If you're conducting a significance test for the difference between the means of two independent samples, what's your null hypothesis? A. H0: = 0 B. H0: p1 - p2 = 0 C. H0: 1 - 2 = 0 D. H0: p = p0 E. H0: = 0

Answer:

B) 6

Step-by-step explanation:

Firstly, we need to know what the question is asking for.

"How many miles does she need to run each hour to complete the run" is asking for a speed in miles per hour.

miles / hour = speed in mph

18 miles / 3 hours = 18/3 mph

18/3 simplifies to 6

Lisa needs to run 6 mph

To answer this question, we'll use the exponential distribution and the concept of the probability density function (pdf). Let X be the time until failure of a single device, with a mean lifetime of 20 months. The exponential distribution has the following pdf:

f(x) = (1/μ) * e^(-x/μ),

where μ is the mean lifetime (20 months in this case).

Now, let's find the probability that the first failure occurs at w months among the 5 independent devices. For this, we need to calculate the probability that none of the other 4 devices fail before w months and that the first device fails at w months.

The probability that a single device does not fail before w months is given by the complementary cumulative distribution function (ccdf) of the exponential distribution:

P(X > w) = e^(-w/μ).

Since the devices are independent, the probability that all 4 devices do not fail before w months is:

P(All 4 devices survive > w) = (e^(-w/μ))^4.

Now, the probability that the first device fails at w months is given by the pdf of the exponential distribution:

P(X = w) = (1/μ) * e^(-w/μ).

Finally, we multiply the two probabilities to find the chance that the first failure occurs at w months:

P(First failure at w) = P(All 4 devices survive > w) * P(X = w)
= (e^(-w/μ))^4 * (1/μ) * e^(-w/μ)
= (1/20) * e^(-5w/20).

Thus, the chance that the first failure will occur at w months is given by the expression (1/20) * e^(-5w/20).

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Answer:

We can find the LCM (Least Common Multiple) of these numbers by finding the prime factorization of each number and then multiplying the highest power of each prime factor together.

Prime factorization of 2: 2

Prime factorization of 4: 2^2

Prime factorization of 6: 2 * 3

Prime factorization of 9: 3^2

Prime factorization of 10: 2 * 5

The highest power of 2 is 2^2.

The highest power of 3 is 3^2.

The highest power of 5 is 5^1.

Multiplying these numbers together gives us:

2^2 * 3^2 * 5^1 = 180

Therefore, the LCM of 2, 4, 6, 9, and 10 is 180.

Step-by-step explanation:

As per the functions given, (f+g)(x) = f(x) + g(x) adding the two functions (f+g)(x) = 3x^2 - 5x + 9.

Adding the two functions, we get:

(f+g)(x) = (2x^2 - 5x + 5) + (x^2 + 4)

(f+g)(x) = 3x^2 - 5x + 9

Therefore, (f+g)(x) = 3x^2 - 5x + 9.

b) (f-g)(x) = f(x) - g(x)

Subtracting the two functions, we get:

(f-g)(x) = (2x^2 - 5x + 5) - (x^2 + 4)

(f-g)(x) = x^2 - 5x + 1

Therefore, (f-g)(x) = x^2 - 5x + 1.

c) (f x g)(x) = f(x) * g(x)

Multiplying the two functions, we get:

(f x g)(x) = (2x^2 - 5x + 5) * (x^2 + 4)

(f x g)(x) = 2x^4 - 5x^3 + 5x^2 + 8x^2 - 20x + 20

(f  x g)(x) = 2x^4 - 5x^3 + 13x^2 - 20x + 20

Therefore, (f x g)(x) = 2x^4 - 5x^3 + 13x^2 - 20x + 20.

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The value of GH in the rectangle is 60 units.

A rectangle is quadrilateral with opposite sides equal to each other and opposite sides parallel to each other.

Therefore, the diagonal of the rectangle divides the rectangle into congruent triangles.

Therefore,

DH = GH

4w + 20 = 6w

subtract 4w from both sides of the equation

4w  - 4w + 20 = 6w - 4w

20 = 2w

divide both sides of the equation by 2

w  =20 / 2

w = 10

Therefore,

GH  = 6(10)

GH = 60 units

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Answer:

29/16, or 1.81 in decimal form.

Step-by-step explanation:

To solve this, we have to find a common denominator between the 2 fractions.

We cannot simplify 15/16 any further without getting a decimal, so let's change 7/8.

A common denominator between the 2 fractions is 16, so multiply 7/8 by 2 to get 14/16.

Now, we have to find out how far she walked in total, so add 14/16 + 15/16:

29/16

Hope this helps! :)

A simple random sampling of 5 observations from a population containing 400 elements was taken. Then, the point estimate of the population means is 18.

You have a simple random sample of 5 observations from a population containing 400 elements, and the observed values are 12, 18, 19, 20, and 21.

To calculate the point estimate of the population mean, we simply take the average of the sample values.

Point estimate of population mean = (12 + 18 + 19 + 20 + 21)/5 = 18

Therefore, the point estimate of the population means is 18.

To clarify the terms used in the question, a "random sample" is a sample that is selected randomly from the population, meaning that every element in the population has an equal chance of being included in the sample. In this case, a simple random sample of 5 observations was taken. "Elements" refers to the individual units or objects within the population that is being studied. In this case, there were 400 elements in the population.

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Answer: use 2 π | b | , where is the frequency.

Step-by-step explanation:

To find the period of any sine or cosine function, use 2 π | b | , where is the frequency. Using the first graph above, this is a valid formula: 2 π 1 2 = 2 π ⋅ 2 = 4 π .

Hope that helps

The 30th term of the given sequence 156, 153, 150, ... is 69.

The given sequence is as follows: 156, 153, 150,...

To locate the 30th term in this sequence, we must first determine the series's pattern. We can observe that each term is dropping by three, resulting in a common difference of -3. As a result, the nth term of this series can be written as a = a1 + (n - 1)d, where a1 represents the first term, d represents the common difference, and n represents the nth term.

We can use the formula for the nth term of an arithmetic sequence:

an = a1 + (n-1)d

In this case, we have:

a1 = 156 (the first term)

d = -3 (the common difference)

n = 30 (the number of terms)

Using the formula, we can calculate the 30th term:

a30 = 156 + (30-1)(-3)

a30 = 156 + (-87)

a30 = 69

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Answer:

9.22

Step-by-step explanation:

pythagorean theorem is C squared= A squared +B squared. because C is 11 and if you square 11 its 121 and 6 squared is 36 so if u do 121-36 its 85

and if u root 85 it comes out as 9.22

Step-by-step explanation:  One way to measure an arc is with degrees. The measure of an arc is equal to the measure of its corresponding central angle. Below, m D C ^ = 70 ∘ and m G H ^ = 70 ∘ . When you measure an arc in degrees, it tells you the relative size of the arc compared to the whole circle.

The length of line segment EB is Option C- 65 units .

In a parallelogram, opposite sides are equal. Therefore, AE = CB = p-8 and CE = AB = 2p-58. Also, AD and BE are diagonals of the parallelogram, and they bisect each other. Thus, we can say that DE = EB. So, we have DE = p+15 and EB = p+15.

AE + EB + CE + DE = perimeter of parallelogram

(p-8) + (p+15) + (2p-58) + (p+15) = 4p - 56

4p - 56 = 4(p - 14)

Therefore, the perimeter of the parallelogram is 4(p-14). Since opposite sides are equal in a parallelogram, we can say that:

2(p-8) + 2(2p-58) = 4(p-14)

p = 50

Substituting the value of p in the equation EB = p+15, we get:

EB = 50 + 15 = 65.

However, we need to remember that DE = EB. Therefore, the length of line segment EB is 65 units (Option C).

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the complete question is:

AE = p 8, CE = 2p 58, and DE = p + 15 in the parallelogram illustrated. How long is the line segment EB?

A - 40units

B.50 units

C.65 units

D.73 units

Answer:

c) 65 units

Step-by-step explanation:

2023 on edge

The first number, 5 x [tex]10^22,[/tex] can be written as 5 followed by 22 zeros:

5,000,000,000,000,000,000,000

To simplify means to make something easier to understand or do by reducing complexity, removing unnecessary details, or using simpler language or concepts.

The second number , 5 × 10², can be written as 5 followed by 2 zeros: 500

The third number, 3.7 x 10⁵³, can be written as 3.7 followed by 53 zeros:

370,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

or in scientific notation as 3.7 x 10⁵³

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Simplify

2. 5 x 10^22. 5 × 10 2 and 3. 7 x 10^53. 7 × 10 5

Answer:

Step-by-step explanation:

Yes, there is a rigid transformation that can map triangle ΔABC to triangle ΔDEC.

A rigid transformation is a transformation that preserves the size, shape, and orientation of a figure. It includes translations, rotations, and reflections. In order for triangle ΔABC to be mapped to triangle ΔDEC, the two triangles must have the same size, shape, and orientation. This can be achieved through a combination of translation, rotation, and/or reflection. For example, if triangle ΔABC is translated by a certain vector and then rotated or reflected, it can be mapped onto triangle ΔDEC.

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From the provided data, it can be deduced that "Butterflies and Ladybugs" is seemingly preferred over the other option in question.

Confirmation of this determination is available because sample 2 received a greater number of votes for "Butterflies and Ladybugs" than sample 1 did. Additionally, the total amount of votes awarded to "Butterflies and Ladybugs" was more pronounced compared to the two remaining choices within sample 2.

One should not make assertions from this dataset stating that "Butterflies and Ladybugs" are the most favored choice overall or universally.

This claim cannot be verified due to the small size of the research survey as solely two samples were utilized; therefore, we may infer that these findings could potentially vary if an alternative method or larger experiment was adopted.

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Answer:

x > 10

Step-by-step explanation:

Subtract 0.75 from 0.81.

This gives you 0.06

Then divide, by the coefficient of x, 0.006

x > 10

Answer:

x > 10

Step-by-step explanation:

0.75 + 0.006x > 0.81

-.75                     -.75

0.006x > 0.06

----------     -------

0.006      0.006

x > 10

The equation that can be used to find the value of x is 120 = (x + 5) × (120/x - 1/3).

Carmen's first trip was 120 miles, and she traveled at an average of x miles per hour. We can use the formula:

distance = rate × time, which can be written as:
120 miles = x miles/hour × time

where, time is the time for outgoing.

For the return trip, Carmen traveled at a rate that was 5 miles per hour faster, so her speed was (x + 5) miles/hour. The time for the return trip was one-third of an hour less than the time for the outgoing trip, so we can represent the return trip time as (time - 1/3) hours. Using the distance formula again for the return trip:
120 miles = (x + 5) miles/hour × (time - 1/3) hours

Now, let's express both times in terms of x. From the first equation, we can find the time for the outgoing trip as:
time = 120 miles / x miles/hour

Substitute this expression for time in the return trip equation:
120 miles = (x + 5) miles/hour × (120/x - 1/3) hours

Now you have an equation that can be used to find the value of x:
120 = (x + 5) × (120/x - 1/3)

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There are two free variables, so the dimension of the eigenspace is 2. So the dimensions of the associated eigenspaces are 2 for all three eigenspace.

To determine which of the given values are complete eigenvalues, we need to find the characteristic polynomial of the matrix. This is done by finding the determinant of (A - λI), where A is the matrix and λ is the eigenvalue:

| 3-λ   2    0   -4    1 |
| 0     1-λ  3    1    0 |
| 1     -1   -1-λ 4    0 |
| -1    0    2    -4-λ 0 |
| 1     1    -1   0    1-λ|

Expanding along the first row, we get:

(3-λ) | 1-λ  3   1   0 |
    |-1   2-λ 4   0 |
    |1    -1  -4-λ 0 |
    |1    -1  0    1-λ |

= (3-λ)[(2-λ)(1-λ)(1-λ) + 4(-1)(1-λ) + 0(4-λ)] - (-1)[(1-λ)(1-λ)(4-λ) + 0(1-λ) + 0(-1)] + (1)[(1-λ)(4-λ)(0) - (2-λ)(1-λ)(-1)] - (1)[(1-λ)(-1)(-1) - (2-λ)(-1)(0)]

= (3-λ)[λ^3 - 6λ^2 + 9λ - 4] + (λ-1)[4λ^2 - 10λ + 6] + (λ-1)(λ-4) - (λ-2)

= λ^5 - 11λ^4 + 44λ^3 - 78λ^2 + 60λ - 16

Now we can check which of the given values satisfy the characteristic polynomial:

(a) 3, († 2), 0, 1
Substituting each value into the polynomial, we get:
3^5 - 11(3^4) + 44(3^3) - 78(3^2) + 60(3) - 16 = 0
2^5 - 11(2^4) + 44(2^3) - 78(2^2) + 60(2) - 16 ≠ 0
0^5 - 11(0^4) + 44(0^3) - 78(0^2) + 60(0) - 16 ≠ 0
1^5 - 11(1^4) + 44(1^3) - 78(1^2) + 60(1) - 16 = 0

So the complete eigenvalues for this matrix are 3, 0, 1.

To find the dimension of the associated eigenspace for each eigenvalue, we need to find the nullspace of (A - λI). For each eigenvalue, we can do this by row reducing the matrix (A - λI) and finding the number of free variables. The dimension of the associated eigenspace is then equal to the number of free variables.

(a) λ = 3:

| 0 -1  1  1 -1 |
| 0 -2  4  0  1 |
| 1 -1 -4  2  1 |
|-1  0  2 -7  1 |
| 1  1 -1  0 -2 |

RREF:

| 1  0 -2  0  0 |
| 0  1 -2  0  0 |
| 0  0  0  1  0 |
| 0  0  0  0  1 |
| 0  0  0  0  0 |

There are two free variables, so the dimension of the eigenspace is 2.

(a) λ = 0:

| 3  2  0 -4  1 |
| 0  1  3  1  0 |
| 1 -1 -1  4  0 |
|-1  0  2 -4  0 |
| 1  1 -1  0  1 |

RREF:

| 1  0 -2  0  0 |
| 0  1 -2  0  0 |
| 0  0  0  1  0 |
| 0  0  0  0  0 |
| 0  0  0  0  0 |

There are two free variables, so the dimension of the eigenspace is 2.

(a) λ = 1:

| 2  2  0 -4  1 |
| 0  0  3  1  0 |
| 1 -1 -2  4  0 |
|-1  0  2 -5  1 |
| 1  1 -1  0  0 |

RREF:

| 1  0 -1  0  0 |
| 0  1 -1  0  0 |
| 0  0  0  1 -1 |
| 0  0  0  0  0 |
| 0  0  0  0  0 |

There are two free variables, so the dimension of the eigenspace is 2.

So, the dimensions of the associated eigenspaces are 2 for all three eigenvalues.

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The negative critical point is approximately -1.812.

The critical values for a two-tailed hypothesis test with a significance level of α = 0.10 and 10 degrees of freedom (sample size - 1) can be found using a t-distribution table or a statistical software.

a) The positive critical point can be found by looking up the t-distribution table or using a statistical software to find the t-value that corresponds to a cumulative probability of 0.95 with 10 degrees of freedom. The value is approximately 1.812.

b) The negative critical point can be found by finding the t-value that corresponds to a cumulative probability of 0.05 with 10 degrees of freedom. Since the t-distribution is symmetric, this value is the negative of the positive critical point. Therefore, the negative critical point is approximately -1.812.

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The image of the point after the reflection over the y-axis is (-3, 6)

For any point of the form (x, y), a reflection across the y-axis just changes the sign of the x-value.

Then the reflection gives:

(x, y) ---> (-x, y)

Here we apply this reflection to the point (3, 6), then we will get:

(3, 6) ---> (-3, 6)

That is the image after the reflection over the y-axis, then the correct option is the fourth one.

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Answer: B

Step-by-step explanation: red to blue

Answer: B

Step-by-step explanation:

Because it asks for you to create a ratio comparing red to blue, you need to order it that way. Since there are 5 reds and 6 blues, you list the 5 in the ratio before you list the 6. It would end up looking like this:

5:6

X(t) = Xo/[1 + (1 - Xo)/Xo exp(-[r - o^2/2]t - oW(t))]

E[X(t)] = Xo/(1 + (1 - Xo)/Xo exp(-r t)),

V[X(t)] = Xo^2 exp(rt)/(1 + (1 - Xo)/Xo exp(rt))^2 - Xo^2/(1 + (1 - Xo)/Xo exp(-r t))^2.

The given equation is a stochastic differential equation (SDE) of the form dX(t) = a(X(t))dt + b(X(t))dW(t), where W(t) is a Wiener process (Brownian motion), a(X(t)) = rX(t)(1 - X(t)), b(X(t)) = oX(t), and Xo is the initial condition.

To solve this SDE, we use Itô's lemma, which states that for a function f(X(t)) of a stochastic process X(t), the SDE for f(X(t)) is given by df(X(t)) = (∂f/∂t)dt + (∂f/∂X)dX(t) + 1/2(∂^2f/∂X^2)(dX(t))^2.

Applying Itô's lemma to the function f(X(t)) = ln(X(t)/(1 - X(t))), we get df(X(t)) = [1/X(t) + 1/(1 - X(t))]dX(t) - 1/2[X(t)^(-2) + (1 - X(t))^(-2)](dX(t))^2.

Substituting a(X(t)) and b(X(t)) in the above expression, we get d[f(X(t))] = [r(1 - 2X(t))dt + o(1 - 2X(t))dW(t)] - 1/2[r^2X(t)(1 - X(t))^2 + o^2X(t)^2]dt.

Integrating both sides of the above expression from time 0 to t and using the initial condition X(0) = Xo, we get ln[X(t)/(1 - X(t))] = ln[Xo/(1 - Xo)] + [r - o^2/2]t + oW(t).

Solving for X(t), we get X(t) = Xo/[1 + (1 - Xo)/Xo exp(-[r - o^2/2]t - oW(t))].

Taking the expectation and variance of X(t), we get:

E[X(t)] = Xo/(1 + (1 - Xo)/Xo exp(-r t)),

V[X(t)] = Xo^2 exp(rt)/(1 + (1 - Xo)/Xo exp(rt))^2 - Xo^2/(1 + (1 - Xo)/Xo exp(-r t))^2.

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The angle of the rhombus is given as 54 degrees (alternate angles)

A rhombus, a four-sided polygon dotted with sides of the corresponding length, has adjacent angles with equal measure and all four edges culminating in 360 degrees.

If one is seeking to identify the measurements of each angle within a rhombus, they may do so by employing the following formula:

angle measurement = (180 - diagonal angle)/2

To begin, single out one of the diagonal angles; then, take 180 minus that angel and subsequently halve it--this is the measure of each neighboring angle.

Repetition of this procedure on the opposing diagonal angle should enable you to uncover all four side lengths of the rhombus.

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The value of angle 1, 2, 3, and 4 is 42⁰, 48⁰, 42⁰ and 42⁰ respectively.

The value of angle 1, 2, 3, and 4 is calculated as follows;

angle 3 = angle 4 (alternate angles are equal)

angle 3 = 42⁰

let the angle adjacent to 3 = y

y = 90 - 42⁰

y = 48⁰

angle 4 + adjacent angle = 180 - (42 + 48)

angle 4 + angle 2 = 180 - 90

angle 4 + angle 2 = 90

angle 4 = 42⁰ (vertical opposite angles)

angle 2 = 90 - 42⁰

angle 2 = 48⁰

angle 1 = angle 4 = 42⁰ (alternate angles).

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The inequality that shows how many questions, q, will be on Mr. Pham's quiz is: 0 ≤ q ≤ 15

What is inequalities?

In mathematics, an inequality is a mathematical statement that indicates that two expressions are not equal. It is a statement that compares two values, usually using one of the following symbols: "<" (less than), ">" (greater than), "≤" (less than or equal to), or "≥" (greater than or equal to).

This inequality states that the number of questions, q, must be greater than or equal to zero (since there cannot be a negative number of questions), but less than or equal to 15 (since Mr. Pham's quiz will have at most 15 questions).

Therefore, the inequality that shows how many questions, q, will be on Mr. Pham's quiz is: 0 ≤ q ≤ 15

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Answer:

  (b)  2

Step-by-step explanation:

You want the mean absolute deviation of the data ...

  {12, 10, 10, 8, 6, 7, 7, 12}

The mean absolute deviation (MAD) is the mean of the absolute values of the differences between the data values and their mean. The calculation of this is shown in the attachment.

The mean absolute deviation is 2.

<95141404393>

The area of rectangle DEFG is 16 square units and its perimeter is 12 units.

To find the area, we can use the formula: Area = length x width We can find the length and width by calculating the distance between the coordinates of opposite sides of the rectangle.

Length = EF =

[tex] \sqrt{} ((2-1)^2 + (1-3)^2)[/tex]

=

[tex] \sqrt{} (2 + 4) = \sqrt{} (6)[/tex]

Width = DG =

[tex] \sqrt{} ((-3+2)^2 + (1+1)^2) = \sqrt{} (2 + 4) = \sqrt{} (6)[/tex]

The area of rectangle DEFG = length x width =

[tex] \sqrt{} (6) x \sqrt{} (6)[/tex]

= 6 x 2 = 16 square units.

To find the perimeter, we can add up the lengths of all four sides: Perimeter = DE + EF + FG + GD

DE =

[tex] \sqrt{} ((1+3)^2 + (-3+(-1))^2) = \sqrt{} (16 + 4) = \sqrt{} (20)[/tex]

EF =

[tex] \sqrt{} ((2-1)^2 + (1-3)^2) = \sqrt{} (2 + 4) = \sqrt{} (6)[/tex]

FG =

[tex] \sqrt{} ((2+2)^2 + (1+1)^2) = \sqrt{} (16 + 4) = \sqrt{} (20)[/tex]

GD =

[tex] \sqrt{} ((-2+3)^2 + (-1-1)^2) = \sqrt{} (1 + 4) = \sqrt{} (5)[/tex]

The perimeter of rectangle DEFG =

[tex] \sqrt{} (20) + \sqrt{} (6) + \sqrt{} (20) + \sqrt{} (5) [/tex]= 12 units.

Hence, The area of the rectangle is 16 square units and the perimeter is 12 units.

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The simplified value of the expression is 12km³.

We have,

[tex]12k^2m^8 \div 4km^5[/tex]

This can be written as:

[tex]\frac{12k^2m^8}{ 4km^5}[/tex]

Canceling common expression.

= 12km³

Thus,

The simplified value of the expression is 12km³.

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At the end of the code, max contains the value of the larger of x and y.

The correct fragment of code that assigns the larger of x and y to another integer variable max is:int max;

if (x > y) {

   max = x;

} else {

   max = y;

}

In this code fragment, we first declare the integer variable max without assigning it a value. We then use an if statement to compare x and y. If x is greater than y, we assign x to max, otherwise, we assign y to max. At the end of the code, max contains the value of the larger of x and y.

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The value of the inflection point is 1/10, and the intervals on which the function is concave up or down are (0, 1/10) and (1/10, ∞).

Taking the second derivative of y(x), we get:

y''(x) = 240x³ - 24x²

Setting y''(x) equal to zero and solving for x, we get:

x = 0 or x = 1/10

These critical points divide the real line into three intervals:

(-∞, 0), (0, 1/10), and (1/10, ∞)

We evaluate the sign of y''(x) on each of these intervals to determine where the function is concave up or down:

For x < 0: y''(x) < 0, so y(x) is concave down.

For 0 < x < 1/10: y''(x) > 0, so y(x) is concave up.

For x > 1/10: y''(x) > 0, so y(x) is concave up.

Therefore, the function is concave down on the interval (-∞, 0) and concave up on the intervals (0, 1/10) and (1/10, ∞).

To find the inflection point, we set y''(x) equal to zero and solve for x:

240x³ - 24x² = 0

Factor out 24x²:

24x²(10x - 1) = 0

So either x = 0 or x = 1/10.

Since the second derivative changes sign at x = 1/10, this is an inflection point.

Therefore, the inflection point occurs at x = 1/10.

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The question is -

Determine the intervals on which the function is concave up or down and find the value at which the inflection point occurs.

Y = 8x^5 - 3x^4

(Express intervals in interval notation. Use symbols and fractions when needed)

point of influence at x = __________

interval on which function is concave up = ____________

interval on which function is concave down = ___________

The projection of f onto the subspace W, we need to take the inner product of f with each of the basis vectors in W and multiply by the basis vectors. Then we add the results together. Therefore, the projection of f onto W is 2/3 + √2.

So, first we need to find the inner products of f with g1 and g2:

(f, g1) = integral -1 to 1, f(x)g1(x) dx

= integral -1 to 1, ([tex]x^2[/tex] + 5x)(1/√2) dx

= (1/√2) integral -1 to 1, [tex]x^2[/tex] dx + (5/√2) integral -1 to 1, x dx

= (1/√2) (2/3) + (5/√2) (0)

= √2/3

(f, g2) = integral -1 to 1, f(x)g2(x) dx

= integral -1 to 1, ([tex]x^2[/tex] + 5x)√(3/2) dx

= √(3/2) integral -1 to 1, [tex]x^2[/tex] dx + √(3/2) integral -1 to 1, 5x dx

= √(3/2) (2/3) + √(3/2) (0)

= √(2/3)

Now we can find the projection of f onto W:

projW(f) = (f, g1) g1 + (f, g2) g2

= (√2/3) (1/√2) + (√(2/3)) (√(3/2))

= 2/3 + √2

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