I’m confused as to how to do this

Answer:

(-6, -3) (-3,-3) (-3,-6)

Step-by-step explanation:

Multiple all of the vertices by 1.5.

(-6, -3) (-3,-3) (-3,-6)

Hope I helped!

[enlargment will still be a triangle]

Answer:

B

Step-by-step explanation:

We know that when x=0 y=5

B and D are the only ones that meet this criteria

we know that when x=2 y= 13 or so

D no longer works

it has to be B

its c because i already did that and got it right

The value of the expression is 17.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

r + 4

When r = 13

r + 4

= 13 + 4

= 17

Thus,

The value is 17.

Learn more about expressions here:

https://brainly.com/question/3118662

#SPJ5

Answer:

128°

Step-by-step explanation:

180-52=128

Answer:

I love alegbra anyways

The ans is in the picture with the steps how i got it

(Hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\tan22=h_1/200,\ \tan29=h_2/200

h_2+h_1=200(\tan29+\tan22)

H\approx 191.667ft

H\approx 191’ 8”

Answer:

1.52%

Step-by-step explanation:

Answer:

128

Step-by-step explanation:

16 x 8 = 128

Answer:

128

Step-by-step explanation:

you multiply 16 and 8 because each team has 16 and there are 8 teams so, 16×8=128

Answer:

so least to greatest? 1/4 1/3 1/2

Answer:

1/4, 1/3, 1/2

Step-by-step explanation:

Answer:

Question 13 is 27/2 (decimal form, 13.5, Mixed fraction 13 1/2)

Question 14 = 4

Step-by-step explanation:

hope this helped you:)

Answer:

[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (1,-2)[/tex] --- Point

[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]

The arc length of a function on interval [a,b]:  [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]

By comparison:

[tex]f'(x)^2 = 144x^{-6}[/tex]

[tex]f'(x)^2 = \frac{144}{x^6}[/tex]

Take square root of both sides

[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]

[tex]f'(x) = \±\frac{12}{x^3}[/tex]

Split:

[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]

To solve fo f(x), we make use of:

[tex]f(x) = \int {f'(x) } \, dx[/tex]

For: [tex]f'(x) = \frac{12}{x^3}[/tex]

[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = \frac{12}{2x^2} + c[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = \frac{6}{1^2} + c[/tex]

[tex]-2 = \frac{6}{1} + c[/tex]

[tex]-2 = 6 + c[/tex]

Make c the subject

[tex]c = -2-6[/tex]

[tex]c = -8[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = \frac{6}{x^2} -8[/tex]

For: [tex]f'(x) = -\frac{12}{x^3}[/tex]

[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = -\frac{12}{2x^2} + c[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = -\frac{6}{1^2} + c[/tex]

[tex]-2 = -\frac{6}{1} + c[/tex]

[tex]-2 = -6 + c[/tex]

Make c the subject

[tex]c = -2+6[/tex]

[tex]c = 4[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = -\frac{6}{x^2} + 4[/tex]

You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

If the function is differentiable in the given interval, then we have:

[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]

where s denotes the length of the arc of the given function from x = a to x = b

Using the above formula, as we're already given the arc length, thus,

[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]

This gives us

[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]

Integrating both sides with respect to x, we get:

[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]

where c is constant of integration.

Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:

[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]

c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]

c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]

The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

Learn more about length of the arc of a curve here:

https://brainly.com/question/14319881

Answer:

3

Step-by-step explanation:

24 + 12 = ___(8+4)

36 = ___(12)

36/12 = 3

Answer:

about 28

Step-by-step explanation:

Step-by-step explanation:

Using Pythagoras theorem

x=✓(35²-21²)=✓784=28 units

Answer:

168.75

Step-by-step explanation:

......

Answer:

168.75

Step-by-step explanation:

Hello!

[tex]\large\boxed{\frac{2\pi}{3} \text{ and } \frac{4\pi}{3}}[/tex]

2cosФ + 1 = 0

Begin by isolating for cosФ. Subtract both sides by -1:

2cosФ = -1

Divide both sides by 2:

cosФ = -1/2

Using the unit circle, we know that from [0, 2π), values that have a cosine of -1/2 are 2π/3 and 4π/3.

Therefore, the solutions of this equation are:

Ф = 2π/3 and 4π/3

Answer:

A  , B, and C

Step-by-step explanation:

i just did it

Answer:

If your polynomial is x^2+x-30, then your answer is (−5)(+6)

Answer:

Sophie has 12 feet more

Step-by-step explanation:

Answer: -628

Step-by-step explanation:

F(140) = 212 - 6(140)

F(140) = 212 - 840

F(140) = -628

Answer: 53.0

Step-by-step explanation:

Then the diameter equals 53.0122774

The diameter of the sphere is 53.01 inch

What is a Sphere?

A sphere is symmetrical, round in shape. It is a three dimensional solid, that has all its surface points at equal distances from the center. It has surface area and volume based on its radius. It does not have any faces, corners or edges.

The Surface Area of a Sphere = 4πr²

The Volume of a Sphere = ( 4/3 ) πr³

where r is the radius of the sphere

Given data ,

Let the diameter of the sphere be = d

The radius of the sphere be = r

The volume of the sphere is V = 78006 inch³

The Volume of a Sphere = ( 4/3 ) πr³

Substituting the values in the equation ,we get

( 4/3 ) πr³ = 78006 inch³

Now , Multiply by ( 3 / 4 ) on both sides , we get

πr³ = ( 78006 x 3 ) / 4

     = 58504.5 inch³

Divide by π on both sides , we get

r³ = 58504.5 / π

   = 18622.56 inch³

Taking cube roots on both sides , we get

r = 26.506 inch

So , the radius of the sphere is r = 26.506 inch

Now , the diameter of the sphere is d = 2 x r

                                                               = 2 x 26.506

                                                               = 53.01 inch

Hence , The diameter of the sphere is 53.01 inch

To learn more about sphere click :

https://brainly.com/question/27933834

#SPJ2

Answers:

Here you go, hope this helps

Step-by-step explanation:

6+2x

Answer:

x=13 y=25

Step-by-step explanation:

Answer:

Step-by-step explanation:

ΔABC has AB = 2BC, hypotenuse is twice the leg

ΔBCD is isosceles right triangle

ΔMPN is isosceles right triangle (∠M = 45°)

ΔMKP is isosceles right triangle (∠M = 45°)