Answer:
Moving vehicles have a lot of kinetic energy, and when brakes are applied to slow a vehicle, all of that kinetic energy has to go somewhere.
Explanation:
True or False. Father of a multitude" obeyed God's command to kill His son because the Ten Commandments had not yet been given.
Answer:
Explanation:
He agreed to the command, because it was God who proposed it. The story is supposed to make a comment on faith. Abraham had faith that somehow God would make everything right. The Ten commandments came later, but really had nothing to do with Abraham's decision.
True.
8.
When minerals seep into and replace the organic cells of a dead organism, creating a
mineral replica of the organism is called ...
Petrification
b. Tar Seeps
C. Amber
d. Mummification
Answer:
a. petrification
Explanation:
tar seeps = natural trade that, because of its close proximity to the ground surface, seeps from the cracks in the Earth or between rocks forming pits or pools (tar pits)
amber = fossilized resin produced by extinct coniferous trees, typically yellow in color
mummification = a process in which the skin and flesh of a corpse can be preserved by embalming and drying
Two students run a race. Student A is 50 kg and runs at 5 m/s. Student B is 30 kg and runs at 2 m/s. Which
student has more Kinetic energy?
Answer:
Explanation:
KEA = ½(50)5² = 625 J
KEB = ½(30)2² = 60 J
Student A has more kinetic energy.
More than ten times more kinetic energy due to both larger mass and higher velocity.
2- What is the kinetic energy in (N.m) and Joules of a 4Kg bowling ball rolling down a
bowling lane at 10 m/s? compare this energy with that of a 250g baseball traveling 50
m/s. which object would hurt more if it hit you (i.e., which object has the greater kinetic
energy)?
Happy Holidays!
Recall the equation for kinetic energy:
[tex]\large\boxed{KE = \frac{1}{2}mv^2 (J)}}[/tex]
m = mass (Kg)
v = velocity (m/s)
KE = kinetic energy (Nm or J)
We can find the kinetic energy for both the bowling ball and baseball:
Bowling ball:
[tex]\large\boxed{KE = \frac{1}{2}(4)(10^2) = 200 J}[/tex]
Baseball:
[tex]\large\boxed{KE = \frac{1}{2}(.25)(50^2) = 312.5 J}[/tex]
Since 312.5 J > 200 J, the BASEBALL has the greater kinetic energy. Thus, it would exert a greater impact force than the bowling ball, so it would hurt more.
8/10
A person stands on a square pedestal whose side lengths are
1.20 m. The person and pedestal together weigh 1.84 x 103 N.
What is the pressure the person and and pedestal exert on the
floor in Pa?
Answer:
Explanation:
P = 1.84 x 10³ N / 1.20² m² = 1,277.77777... N/m²
P = 1.28 x 10³ Pa
PLEASE ANSWER QUICK GIVING BRAINLIEST TO THE ONE WHO ANSWERS
Describe what happens when iron and oxygen combine. Can the change be reversed?
Answer:
iron combines with oxygen to produce rust, which is the compound named iron oxide.
Explanation:
6. The first vertebrates appeared during
a. Precambrian time
b. the Paleozoic Era
C. the Mesozoic Era
d. The Cenozoic Era
Answer:
b. the Paleozoic Era
Explanation:
The first vertebrates to appear are primitive fish in the Cambrian Period, but bony fishes with actual bony vertebratae didn't appear for another 100 million years. The Cambrian Period is the first of three periods in the Paleozoic Era. The Cambrian explosion was an event when practically all major animal phyla started appearing in the fossil record.
Blonde hair is produced by inheriting double recessive alleles (bb) from one’s parents. What is the probability of their offspring having blonde hair?
plz help
Answer:
25%
Explanation:
2. What is the oxidation number of oxygen in most compounds?
A. 6
B.-2
C. 8
D.O
Answer:i am pro
kExplanation:
if it takes a track runner 2.16 seconds to reach a speed of 5.31 m/s from the start of a race, what is the runners acceleration?
Answer:
Explanation:
Answer:
Explanation:
Velocity v (m/s)
11/A stone is dropped from the top of a 45 m high building, How
fast will it be moving when it reaches the ground? And what
lits velocity be?
Explanation:
given solution
h=45m v^2=u^2+2gh
g=10m/s^2 v^2=0^2+2×10m/s^2×45m
vi=0 v^2=900m^2/s^2
v=30plz help ASAP I'll mark as brainliest
Hi there!
1.
Hooke's law states that:
F = -kx
k = Spring constant (N/m)
x = DISPLACEMENT from equilibrium (m)
Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.
2.
The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)
3.
The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.
4.
We can begin by looking at the given graph.
When the spring force = 4N, the total length of the spring is 35 cm.
Now, the EQUILIBRIUM length is 30 cm, so the total elongation is:
35 - 30 = 5 cm.
5.1.
If the spring elongates by 10 cm, the total length of the spring is:
30 + 10 = 40 cm
According to the graph, a length of 40 cm corresponds to a force of 8N.
5.2.
We can solve for the weight of the ball using the following:
W (weight) = m (mass) · acceleration due to gravity (10N/kg)
Using a summation of forces:
∑F = T - W
The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:
0 = T - W
T = W = 8 N
5.3.
0 = T - Mg
T = Mg
Use the prior value of T and gravity to solve:
8 = 10M
m = 0.8 kg
Energy can be changed from one form to another. Which terms can be used to describe these changes? Check all
that apply.
energy conversion
energy conservation
energy correlation
energy transformation
energy transference
Answer:
energy transformation
Answer: Energy Transformation & Energy Conversion.
A boy weighing 445 N swings on a 2-m long swing. If his horizontal speed at the lowest point is 3 m/s, what total force must the ropes holding the swing be able to withstand?
Explanation:
We need to calculate the centripetal force:
Fc = W + F
With Fc being the centripetal force, W the weight of the boy, F the centrifugal force (apparent).
We know that we can calculate the apparent centrifugal force thank to the formula:
F = (m·v²)/r = 204N
So we can write:
Fc = W + F = 445N + 204N = 649N
how long is the photons journey from the milky way to earth
1. A 1.30 kg ball strikes a wall with a velocity of -10.5 m/s. The ball bounces off with a velocity of 6.50 m/s. If the ball is in contact with the wall for 0.0210 seconds, what is the force exerted
on the ball by the wall?
O 1050 N
22.1 N
0 402 N
0 651 N
CAN SOMEONE PLS PLS ACTUALLY HELP ME
Let F be the magnitude of the force. The impulse of this force while the ball is in contact with the wall is
Ft = F (0.0210 s)
and this impulse is equal to the change in the ball's momentum,
m ∆v = (1.30 kg) (6.50 m/s - (-10.5 m/s)) = (1.30 kg) (17.0 m/s)
Solve for F :
F (0.0210 s) = (1.30 kg) (17.0 m/s)
F = (1.30 kg) (17.0 m/s) / (0.0210 s)
F ≈ 1050 N
Who did the ram caught in the thicket (Genesis 22:13) represent?
Answer:
I'm no Bible person, but I think it stands for i-dont-give-a-donkey-poop.
and suck-dog-nuts.
an object is traveling with a constant velocity of 5m/s. How far will it have gone after 7s
Answer:
35m/s
Explanation:
Answer:
35m/s
Explanation:
Simply multiply 5 and 7.
Anita Knapp needs to get hay to cows in a frozen field using an airplane flying 80.0 m/s, at a height of 300,m. If at the last minute, how far from the cow would she have to release the hay in order to hit the cow? *
Answer:
Explanation:
If we ignore wind resistance, the time needed for the hay to drop from vertical rest is
t = √(2h/g) = √(2(300)/9.81) = 7.82 s
d = vt = 80.0(7.82) = 626 m before passing over the cow.
What is the name of Fe(NO3)3
Answer:
Iron(III) nitrate
Explanation:
Explain how the graphic organizer helped you formulate your decision and participate in the discussion.
Answer:
The graphic organizers help to keep track of the details. They are a visual representation of knowledge that rescue the important aspects of a concept using labels within a scheme. They also present information in a concise manner, highlighting the organization and the relationship of the concepts. Graphic organizers help students organize their thinking process and their writing.
Explanation:
find the total volume of the material used to making the cylinder
Answer:
Hey mate
Explanation:
Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.
pls mark me as brainliest!!
1. 1. are the charged parts of an atom.
a. Only electrons
b. Only protons
c. Neutrons only
d. Electrons and neutrons
e. Electrons and protons
f. Protons and neutrons
Answer:
e. Electrons and protons
Explanation:
A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from
the base of the cliff does it land?
Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.
[tex]\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}[/tex]
There is NO initial vertical velocity, so:
[tex]\large\boxed{\Delta d= \frac{1}{2}at^2}}[/tex]
Rearrange to solve for time:
[tex]2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}[/tex]
Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)
[tex]t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s[/tex]
Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
[tex]\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}[/tex]
How can whales descend quickly and face no problems
Answer:
Whales face an increasing number of threats including: For hundreds of years people hunted whales for their oil to fuel lamps and candles, to lubricate machinery and to make margarine, lipsticks and other products. They also used baleen whales to make tennis racquets and corsets!
Explanation:
A cylinder with a radius of 1.8 cm is floating in water as shown below. The mass of the cylinder is 1.80 kg. Calculate the depth of the bottom end of the cylinder
Answer:
Explanation:
I will ASSUME that the cylinder floats with the axis through the center of its flat ends is perpendicular to the water surface.
The cylinder will displace it's mass in water.
water density has a value of 1000 kg/m³
if the depth of the bottom is "h" in meters
1.80 kg = π(0.018² m²)(h m)(1000) kg/m³
h = 1.768388256...
or about 1.77 m
The potential at point P is the work required to bring a one-coulomb test charge from far
away to the point P?
True or false ?
6. A man with a mass of 75 kg standing on a skateboard is holding a medicine ball that has
a mass of 20 kg. If the man throws the ball to the left with a speed of 10 m/s,
a) What happens to the man on the skateboard?
b) What is the man's speed after throwing the ball?
Answer:
Explanation:
Conservation of momentum
a) the man and skateboard move to the right.
b) His speed depends on the reference frame of the ball speed.
If the speed of the ball is 10 m/s relative to ground and the man's final speed is v, then.
(75 + 20)(0) = 20(10) + 75(v)
v = -200/75 = -2.6666...
|v| = 2.7 m/s relative to the ground
This is the likely answer they are seeking.
If the ball is thrown with a speed of 10 m/s relative to the man
(70 + 20)(0) = 20(v + 10) + 75v
20v + 200 = - 75v
200 = - 95v
v = -2.105... m/s velocity or a speed of
|v| = 2.1 m/s relative to ground
and the ball has a velocity of 10 - 2.1 = 7.9 m/s relative to ground.
A 30.0 kg child, initially at rest, slides down a 2.0 m tall slide. The child reaches the bottom of the slide with a speed of 6 m/s. There is friction between the child and the slide. Write a Law of Conservation of Energy equation to represent the transfer of energy from the top of the slide to the bottom. a. b. Use the equation from part (b) to calculate the energy dissipated by friction between the slide and the child? (g = 9.81 m/s) = 13
Answer:
Explanation:
Total energy is constant
E = mgh + ½mv² + Fd
At the top of the slide, all energy is potential
E = mgh + 0 + 0
At the bottom of the slide, all potential energy has converted to kinetic and work of friction.
mgh = ½mv² + W
W = mgh - ½mv²
W = 30.0[(9.81)(2.0) - ½6²]
W = 48.6 J
Define the following units used for measuring distances in space.
a. Arcsecond
b. Astronomical unit
c. Parsec
d. Light year
Answer:
The astronomical unit is used primarily for measuring distances within the Solar System or around other stars.