Ifx + iy = 1
1+i/
1-i
prove that, x² + y² = 1

Answer:

Step-by-step explanation:

The statement

3x less than two times the sum of 2X and one is written as

2( 2x + 1) - 3x

the sum of 2 and 5 is written as

2 + 5

Equate the two statements

We have

2( 2x + 1) - 3x = 2+5

Expand

4x + 2 - 3x = 7

Simplify

4x - 3x = 7 - 2

We have the final answer as

Hope this helps you

Answer:

18

Step-by-step explanation:

Given the above table of the data set, the number of values less than or equal to 6 would be the sum of the frequencies of all values that is equal to or less than 6.

From the table above, we would add up the frequencies of the values of 6 and below, which is:

2 + 3 + 6 + 4 + 3 = 18

Answer = 18

The number of values less than or equal to 6 is 18

Here the number of values should be less than or equivalent to 6 represent the sum of the frequencies i.e. equal or less than 6

So, here the number of values should be

= 2 + 3 + 6 + 4 + 3

= 18

Hence, we can conclude that  The number of values less than or equal to 6 is 18

Learn more about frequency here: https://brainly.com/question/20875379

Answer:

x = 4/3

Step-by-step explanation:

Direct variation:

y = kx

We use the given x-y point to find k.

6 = k * 2/3

k = 6 * 3/2

k = 9

The equation is

y = 9x

For y = 12,

12 = 9x

x = 12/9

x = 4/3

Answer:

see below.

Step-by-step explanation:

1st row has four small boxes

2nd row has three big boxes

big box 1 has no items ragged in it.

big box 2 has small box 1 and also small box 1 dragged into it.

big box 3 has small box 3 and small box 4 dragged into it.

Answer:

90/x=70/100 that's my answer

[tex]90 \x = 70 \100[/tex]

Answer:

90/x = 70/100

Step-by-step explanation:

Is means equals and of means multiply

90 = 70% *x

Changing to decimal form

90 = .70x

Changing to fraction form

90 = 70/100 *x

Divide each side by x

90/x = 70/100

Answer:

Discount : $34.25 off. Percent of the discount : 25%

Step-by-step explanation:

137 - 102.75 = 34.25.

34.25/137 x 100 = 25%

Answer:

Chain rule: [tex]\frac{d}{dx} [f[u(x)]] = \frac{df}{du} \cdot \frac{du}{dx}[/tex], u-Substitution: [tex]f\left[u(x)\right] = \int {\frac{df }{du} } \, du[/tex]

Step-by-step explanation:

Differentiation and integration are reciprocal to each other. The chain rule indicate that a composite function must be differentiated, describing an inductive approach, whereas u-substitution allows integration by simplifying the expression in a deductive manner. That is:

[tex]\frac{d}{dx} [f[u(x)]] = \frac{df}{du} \cdot \frac{du}{dx}[/tex]

Let integrate both sides in terms of x:

[tex]f[u(x)] = \int {\frac{df}{du} \frac{du}{dx} } \, dx[/tex]

[tex]f\left[u(x)\right] = \int {\frac{df }{du} } \, du[/tex]

This result indicates that f must be rewritten in terms of u and after that first derivative needs to be found before integration.

Answer:

D. 4x − 6

Step-by-step explanation:

f(x) = 4x − 2

f(x−1) = 4(x−1) − 2

f(x−1) = 4x − 4 − 2

f(x−1) = 4x − 6

Answer:

There is sufficient evidence to conclude that women make less money than men doing the same job.

Step-by-step explanation:

The hypothesis for the test can be explained as follows:

H₀: Women does not make less money than men doing the same job, i.e. [tex]\mu\geq \$1343[/tex].

Hₐ: Women make less money than men doing the same job, i.e. [tex]\mu<\$1343[/tex].

From the provided data compute the sample mean and standard deviation:

[tex]\bar x=\frac{1}{n}\sum X=\frac{1}{18}[1811+728+...+1170]=1125.11\\\\s=\sqrt{\frac{1}{n-1}\sum (X-\bar x)^{2}}=\sqrt{\frac{1}{18-1}\times 1322541.86}=278.92[/tex]

Compute the test statistic as follows:

[tex]t=\frac{\bar x-\mu}[\s/\sqrt{n}}=\frac{1125.11-1343}{278.92/\sqrt{18}}=-3.143[/tex]

The test statistic value is -3.143.

Compute the p-value as follows:

[tex]p-value=P(t_{n-1}<-3.143)=P(t_{17}<-3.143)=0.003[/tex]

*Use a t-table.

The p-value of the test is 0.003.

The p-value of the test is very small for all the commonly used significance level. The null hypothesis will be rejected.

Conclusion:

There is sufficient evidence to conclude that women make less money than men doing the same job.

Answer:

The  probability is   [tex]P(A') = 0.485[/tex]

Step-by-step explanation:

Let assume that the number of computer produced by factory C is  k = 1  

 So  From the  question we are told that

       The number produced by  factory A is  4k =  4

        The  number produced by factory B is  7k  = 7

        The  probability of defective computers from A is  [tex]P(A) = 0.04[/tex]

        The  probability of defective computers from B is  [tex]P(B) = 0.02[/tex]

        The  probability of defective computers from C is [tex]P(C) = 0.03[/tex]

Now the probability of factory A producing a defective computer out of the 4 computers produced is  

       [tex]P(a) = 4 * P(A)[/tex]

substituting values

        [tex]P(a) = 4 * 0.04[/tex]

        [tex]P(a) = 0.16[/tex]

The probability of factory B producing a defective computer out of the 7 computers produced is  

       [tex]P(b) = 7 * P(B)[/tex]

substituting values

        [tex]P(b) = 7 * 0.02[/tex]

        [tex]P(b) = 0.14[/tex]

The probability of factory C producing a defective computer out of the 1 computer produced is  

       [tex]P(c) = 1 * P(C)[/tex]

substituting values

        [tex]P(c) = 1 * 0.03[/tex]

        [tex]P(b) = 0.03[/tex]

So the probability that the a computer produced from the three factory will be defective is  

     [tex]P(t) = P(a) + P(b) + P(c)[/tex]

substituting values

     [tex]P(t) = 0.16 + 0.14 + 0.03[/tex]

     [tex]P(t) = 0.33[/tex]

Now the probability that the defective computer is produced from factory A is

      [tex]P(A') = \frac{P(a)}{P(t)}[/tex]

       [tex]P(A') = \frac{ 0.16}{0.33}[/tex]

        [tex]P(A') = 0.485[/tex]

Answer:

14.05

Step-by-step explanation:

We have the following:

Current Dividend = D0 = $ 1.40

g = growth rate = 2%

r = discount rate = 13%

Dividend in Year 5

= D5 = D0 * (1 + g) ^ 5

= $ 1.40 * (1 + 2%) ^ 5

= $ 1.40 * (1.02) ^ 5

Firm Stock Price at the end of year 4 = Dividend in Year 5 / (r - g)

= $ 1.40 * (1.02) ^ 5 / (13% -2%)

= $ 1.40 * (1.02) ^ 5 / (0.13 - 0.02)

Therefore, firm stock at the end of year 4 is

P4 = $ 1.40 * (1.02) ^ 5 / (0.13 - 0.02) = 14.05

Answer:

Step-by-step explanation:

y=4x

Answer:

We conclude that the population means checkout times of the two new systems differ.

Step-by-step explanation:

We are given the result in the following summary of the data;

System          System B

n1=120             n2=100

x1=4.1 min       x2=3.4 min

σ1=2.2 min     σ2= 1.5 min

Let [tex]\mu_1[/tex] = population mean checkout time of the first new system

[tex]\mu_2[/tex] = population mean checkout time of the second new system

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1=\mu_2[/tex]      {means that the population mean checkout times of the two new systems are equal}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1\neq \mu_2[/tex]      {means that the population mean checkout times of the two new systems differ}

The test statistics that will be used here is Two-sample z-test statistics because we know about population standard deviations;

                          T.S.  =  [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1} + \frac{\sigma_2^{2} }{n_2}} }[/tex]  ~ N(0,1)

where, [tex]\bar X_1[/tex] = sample mean checkout time of the first new systems = 4.1 min

[tex]\bar X_2[/tex] = sample mean checkout time of the second new systems = 3.4 min

[tex]\sigma_1[/tex] = population standard deviation of the first new systems = 2.2 min

[tex]\sigma_2[/tex] = population standard deviation of the second new systems = 1.5 min

[tex]n_1[/tex] = sample of the first new systems = 120

[tex]n_2[/tex] = sample of the second new systems = 100

So, the test statistics =  [tex]\frac{(4.1-3.4)-(0)}{\sqrt{\frac{2.2^{2} }{120} + \frac{1.5^{2} }{100}} }[/tex]  

                                    =  2.792

The value of z-test statistics is 2.792.

Now, at 0.05 level of significance, the z table gives a critical value of -1.96 and 1.96 for the two-tailed test.

Since the value of our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the population mean checkout times of the two new systems differ.

Answer:

[tex]d \approx 5.8[/tex]

Step-by-step explanation:

Just use the distance formula.

[tex]d=\sqrt{(x_2-x_{1})^2+(y_2-y_{1})^2}[/tex]

[tex]d=\sqrt{(3-0)^2+(5-0)^2}}[/tex]

[tex]d=\sqrt{(3)^2+(5)^2}}[/tex]

[tex]d=\sqrt{9+25}[/tex]

[tex]d=\sqrt{34[/tex]

[tex]d \approx 5.8[/tex]

Answer:

d. 38

Step-by-step explanation:

AB = AD - BD = 54 - 36 = 18

AC = AB + BC = 18 + 20 = 38

Answer:

-3x^2 -5x +2

Step-by-step explanation:

-2x(x+3)-(x+1)(x-2)=

Distribute

-2x^2 -6x  -(x+1)(x-2)

Foil

-2x^2 -6x  -(x^2 -2x +x -2)

Combine like terms

-2x^2 -6x  -(x^2 -x  -2)

Distribute the minus sign

-2x^2 -6x  -x^2  +x +2

Combine like terms

-2x^2  -x^2  -6x +x +2

-3x^2 -5x +2

Answer:

[tex]\huge\boxed{-2x(x+3)-(x+1)(x-2)=-3x^2-5x+2}[/tex]

Step-by-step explanation:

[tex]-2x(x+3)-(x+1)(x-2)[/tex]

Use the distributive property: a(b + c) = ab + ac

and FOIL: (a + b)(c + d) = ac + ad + bc + bd

[tex]=(-2x)(x)+(-2x)(3)-\bigg[(x)(x)+(x)(-2)+(1)(x)+(1)(-2)\bigg]\\\\=-2x^2-6x-\bigg(x^2-2x+x-2\bigg)=-2x^2-6x-x^2-(-2x)-x-(-2)\\\\=-2x^2-6x-x^2+2x-x+2[/tex]

Combine like terms:

[tex]=(-2x^2-x^2)+(-6x+2x-x)+2=-3x^2+(-5x)+2\\\\=-3x^2-5x+2[/tex]

Answer:

a.  $75.60

b.  $1335.60

Step-by-step explanation:

A.  First convert the percentage to a decimal.

6% = 0.06

Multiply the cost of the computer by the decimal to find the tax paid.

$1260 × 0.06 = $75.60

B.  To find the total cost, add the cost of the computer with the tax.

$1260 + $75.60 = $1335.60

Answer:

$15,842

Step-by-step explanation:

We use the Present value formula

Present Value = Future value/(1 + r)ⁿ

r = 6% = 0.06

n = 4 years

Future value = $20,000

Present value = 20,000/(1 + 0.06)⁴

= $15841.873265

≈ $15,842

Answer:

quadratic

Step-by-step explanation:

This graph has a parabola form wich is a propertie for qaudratic functions

Answer:

A

Step-by-step explanation:

Answer:

its 14/C

Step-by-step explanation:

i got i right on edg U^U

Answer:

16

Step-by-step explanation:

i did edge test yea dont  be imma fake :***    

Answer:

answer D

Step-by-step explanation:

Lets have a look to the graph and to the  each of given functions.

As we can see in graph it intersects X in points (-3;0) and (-6;0) that means the function has the roots x1=-3 and x2=-6

Function A  has the roots x1=+3 and x2=+6 => doesn' t fit

Function B has only 1 root x=2 , so can be factorized y=(x-2)^2 => doesn' t fit

Function C has 2 roots  x1=4  and x2=-5 => doesn' t fit

Function D can be factotized as y=(x+6)*(x+3) so has 2 roots x1=-6 x2=-3 => exactly what we need!!!

We can also notice that the coefficient near x²  is equal to 1  and is positive.

That means the legs of the graph directed up,- this is exactly like in our graph. It gives us extra argument why we choose D.

Answer:

Step-by-step explanation:

Given the system of equation  x−3y=−3 and x+y=5, we can solve for x and y by solving the equation simultaneously using the substitution method.

x−3y=−3_____________ 1

x+y=5 ______________2

From equation 2; x = 5- y ________ 3

Substitute equation 3 into equation 1

Since x - 3y = -3

(5-y)-3y = -3

5-y-3y = -3

5-4y = -3

Subtract 5 from both sides of the equation

5-4y-5 = -3-5

-4y = -8

Divide both sides by -4

-4y/-4 = -8/-4

y = 2

Substitute y = 2 into equation 2 to get the value of y;

From equation 2, x+y = 5

x+2 = 5

Subtract 2 from both sides of the equation

x+2-2 = 5-2

x = 3

Hence the value of x and y from the graph will be 3 and 2 respectively.

Answer:

Step-by-step explanation:

f(x)=3x+15

let  f(x)=y

y=3x+15

flip x and y

x=3y+15

3y=x-15

y=1/3 x-5

or f^{-1}x=1/3 x-5

Answer:

$7

Step-by-step explanation:

Simple interest formula:

I = Prt

6 months = 6 * 30 days = 180 days

1 year = 360 days

t = (180 days)/(360 days) = 0.5

I = $7000 * 0.002 * 0.5

I = $7

Answer:

$7

Step-by-step explanation:

Recall that simple interest is given by

I = Prt,

Where :

I = interest (we are asked to find this)

P = principal amount = given as $7000

r = rate = given as 0.2% = 0.002

t = time in years = given as 6 months = 0.5 years

SImply substitute the known values into the equation above:

I = Prt

= (7000)(0.002)(0.5)

= $7

Answer:

3.27 hours

Step-by-step explanation:

Calculate the difference in speed and distance between the trains.

The relative speed:

101 - 90 = 11 mph

Difference in distance:

42 - 6 = 36 miles

[tex]time=\frac{distance}{speed}[/tex]

[tex]t=\frac{36}{11}[/tex]

[tex]t = 3.27[/tex]

Answer:

yeah she is correct

Step-by-step explanation:

Answer:

An architect is designing a house for the Frazier family. In the design he must consider the desires of the family and the local building codes. The rectangular lot on which the house will be built has 91 feet of frontage on a lake and is 158 feet deep.

The building codes states that one can build no closer than 10 ft. to the lot line. Write an inequality and solve to see how long the front of the house facing the lake may be.

------

length = 91 - 2*10 = 71 ft.

-------------------------------

The Fraziers requested that the house contain no less 2800 ft square and no more than 3200 ft square of floor sample. Write an inequality to represent the range of permissible widths for the house.

---------

2800 <= area <= 3200

2800 <= (length)(width) <= 3200

2800 <= 71w <= 3200

39.44 <= width <= 45.07

hope it helpsss

Step-by-step explanation:

Answer: An architect is designing a house for the Frazier family. In the design he must consider the desires of the family and the local building codes. The rectangular lot on which the house will be built has 91 feet of frontage on a lake and is 158 feet deep.

The building codes states that one can build no closer than 10 ft. to the lot line. Write an inequality and solve to see how long the front of the house facing the lake may be.

------

length = 91 - 2*10 = 71 ft.

-------------------------------

The Fraziers requested that the house contain no less 2800 ft square and no more than 3200 ft square of floor sample. Write an inequality to represent the range of permissible widths for the house.

---------

2800 <= area <= 3200

2800 <= (length)(width) <= 3200

2800 <= 71w <= 3200

39.44 <= width <= 45.07

Step-by-step explanation:

brain list me please......

Answer:

Jacob:

Alive 69-70

alive 79-80

alive 62-63

alive 73-74

alive 78-Died 79

Carol:

alive 88-89

alive 67-68

alive 99-100

alive 73-74

alive 94- Died 95

Step-by-step explanation:

Answer:

-21/5 = -4.2

Step-by-step explanation:

-21.87 / 4.79 = -4.5657.....

So, the quotients is -4

Now, Let's see who's quotient is equal to think one:

-21/4 = -5.25

-21/5 = -4.2

-40/4 = -5

-20/5 = 4

Answer:

-21/5 = -4.2

Step-by-step explanation:

Answer:

Correct option: D

Step-by-step explanation:

In the figure we have a right triangle, that is, one of the angles is a 90° angle. Therefore, we can use the Pythagoras' theorem to find the relation between the sides of the triangle:

[tex]a^2 = b^2 + c^2[/tex]

Where b and c are cathetus of the triangle (sides adjacent to the 90° angle) and a is the hypotenuse (opposite side to the 90° angle).

So in our case, we have that x is the hypotenuse, and 40 and 42 are cathetus, so we have:

[tex]x^2 = 40^2 + 42^2[/tex]

[tex]x^2 = 1600 + 1764[/tex]

[tex]x^2 = 3364[/tex]

[tex]x = 58[/tex]

So the correct option is D.