significance, which means that we fail to reject the null hypothesis.
Therefore, we cannot conclude that the true average fuel economy today is significantly different from 22.74 MPG. It is important to note that a random sample of data was used in this hypothesis test to draw a conclusion about the population.
To answer this question, let's look at the given information and the 5% level of significance:
1. You have a null hypothesis (H) that states the average fuel economy today is equal to 22.74 MPG.
2. The alternative hypothesis (ui) states that the average fuel economy today is not equal to 22.74 MPG.
3. You performed a hypothesis test on a random sample of data and found a p-value of 0.6901.
4. You are asked to conclude at the 5% level of significance, which means you would reject the null hypothesis if the p-value is less than 0.05.
Since the observed p-value (0.6901) is greater than the 5% level of significance (0.05), you fail to reject the null hypothesis. This means there is not enough evidence to say a significant difference exists between the true average fuel economy today and 22.74 MPG.
So, the appropriate conclusion is:
5) We did not find enough evidence to say a significant difference exists between the true average fuel economy today and 22.74 MPG.
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5 customers entered a store over the course of 2 minutes. At what rate were the customers entering the store in customers per minute?
Answer:
Step-by-step explanation: what would halve of 5 be?
Three tulip bulbs are planted in a window box. Find the probability that at least one will flower if the probability that all will fail to flower is 1/8 .
The probability that none of the bulbs will fail to flower (i.e. at least one will flower) is 1 - 1/8, or 7/8. Therefore, the probability that at least one tulip bulb will flower is 7/8.
To find the probability that at least one tulip will flower, we can use the complementary probability. The complementary probability is the probability of the opposite event occurring, which in this case is the probability of not all tulips failing to flower.
Given that the probability that all tulips will fail to flower is 1/8, the probability that at least one tulip will flower is:
P(at least one tulip flowers) = 1 - P(all tulips fail to flower) = 1 - 1/8 = 7/8
So, when the three tulip bulbs are planted in the window box, there is a 7/8 probability that at least one will flower.
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Asume that you have a balance of 6000 on your MasterCard and that you make that are minimum payment of the balance Find a turmus for the balance er month term decimal You with a which with a new The product within the sale showtember that Hint You are not read to use the symbole that were Tower of lette en MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER 9. Points DETAILS 13.00 Assume that you have a balance of 56000 on your MasterCard and that you more charges. Asume that are the same minimum payment of of the balance Find a formula for the balanceert met pynt (encat four decimates.) Mine : You must write the formulation, which means that The product within the square brackets should be entered that is Hint You are not the type the way we your yard , Het 3 Typ the boter the exponent
I apologize, but I am having difficulty understanding your question. Can you please provide more information or clarify the terms and calculations you are requesting. Here's a step-by-step explanation to find a formula for the balance after each month:
1. Start with the initial balance on your MasterCard: $6,000.
2. Each month, you make a minimum payment (let's call it 'P') of the balance.
3. After making the payment, the remaining balance will be Balance - Payment = 6000 - P.
4. Assuming no additional charges and an interest rate (let's call it 'i'), we can calculate the new balance after interest is added.
5. New balance = (Remaining balance) * (1 + i) = (6000 - P) * (1 + i).
6. To find the balance after each month, replace 'n' in the formulation with the number of months that passed.
The formula for the balance after 'n' months would be: (6000 - P) * (1 + i)^n.
Please note that you will need to know the minimum payment percentage ('P') and the interest rate ('i') to calculate the exact balance.
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The manager of an automobile dealership is considering a new bonus plan in order to increase sales. Currently, the mean sales rate per salesperson is five automobiles per month. The correct set of hypotheses for testing the effect of the bonus plan is:________
The correct set of hypotheses for testing the effect of the bonus plan is:
To test the effect of the new bonus plan on increasing sales at the automobile dealership, the manager can use the following set of hypotheses:
Null Hypothesis: The mean sales rate per salesperson remains the same or less than five automobiles per month (H0: μ ≤ 5)
Alternative Hypothesis: The mean sales rate per salesperson increases with the implementation of the bonus plan (HA: μ > 5)
These hypotheses will help determine if the bonus plan has a significant impact on increasing sales.
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How do i write six hundred thousand eight in standard form
Th given number " six hundred thousand eight" can be written in the standard form as 600,008.
To write "six hundred thousand eight" in standard form, we need to write the number using digits in the appropriate place value positions.
The digit "8" is in the "ones" position, the digit "0" is in the "tens" position, the digit "0" is in the "hundreds" position, the digit "0" is in the "thousands" position, the digit "0" is in the "ten thousands" position, and the digit "6" is in the "hundred thousands" position.
Therefore, it can be concluded that we can write the given number in standard form as 600,008.
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About 15% of people in America use a certain social media website. In a group with 20 people (assume that it is a random sample of people in America), what are the following probabilities? (Round your answers to three decimal places. )
The probability( likelihood ) that fewer than 3 people in the group of 20 use the social media website is approximately 0.483.
Let X be the number of individuals within the gather of 20 who utilize the social media website.
Since each individual within the bunch either employments or does not utilize the site, X takes after a binomial conveyance with parameters n=20 and p=0.15.
a) P(X = 3) can be calculated utilizing the binomial likelihood equation:
P(X = 3) = (20 choose 3) * [tex]0.15^3 * 0.85^17[/tex]
Employing a calculator, we get:
P(X = 3) ≈ 0.202
In this manner, the likelihood that precisely 3 individuals within the bunch of 20 utilize the social media site is roughly 0.202.
b) P(X < 3) can be calculated utilizing the aggregate dispersion work of the binomial conveyance:
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)
Utilizing the binomial likelihood equation, we get:
P(X = 0) = [tex]0.85^20[/tex] ≈ 0.026
P(X = 1) = (20 select 1) * [tex]0.15^1 * 0.85^19[/tex] ≈ 0.149
P(X = 2) = (20 select 2) * [tex]0.15^2 * 0.85^18[/tex] ≈ 0.308
Including these probabilities, we get:
P(X < 3) ≈ 0.483
In this manner, the likelihood that less than 3 individuals within the gather of 20 utilize the social media site is around 0.483.
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pls hlp thx your the best
Answer:
y=3x-12
Step-by-step explanation:
We can simply apply the formula;
[tex]y = y1 = m(x - x1)[/tex]
When x1 and y1 are points on the line and m is the gradiant
Hence,
[tex]y - ( - 3) = 3(x - 3)[/tex]
[tex]y + 3 = 3x - 9[/tex]
Hence when arranging to yields:
[tex]y = 3x - 12[/tex]
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An analyst collected data from 25 randomly selected transactions and found the purchase amounts (in $) The mean is $32.84 and the standard deviation is $14.35. The analyst wants to know if the mean purchase amount of all transactions is at least $27. Use the given information to complete parts a through e. 45.08 43.89 48.85 46.09 37.34
47.54 20.63 26.79 37.08 43.22
47.34 16.98 5.17 44.84 24.68
23.24 45.32 14.49 19.47 3.18
49.39 33.34 41.09 38.48 17.41
a) What is the null hypothesis ? H0: mu = $27 (Type an integer or a decimal) b) Is the alternative one-or two-sided?
The alternative hypothesis is __ c) What is the value of the test statistic? The test statistic is. __ (Round to two decimal places as needed.) d) What is the P-value of the test statistic? P-value = __ (Round to four decimal places as needed.) e) What do your conclude at a = 0.005? The P-value is___, so ___the null hypothesis. There is ___evidence to conclude that the mean purchase amount of all transactions is greater than $27
a) The null hypothesis is H0: mu = $27.
b) The alternative hypothesis is one-sided, as the analyst wants to know if the mean purchase amount of all transactions is at least $27. So, Ha: mu > $27.
c) To calculate the test statistic, use the formula: (sample mean - null hypothesis mean) / (standard deviation / sqrt(sample size)). Plugging in the given values: (32.84 - 27) / (14.35 / sqrt(25)) = 5.84 / (14.35 / 5) = 5.84 / 2.87 = 2.04. The test statistic is 2.04 (rounded to two decimal places).
d) To find the P-value, look up the test statistic (2.04) in the t-distribution table with 24 degrees of freedom. The P-value for a one-sided test is 0.0264 (rounded to four decimal places).
e) With a significance level of α = 0.005, the P-value is 0.0264, which is greater than α. So, we fail to reject the null hypothesis. There is not enough evidence to conclude that the mean purchase amount of all transactions is greater than $27.
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if the line y=x-5 was added to the same graph, it would intersect the circle at (___,___) and (___,___)
The points of intersection of the line and of the circle are given as follows:
(0.94, -4.06) and (17.06, 12.06).
How to obtain the points of intersection of the line and of the circle?The equations are given as follows:
Circle: (x - 5)² + (y + 1)² = 25.Line: y = x - 5.Replacing y = x - 5 into the equation of the circle, we obtain the x-coordinates of the points of intersection, as follows:
(x - 5)² + (x - 5 + 1)² = 25
(x - 5)² + (x - 4)² = 25
x² - 10x + 25 + x² - 8x + 16 = 25
x² - 18x + 16 = 0.
The coefficients of the quadratic equation are given as follows:
a = 1, b = -18, c = 16.
Using a calculator, the solutions are:
x = 0.94 and x = 17.06.
Hence the y-coordinates are:
x = 0.94 -> y = 0.94 - 5 = -4.06.x = 17.06 -> y = 17.06 - 5 = 12.06.Hence the points are:
(0.94, -4.06) and (17.06, 12.06).
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a measure of the amount of variation in the observed values of the response variable that is explained by the multiple linear regression is the___.
The measure of the amount of variation in the observed values of the response variable that is explained by multiple linear regression is called the coefficient of determination, or R-squared.
R-squared is a statistical measure that ranges from 0 to 1 and represents the proportion of the variance in the dependent variable that is explained by the independent variables in the model. An R-squared value of 1 indicates that all of the variation in the response variable is explained by the independent variables, while a value of 0 indicates that none of the variation is explained by the model.
R-squared is a useful tool for evaluating the goodness of fit of a multiple linear regression model and can be used to compare different models. However, it is important to keep in mind that R-squared alone does not necessarily indicate the validity or usefulness of a model, and other factors should also be considered in model selection and evaluation.
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Assume that farm sizes in a particular region are normally distributed with a population standard deviation of 200 acres. a random sample of 11 farm sizes in this region, in acres, is given below. estimate the mean farm size for this region with 90% confidence. round your answers to two decimal places and use ascending order. Farm size 67 165 170 296 351 409 486 770 1092 1321 2612
To estimate the mean farm size for the region with 90% confidence, we can use the t-distribution since the population standard deviation is not known and the sample size is small (n = 11).
First, we need to calculate the sample mean and the sample standard deviation:
Sample mean (x) = (67 + 165 + 170 + 296 + 351 + 409 + 486 + 770 + 1092 + 1321 + 2612) / 11 = 643.36
Sample standard deviation (s) = √[Σ(xi - x)² / (n - 1)] = 565.90
Next, we need to find the t-value for a 90% confidence interval with 10 degrees of freedom (n-1=11-1=10). Using a t-distribution table or calculator, the t-value for a 90% confidence interval with 10 degrees of freedom is 1.812.
Finally, we can calculate the confidence interval for the population mean:
Margin of error (E) = t-value * (s / √n) = 1.812 * (565.90 / √11) = 374.23
Lower bound of the confidence interval = x- E = 643.36 - 374.23 = 269.13
Upper bound of the confidence interval = x+ E = 643.36 + 374.23 = 1017.59
Therefore, we can estimate with 90% confidence that the mean farm size in the region is between 269.13 acres and 1017.59 acres. Rounded to two decimal places in ascending order, the interval is (269.13, 1017.59).
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Perform the following base conversions using subtraction or division-remainder: d) 310410 = ________ 9
The converted number is 4248, which matches the result obtained using division-remainder method or subtraction.
To convert 310410 to base 9, we can use division-remainder method.
Step 1: Divide 3104 by 9. The quotient is 344 and the remainder is 8. Write down the remainder (8) as the rightmost digit of the converted number.
Step 2: Divide 344 by 9. The quotient is 38 and the remainder is 2. Write down the remainder (2) to the left of the previous remainder.
Step 3: Divide 38 by 9. The quotient is 4 and the remainder is 2. Write down the remainder (2) to the left of the previous remainder.
Step 4: Divide 4 by 9. The quotient is 0 and the remainder is 4. Write down the remainder (4) to the left of the previous remainder.
Therefore, the converted number is 4248.
Alternatively, we could also use subtraction method as follows:
Step 1: Find the largest power of 9 that is less than or equal to 3104. This is 9^3 = 729.
Step 2: Divide 3104 by 729. The quotient is 4 and the remainder is 368. Write down the quotient (4) as the leftmost digit of the converted number.
Step 3: Find the largest power of 9 that is less than or equal to 368. This is 9^2 = 81.
Step 4: Divide 368 by 81. The quotient is 4 and the remainder is 64. Write down the quotient (4) to the right of the previous digit.
Step 5: Find the largest power of 9 that is less than or equal to 64. This is 9^1 = 9.
Step 6: Divide 64 by 9. The quotient is 7 and the remainder is 1. Write down the quotient (7) to the right of the previous digit.
Step 7: The remainder is 1, which is the final digit of the converted number.
Therefore, the converted number is 4248, which matches the result obtained using division-remainder method.
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Geometry
Find X hjjiftudr
Using the inscribed angle theorem, the value of x is calculated as: x = 96 degrees.
How to Find the Value of x Using the Inscribed Angle Theorem?We have to recall the inscribed angle theorem in order for us to create an equation that would enable us calculated the value of x in the circle that is given above. The theorem simply states the following:
Measure of intercepted arc = 2(measure of inscribed angle).
The intercepted arc = x
The inscribed angle = 48 degrees
Therefore, applying the theorem we have equation below:
x = 2(48)
x = 96°
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In a class of students, the following data table summarizes how many students have a brother or a sister. What is the probability that a student chosen randomly from the class does not have a sister? Has a brother Does not have a brother Has a sister 3 12 Does not have a sister 2 7
The probability that a student chosen randomly from the class has a brother and a sister is 3/29
How to determine the probability?From the table, we have the following values
Number of students = 29
Students that have a brother and a sister = 3
The probability is then calculated using:
P = Students that have a brother and a sister/Number of students
Substitute known values
P = 3/29
Hence, the probability that a student chosen randomly from the class has a brother and a sister is 3/29
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(Chapter 13) If |r(t)| = 1 for all t, then |r'(t)| is a constant.
If |r(t)| = 1 for all t, then r(t) lies on the surface of a unit sphere centered at the origin. The magnitude of the tangent vector r'(t) represents the speed of motion along this surface at time t.
Since r(t) lies on the surface of the unit sphere, it follows that r(t) is a constant distance away from the origin, namely 1. Therefore, any motion along this surface must conserve the distance of the point to the origin, meaning that the magnitude of the tangent vector r'(t) is constant.
In other words, we have:
|r(t)| = 1 -> r(t) dot r(t) = 1
Differentiating both sides with respect to t, we obtain:
2r(t) dot r'(t) = 0
Taking the magnitude of both sides, we get:
2|r(t)||r'(t)|cos(θ) = 0
where θ is the angle between r(t) and r'(t).
Since |r(t)| = 1 for all t, we have cos(θ) != 0, which implies that |r'(t)| must be constant in order to satisfy the equation. Therefore, we can conclude that if |r(t)| = 1 for all t, then |r'(t)| is a constant.
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Find the critical value(s) of t that specify the rejection region for the situation given. (Round your answers to three decimal places. If the test is one-tailed, enter NONE for the unused region.) a left-tailed test witha = 0.01 and 8 dft>t
In this case, you're looking for the critical value of a left-tailed t-test with a significance level (α) of 0.01 and 8 degrees of freedom (df).
A left-tailed test focuses on the lower tail of the distribution, and the rejection region is in the left tail. Since it's a one-tailed test, there's no need to find a critical value for the unused region, so we will enter "NONE" for that.
To find the critical value, you need to consult a t-distribution table or use a calculator or software that provides t-distribution values. Look for the value that corresponds to a 0.01 significance level (α) and 8 degrees of freedom (df).
After checking the t-distribution table or using a calculator, you'll find the critical value to be approximately -2.896. So, for this left-tailed t-test, any t-value less than -2.896 would fall into the rejection region, indicating a significant result.
In summary:
- Critical value (left-tailed): -2.896 (rounded to three decimal places)
- Critical value (unused region): NONE
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what is the quotient of the polynomials shown below (12x^3+26x^2+25)÷(2x+5)
The quotient of the polynomials is 6x^2 - 2x + 5 with a remainder of -50.
The quotient of polynomials show (12x^3+26x^2+25)÷(2x+5)
To find the quotient of the polynomials ÷ (2x + 5), you can use polynomial long division as follows:
6x^2 - 2x + 5
-----------------------
2x + 5 | 12x^3 + 26x^2 + 25
- (12x^3 + 30x^2)
---------------
-4x^2 + 25
- (-4x^2 - 10x)
--------------
35x + 25
- (35x + 75)
-------------
-50
Therefore, the quotient of the polynomials is 6x^2 - 2x + 5 with a remainder of -50.
According to the general equation for conditional probability, if P(A^ B') = ²
and P(B) = 3, what is P(A[B) ?
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Answer:
To solve for P(A[B), we can use Bayes' theorem, which states that P(A[B) = P(A^B) / P(B). Using the information given, we know that P(A^B') = ², which means that P(B') = 1 - P(B) = 1 - 3 = 2. Therefore, we can also find that P(A^B) = P(B) - P(B^A') = 3 - ² = ². Finally, we can plug these values into Bayes' theorem to get P(A[B) = ² / 3.
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2/3 is answer
Find the critical numbers of the function f below, and describe the behavior of f at these numbers.List your answers in increasing order, with the smallest one first. Enter your answers as whole numbers or fractions.f(x) = x8(x - 4)7At ___ the function has a local maxmum .At ___ the function has a local minimum.At ___ the function has not a max and min.
The critical numbers in increasing order, we have:
x = 0, 4/9, 4
At x = 0, the function has a local minimum.
At x = 4/9, the function has a local maximum.
At x = 4, the function has neither a local maximum nor minimum.
To find the critical numbers of the function f(x) = [tex]x^8(x - 4)^7[/tex]:
We need to take the derivative of the function and set it equal to zero.
f'(x) = [tex]8x^7(x - 4)^7 + 7x^8(x - 4)^6(-1)[/tex]
Setting f'(x) = 0 and solving for x, we get:
x = 0 or x = 4/9
To describe the behavior of f at these critical numbers:
At x = 0, the function has a local minimum.
This is because the derivative changes sign from negative to positive at this point, indicating a change from decreasing to increasing behavior.
At x = 4/9, the function has a local maximum.
This is because the derivative changes sign from positive to negative at this point, indicating a change from increasing to decreasing behavior.
At x = 4, the function has neither a local maximum nor minimum.
This is because the derivative is zero at this point, but does not change sign. Instead, the behavior of the function changes from decreasing to increasing to decreasing again as we move from left to right around x = 4.
Listing the critical numbers in increasing order, we have:
x = 0, 4/9, 4
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(x-2) long divided by 6x^2-7x-5
[tex]\frac{6 x^{2} - 7 x - 5}{x - 2}=6 x + 5+\frac{5}{x - 2}[/tex] and long division is explained below.
Step 1:
Divide the leading term of the dividend by the leading term of the divisor: [tex]6x^2/x=6x[/tex].
Write down the calculated result in the upper part of the table.
Multiply it by the divisor: 6x(x−2)=6x²−12x.
Subtract the dividend from the obtained result: (6x²−7x−5)−(6x²−12x)=5x−5.
Step 2
Divide the leading term of the obtained remainder by the leading term of the divisor: 5x/x=5.
Write down the calculated result in the upper part of the table.
Multiply it by the divisor: 5(x−2)=5x−10.
Subtract the remainder from the obtained result: (5x−5)−(5x−10)=5.
[tex]\frac{6 x^{2} - 7 x - 5}{x - 2}=6 x + 5+\frac{5}{x - 2}[/tex]
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