If you can’t see it let me know and I will type it

Answer:

its b

Step-by-step explanation:

edg 20/21

Answer:

8u =32 this is the equation

Answer and Step-by-step explanation:

8u = 32 is the answer.

This is because there are eight U's, and it is equal to 32.

#teamtrees #PAW (Plant And Water)

Answer:

Hello! answer: x = 15

Step-by-step explanation:

Here is a visual i created of what the complementary angle would look like!

Answer:

33% of the people preferred onions

can i get brainliest now lol

Answer:

Operations on Complex Numbers (page 2 of 3) ... Simplify (2 – i)(3 + 4i). (2 – i)(3 + 4i) = (2)(3) + (2)(4i) + (–i)(3) + (–i)(4i). = 6 + 8i – 3i – 4i2 = 6 + 5i – 4(–1) ... exact same techniques for simplifying complex-number expressions as you do for polynomial ... Suppose you have the following exercise:

Step-by-step explanation:

Answer:

45 square ft^2

Step-by-step explanation: The formula of the area of the trapezoid is A=(a+b)/2 x h. A represents the top while b represents the bottom. 15+3=18 and 18/2=9. If multiply the result by 5, you get 45 as the answer.

Answer:

k=8

Step-by-step explanation:

Cab 1 : 1/km

Cab2: 0.5 /km with Base charge =4

x=0.5 x+4

x-0.5x=4

0.5x=4

4/0.5=x

x=8

Assume x=k

k=8

Answer:

Step-by-step explanation:

30 percent off 180.00 is 126.00.

the difference is $54

Answer:

50

Step-by-step explanation:

32/0.64 = 50

Answer:

Solution given:

x³-3x²+x

taking common

x(x²-3x+1)

is a required answer.

Step-by-step explanation:

I dont know if this helps but that what I came up with

= [tex] log_{ 3}({x}^{2} - 4) - log_{3}(x - 2) + log_{3}(x) [/tex]

= [tex] log_{ 3}(\dfrac{{x}^{2} - 4}{x - 2}) + 2 × 1[/tex]

= [tex] log_{ 3}(\dfrac{(x-2)(x+2)}{x - 2}) + 2 × 1[/tex]

= [tex] log_{ 3}(x+2) + 2 × 1[/tex]

If cos < 0 and cot > 0, then the terminal point is determined by

C. quadrant 3.

In quadrant I the referece angle Ф is Ф.

In quadrant II the referece angle Ф is (π - Ф).

In quadrant III the referece angle Ф is (π + Ф).

In quadrant IV the referece angle Ф is (2π - Ф).

We know, cos is -ve on III and IV quadrants, and cot = 1/tan is +ve on I and III quadrant.

Therefore, The combined condition cos < 0 and cot > 0 satisfies on the II quadrant.

learn more about quadrants here :

https://brainly.com/question/7196312

#SPJ7

Answer:

790000

Step-by-step explanation:

Answer:

790,000

Step-by-step explanation:

You have an equation and a table with the x value given.

Replace x in the formula with the x value in the table and solve for y.

y = x^2 + 1

y = (-3)^2 + 1 = 9+1 = 10

y = (-2)^2 +1 = 4+1 = 5

y = (-1)^2 +1 = 1+1 = 2

y = (0)^2 + 1 = 0+1 = 1

y = (1)^2 +1 = 1+1 = 2

y = (2)^2 +1 = 4+1 = 5

y = (3)^2 +1 = 9+1 = 10

Answer:

x = 19

Step-by-step explanation:

Let's start solving:

5² - 3(3-1) = x

Multiply 5 and 5 and also multiply 3(3-1)

25 - (9-3) = x

Subtract 6 from 25

25 - 6 = x

Simplify

x = 19

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

can't explain how but i'm confident the answer is:

A. G(X) > -6

Answer:

b

Step-by-step explanation:

Answer:

the number of days when instructor do the work alone is 8 days

Step-by-step explanation:

Given that

The apprentice can do the work in 24 days

And, the apprentice and  instructor together can do it in 6 days

We need to find out the number of days when instructor do the work alone

So,

[tex]= \frac{1}{6} - \frac{1}{24} \\\\= \frac{4 - 1}{24} \\\\= \frac{3}{24} \\\\= \frac{1}{8} \\\\= 8[/tex]

hence, the number of days when instructor do the work alone is 8 days

Answer:

The third option

Step-by-step explanation:

[tex]\frac{-56}{8} = -7[/tex]

Answer:

r = [tex]\sqrt{x} A/4\pi[/tex] , or the third option :)

Step-by-step explanation:

Answer:c

Step-by-step explanation:

Answer:

y = mx + b

m = (-5-1)/(3-1)

m = -3

1=(-3)1 + b

b= 4

y= -3x + 4

Answer:

700,000

Step-by-step explanation:

Answer:

700,000

Step-by-step explanation:

It's closer to 700,000 than 800,000. Hope this helps! Have a nice day :)

Answer:

All of them.

Step-by-step explanation:

Rational numbers are defined as the numbers that can be expressed as the ratio of two integers(a/b) where b must be a non-zero number. The rational numbers display a terminating characteristic and they also contain repeating, as well as, recurring digits. All the given numbers are rational as they can be written in the form of p/q.

23.429 = It can be written as a fraction. So, it is a rational number.

10 = 10 is a whole number and it can be written in the form of a/b i.e. 10/1. So, it is a rational number.

13 = 13 also can be written in ration form as 13/1. Therefore, it is also a rational number.

151 = It can be written as 151/1. Hence, it is a rational number.

8/7 = It is already mentioned in the form of a/b. So, it is a rational number.

-4.93 = since it is an integer, it will surely be a rational number.

Answer:

9/4x^2 - 6x +4

Step-by-step explanation:

( 3/2x-2)^2

(3/2x-2)(3/2x-2)

9/4x^2 - 3x - 3x +4

9/4x^2 - 6x +4

3/2 x 2 = 6/2 = 3

Step-by-step explanation:

( 3/2x-2)² = 9/4 x²- 6x +4

Answer:

The number of non-positive integral values of [tex]k[/tex] are contained in the following set:

[tex]S_{k} = \{-1, 0\}[/tex]

Step-by-step explanation:

Let be the following second order polynomial:

[tex]x^{2}-(k + 1)\cdot x + (k^{2}+k -8) = 0[/tex], [tex]k \le 0[/tex] (1)

Whose roots can be found by the Quadratic Formula:

[tex]x_{1,2} =\frac{k + 1\pm \sqrt{k^{2}+2\cdot k +1 - 4\cdot k^{2}-4\cdot k +32 }}{2}[/tex]

[tex]x_{1,2} = \frac{k+1}{2} \pm \frac{\sqrt{33-2\cdot k -3\cdot k^{2}}}{2}[/tex]

Based on the statement, we have the following system of inequations:

[tex]\frac{k+1}{2} + \frac{\sqrt{33 - 2\cdot k -3\cdot k^{2}}}{2} > 2[/tex] (2)

[tex]\frac{k+1}{2} - \frac{\sqrt{33 - 2\cdot k -3\cdot k^{2}}}{2} < 2[/tex] (3)

By (2) we have:

[tex]k + 1 + \sqrt{33-2\cdot k -3\cdot k^{2}} > 4[/tex]

[tex]\sqrt{33 -2\cdot k - 3\cdot k^{2}} > 4 - (k + 1)[/tex]

[tex]33 - 2\cdot k -3\cdot k^{2} > [4 - (k+ 1)]^{2}[/tex]

[tex]33 - 2\cdot k -3\cdot k^{2} > 16 -8\cdot (k+1)+(k+1)^{2}[/tex]

[tex]33 - 2\cdot k - 3\cdot k^{2} > 16-8\cdot k -8 + k^{2}+2\cdot k + 1[/tex]

[tex]33 - 2\cdot k -3\cdot k^{2} > 9 -6\cdot k + k^{2}[/tex]

[tex]0 > 4\cdot k^{2}-4\cdot k -24[/tex]

[tex]4\cdot k^{2}-4\cdot k -24< 0[/tex]

[tex]4\cdot (k^{2}-k-6) < 0[/tex]

[tex]k^{2}-k - 6 < 0[/tex]

[tex](k -3)\cdot (k+2) < 0[/tex]

The solution is:

[tex]k \in (-2, 3)[/tex]

Likewise, we get the following expression from (3):

[tex]k^{2}-k - 6 > 0[/tex]

[tex](k -3)\cdot (k + 2) > 0[/tex]

The solution is:

[tex]k \in (-\infty, -2)\,\cup\,(3, +\infty)[/tex]

The number of non-positive integral values of [tex]k[/tex] are contained in the following set:

[tex]S_{k} = \{-1, 0\}[/tex]

Answer: 7×4³

Step-by-step explanation:

Answer:

7 x 4³

Step-by-step explanation:

using exponents to my understanding,

the answer vis supposed to be;

7 x 4³